Lesson10 Pressure Vessel 1

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    (10) Pressure Vessels

    Faculty of Engineering

    Kingston University

    Dr Homa Hadavinia

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    Pressure Vessels Failure

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    Thin-Walled Pressure Vessels

    Several assumptions are made.

    1. Plane sections remain plane.

    2. r/t 10 with t being uniform and constant.

    3. Material is linear-elastic, isotropic and homogeneous.4. Stress distributions throughout the wall thickness will not

    vary.

    5. Element of interest is remote from the end of the cylinder

    and other geometric discontinuities.

    6. Working fluid has negligible weight.

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    Thin-Walled Pressure Vessels

    Consider a cylindrical pressure vessel:

    The hydrostatic pressure causes stresses in three directions:

    1. Longitudinal stress (axial) L

    2. Radial stress, r

    3. Hoop stress, h

    P

    t

    Internal pressure P

    L

    D L

    r

    h

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    Thin-Walled Pressure Vessels

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    Thin-Walled Pressure Vessels

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    Thin-Walled Spherical Pressure Vessels

    t

    PD

    DtD

    P

    h

    h

    4

    4

    2

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    Failure of Metallic Materials

    2

    13

    2

    32

    2

    21 )()()(2

    1

    e

    http://upload.wikimedia.org/wikipedia/commons/c/cc/Yield_surfaces.svg
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    Surface Crack

    The stress-intensity factor

    at the location of maximum

    stress intensity is given by

    kI MQaK 12.1

    Mkis approximately 1.0 as long as the crack depth, a, is less than one-half the

    wall thickness, t. As a approaches t, Mkapproaches 1.6, and a useful

    approximation is:

    5.02.10.1

    t

    aMk

    Flaw shape parameter, Q

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    Example

    A high strength cylindrical steel pressure vessel must be built towithstand 5000 psi of internal pressure,p. The nominal diameter

    of the vessel is d=30 in and the yield stress is ys =180 ksi.

    (a) Fora factor of safety of 2 based on yielding find the

    thickness of the vessel.

    in83.0)90000(2)30)(5000(

    2

    ksi902

    180

    2

    design

    design

    pdprt

    ys

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    Example (cont.)

    k

    I

    kIMa

    QKM

    Q

    aK

    12.112.1

    we want to prevent failure caused by a crack propagation which exist in thevessel due to improper fabrication or crack growth by fatigue or stress

    corrosion. Assume a possible surface flaw of depth a=0.5 in with an a/2c ratio

    of 0.25. Find the vessel thickness fora safety factor of 2.0 against fracture.

    Assume KIc=220 ksiin

    Therefore, the design stress for a safety factor of 2.0 against fracture

    is found from above by replacing KI with KI design=KIc/2

    design2

    pdtand

    12.1

    2

    k

    Ic

    designMa

    QK

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    Example (cont.)

    in

    ksidesign

    8.0)95(2)30)(5(

    2pdt

    950.1)5.0(12.1

    4.12

    220

    design

    initial iteration: Assume Mk=1.0 and /ys=0.55, from the figure Q=1.4.

    For t=0.8 in, a/t=0.5/0.8=0.63. Therefore Mk=1.15. Also design/ys=95/180=0.53

    therefore from figure Q=1.4

    First iteration: Mk=1.15 and Q=1.4.

    in

    ksidesign

    91.0)2.82(2

    )30)(5(

    2

    pdt

    2.8215.1)5.0(12.1

    4.12

    220

    design

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    Example (cont.)

    in

    ksidesign

    85.0)90(2

    )30)(5(

    2

    pdt

    9006.1)5.0(12.1

    42.12

    220

    design

    For t=0.91 in, a/t=0.5/0.91=0.55. Therefore Mk=1.06. Also design/ys=82.2/180=0.46therefore from figure Q=1.42

    Second iteration: Mk=1.06 and Q=1.42

    For t=0.85 in, a/t=0.5/0.85=0.59. Therefore Mk=1.11. Also design/ys=90/180=0.5

    therefore from figure Q=1.42. Third iteration:

    in

    ksidesign

    87.0

    )8.85(2

    )30)(5(

    2

    pdt

    8.8511.1)5.0(12.1

    42.12

    220

    design

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    Example (cont.)

    in

    ksidesign

    86.0)87(2

    )30)(5(

    2

    pdt

    871.1)5.0(12.1

    42.12

    220

    design

    For t=0.87 in, a/t=0.5/0.87=0.57. Therefore Mk=1.1. Also design/ys=86/180=0.48therefore from figure Q=1.42

    4th iteration: Mk=1.1 and Q=1.42

    This value agrees with the initial value of thickness of 0.87 in and thus further

    trials are not required.

