LN04-Day Count Conventions

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Transcript of LN04-Day Count Conventions

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Day Count Conventions

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Why “Count” Differently? 

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In the capital markets, there are anumber of ways that days betweendates are computed for interest rate

calculations These conventions developed in

different markets in order to simplify

calculations (before the days of calculators and computers), but theyhave continued to persist

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Calculating Interest Earned

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The day count convention is usually expressed as X  / Y  

When calculating the interest earned between twodates,

◦ X defines the way in which the number of days betweenthe two dates is calculated

◦ Y defines the way in which the total number of days in thereference period is measured

The interest earned between the two dates is

Number of days between dates Interest earned in reference periodNumber of days in reference period

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Five Basic Day CountConventions

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 Actual/360

 Actual/365

 Actual/Actual

30/360

30/360 European

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 Actual/360

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This calculates the actual number of days between two dates and assumesthe year has 360 days

Many calculations for money marketinstruments with less than a year tomaturity use this day count basis,

including Treasury bills

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 Actual/360 – Example

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What would the interest payment befor a $1 million six-month CD issuedon 01/31/04 and maturing on

07/31/04, and that has a 6% coupon?◦ Actual number of days between 01/31/04

and 07/31/04 = 182 days

Interest = 0.06 × $1,000,000 × (182/360)= $30,333.33

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 Actual/365

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This calculates the actual number of days between two dates and assumesthe year has 365 days

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 Actual/365 – Example

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What would the interest payment befor the same $1 million six-month CDissued on 01/31/04 and maturing on

07/31/04, and that has a 6% coupon?◦ Actual number of days between 01/31/04

and 07/31/04 = 182 days

Interest = 0.06 × $1,000,000 × (182/365)= $29,917.81

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 Actual/Actual

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This day count basis calculates the actualnumber of days between two dates andassumes the year has either 365 or 366days depending on whether the year is aleap year 

◦ More precisely, if the range of the datecalculation includes February 29 (the leap day),the divisor is 366, otherwise it is 365

This day count basis is used for Treasurybonds

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30/360

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This day count convention assumes that eachmonth has 30 days and the total number of days inthe year is 360◦ There are adjustments for February and months with 31

days

◦  Assume Date 1 is of the form M1/D1/Y1 and Date 2 is of the form M2/D2/Y2, with Date 2 being later than Date 1 If D1 = 31, change D1 to 30

If D2 = 31 and D1 = 30, change D2 to 30

Days between dates = (Y2 – Y1)×360 +(M2 – M1)×30 + (D2 – 

D1) This day count basis is used for U.S. corporate and

municipal bonds

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30/360 – Example

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What would the interest payment befor the same $1 million six-month CDissued on 01/31/04 and maturing on

07/31/04, and that has a 6% coupon?◦ Number of days between 01/31/04 and

07/31/04 = 0 + (6 × 30) + 0 = 180 days

Interest = 0.06 × $1,000,000 × (180/360)= $30,000.00

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30/360 European

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The 30/360 day count basis is differentoutside the United States, where thecalculation was further simplified

◦  Assume Date 1 is of the form M1/D1/Y1 andDate 2 is of the form M2/D2/Y2, with Date 2being later than Date 1 If D1 = 31, change D1 to 30

If D2 = 31, change D2 to 30

Days between dates = (Y2 – Y1)×360 +(M2 – M1)×30 +(D2 – D1)

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30/360 European – Example

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What would the interest payment befor the same $1 million six-month CDissued on 01/31/04 and maturing on

07/31/04, and that has a 6% coupon?◦ Number of days between 01/31/04 and

07/31/04 = 0 + (6 × 30) + 0 = 180 days

Interest = 0.06 × $1,000,000 × (180/360)= $30,000.00

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