81796723 Veterinary Neuropharmacology VPT 321 Lecture Notes TANUVAS
Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.
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Transcript of Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.
![Page 1: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/1.jpg)
Lecture 32Lecture 32 11
Unit 4 Lecture 32Unit 4 Lecture 32Quadratics Applications & Quadratics Applications &
Their GraphsTheir Graphs
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Lecture 32Lecture 32 22
ObjectivesObjectives
• Formulate a quadratic equation from a Formulate a quadratic equation from a problem situationproblem situation
• Solve a quadratic equation by using the Solve a quadratic equation by using the quadratic formulaquadratic formula
• Graph the quadratic equationGraph the quadratic equation
• Interpret the graph in terms of the problem Interpret the graph in terms of the problem situationsituation
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Lecture 32Lecture 32 33
Revenue:Revenue: R = 78x - xR = 78x - x22
Cost: Cost: C = xC = x2 2 –38 x + 400–38 x + 400
Find the equation for ProfitFind the equation for Profit
Profit = Profit = RevenueRevenue - - CostCost
Earl Black makes tea bags. The cost of making x Earl Black makes tea bags. The cost of making x million teas bags per month ismillion teas bags per month is C = xC = x2 2 –38 x+400. –38 x+400. The revenue from selling x million tea bags per The revenue from selling x million tea bags per month is R = 78x - xmonth is R = 78x - x22
![Page 4: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/4.jpg)
Lecture 32Lecture 32 44
The equation for profit is, The equation for profit is, Profit = Profit = RevenueRevenue - - CostCost
Revenue:Revenue: R = 78x - xR = 78x - x22
P = ( 78x – xP = ( 78x – x22) – () – (xx2 2 –38 x + 400–38 x + 400))
Cost:Cost:C = xC = x2 2 –38 x + 400–38 x + 400
![Page 5: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/5.jpg)
Lecture 32Lecture 32 55
The equation for profit is, The equation for profit is, Profit = Profit = RevenueRevenue - - CostCost
Revenue:Revenue: R = 78x - xR = 78x - x22
P = ( 78x – xP = ( 78x – x22) – () – (xx2 2 –38 x + 400–38 x + 400))
Cost:Cost:C = xC = x2 2 –38 x + 400–38 x + 400
P = 78x – xP = 78x – x22 – – xx2 2 +38 x - 400+38 x - 400
![Page 6: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/6.jpg)
Lecture 32Lecture 32 66
The equation for profit is, The equation for profit is, Profit = Profit = RevenueRevenue - - CostCost
Revenue:Revenue: R = 78x - xR = 78x - x22
P = ( 78x – xP = ( 78x – x22) – () – (xx2 2 –38 x + 400–38 x + 400))
Cost:Cost:C = xC = x2 2 –38 x + 400–38 x + 400
P = 78x – xP = 78x – x22 – – xx2 2 + 38 x - 400+ 38 x - 400
P = P = – 2x– 2x22
![Page 7: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/7.jpg)
Lecture 32Lecture 32 77
The equation for profit is, The equation for profit is, Profit = Profit = RevenueRevenue - - CostCost
Revenue:Revenue: R = 78x - xR = 78x - x22
P = ( 78x – xP = ( 78x – x22) – () – (xx2 2 –38 x + 400–38 x + 400))
Cost:Cost:C = xC = x2 2 –38 x + 400–38 x + 400
P = 78x – xP = 78x – x22 – – xx2 2 + 38 x - 400+ 38 x - 400
P = P = – 2x– 2x2 2 + + 116 x116 x
![Page 8: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/8.jpg)
Lecture 32Lecture 32 88
The equation for profit is, The equation for profit is, Profit = Profit = RevenueRevenue - - CostCost
Revenue:Revenue: R = 78x - xR = 78x - x22
P = ( 78x – xP = ( 78x – x22) – () – (xx2 2 –38 x + 400–38 x + 400))
Cost:Cost:C = xC = x2 2 –38 x + 400–38 x + 400
P = 78x – xP = 78x – x22 – – xx2 2 + 38 x - 400+ 38 x - 400
P = P = – 2x– 2x2 2 + + 116 x116 x - 400- 400
![Page 9: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/9.jpg)
Lecture 32Lecture 32 99
Graph the Profit EquationGraph the Profit Equation
P = P = – 2x– 2x2 2 + 116 x - 400+ 116 x - 400
![Page 10: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/10.jpg)
Lecture 32Lecture 32 1010
Graph the Profit EquationGraph the Profit Equation
Vertex: Vertex: P = P = – 2– 2xx2 2 + + 116116 x - 400 x - 400
2x
ab
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Lecture 32Lecture 32 1111
Graph the Profit EquationGraph the Profit Equation
