Lecture – 5 Course Code – MIS4102. Edgar F. Codd, the inventor of the relational model,...
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Transcript of Lecture – 5 Course Code – MIS4102. Edgar F. Codd, the inventor of the relational model,...
Lecture – 5Course Code –
MIS4102
Edgar F. Codd, the inventor of the relational model, introduced the concept of normalization and what we now know as the First Normal Form (1NF) in 1970.
Codd went on to define the Second Normal Form (2NF) and Third Normal Form (3NF) in 1971, and Codd and Raymond F. Boyce defined the Boyce-Codd Normal Form (BCNF) in 1974.
Higher normal forms were defined by other theorists in subsequent years, Fagin introduced Forth and Fifth normal form (Fagin 1977, 1979).
The most recent being the Sixth Normal Form (6NF) introduced by Chris Date, Hugh Darwen, and Nikos Lorentzos in 2002.
Introduction
Why Normalization? The step-by-step process of identifying and
eliminating data redundancies and inconsistencies is called normalization.
Tables are the basic building blocks of the database, so good database design must be matched with good table structures.
Normalization enables us to recognize bad table structures and allow us to create good table structures.
Redundancy & Anomalies Data redundancy = data stored in several places
Too much data redundancy causes problems--which value is correct?
Data integrity and consistency suffer Data anomaly = abnormal data relationships
Insertion anomaly - Can’t add data because don’t know entire primary key value, e.g., primary key based on first, middle, and last name
Deletion anomaly - Deletions result in too many fields being removed unintentionally, e.g., delete an employee but lose transaction data
Update anomaly - Change requires many updates, e.g., if you store customer names in transaction tables
Normalization stages are called normal forms (1NF, 2NF and 3NF) each better than previous (less anomalies/redundancy).
Highest level not always the most desirable.
Most professionally designed databases reach third normal form.
Fourth and Fifth normal forms are seldom used.
Normalization (Cont…)
Non-loss Decomposition
The process of transforming an un- normalized data set into a fully normalized database is frequently referred to as a process of non-loss decomposition.
This is because we continually fragment our data structure into more tables without losing the fundamental relationships between data items.
Normalization Example
To recognize good design, first look at bad one
Example, construction company manages several projects and whose charges are dependent on employee’s position.
Desired Report
Proj No Proj Name Emp No Emp Name Job Class Chg/Hr ($) Hrs Billed Tot Chg ($)
1 Hurricane 101 Kamal Hossain Elec Eng 65 13 845
102 David Pol Comm Eng 60 16 960
104 Didar Ahmed Comm Eng 60 19 1,140
Sub Total 2,945
2 Coast 101 Kamal Hossain Elec Eng 65 15 975
103 Younus Mia Asst Eng 55 17 935
Sub Total 1,910
3 Satellite 104 Didar Ahmed Comm Eng 60 18 1,080
102 David Pol Comm Eng 60 14 840
Sub Total 1,920
Total 6,775
Table view of the previous report
P_No P_Name E_No E_Name Job_Class Chg_Hr Hrs
1 Hurricane 101 Kamal Hossain Elec Eng 65 13
102 David Pol Comm Eng 60 16
104 Didar Ahmed Comm Eng 60 19
2 Coast 101 Kamal Hossain Elec Eng 65 15
103 Younus Mia Asst Eng 55 17
3 Satellite 104 Didar Ahmed Comm Eng 60 18
102 David Pol Comm Eng 60 14
Problems P_No intended to be primary key but contains
null values
Data redundancies Invites data inconsistencies (Elect Eng & EE) Wastes data entry time, wastes storage space
Anomalies Update anomaly – modify Job_Class for E_No 101
requires many alterations Insert anomaly – to add a project row we need an
employee Deletion anomaly – delete E_No 101, we delete
other vital data too
Problems (cont…)
Table above has repeating groups Each P_No has a group of entries
P_No P_Name E_No E_Name Job_Class Chg_Hr Hrs
