Lesson 8.1 & 8.2

95

description

Lesson 8.1 & 8.2. Solving Problems with Ratio and Proportion. Today, we will learn to… …find and simplify ratios ...use proportions to solve problems. Ratio. A ratio is a comparison of two numbers written in simplest form. a a : b a to b b. Simplify the ratio. - PowerPoint PPT Presentation

Transcript of Lesson 8.1 & 8.2

Page 1: Lesson 8.1 & 8.2
Page 2: Lesson 8.1 & 8.2

Lesson 8.1 & 8.2Solving Problems with Ratio and Proportion

Today, we will learn to……find and simplify ratios...use proportions to solve problems

Page 3: Lesson 8.1 & 8.2

RatioA ratio is a comparison of

two numbers written in simplest form.

a a : b a to b b

Page 4: Lesson 8.1 & 8.2

Simplify the ratio.K H D M D C M

1. 2 m : 300 cm200 cm : 300 cm 2 : 3

2. 2 km : 600 m 2000 m : 600 m 10 : 3

3. 10 mm : 5.5 cm 10 mm : 55 mm 2 : 11

Page 5: Lesson 8.1 & 8.2

4. In the diagram, DE : EF is1 : 2 and DF = 45. Find DE and EF.

D E F

1x + 2x = 453x = 45x = 15

1 2

DE =EF =

x x

1530

Page 6: Lesson 8.1 & 8.2

5. In ΔABC, the measures of the angles are in the

extended ratio of 3:4:5. Find the measures of the angles.

12x = 180x = 15

3x + 4x + 5x = 180

°, °, °

What do we know about the angles of a triangle?

45 60 75

Page 7: Lesson 8.1 & 8.2

6. The perimeter of a rectangle is 70 cm. The ratio of the length to the width is 3 : 2. Find the length and the width of the rectangle.

3x

2x 2x

3x 3x+2x+3x+2x = 70

Length is Width is

10x = 70x = 7

2114

Page 8: Lesson 8.1 & 8.2

7. A triangle has an area of 48 m 2. The ratio of the base to the

height is 2 : 3. Find the base and height.

A = ½ bh48 = ½ (2x)(3x)48 = 3x2

16 = x2

4 = xbase is height is

8 m12 m

2x

3x

Page 9: Lesson 8.1 & 8.2

Solve the proportion for x.

8. 2 8 7 x-2

2(x-2) = 562x - 4 = 56

2x = 60x = 30

Page 10: Lesson 8.1 & 8.2

9. On a map, 2 inch = 180 miles. Two cities are about 2 ¾ inches apart.

Estimate the actual distance between them.

2 in 180 mi

2x = 180(2¾) x = 247.5 miles

2 ¾ inx mi

Page 11: Lesson 8.1 & 8.2

10. In a photograph taken from an airplane, a section of a city street is 3 1/2 inches long and

1/8 of an inch wide. If the actual street is 30 feet wide, how long is it?

1/8 30x=

x = 840 feet

31/2

x = (3 )(30)1/8 1/2

Page 12: Lesson 8.1 & 8.2

11. AB : AC is 3 : 2. Find x.

3x+3x+1 2=

3(x+1) = 2(x+3)3x+3 = 2x+6

x + 3 = 6x = 3

Page 13: Lesson 8.1 & 8.2

12. Given MN MP find PQ. NO PQ=

x

14-x

46

14-xx=

x = 8.4

4x = 6(14-x)

?

?

4x = 84 - 6x4

M

6

N

O Q

P14

Page 14: Lesson 8.1 & 8.2

5

A

2B

C E

D

7+x

x

7

57

77+x=

x = 2.8

Given AB AD find DE. AC AE=13.

5(7+x) = 49

?

? 35+5x = 495x = 14

Page 15: Lesson 8.1 & 8.2

14. Standard paper sizes are all over the world. The sizes all have the same width-to-length ratios. Two sizes of paper shown are A4 and A3. Find x.

210 mm

x

x

420 mm

210 x420x =

x2 = (210)(420)

x ≈ 297 mm

Page 16: Lesson 8.1 & 8.2

15. The batting average of a baseball player is the ratio of

the number of hits to the number of official at-bats.

x.308643 1= x = (643)(.308)

x = 198 hits

In 1998, Sammy Sosa of the Chicago Cubs had 643 official at-bats and a batting average of .308. How many hits did Sammy Sosa get?

Page 17: Lesson 8.1 & 8.2

16. A wheelchair ramp should have a slope of 1/12. If a ramp rises 2

feet, what is its run?

1 2 ftx12 =

x = (12)(2 ft)x = 24 feet

What is its length? length2 = 22 + 242 length2 = 4 + 576 length2 = 580 length = 24.08 feet

2 ft ?

