Lesson 1 Menu Warm-up Problems 1.What is the value of x 2 + 3yz if x = 3, y = 6, and z = 4? 2.Solve...

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Warm-up Problems 1.What is the value of x 2 + 3yz if x = 3, y = 6, and z = 4? 2.Solve 2(x – 7) = 5x + 4. 3.Is (–2, 5) a solution of 3x + 4y = 14? 4.Factor 9x 2 – 25y 2 . 5.Graph y = 3x + 2. 6.Find all of the solutions of 2x 2 + 5x – 3 = 0. a. –3 only b. ½ and 3 c. –3 and ½ d. no solutions

Transcript of Lesson 1 Menu Warm-up Problems 1.What is the value of x 2 + 3yz if x = 3, y = 6, and z = 4? 2.Solve...

  • Lesson 1 Menu

    Warm-up Problems

    What is the value of x2 + 3yz if x = 3, y = 6, and z = 4?Solve 2(x 7) = 5x + 4.Is (2, 5) a solution of 3x + 4y = 14?Factor 9x2 25y2.Graph y = 3x + 2.Find all of the solutions of 2x2 + 5x 3 = 0.3 only and 33 and no solutions

  • Lesson 1 MI/Vocabundefined termpointlinecollinearIdentify and model points, lines, and planes.Identify collinear and coplanar points and intersecting lines and planes in space.planecoplanarspacelocus

  • Lesson 1 KC1

  • Lesson 1 Ex1Name Lines and PlanesA. Use the figure to name a line containing point K.Answer: The line can be named as line a.

  • Lesson 1 Ex1Name Lines and PlanesB. Use the figure to name a plane containing point L.You can also use the letters of any three noncollinear points to name the plane.plane JKMplane KLMplane JLMAnswer: The plane can be named as plane B.

  • Lesson 1 Ex1Name Lines and PlanesThe letters of each of these names can be reordered to create other acceptable names for this plane. For example, JKM can also be written as JMK, MKJ, KJM, KMJ, and MJK. There are 15 different three-letter names for this plane.

  • Lesson 1 Ex2A. Name the geometric shape modeled by a 10 12 patio.Answer: The patio models a plane.Model Points, Lines, and Planes

  • Lesson 1 Ex2B. Name the geometric shape modeled by a water glass on a table.Answer: The glass on the table models a point on a plane.Model Points, Lines, and Planes

  • Lesson 1 Ex3Draw Geometric FiguresDraw a surface to represent plane R and label it.

  • Lesson 1 Ex3Draw Geometric FiguresDraw a line anywhere on the plane.

  • Lesson 1 Ex3Draw Geometric FiguresDraw dots on the line for point A and B. Label the points.

  • Lesson 1 Ex3Draw Geometric Figures

  • Lesson 1 Ex3Draw Geometric FiguresDraw dots on this line for point D and E. Label the points.

  • Lesson 1 Ex3Draw Geometric FiguresLabel the intersection point of the two lines as P.

  • Lesson 1 Ex3Draw Geometric FiguresAnswer:

  • Lesson 1 Ex3Draw Geometric FiguresThere are an infinite number of points that are collinear with Q and R. In the graph, one such point is T(1, 0).Answer:

  • Lesson 1 Ex4A. How many planes appear in this figure?Answer: There are two planes: plane S and plane ABC.Interpret Drawings

  • Lesson 1 Ex4B. Name three points that are collinear.Answer: Points A, B, and D are collinear.Interpret Drawings

  • Lesson 1 Ex4C. Are points A, B, C, and D coplanar? Explain.Answer: Points A, B, C, and D all lie in plane ABC, so they are coplanar.Interpret Drawings

  • Lesson 1 Ex4Answer: The two lines intersect at point A.Interpret Drawings

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CLASE 36 –3 x x 3 3 2 2 x x y y 2,1 y y 5x5x 5x5x 7 7 x x 2 2 y y 5 5 = 7 x 0 0 ( x 0) 4 x x 3 +2 x x 2 –1 P( x ) =