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    Leak-Before-Break (LBB)

    The leak-before-break criterion was proposed by Irwin et al. as a means ofestimating the necessary fracture toughness of pressure-vessel steels so that

    a surface crack could grow through the wall and the vessel leaks before

    fracturing. It is often advantageous to design pressure containing plant, such

    as pipework, tubes, vessels, and boilers, on the basis of leak-before-break.

    This means that partial failures which occur by sub-critical mechanisms

    (fatigue crack growth, stress corrosion cracking ) are detected by loss of

    pressure in the plant before final catastrophic fracture occurs. This requires a

    crack to grow in a stable manner through the wall of the component and

    cause a detectable leak and consequent loss of pressure. This indication of a

    partial failure allows the plant to be shut down in a controlled manner and

    repairs/replacement carried out.

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    Leak-Before-Break (LBB)

    The LBB concept has received increased consideration, on the industry side,as an alternative criterion for elimination or reducing design provisions that

    have to cope with dynamic effects such as pipe whipping, rapid fluid transient

    phenomena that result from postulated high energy pipe ruptures.

    The strategy in performing the analysis is as follows. A surface (part-through)

    crack is assumed to initiate and grow by a sub-critical mechanism.

    Generally, initiation will be from the inner surface of the pressurised

    container, as stresses are usually higher at this point and there may well be

    a corrosive environment present. However, industrial situations where

    cracking can occur from the external surface are relatively common. A typical

    example might involve intergranular attack of pipework at elevatedtemperatures.

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    Leak-Before-Break (LBB)

    An initial surface crack can grow through the pipe wall by several potential

    mechanisms such as fatigue, tearing or any other process due to service loadingand environment called degradation mechanism. Crack growth through the wall

    thickness comes to an end at the time when the remaining ligament fails. If the defect

    length at breakthrough or even during its growth exceeds the limiting (or critical) crack

    size, the conditions of crack instability are met and the catastrophic failure of the

    component due to rapid crack extension will occur should a high loading transient

    arise. If the defect length at breakthrough is less than the critical crack size, the now

    fully penetrating crack can keep growing in size, possibly leading to a detectable leak,

    until the limiting size is reached.

    The main steps of the conventional LBB procedure include:

    1. Material characterisation and stress calculation2. Determination of critical through-wall crack lengths (incl. crack location

    assessment)

    3. Calculation of crack opening area

    4. Evaluation of leak rate

    5. Assessment of results

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    Leak-Before-Break (LBB)The leak-before-break criterion

    assumes that a crack of twice thewall thickness in length should be

    stable at a stress equal to the nominal

    design stress.

    The stress intensity factor for a

    through crack in a large plate wherethe applied stress approaches yield

    stress is:

    Section A-A

    B

    2a

    2a

    A

    A

    2

    22

    )/(

    2

    11 ys

    I

    aK

    Where:

    2a = effective crack length

    = tensile stress normal to the crack

    ys =yield stress

    Note that for low design stress, , this expression reduce to: aKI

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    Leak-Before-Break (LBB)

    At fracture KI= Kc (assuming plane-stress behaviour)

    2

    22

    )/(2

    11 ys

    c

    aK

    Standard material properties were usually obtained in terms of KIc, the following

    relationship between Kc and KIc was suggested by Irwin to establish the LBBcriterion in terms of KIC

    2

    2

    2

    224.11

    ys

    IcIcc

    B

    KKK

    Substituting for Kc in the above equation will result

    42

    42

    2

    2

    4.11

    )/(

    2

    11 ys

    ICIC

    ys

    B

    KK

    a

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    Leak-Before-Break (LBB)

    42

    4

    2

    2

    2

    4.11)/(

    2

    11 ys

    ICIC

    ys

    B

    KK

    B

    2a=2B

    aB

    In the LBB criterion, the depth ofthe surface crack, a, is set equal

    to the plate thickness, B, we

    obtain:

    42

    42

    2

    2

    4.11

    )/(2

    11 ys

    ICIC

    ys

    BK

    BK

    or

    Where

    = nominal design stressys =yield stress

    B = vessel wall thickness

    KIc= plane-strain fracture toughness

    required to satisfy the leak-before-

    break criterion for a material with

    particularys, a vessel with wall

    thickness B and design stress .

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    Leak-Before-Break (LBB)

    42

    42

    2

    2

    4.11

    )/(2

    11 ys

    ICIC

    ysys

    ys

    B

    K

    B

    K

    43

    622 4.12

    ys

    ICICys

    B

    K

    B

    K

    For the critical situation of = ys, the criterion becomes:

    22

    43

    6

    24.1

    ysIC

    ys

    IC

    B

    K

    B

    K

    The engineer must first select the nominal yield stress of the steel, thendetermine the wall thicknesses. These two factors might be established

    based on a general strength criterion to withstand a given internal

    pressure. Finally the required minimum fracture toughness necessary to

    meet the LBB criterion can be found from LBB criterion.