Page 18: Lesson 8.1 & 8.2

Geometric MeanThe geometric mean of two

positive numbers

(a and b) is …. a x

x b

Page 19: Lesson 8.1 & 8.2

Find the geometric mean of the given numbers.

35 and 175

x ≈ 78.3

xx35

175=

x2 = 35(175)

Page 20: Lesson 8.1 & 8.2
Page 21: Lesson 8.1 & 8.2

Lesson 8.3Similar Polygons

Today, we will learn to……identify similar polygons...use similar polygons

Page 22: Lesson 8.1 & 8.2

Two polygons are similar ifall corresponding angles are congruent and corresponding

sides are proportional.

AB BC AC

ΔABC ~ Δ XYZ if

A B C X Y Z

XY YZ XZand

Page 23: Lesson 8.1 & 8.2

B

C

DA

FG

HE

ABCD ~ EFGH

CDGH

ADEH

ABEF

BCFG

A E, B F, C G, D H

Statement of Proportionality

Page 24: Lesson 8.1 & 8.2

Scale Factor

The scale factor is the ratio of the lengths of two corresponding sides.

Page 25: Lesson 8.1 & 8.2

6 8 10

1. Are the triangles similar? If they are, find the scale factor and write a

statement of similarity.

9 12 15

Yes, the scale factor is 2

3XAR ~ __ __ __

M N T

Page 26: Lesson 8.1 & 8.2

4.5 6 9

2. Are the triangles similar? If they are, find the scale factor and write a

statement of similarity.

6 8 12

Yes, the scale factor is 3

4LMN ~ __ __ __T P O

Page 27: Lesson 8.1 & 8.2

12 15 x

A

B

C

D

E

F10

1215

12 y

x

4. Δ ABC ~ Δ DEF

15 10

3 2=

y 10 12 x 12 = 15

10

x = 1812 y = 15

10 y = 8

Scale Factor?

Page 28: Lesson 8.1 & 8.2

The triangles are similar. Find x and y.5.

AC

8 x

12

Map the triangles to find corresponding sides.

B

E

DF

9

y

18B

A C

x

12

8

B

A C

x

12

8

9 y 18 x 12 8

9 x =

x = 4

18 8

y 12 = 18

8

y = 27

Page 29: Lesson 8.1 & 8.2

5 = 3

6. RSTU ~ LMNO. Find the following.

125mT =mS =55

x 2.4

x

x = 4

Page 30: Lesson 8.1 & 8.2

7. You have a 3.5 inch by 5 inch photo that you want to enlarge. You want the enlargement to be 16 inches wide. How long will it be?

3.5 16x5 =

3.5x = (16)(5)x = 22.9 ≈ 23 inches

Page 31: Lesson 8.1 & 8.2

A triangular work of art and the frame around it are similar equilateral triangles.

12 in.

16 in.9. Find the ratio of the perimeters. (artwork : frame)

34

34

3648

8. Find the ratio of the artwork to the

frame.

Page 32: Lesson 8.1 & 8.2

The rectangles are similar.

11. Find the ratio of the perimeters.

45

45

2227.5

10. Find the ratio of corresponding sides.

47

5

8.75

220275

Page 33: Lesson 8.1 & 8.2

Theorem 8.1If 2 polygons are similar,

then the ratio of the perimeters is __________ the ratio of corresponding

side lengths.

equal to

Page 34: Lesson 8.1 & 8.2

12. The patio around a pool is similar to the pool. The perimeter of the pool is 96 feet. The ratio of the

patio to the pool is 3 to 2. Find the perimeter

of the patio.

3 x962 = 2x = (3)(96)

x = 144 feet

patiopool

Page 35: Lesson 8.1 & 8.2

Turn to page 145 in your workbook!

Page 36: Lesson 8.1 & 8.2
Page 37: Lesson 8.1 & 8.2

Lesson 8.4

Proving Triangles are Similar Triangles

Today, we will learn to……identify similar triangles...use similar triangles

Page 38: Lesson 8.1 & 8.2

Postulate 25Angle-Angle (AA) Similarity

Two triangles are similar if 2 pairs of corresponding

angles are congruent.

Page 39: Lesson 8.1 & 8.2

Determine whether the triangles are similar. If they are, write a similarity statement.

1. R M

NL

27˚

LT S

35˚

80˚

65˚

80˚

ΔRTS ~ Δ____M

35˚65˚

LN

Page 40: Lesson 8.1 & 8.2

Determine whether the triangles are similar. If they are, write a similarity statement.

