Lecture for Tuesday September 23, 2003 What’s due? CH2 problem set Assignments: CH4 problems: 1-5,...
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Transcript of Lecture for Tuesday September 23, 2003 What’s due? CH2 problem set Assignments: CH4 problems: 1-5,...
Lecture for Tuesday September 23, 2003What’s due?
CH2 problem setAssignments:
CH4 problems:
1-5, 8, 10, 11, 14, 16, 17, 21, 22
What’s due Thursday 9/25?
CH3 problem set
Today’s lecture:
Review material from 9/18
Human Pedigrees
Begin CH4
Today’s Lab:
Maize segregating ears: Dihybrid cross and chi-square analysis
*Exam I is one week from today!
Reading assignment:
Omit sections 4.8 and 4.9
Review:Trihybrid cross- A genetic cross between two individuals involving three characters (also referred to as a three-factor cross)The Forked-Line Method (branch diagram):
Recall:
*The F1 that result from a monohybrid cross (AA x aa) all have the genotype Aa and the phenotype represented by A*The F2 that result from a cross between 2 individuals from the F1, have a phenotypic ratio of 3:1*Assume independent assortment of the 3 gene pairs
KEY: We are
examining the
resulting phenotypes
!
Review Chi-Square Analysis:Mendel’s monohybrid and dihybrid ratios are predictions based on the following assumptions:
1. Each allele is dominant or recessive
2. Random segregation of alleles
3. Independent assortment
4. Fertilization is random
NOTE:
*The outcomes of 2-4 are “chance events” and are subject to random fluctuation
*As sample size increases, the average deviation from expected results decreasesEstablishing a null hypothesis (H0):
States that there is no difference between the observed and expected data
An Example (for a monohybrid cross):
The observed phenotypic ratio is 3:1
Review Chi-Square Analysis:The null hypothesis is analyzed statistically:
*It may be rejected or
*It may fail to be rejected
Chi-Square (X2) Analysis:
*Examines deviation between observed and expected numbers
*Accounts for sample size(o-e)2
X2 = e
Interpretation:
*determine df (n-1)
*typically use p value of 0.05 or greater (i.e. 0.01, 0.001)
*reject or fail to reject null hypothesis
Review Chi-Square Analysis:p value (probability): consider as a percentage (i.e. 0.05 = 5%)
*A level of error that is acceptable to the researcher in analysis of data
*5% of the time your result (or outcome) is due to chance
*95% of the time your results are not due to chance*If your calculated X2 is GREATER than that shown at p = 0.05, then you reject your null hypothesis
*Therefore, we CAN NOT reject our null hypothesis!
Example from Table 3.1:
Calculated X2 = 0.53
Human PedigreesPedigree- a family tree that shows the phenotype of a particular trait for each family member
= Female
= Male
=Unknown
*Shaded symbol=expressed phenotype*Individuals KNOWN to be heterozygous are half shaded
*Horizontal lines connect parents, vertical lines lead to offspring
*Proband (p)= individual in whom a genetically determined trait of interest is first determined
Chapter 4: Modification of Mendelian RatiosAllele- (short for allelomorph) alternative forms of the same gene
*Wild-type allele- allele that occurs most frequently in a population (arbitrarily designated as “normal”); usually dominant
*Mutant allele- allele that contains modified genetic information and often specifies an altered gene product
Conventional symbols for alleles:
recessive allele- initial letter of the name of the recessive trait, lowercased and italicized
dominant allele- same letter in uppercase
Tall = D Dwarf = d
Example:
BRCA1 or BRCA2- (humans) Breast Cancer susceptibility
SUPERMAN- (Arabidopsis) regulates genes involved in floral development
Genetic nomenclature is extremely diverse!
Incomplete or Partial Dominance
Incomplete dominance- expression of a heterozygous phenotype which is distinct from, and often intermediate to, that of either parent
Cross between parents with contrasting traits: Red flowers or white
flowers
Offspring with an intermediate
phenotype: pink flowers
Incomplete or Partial Dominance con’tCRCR x CWCW
CRCW
CRCW x CRCW
¼ CRCR ½ CRCW ¼ CRCW
Codominance:Codominance- Condition in which the phenotypic effects of a gene’s alleles are fully and simultaneously expressed in the heterozygote
Example:
MN Blood group- red blood cells contain a transmembrane glycoprotein (glycophorin); two different forms of this protein exist, M and N
Genotype LMLM
LMLN LNLN
Phenotype M MN
NLMLM X LMLN
¼ LMLM ½ LMLN ¼ LMLN
We can predict genotypic and
phenotypic ratios
Multiple Alleles- three or more alleles of the same gene
Examples:
*Table 4.1: over 100 alleles at a given locus in Drosophila
*ABO Blood group in humans
Multiple Alleles:
*Characterized by the presence of glycoprotein antigens on the surface of red blood cells
*Distinct from the M and N antigens
*Also exhibits codomiance
Genotype IAIA IAIO IBIB IBIO IAIB
IOIO
Antigen A A B B A,B
Neither
Phenotype A A
B B AB
O
Lethal Alleles:Lethal Allele- recessive allele in which a homozygous genotype results in death
Example: Coat color in mice
*A = agouti = wild-type allele
*AY = yellow = mutant allele
Dominant Lethal: Huntington’s disease (H); heterozygous individuals (Hh) have late onset
Combining modified modes of inheritance:
Gene interaction:Individual characteristics (discrete phenotypes) are often under the control of more than one gene
Epistasis- from the greek “stoppage”, interaction between genes such that one gene interferes with or prevents the expresion of another gene
Example:
In Drosophila, the recessive gene eyeless (when homozygous) prevents the expression of eye color genes present in genomeNovel phenotypes due to gene interaction
Example:
disc-shaped fruit (AABB) X long fruit (aabb)
F1 are all AaBb and disc-shaped
F2 Ratio 9/16 3/16 3/16 1/16
GenotypeA-B- A-bb aaB- aabb
Phenotype disc sphere sphere
long
Final phenotypic ratio 9/16 disc
6/16 sphere
1/16 long