1 Hurricane 101 Kamal Hossain Elec Eng 65 13
102 David Pol Comm Eng 60 16
104 Didar Ahmed Comm Eng 60 19
Conversion to 1NF
Eliminate repeating groups By adding entries in primary key column
P_No P_Name E_No E_Name Job_Class Chg_Hr Hrs
1 Hurricane 101 Kamal Hossain Elec Eng 65 13
1 Hurricane 102 David Pol Comm Eng 60 16
1 Hurricane 104 Didar Ahmed Comm Eng 60 19
2 Coast 101 Kamal Hossain Elec Eng 65 15
2 Coast 103 Younus Mia Asst Eng 55 17
3 Satellite 104 Didar Ahmed Comm Eng 60 18
3 Satellite 102 David Pol Comm Eng 60 14
Problems
Primary key P_No does not uniquely identify all attributes in row
Must create composite key made up of P_No & E_No
Dependency Diagram
Helps us to discover relationships between entity attributes
Upper arrows implies dependency on P_No & E_No Lower arrows implies dependency on only one
attribute
P_No P_Name E_No E_Name Job_Class Chg_Hr Hrs
Dependencies
Upper arrows If you know P_No & E_No you can determine the
other row values Lower arrows
Partial dependencies – based on only part of key P_Name only dependent on P_No E_Name, Job_Class, Chg_Hr only dependent on E_No
Dependency diagram may be written: P_No, E_No P_Name, E_Name, Job_Class, Chg_Hr, Hrs P_No P_Name E_No E_Name, Job_Class, Chg_Hr
New Table (1NF) Composite primary key P_No & E_No
Charges Table
P_No P_Name E_No E_Name Job_Class Chg_Hr Hrs
1 Hurricane 101 Kamal Hossain Elec Eng 65 13
1 Hurricane 102 David Pol Comm Eng 60 16
1 Hurricane 104 Didar Ahmed Comm Eng 60 19
2 Coast 101 Kamal Hossain Elec Eng 65 15
2 Coast 103 Younus Mia Asst Eng 55 17
3 Satellite 104 Didar Ahmed Comm Eng 60 18
3 Satellite 102 David Pol Comm Eng 60 14
1NF Definition
1. All the key attributes are defined Any attribute that is part of the primary key
2. There are no repeating groups in the table Each cell can contain one and only one
value, rather than set
3. All attributes are dependent on the primary key
Problem - Partial Dependencies
Contains partial dependencies Dependencies base on only part of the primary key
This makes table subject to data redundancies and hence to data anomalies
Redundancy caused by fact that every row entry requires duplicate data E.g., suppose E_No 104 is entered 20 times, must
also enter E_Name, Job_Class, Chg_Hr
Anomalies caused by redundancy E.g., employee name may be spelled Didar Ahmed,
Dedar Ahmed, Diader Ahmad or D. Ahmed
Conversion to 2NF
1. Starting with 1NF write each of the key components on separate lines, then write the original key on the last line
P_NoE_NoP_No E_No
Each will become key in a new table Here, original table split into three tables
Conversion to 2NF (cont…)
2. Write the dependent attributes after each of the new keys using the dependency diagram
P_No P_NameE_No E_Name, Job_Class, Chg_HrP_No E_No Hrs
Three New Tables (2NF)
P_No P_Name
1 Hurricane
2 Coast
3 Satellite
E_No E_Name Job_Class Chg_Hr
101 Kamal Hossain Elec Eng 65
102 David Pol Comm Eng 60
103 Younus Mia Asst Eng 55
104 Didar Ahmed Comm Eng 60
Project Table
Employee Table
Assign Table
P_No E_No Hrs
1 101 13
1 102 16
1 104 19
2 101 15
2 103 17
3 104 18
3 102 14
2NF Definition
1. Table is in 1NF and2. It includes no partial dependencies (no
attribute is dependent on only a portion of the primary key)
**Note: Since partial dependencies can exist only if there is a composite key, a table with a single attribute as primary key is automatically in 2NF if it is in 1NF
Problem - Transitive Dependency
Note that Chg_Hr is dependent on Job_Class, but neither Chg_Hr nor Job_Class is part of the primary key
This is called transitive dependency A condition in which an attribute is functionally
dependent on non-key attributes (another attribute that is not part of the primary key)
Transitive dependency yields data anomalies
Conversion to 3NF
Break off the pieces that are identified by the transitive dependency arrows (lower arrows) in the dependency diagram