2. G

H

JK

L 27˚

27˚

ΔGLH ~ Δ____G KJ

Page 41: Lesson 8.1 & 8.2

4. If the triangles are similar, write a similarity statement.

31˚

47˚

not similar

Page 42: Lesson 8.1 & 8.2

5. If the triangles are similar, write a similarity statement.

43˚

not similar

Page 43: Lesson 8.1 & 8.2

6. The triangles are similar, find x.

3 5 7

x2 =3x = 10

x ≈ 3.33

yx2

53y2

3y = 14y ≈ 4.67

73

Page 44: Lesson 8.1 & 8.2

8. The triangles are similar. Find x. A B

C

D E

15

2518

9

x

15 925 x=

x = 15

Page 45: Lesson 8.1 & 8.2

Are the triangles similar? If they are, write a similarity statement.

Not ~ XZW ~ XTY

T

YX

X

Z

W

Page 46: Lesson 8.1 & 8.2

Are the triangles similar? If they are, write a similarity statement.

Not ~ABD ~ BCE

40

75

Page 47: Lesson 8.1 & 8.2

Lesson 8.5Proving Triangles are

Similar Triangles

Today, we will learn to……use similarity theorems to prove

that two triangles are similar

Page 48: Lesson 8.1 & 8.2

Theorem 8.2Side-Side-Side (SSS)

Similarity

If all three corresponding sides are proportional, then

the triangles are similar.

Page 49: Lesson 8.1 & 8.2

Determine whether the triangles are similar. If they are, write a

similarity statement.1. D

E

F8 10

12

A

B

C 1512

18

ΔACB ~ Δ____ by _____ DFE

12 15 188 10 12

scale factor?3:2

SSS

Page 50: Lesson 8.1 & 8.2

Theorem 8.3Side-Angle-Side (SAS)

Similarity If two sides are proportional

and the angles between them are congruent, then

the triangles are similar.

Page 51: Lesson 8.1 & 8.2

Determine if the triangles are similar. If they are, write a

similarity statement.2. A

B

C

D

E

F6

8

8

12

Not similar

8 12 6 8

Page 52: Lesson 8.1 & 8.2

Determine whether the triangles are similar. If they are, write a

similarity statement.3. A

B

C D

E5

5

3

3

ΔABE ~ Δ____ by _____ACD SAS

3 5 6 10Scale Factor? 1:2

Page 53: Lesson 8.1 & 8.2

Separate the triangles if it helps.3. A

C D

106

ΔACD ~ ΔABE by

B E

A

53

SAS

3 5 6 10

Page 54: Lesson 8.1 & 8.2

Find x. GLH ~ GKJ4.

x = 7.5

G

H

JK

L6 x

108 10 + x14

8 10 14 10 + x14 10 + x

8(10 + x) = 140

Page 55: Lesson 8.1 & 8.2

x = 7.5

G

H

JK

L6 x

108

8 10 6 x

8x = 60

What can we

conclude?

Find x. GLH ~ GKJ5.

Page 56: Lesson 8.1 & 8.2

Theorem 8.4Triangle Proportionality Theorem

If a line parallel to one side of a triangle intersects the other

two sides, then it divides the two sides proportionally.

Page 57: Lesson 8.1 & 8.2

Find x. The triangles are similar.

6. 7.

x12

14

39

x = 18 x = 4

12 x 5 10

x10

5

2

26 392 x

Page 58: Lesson 8.1 & 8.2

Estimate the height of the tree.8.

4 ft.

6 ft.

16 ft.

x ft.

x = 24 feet

4 6

=16 x

Page 59: Lesson 8.1 & 8.2

3 5.5

=

Estimate the height of the tree.9.

3 ft.

5.5 ft.

12 ft.

x ft.

x = 27.5 feet

15 x

Page 61: Lesson 8.1 & 8.2

Lesson 8.6Proportions and Similar Triangles

Today, we will learn to……use proportionality theorems to

calculate segment lengths

Page 62: Lesson 8.1 & 8.2

Find the value of x.

1. 2.

x4

6

12

x = 4.8 x = 2.8 4 x

5 7

x7

5

2

10 12

2 x

Page 63: Lesson 8.1 & 8.2

Find the value of x.

3. 4. x5

7

15

x = 6.25 x ≈ 2.67

5 x

6 8

x8

6

2

2 x 12 15

Page 64: Lesson 8.1 & 8.2

Find the value of x.

5. 6.10

14 x

x = 21 x = 11

36 x

x 33

x20

10

24 14 10 30

3633

Page 65: Lesson 8.1 & 8.2

Theorem 8.5Triangle Proportionality

Converse

If a line divides two sides of a triangle proportionally, then it is

parallel to the third side.

Page 66: Lesson 8.1 & 8.2

Use similar triangles to find x.

7. 8.

12

7 8x

x = 6 x = 20 6 10

8 x

x10

86

?7 ?8

16 1212 x

Page 67: Lesson 8.1 & 8.2

Mid-Segment TheoremThe segment connecting the

midpoints of two sides of a triangle is parallel to the third

side and is _____ as long.half

Page 68: Lesson 8.1 & 8.2

Theorem 8.6

If three or more parallel lines intersect two transversals,

then they divide the transversals proportionally.

