MATH 6101 Fall 2008

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MATH 6101 MATH 6101 Fall 2008 Functions, Sequences and Limits Functions, Sequences and Limits

Transcript of MATH 6101 Fall 2008

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MATH 6101MATH 6101Fall 2008

Functions, Sequences and LimitsFunctions, Sequences and Limits

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The Topology of the RealsThe Topology of the Reals

We will make some simple definitions. Let a and bpbe any two real numbers with a < b.

(a,b) = { x є R | a < x < b}[a,b] = { x є R | a ≤ x ≤ b}(a,b] = { x є R | a < x ≤ b}[a,b) = { x є R | a ≤ x < b}(a,∞) = { x є R | a < x }[ ) { | }[a,∞) = { x є R | a ≤ x }(–∞,b) = { x є R | x < b }( b] { R | b }(–∞,b] = { x є R | x ≤ b }

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Topology of the RealsTopology of the RealsIf r є R then a neighborhood of r is an open i l ( b) h ( b)interval (a,b) so that r є (a,b).

The neighborhood is centered at r if r = (a + b)/2

If ε and a are reals, then the ε-neighborhood of i th i t l ( )a is the interval (a – ε, a + ε)

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FunctionsFunctionsNicole Oresme – 1350 – described the laws of

l i i d d f nature as laws giving a dependence of one quantity on another.

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History of FunctionHistory of FunctionGalileo – 1638 – studies of motion contain the l d di f l i b clear understanding of a relation between

variables

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History of FunctionHistory of FunctionDescartes - an equation in two variables,

i ll d b i di geometrically represented by a curve, indicates a dependence between variable quantities

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Euclid’s Rational NumbersEuclid s Rational NumbersNewton – showed how functions arise from i fi i iinfinite power seriesLeibniz – 1673 – the first to use the term f ti H t k f ti t d i t i function. He took function to designate, in very general terms, the dependence of geometrical quantities on the shape of a curvequantities on the shape of a curve.

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History of FunctionHistory of Function• Jean Bernoulli - 1718 - function of a variable

as a quantity that is composed in some way as a quantity that is composed in some way from that variable and constants

• Euler – 1748 - A function of a variable Euler 1748 A function of a variable quantity is an analytic expression composed in any way whatsoever of the variable

tit d b t t titiquantity and numbers or constant quantities.• Euler – 1755 - If some quantities so depend

on other quantities that if the latter are on other quantities that if the latter are changed the former undergoes change, then the former quantities are called functions of h l

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the latter.

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History of FunctionHistory of Function• Cauchy – 1821 – still thinking of a function

in terms of a formula (either explicit or in terms of a formula (either explicit or implicit)

• Fourier – 1822 – introduced general Fourier Fourier 1822 introduced general Fourier series but fell back on old definitions

• Dirichlet – 1837 – defined general function and continuity (in modern terms)

• Weierstrauss – 1885 – any continuous function is the limit of a uniformly function is the limit of a uniformly convergent sequence of polynomials

• Goursat – 1923 – modern definition

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Goursat 1923 modern definition

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DefinitionsDefinitionsBernoulli – 1718 – One calls here a function of

i bl i d i a variable a quantity composed in any manner whatever of this variable and constantsconstants.

Basically this meant + × ÷ √ logs and Basically this meant +, –, ×, ÷, √, logs and sines.

They would say that f (x) depended analytically on the variable x

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analytically on the variable x.

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DefinitionsDefinitionsFourier – 1822 – In general the function f(x)

i di h f represents a succession or ordinates each of which is arbitrary. An infinity of values being given to the abscissa x there area an equal given to the abscissa x, there area an equal number of ordinates f(x). All have actual numerical values, either positive or negative , p gor null. We do not suppose these ordinates to be subject to common law; the succeed each other in any manner whatever, and each of them is given as it were a single quantity.

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DefinitionsDefinitionsFourier removed the requirement of “analytic” f h d fi i i I id l d from the definition. It was not widely accepted for years.

