Lesson 10-1 Pages 492-497
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Transcript of Lesson 10-1 Pages 492-497
Lesson 10-1 Pages 492-497
Line and Angle Relationships
Lesson Check Ch-9
What you will learn!1. How to identify the relationships
of angles formed by two parallel lines and a transversal.
2. How to identify the relationships of vertical, adjacent, complementary, and supplementary angles.
Parallel linesParallel lines Corresponding anglesCorresponding angles
TransversalTransversal Vertical anglesVertical angles
Interior anglesInterior angles Adjacent anglesAdjacent angles
Exterior anglesExterior angles Complementary anglesComplementary angles
Alternate interior anglesAlternate interior angles Supplementary anglesSupplementary angles
Alternate exterior anglesAlternate exterior angles Perpendicular linesPerpendicular lines
What you really need to know!
When two parallel lines are intersected by a third line called a transversal, eight angles are formed!
What you really need to know!
Interior angles lie inside the parallel lines!
3, 4, 5, 6
What you really need to know!
Exterior angles lie outside the parallel lines!
1, 2, 7, 8
What you really need to know!Alternate interior angles are on opposite sides of the transversal and inside the parallel lines!
3 and 5,
4 and 6
What you really need to know!Alternate exterior angles are on opposite sides of the transversal and outside the parallel lines!
1 and 7,
2 and 8
What you really need to know!Corresponding angles are in the same positions on the parallel lines in relation to the transversal!
1 and 5,
4 and 8,
2 and 6,
3 and 7
What you really need to know!
Example 1:
In the drawing, m ║ n and t is a transversal. If m 7 = 123°, find m 2 and m 8.
Example 1:
m 2 = 57°
and
m 8 = 57°
Example 2:
If m D = 53° and D and E are complementary, what is m E?
AA BB CC DD
5353°° 3737°° 127127°° 77°°
AA BB CC DD
5353°° 3737°° 127127°° 77°°
Example 3:
Angles PQR and STU are supplementary. If m PQR = x – 15 and m STU = x – 65, find the measure of each angle.
(x – 15) + (x – 65) = 180
2x – 80 = 180
2x = 260
x = 130
m PQR = 130 – 15 = 115°
m STU = 130 – 65 = 65°
Example 4:
A road crosses railroad tracks at an angle as shown. If m1 = 131°, find the m6, and m5.
m6 = 49°
and
m5 = 131°
Page 495
Guided Practice
#’s 3-9
Pages 492-495 with someone at home and
study examples!
Read:
Homework: Pages 496-497
#’s 10-31 all
#’s 35-36, 43-45
Lesson Check 10-1
Page
747
Lesson 10-1
Lesson Check 10-1