CLASE 36 –3 x x 3 3 2 2 x x y y 2,1 y y 5x5x 5x5x 7 7 x x 2 2 y y 5 5 = 7 x 0 0 ( x 0) 4 x x 3 +2 x x 2 –1 P( x ) =

CLASE 43 –3 x x 3 3 2 2 x x y y 2,1 y y 5x5x 5x5x 7 7 x x 2 2 y y 5 5 = 7 x 0 0 ( x 0) 4 x x 3 +2 x x 2 –1 P( x ) =

CLASE 43 –3 x x 3 3 2 2 x x y y 2,1 y y 5x5x 5x5x 7 7 x x 2 2 y y 5 5 = 7 x 0 0 ( x 0) 4 x x 3 +2 x x 2 –1 P( x ) =

Fungsi Logik Dasar dan Tabel Kebenaranelearning.amikom.ac.id/index.php/download/materi/190000005-ST017-2... · x 1 x 2 x n x 1 x 2 } x n + + + x 1 x 2 x 1 x 2 + x 1 x 2 x n x 1 x

Fungsi Logik Dasar dan Tabel Kebenaranelearning.amikom.ac.id/index.php/download/materi/190000005-ST017-2... · x 1 x 2 x n x 1 x 2 } x n + + + x 1 x 2 x 1 x 2 + x 1 x 2 x n x 1 x

() D D, P(x)) ≡∀x∈ D P(x - University of Wollongongbmaloney/wuct121/LogicWeek6Lecture1.pdf · 2 1 0 2 1 2 2 1 2 working: 2 2 2 2 x x x x x ... Recall the following logical equivalence:

() D D, P(x)) ≡∀x∈ D P(x - University of Wollongongbmaloney/wuct121/LogicWeek6Lecture1.pdf · 2 1 0 2 1 2 2 1 2 working: 2 2 2 2 x x x x x ... Recall the following logical equivalence:

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Funktionen-Katalog · (nach Polynomdivision), da Zählergrad = Nennergrad +1 f(x) = 2( 2) 5 2 2 2 2 2 2 4 2 4 − = + ++ − + x x x x x x x Näherungspolynom y = 2x² + 2x + 2 (nach

Funktionen-Katalog · (nach Polynomdivision), da Zählergrad = Nennergrad +1 f(x) = 2( 2) 5 2 2 2 2 2 2 4 2 4 − = + ++ − + x x x x x x x Näherungspolynom y = 2x² + 2x + 2 (nach

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Written Practice Lesson 20. 1. (+3) + (-14) 2. 4xyz – 3yz - zxy.

Written Practice Lesson 20. 1. (+3) + (-14) 2. 4xyz – 3yz - zxy.

Sen 2 x + cos 2 x = 1 sen 2 x sen 2 x + cos 2 x cos 2 x = 1.

Sen 2 x + cos 2 x = 1 sen 2 x sen 2 x + cos 2 x cos 2 x = 1.

2 x 6= 2 x 2= 2 x 9= 2 x 3 - Homeschool Den

2 x 6= 2 x 2= 2 x 9= 2 x 3 - Homeschool Den

36 / \ 4 x 9 / \ / \ 2 x 2 x 3 x 3 = 2 2 x 3 2 by D. Fisher.

36 / \ 4 x 9 / \ / \ 2 x 2 x 3 x 3 = 2 2 x 3 2 by D. Fisher.