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DefinitionsDefinitionsDirichlet – 1837 – Let us suppose that a and b are t d fi it l d i i bl tit hi h two definite values and x is a variable quantity which is to assume, gradually, all values located between a and b. Now, if to each x there corresponds a unique, finite y …, then y is called a … function of x for this interval. It is, moreover, not at all necessary, that y depends on x in this whole interval according to the depends on x in this whole interval according to the same law; indeed, it is not necessary to think of only relations that can be expressed by mathematical

tioperations.

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DefinitionsDefinitionsEvery “Bernoulli” function is a “Fourier” or a “Di i hl ” f i“Dirichlet” function.

Dirichlet:

1 if is rational and 0 1( )

x xf x

ì £ £ïïí( )0 if is irrational and 0 1

f xx x

=íï £ £ïî

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Another “Bad Example”Another Bad Exampled’Alembert was working on the problem of describing a vibrating string. The initial describing a vibrating string. The initial position for the string is not the graph of any analytical expression.

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A More Modern DefinitionA More Modern DefinitionLet D be a set of real numbers. A function

f D Rf: D Ris a rule that assigns a number f (x) to every element x of D element x of D.

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Modern Set Theory DefinitionA f i i d d i l f (F X Y) i h A function ƒ is an ordered triple of sets (F,X,Y) with

restrictions, where F (the graph) is a set of ordered pairs (x,y), X(the source) contains all the first elements of F and perhaps more, and Y (the target) contains all the second elements of Fmore, and Y (the target) contains all the second elements of Fand perhaps more.

The most common restrictions are that F pairs each x with just one y, and that X is just the set of first elements of F and no more.

When no restrictions are placed on F, we speak of a relationbetween X and Y rather than a function. The relation is “single-valued” when the first restriction holds: (x y ) F and (x y ) Fvalued when the first restriction holds: (x,y1) F and (x,y2) Ftogether imply y1 = y2.

Relations that are not single valued are sometimes called multivalued functions. A relation is total when a second restriction holds: if x X then (x,y) F for some y. Thus we can also say that

A function from X to Y is a single-valued, total relation between X and Y

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between X and Y.

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SequencesSequencesLet N = the set of natural numbers (it will not

if i i h i h )matter if it starts with 0 or with 1).A sequence is a function a: N R.

We will normally denote a sequence by its set f { } h ( ) of outputs {an}, where an = a(n).

Occasionally you will see a0, a1, a2, a3, … or {an}∞n=0

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ExamplesExamples1) {1,2,3,4,5,6,…} – an arithmetic progression

(f (n) = n)2) {a + bn | n=0,1,2,3,…} – a different type of

arithmetic progression – (f (n) = a + bn)3) {a0,a1,a2,a3,a4,…} – a geometric progression

(f (n) = an)4) {1,¹/² ,¹/³ ,¹/⁴ ,¹/⁵ ,…} - (f (n) = 1/n) 5) f (n) = an =(-1)n. Note that the range is

{-1,1}

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ExamplesExamples1) f (n) = an = cos(πn/³)

a1 = cos(π/³) =cos 60° = ¹/² a1 cos( /³) cos 60 /² {an} = {½, -½, -1, -½, ½, 1,½, -½, -1, -½, ½, 1, …}. The function takes on only a finite number of values, but the sequence has an infinite number of

lelements.2) f (n) = an = n1/n,

{ 1, 21/2, 31/3,41/4,…} = {1, 1.41421, 1.44225, 1.41421, 8 68 6 1.37973, 1.34801, 1.32047, 1.29684, 1.27652,

1.25893,…} Also a100=1.04713, a10,000 = 1.00092

3) b (1+1/n)n3) bn = (1+1/n)n

{2, (3/2)2, (4/3)3, (54)4,…} = {2, 2.25, 2.37037, 2.44141, 2.48832, 2.52163, 2.54650, 2.56578, 2 58117 2 59374 }

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2.58117, 2.59374,…}Also a100=2.74081 and a10,000 = 2.71815

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Almost all Almost all … Definition: It is said that almost all the terms

f h { } h i of the sequence {an} have a certain property provided that there is an index N such that {an} possesses this property whenever n ≥ Npossesses this property whenever n ≥ N.