Vertex: Vertex: P = P = – 2– 2xx2 2 + + 116116 x - 400 x - 400
2x
ab 116
294( 2)
112
6x
![Page 12: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/12.jpg)
Lecture 32Lecture 32 1212
Graph the Profit EquationGraph the Profit Equation
Vertex: Vertex: P = P = – 2– 2xx2 2 + + 116116 x - 400 x - 400
2x
ab 116
294( 2)
112
6x
P = P = – 2– 2(29)(29)2 2 + + 116116 (29) – 400=1282 (29) – 400=1282
![Page 13: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/13.jpg)
Lecture 32Lecture 32 1313
Graph the Profit EquationGraph the Profit Equation
Vertex: Vertex: P = P = – 2– 2xx2 2 + + 116116 x - 400 x - 400
2x
ab 116
294( 2)
112
6x
P = P = – 2– 2(29)(29)2 2 + + 116116 (29) – 400=1282 (29) – 400=1282
Vertex: (29,1282) Vertex: (29,1282)
x=29, P = $1282x=29, P = $1282
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Lecture 32Lecture 32 1414
Graph the Profit EquationGraph the Profit Equation
X-Intercepts: when P = 0, what is x?X-Intercepts: when P = 0, what is x?
P = P = – 2– 2xx2 2 + + 116116 x - 400 x - 400
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Lecture 32Lecture 32 1515
Graph the Profit EquationGraph the Profit Equation
X-Intercepts: when P = 0, what is x?X-Intercepts: when P = 0, what is x?
P = P = – 2– 2xx2 2 + + 116116 x - 400 x - 400
P = P = – 2– 2xx2 2 + + 116116 x - 400 x - 400
0 = 0 = – 2– 2xx2 2 + + 116116 x x - 400- 400
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Lecture 32Lecture 32 1616
Graph the Profit EquationGraph the Profit Equation
X-Intercepts: when P = 0, what is x?X-Intercepts: when P = 0, what is x?
P = P = – 2– 2xx2 2 + + 116116 x - 400 x - 400
P = P = – 2– 2xx2 2 + + 116116 x - 400 x - 400
0 = 0 = – 2– 2xx2 2 + + 116116 x x - 400- 4002 4
2x
cb b a
a
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Lecture 32Lecture 32 1717
Graph the Profit EquationGraph the Profit Equation
X-Intercepts: when P = 0, what is x?X-Intercepts: when P = 0, what is x?
P = P = – 2– 2xx2 2 + + 116116 x - 400 x - 400
P = P = – 2– 2xx2 2 + + 116116 x - 400 x - 400
0 = 0 = – 2– 2xx2 2 + + 116116 x x - 400- 4002 4
2x
cb b a
a
2 4
2
( 2)
( 2
116 11
)
006 ( 4 )x
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Lecture 32Lecture 32 1818
Graph the Profit EquationGraph the Profit Equation
X-Intercepts: when P = 0, what is x?X-Intercepts: when P = 0, what is x?P = P = – 2– 2xx2 2 + + 116116 x - 400 x - 400
2 4
2x
cb b a
a
2 4
2
( 2)
( 2
116 11
)
006 ( 4 )x
116 13456 3200
4x
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Lecture 32Lecture 32 1919
Graph the Profit EquationGraph the Profit Equation
X-Intercepts: when P = 0, what is x?X-Intercepts: when P = 0, what is x?P = P = – 2– 2xx2 2 + + 116116 x - 400 x - 400
2 4
2x
cb b a
a
2 4
2
( 2)
( 2
116 11
)
006 ( 4 )x
116 13456 3200
4x
116 10256
4x
![Page 20: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/20.jpg)
Lecture 32Lecture 32 2020
Graph the Profit EquationGraph the Profit Equation
X-Intercepts: when P = 0, what is x?X-Intercepts: when P = 0, what is x?P = P = – 2– 2xx2 2 + + 116116 x - 400 x - 400
2 4
2
( 2)
( 2
116 11
)
006 ( 4 )x
116 13456 3200
4x
116 10256
4x
116 101.3
4x
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Lecture 32Lecture 32 2121
Use the Quadratic Formula to solve:Use the Quadratic Formula to solve:
0 =0 = -2x -2x2 2 + 116x+ 116x - 400- 400116 101.3
4x
116 101.3 14.7
3.7116 101.34 4
4x
![Page 22: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/22.jpg)
Lecture 32Lecture 32 2222
Use the Quadratic Formula to solve:Use the Quadratic Formula to solve:
0 =0 = -2x -2x2 2 + 116x+ 116x - 400- 400116 101.3
4x
116 101.3 14.7
3.7116 101.3 4 4
4 116 101.3 217.354.3
4 4
x
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Lecture 32Lecture 32 2323
Use the Quadratic Formula to solve:Use the Quadratic Formula to solve:
0 =0 = -2x -2x2 2 + 116x+ 116x - 400- 400
116 101.3 14.73.7
116 101.3 4 44 116 101.3 217.3
54.34 4
x
Two solutions to make P = 0: Two solutions to make P = 0: x = 3.7 and x = 54.3 itemsx = 3.7 and x = 54.3 items
116 101.3
4x
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Lecture 32Lecture 32 2424
Graph the Profit EquationGraph the Profit Equation
P-Intercept: when x = 0, what is P?P-Intercept: when x = 0, what is P?