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CLASE 48 –3 x x 3 3 2 2 x x y y 2,1 y y 5x5x 5x5x 7 7 x x 2 2 y y 5 5 = 7 x 0 0 ( x 0) 4 x x 3 +2 x x 2 –1 P( x ) =

CLASE 48 –3 x x 3 3 2 2 x x y y 2,1 y y 5x5x 5x5x 7 7 x x 2 2 y y 5 5 = 7 x 0 0 ( x 0) 4 x x 3 +2 x x 2 –1 P( x ) =

Thinking Out Loud - aceguitarcourse.com · 10/12 141 3 0 0 2 x x x 3 2 0 2 (3) (2) (0) (2)2 x x x 0 0 0 3 x x x 2 2 2 0 144 (2) (2) (2) (0)0 x x x 3 0 0 2 x x ... 11/12 156 2 2 2

Thinking Out Loud - aceguitarcourse.com · 10/12 141 3 0 0 2 x x x 3 2 0 2 (3) (2) (0) (2)2 x x x 0 0 0 3 x x x 2 2 2 0 144 (2) (2) (2) (0)0 x x x 3 0 0 2 x x ... 11/12 156 2 2 2

1. g(x) = -x + 2 2. g(x) = x 2 2 3. g(x)= 2 0.2x 4. g(x) = 2|x| 2 5. g(x) = 2.2(x+ 2) 2 Algebra II 1.

1. g(x) = -x + 2 2. g(x) = x 2 2 3. g(x)= 2 0.2x 4. g(x) = 2|x| 2 5. g(x) = 2.2(x+ 2) 2 Algebra II 1.

1-1 Points, Lines, and Planes A.27B.33 C.72D.81 What is the value of x 2 + 3yz if x = 3, y = 6, and z = 4? A.6B.C.2D.6 Solve 2(x 7) = 5x + 4. 5-Minute.

1-1 Points, Lines, and Planes A.27B.33 C.72D.81 What is the value of x 2 + 3yz if x = 3, y = 6, and z = 4? A.6B.C.2D.6 Solve 2(x 7) = 5x + 4. 5-Minute.

LenkaPřibylová 23.června2009pribylova/rlf.pdf · 2009-06-23 · Rozložte na parciální zlomky: x+3 x2 +x−2 x+3 x2 +x−2 x+3 (x−1)(x+2) = A x−1 + B x+2 x+3 = A(x+2)+B(x−1)

LenkaPřibylová 23.června2009pribylova/rlf.pdf · 2009-06-23 · Rozložte na parciální zlomky: x+3 x2 +x−2 x+3 x2 +x−2 x+3 (x−1)(x+2) = A x−1 + B x+2 x+3 = A(x+2)+B(x−1)

Factoring Trinomials. Multiply. (x+3)(x+2) x x + x 2 + 3 x + 3 2 Multiplying Binomials (FOIL) FOIL = x 2 + 2x + 3x + 6 = x 2 + 5x + 6 Distribute.

Factoring Trinomials. Multiply. (x+3)(x+2) x x + x 2 + 3 x + 3 2 Multiplying Binomials (FOIL) FOIL = x 2 + 2x + 3x + 6 = x 2 + 5x + 6 Distribute.

06 Bab 5 · Tuliskan pernyataan berikut dalam bentuk eksponen a. 2 x 2 x 2 x 2 x 2 Bilangan pokoknya adalah 2 dan faktornya adalah 5. 2 x 2 x 2 x 2 x 2 = 25. b. m x m x m x m Bilangan

06 Bab 5 · Tuliskan pernyataan berikut dalam bentuk eksponen a. 2 x 2 x 2 x 2 x 2 Bilangan pokoknya adalah 2 dan faktornya adalah 5. 2 x 2 x 2 x 2 x 2 = 25. b. m x m x m x m Bilangan

tafel van één X tafel van twee X tafel van drie X 6 9 · 2 2 1 3 4 5 6 7 8 9 10 X X X X X X X X X X 2 2 2 2 2 2 2 2 2 2 = = = = = = = = = = 2 4 6 8 10 12 14 16 18 tafel van twee

tafel van één X tafel van twee X tafel van drie X 6 9 · 2 2 1 3 4 5 6 7 8 9 10 X X X X X X X X X X 2 2 2 2 2 2 2 2 2 2 = = = = = = = = = = 2 4 6 8 10 12 14 16 18 tafel van twee