Page 69: Lesson 8.1 & 8.2

9. Find x and y.

y24

x 10.5

78

x= 10.5

24 =

y

x = 12

y = 21

8 7

78

Page 70: Lesson 8.1 & 8.2

10. Find x, y, and z.

x15

13 y

z10

30.4

15= x

30.438

38x = 456

x = 12

Page 71: Lesson 8.1 & 8.2

10. Find x, y, and z.

1215

13 y

z10

30.4

15= 12

y1315y = 156

y = 10.4

15= 12

z1015z = 120

z = 8x = 12

Page 72: Lesson 8.1 & 8.2

Theorem 8.7An angle bisector of a triangle divides the opposite side into segments whose lengths are proportional to the other two

sides.

Page 73: Lesson 8.1 & 8.2

11. Find x. 12. Find x.

21 =

24 x = 7

24

x 8

21

x 8

3

5

2x

3 =

2 x 5 x = 7.5

Page 74: Lesson 8.1 & 8.2

24

12

8

13. Find x.

?

8= 12

x 24-x

x = 9.624 - x

Page 75: Lesson 8.1 & 8.2

14. Find x and y.

18

16

8.5

What is another way to write y?

8.5 - x

18= 16

x 8.5-xx = 4.5

8.5 - x = 4

y = 4

Page 77: Lesson 8.1 & 8.2
Page 78: Lesson 8.1 & 8.2

Lesson 8.7Dilations

Today, we will learn to……identify dilation...use properties of dilations to create a perspective

drawing

Page 79: Lesson 8.1 & 8.2

Dilation

A dilation is a transformation that

results in a reduction or enlargement of a figure.

Page 80: Lesson 8.1 & 8.2

=

1. A circle in a photocopier enlargement has a 6 inch diameter. If the enlargement percentage is 125%, what is the diameter of the preimage circle?

4.8 in.100 x125 6 in.

Page 81: Lesson 8.1 & 8.2

C3

6

Scale Factor = CPCP

'

P

Q

R

R´Reduction

Page 82: Lesson 8.1 & 8.2

C

Scale Factor =

38

P

Q

R

R´Reduction

38

new image preimage

Page 83: Lesson 8.1 & 8.2

C2

5P

QR

Scale Factor =

52

CPCP

'Enlargement

Page 84: Lesson 8.1 & 8.2

C

P

QR

Q´R´

515

Scale Factor =

Enlargement new image preimage

Page 85: Lesson 8.1 & 8.2

C

P

Q

R

410

Find x.

x 6

x = 2.4 410 = x

6

Page 86: Lesson 8.1 & 8.2

2510 =

P

CQ

R

10

25Find x.

10

4

5

y

x

x = 25x

Page 87: Lesson 8.1 & 8.2

P

CQ

R

10

25Find y.

10

4

5

y

x

y = 102510 =

y4

Page 88: Lesson 8.1 & 8.2

Rectangle ABCD has vertices A (3,1) , B (3, 3) , C (2, 3), and D (2, 1). Find the coordinates of the dilation with center (0,0) and scale factor of 2.

Graph on next slide…

Page 89: Lesson 8.1 & 8.2

A (3,1) , B (3, 3) , C (2, 3), D (2, 1)

A’(6,2) , B’(6, 6) , C’(4, 6), D’(4, 2)

Scale Factor is 2

x

2x

A’

B’C’

D’

Do you notice a pattern?

Page 90: Lesson 8.1 & 8.2

Rectangle ABCD has vertices A (-3,3) , B (3, 6) , C (6, -3), and D (-3, -6). Find the coordinates of the dilation with center (0,0) and scale factor of 1/3.

(-1,1) B’D’ C’

A’ (2, -1)

(1, 2)(-1, -2)

Page 91: Lesson 8.1 & 8.2

A’ (-1,1) B’ (1,2) C’ (2,-1) D’(-1,-2)

Scale Factor is 1/3

A(-3,3) B(3, 6) C(6, -3) D(-3, -6)

A’B’

C’D’

A

B

C

D

Page 92: Lesson 8.1 & 8.2

Find x.

5126

=12x = 30

x = 2.5

x

Page 93: Lesson 8.1 & 8.2

A’B’C’

(0, 6)(6, 6)

(4.5, 3)

A’ B’

C’

ABC

(0, 4)(4, 4)(3, 2)

Page 94: Lesson 8.1 & 8.2

X’Y’Z’

(-0.75,-0.5)(2, 1)(1, -1)

XYZ

(-1.5, -1)(4, 2)(2, -2)X’

Y’

Z’