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ConvergenceConvergenceDefinition 1: A sequence of real numbers is said to

t l b L if f converge to a real number L if for every ε > 0 there is an integer N > 0 such that if k > N then |ak - L| < ε. | k |

Definition 2: A sequence of real numbers is said to qconverge to a real number L if every neighborhood of L contains almost all of the terms of {an}.

The number L is called the limit of the sequence.

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ConvergenceConvergenceLemma 1: The sequence {1/n} converges to 0.

Proof : Let (a,b) be any neighborhood of 0. This means that a < 0 < b Let N>[1/b] be an This means that a < 0 < b. Let N>[1/b], be an integer greater than 1/b. Then 1/ N < b and for every integer n > N, we have that

a < 0 < 1/n < 1/ N < band (a,b) contains almost all of the elements of h Th h the sequence. Thus, the sequence converges to

0.

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ConvergenceConvergenceLemma 1: The sequence {1/n} converges to 0.

Proof : You prove this using Definition 1.

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ConvergenceConvergenceDefinition: A sequence is convergent if it has a limit If it is not convergent it is called limit. If it is not convergent it is called divergent.

Lemma 2: The sequence {an} converges to L if and only if every neighborhood of L that is centered at L contains almost all of the terms of the sequence.

Note that this tells us that the two definitions are the same.

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are the same.

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ExampleExampleLet an = n/2n. {an} = {1/2, 2/22, 3/23, 4/24,…} 4/2 ,…} Educated guess: {an} -> 0.

L Let ε = 0.1, 0.01, 0.001, 0.0001, 0.00001. ε N

1 N>0We need to find an integer N so that

| N/2N – 0 |< ε

1 N>0

0.1 N>5

0.01 N>9

Look in the table of values. Note that for N = 6 the above is true if ε = 0.1

0.001 N>14

0.0001 N>18

0.00001 N>22

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Theorem(Convergent sequences are bounded) Let {a } be a convergent sequence Then the Let {an} be a convergent sequence. Then the sequence is bounded, and the limit is unique.

Proof:(i)Uniqueness: Suppose the sequence has two limits,

L d K L t > 0 Th i i t N h th t L and K. Let ε > 0. There is an integer NK such that | an – K | < ε /2 if n > NK . Also, there is an integer NL such that | an – L | < ε/ if N/2 if n > NL.

By Triangle Inequality:| L – K |<| a – L |+| a – K |< ε /2 + ε /2 = ε| L K |<| an L |+| an K |< ε /2 + ε /2 ε

if n >max {NK, NL }.Therefore | L – K | < ε for any ε > 0. But this means that L = K

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that L = K.

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Theorem(Convergent sequences are bounded)

Proof:(ii) Boundedness. Since the sequence converges, ( ) q g ,choose any ε > 0. Specifically take ε = 1. There is N so that

| L | if N| an – L | < 1 if n > N.Fix N. Then| a | ≤ | a L | + |L| < 1 + |L| P for all n > N| an | ≤ | an – L | + |L| < 1 + |L| = P for all n > N.

Let M=max{|a1|,|a2|,…|aN|, P}. Thus |an| < M for all n, which makes the sequence bounded.

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all n, which makes the sequence bounded.

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Theorem: If {an}öL, {bn}öM and α is a f n , nreal number, then1. limnö∞ α = α.nö∞

2. limnö∞ (an ± bn ) = L ± M3. limnö∞ (an × bn ) = L × M 3 nö∞ ( n n )4. limnö∞ (αan) = αL 5. If an ≤ bn for all n ≥ m, then L ≤ M5. If an ≤ bn for all n ≥ m, then L ≤ M6. If bn ≠ 0 for all n and if M ≠ 0, then

glb{|bn|}>0.g {| n|}7. limnö∞ (an /bn ) = L/M , provided M ≠ 0.

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Proof:1. limnö∞ α = α

Since α – α = 0, for any ε > 0, | α – α |< ε and Since α α 0, for any ε > 0, | α α |< ε and we are done.