Store them in a separate tableP_No P_NameE_No E_Name, Job_ClassP_No E_No HrsJob_Class Chg_Hr
**Note: Job_Class must be retained in Employee table to establish a link to the newly created Job table
New Tables (3NF)
P_No P_Name
1 Hurricane
2 Coast
3 Satellite
E_No E_Name Job_Class
101 Kamal Hossain Elec Eng
102 David Pol Comm Eng
103 Younus Mia Asst Eng
104 Didar Ahmed Comm Eng
Project Table
Employee Table
Assign Table P_No E_No Hrs
1 101 13
1 102 16
1 104 19
2 101 15
2 103 17
3 104 18
3 102 14
Job_Class Chg_Hr
Elec Eng 65
Comm Eng 60
Asst Eng 55
Job Table
3NF Definition
1. Table is in 2NF and2. It contains no transitive dependencies
Problem
Although the four tables are in 3NF, we have a potential problem
The Job_Class is entered for each new employee in the Employee table
For example, too easy to enter Electrical Engr, or EE, or El Eng
E_No E_Name Job_Class
101 Kamal Hossain Elec Eng
102 David Pol Comm Eng
103 Younus Mia Asst Eng
104 Didar Ahmed Comm Eng
105 Ali Ahmed Asst Eng
106 Nipa Ahmed Elec Eng
Employee Table
New Attribute Create a Job_Code attribute to serve as primary
key in the Job table and as a foreign key in the Employee table
New Tables
P_No P_Name
1 Hurricane
2 Coast
3 Satellite
E_No E_Name Job_Code
101 Kamal Hossain 500
102 David Pol 501
103 Younus Mia 502
104 Didar Ahmed 501
Project Table
Employee Table
Assign Table P_No E_No Hrs
1 101 13
1 102 16
1 104 19
2 101 15
2 103 17
3 104 18
3 102 14
Job_Code Job_Class Chg_Hr
500 Elec Eng 65
501 Comm Eng 60
502 Asst Eng 55
Job Table
Another Example…
The Problem:Keeping Track of a Stack of Invoices
Required TableOrders
order_id order_datecustomer_idcustomer_namecustomer_addresscustomer_citycustomer_stateitem_iditem_descriptionitem_qtyitem_price
First Normal Form:No Repeating Elements or Groups of Elements
NF1 addresses two issues:
1. A row of data cannot contain repeating groups of similar data (atomicity)
2. Each row of data must have a unique identifier (or Primary Key)
Orders
order_id (PK)order_datecustomer_idcustomer_namecustomer_addresscustomer_citycustomer_stateitem_id (PK)item_descriptionitem_qtyitem_price
Second Normal Form:No Partial Dependencies on a Concatenated Key
Here we test each table for partial dependencies on a concatenated key.
This means that for a table that has a concatenated primary key, each column in the table that is not part of the primary key must depend upon the entire concatenated key for its existence.
If any column only depends upon one part of the concatenated key, then we say that the entire table has failed Second Normal Form and we must create another table to rectify the failure.
Checking Partial Dependencies
Ordersorder_id (PK)order_date customer_id ?customer_name ?customer_address ?customer_city ?customer_state ?item_id (PK)item_description item_qty item_price
Orders
order_id (PK)order_datecustomer_idcustomer_namecustomer_addresscustomer_citycustomer_stateitem_id (PK)item_descriptionitem_qtyitem_price
Second Normal Form:
ordersorder_id (PK)order_datecustomer_idcustomer_namecustomer_addresscustomer_citycustomer_state
itemsitem_id (PK)item_descriptionitem_price
order_itemsorder_id (PK)item_id (PK)item_qty
Third Normal Form:No Dependencies on Non-Key Attributes
Here, we return to the problem of the repeating customer information. As our database now stands, if a customer places more than one order then we have to input all of that customer's contact information again. This is because there are columns in the orders table that rely on "non-key attributes".
Third Normal Form:
ordersorder_id (PK)customer_id (FK)order_date
itemsitem_id (PK)item_descriptionitem_price
order_itemsorder_id (PK)item_id (PK)item_qty
customers customer_id (PK)customer_namecustomer_addresscustomer_citycustomer_state
Summary
1NF – Eliminate repeating groups
2NF – Eliminate partial dependencies
3NF – Eliminate transitive dependencies
Thanks to All