Science Microteaching Unit Heather Beaver Jennifer Hambley Katie Hogge.
Lecture 7 - University of California, Santa Cruz 07.pdf · Lecture 7 Norton Equivalent Circuits...
Transcript of Lecture 7 - University of California, Santa Cruz 07.pdf · Lecture 7 Norton Equivalent Circuits...
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Lecture 7
Norton Equivalent Circuitsq
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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Thévenin Equivalent CircuitsThévenin Equivalent Circuits
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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Thévenin Equivalent CircuitsThévenin Equivalent Circuits
oct vV =ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
oct
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Thévenin Equivalent CircuitsThévenin Equivalent Circuits
Vtsc R
Vi =
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
tR
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Thévenin EquivalentThévenin Equivalent Circuits
voc
ivRt =
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
sci
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ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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iI = scn iI =
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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Step-by-step Thévenin/Norton EquivalentThévenin/Norton-Equivalent-
Circuit Analysisy1. Perform two of these:
D t i th i it lt Va. Determine the open-circuit voltage Vt = voc.
b Determine the short-circuit current I = ib. Determine the short circuit current In = isc.
c. Zero the sources and find the Thévenin resistance Rt looking back into the terminals.
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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2. Use the equation Vt = Rt In to compute the remaining value.
3. The Thévenin equivalent consists of a voltage source Vt in series with Rt .
4. The Norton equivalent consists of a current source In in parallel with Rt .
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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Find the Norton Equivalent
15
Rd dV l
RRv
Rvv
KCL ococx
250
015
4:
3
321=
++
−+
Vvvvv
vvRR
vdividerVoltage
ococococ
ococx
62.401525.0
25.0:32
3
=→=+−
+
=+
=
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
VvRRR oc 62.40
4 321→
+++
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Find the Norton Equivalent
= 0vx
=Ω
=→=− 75.02015015
0
1 AViVRi
v
scsc
x
Ω===
Ω
15.662.420
VvR oc
t
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
Ω15.675.0 Ai
Rsc
t
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Find the Norton Equivalent
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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++−
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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Find the Norton Equivalent
Vvvv ococ 63151250110==→=−+
− Vvoc 63.158
012515
==→=+
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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Find the Norton Equivalent
To find Rt zero the sources:
Rt 38.92515
)25)(15(Ω=
Ω+ΩΩΩ
=
AVRV
i tsc 67.1
38963.15
=Ω
==
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
Rt 38.9 Ω
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Find the Norton Equivalent
Rt 38.9 Ω=Ain
t
67.1=ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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Find the Norton Equivalentvoc
+−
vvvvvKVL xocxxoc
2302: =→=−−
Vvvvv
KCL ococxoc 3002
30102
: =→=−+−
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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Find the Norton Equivalent
isc+−
x
xxx
Av
C
vvvKVL−
=→=−−
20220
002:
nscscx iAii
vKCL ==→=−+ 202
1020
:
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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Find the Norton Equivalent
= 2Ain
Ω=== 152
30AV
iv
Rsc
oct
n
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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Source TransformationsSource Transformations
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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Source Transformations
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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Source Transformations
VARiV 10)10)(1( =Ω==
ARR
iiRiR
VARiV tnt
667.01002010
10)10)(1(
11211 ==→=−++
=Ω==
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
RR 2111211 +
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Source Transformations
Aii
AVRV
it
tn
5
4520
=Ω
==
AAARR
RidividerCurrent
Aii
667.15105
55:
5
12
32
=+
=+
=
=+
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
RR 10521 ++
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Transform the Norton equivalent into a Thevenin equivalent with Vt = (2A)(5Ω) = 10V, Rt = 5Ωequivalent with Vt (2A)(5Ω) 10V, Rt 5Ω
= 5ΩNote the reference di i f h
10v +−
direction for the current gives the polarity for the voltage source!
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
voltage source!
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Source Transformations= 5Ω
10v +−
VViiVRiRiVKVL t
200205101010: 22222 =−+=−++−
AVi 33.1510
202 =
+=
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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Source Transformations
AAAiiAii 667.02333.122 2112 −=−=−=→+=
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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Thévenin/Norton Equivalents
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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Thévenin/Norton Equivalents
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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Maximum Power TransferMaximum Power Transfer
The load resistance that absorbs the maximum power from a two-terminalmaximum power from a two-terminal circuit is equal to the Thévenin resistanceresistance.
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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tLL
LL
Lt
tLLL
Lt
tL RR
dRdPR
RRV
RiPRR
VI =→=⎟⎟
⎠
⎞⎜⎜⎝
⎛+
==+
= 02
2
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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Find the load resistance for maximum power
)5)(20(21RRΩ=→Ω=
+=
+= 44
520)5)(20(
21
21MaxLt R
RRRRR
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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SUPERPOSITION PRINCIPLE
The superposition principle states that the total response is the sum of pthe responses to each of the independent sources actingindependent sources acting individually. In equation form, this is
nT rrrr +++= L21
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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Superposition Principle
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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Superposition PrincipleCurrent source
i itopen circuit
VVvRv 51552 VVvRR
v s 51510521
21 =
+=
+=
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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Superposition PrincipleVoltage source h t i it
Reqshort circuit
VAARRiRiv 666)333)(2()5)(10()2(21 =Ω====
VVVvvv
VAARR
iRiv
T
seqs
66.1166.65
66.6)33.3)(2(510
)2(
21
212
=+=+=
=Ω=+
=+
==
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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Superposition Principle
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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Circuit with just vs1j s1
Vs2 short circuit
Req=3.75Ω
VvR
Rv s
eqT 45.520
1075375.3
10 11 ===
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
R seq
T 1075.310 11 ++
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Circuit with just vs2j s2
Vs1 short circuit
Req=3.33Ωeq
VvR
Rv s
eq
eqT 82.110
1533.333.3
15 12 =+
=+
=
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
Vvvv TTT
eq
27.782.145.521 =+=+=
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Superposition Principle
VV 27720 AVVvvi TsT 27.1
1027.720
101 =
Ω−
=Ω−
=
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
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WHEATSTONE BRIDGEThe Wheatstone bridge is used by mechanical and civil engineers to measure the resistancesand civil engineers to measure the resistances of strain gauges in experimental stress studies of machines and buildingsof machines and buildings.
R3
2 RRRRx =
1R
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.