2. limnö∞ (an ± bn ) = L ± Mnö∞ ( n n )Do this for the sum. The difference is similar. Let ε > 0, there exist Na and Nb so that, a b

| an – L | < ε/2 if n > Na and| bn – M | < ε/2 if n > Nb.| n | / b

Let K = max{Na, Nb}, then if n > K|(an+bn) – (L+M)|≤ |an – L|+|bn – M| < ε/2 + ε/2 = ε

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|( n n) ( )| | n | | n | / /

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3. limnö∞ (an × bn ) = L × M Note:|(anbn) – (LM)|≤ |(an – L) bn +L(bn – M)|

≤ |(an – L) bn |+|L(bn – M)|= |(an – L)||bn |+|L||(bn – M)|

Then use the fact that {bn} is bounded.

4. limnö∞ (αan) = αL 4 nö∞ ( n)Consider ε/α if α ≠ 0. If α =0 this is easy.

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5. If an ≤ bn for all n ≥ m, then L ≤ M

6. If bn ≠ 0 for all n and if M ≠ 0, then glb{|bn|}>0.L |M|/ {b } M h i N h if Let ε =|M|/2 > 0. {bn} öM so there is N so that if n > N then | bn - M |<|M|/2.So if n > N we must have | b | ≥ |M|/2 So if n > N we must have | bn | ≥ |M|/2. If not by the Triangle Inequality

|M| = |M - b + b |≤ |M - b | + | b | |M| = |M - bn + bn |≤ |M - bn | + | bn | < |M|/2+|M|/2=|M|

So setSo setm = min {|M|/2,| b1 |,| b2 |,…,| bN |}.

Then m > 0 and | bn | ≥ m for all n

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Then m > 0 and | bn | ≥ m for all n

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7. limnö∞ (an /bn ) = L/M , provided M ≠ 0.

Reduce to limnö∞ (1/bn ) = 1/M – How?

Let ε > 0. By (6) there is m > 0 so that | bn | ≥ m. Since {bn} is convergent there is N so that if n > N

b|M – bn |< ε m |M|Then for n > N| 1/bn – 1/M| = | bn – M|/|bn M|

≤ | bn – M|/(m|M|) < ε

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ExampleExample

4 3 2

4 2

4 7 5280 32165475588741226 7

3lim

7n

n n nn

nn¥

+ - - ++ -

4 3 2

4 4 4 4 4

4 2

14 7 5280 3216547

1

3limn

n n n

n

nn n n n n

+ - - += 4

4 4 4

15588741226 7

4 7 5280 3216547

7

3

n nnn n n

¥+ -

+ - - +2 3 4

2 4

5588741226

3 3lim

77 7n

n n n n

n n¥

+ - - +

+ -= =

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n n

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The Squeeze TheoremTheorem: If {an}öL, {bn}öL and

The Squeeze Theorem

an ≤ cn ≤ bn for all n ≥ mThen {cn}öL.{ n}

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The Power TheoremTheorem: Let a be fixed. Then

The Power Theorem

0 if | | 1aì <ïï1 if 1

limif | | 1n

n aa

dne a¥

ïïï =ï=íï >ï if | | 1if 1

dne adne a

>ïïï =-ïî

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FindFind

2

lim13 5n n+ +

1n n¥ +

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FindFind

2

2

3lim

5 1n n+ +2 1n n¥ +

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FindFind

2

3

3lim

5 1n n+ +3 1n n¥ +

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FindFind

0.5 3s ni

( )l

im

n n+n n¥

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lim2 1n

n

-3 1n n¥ +

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lim2 1n

n

+3 1n n¥ -

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im2

l3n n

n n

+23n nn¥ -

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3

2 4li3

m4n n

nn

-

+ +

+2 45 2nn n+ +¥ -

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2 3 5 6

3 2 10i4 2

l mn n

nn

- +

+

+3 2 105 3nn n¥ - +-

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FindFind

lim nnn¥

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1lim nn nn¥

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æ ösin( )lim 1

næ ö÷ç - ÷ç ÷ç ÷n n¥ ÷ç ÷è ø

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lim n

n2n n¥

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2

limn2n n¥

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!lim n

nn nn¥

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lim!n

n2n n¥

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