P = P = – 2– 2xx2 2 + + 116116 x - 400 x - 400
P = P = – 2– 2xx2 2 + + 116116 x - 400 x - 400
![Page 25: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/25.jpg)
Lecture 32Lecture 32 2525
Graph the Profit EquationGraph the Profit Equation
P-Intercept: when x = 0, what is P?P-Intercept: when x = 0, what is P?
P = P = – 2– 2xx2 2 + + 116116 x - 400 x - 400
P = P = – 2– 2xx2 2 + + 116116 x - 400 x - 400
P = P = – 2– 2(0)(0)2 2 + + 116116 (0) (0) – 400 – 400 = - 400= - 400
![Page 26: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/26.jpg)
Lecture 32Lecture 32 2626
Graph the Profit EquationGraph the Profit Equation
P-Intercept: when x = 0, what is P?P-Intercept: when x = 0, what is P?
P = P = – 2– 2xx2 2 + + 116116 x - 400 x - 400
P = P = – 2– 2xx2 2 + + 116116 x - 400 x - 400
P = P = – 2– 2(0)(0)2 2 + + 116116 (0) (0) – 400 – 400 = - 400= - 400
P P = - 400= - 400
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Lecture 32Lecture 32 2727
Graph the Profit EquationGraph the Profit Equation
P = P = – 2x– 2x2 2 + 116 x - 400+ 116 x - 400
1.1. Because a = -2, parabola opens downBecause a = -2, parabola opens down
2.2. Vertex: (Vertex: ( 29,1282)29,1282) 3.3. X-Intercepts: (3.7, 0) and (54.3,0)X-Intercepts: (3.7, 0) and (54.3,0)
4.4. P-Intercept: (0,-400)P-Intercept: (0,-400)
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Lecture 32Lecture 32 2828
10 20 30 40 50 60
400
800
1200
-400
-800
(29,1282)
Graph:Graph: P = P = – 2x– 2x2 2 + 116 x - 400+ 116 x - 400
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Lecture 32Lecture 32 2929
10 20 30 40 50 60
400
800
1200
-400
-800
(29,1282)
(54.3,0)(3.7,0)
Graph:Graph: P = P = – 2x– 2x2 2 + 116 x - 400+ 116 x - 400
![Page 30: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/30.jpg)
Lecture 32Lecture 32 3030
10 20 30 40 50 60
400
800
1200
-400
-800
(29,1282)
(54.3,0)(3.7,0)
(0,-400)
Graph:Graph: P = P = – 2x– 2x2 2 + 116 x - 400+ 116 x - 400
![Page 31: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/31.jpg)
Lecture 32Lecture 32 3131
10 20 30 40 50 60
400
800
1200
-400
-800
(29,1282)
(54.3,0)(3.7,0)
(0,-400)
Graph:Graph: P = P = – 2x– 2x2 2 + 116 x - 400+ 116 x - 400
![Page 32: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/32.jpg)
Lecture 32Lecture 32 3232
How many items must be made and sold How many items must be made and sold to generate $500 profit.to generate $500 profit.
P = P = – 2x– 2x2 2 + + 116 x116 x - 400- 400
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Lecture 32Lecture 32 3333
How many items must be made and sold How many items must be made and sold to generate $500 profit.to generate $500 profit.
P = P = – 2x– 2x2 2 + + 116 x116 x - 400- 400
500 =500 = -2x -2x2 2 + 116x+ 116x - 400- 400
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Lecture 32Lecture 32 3434
How many items must be made and sold How many items must be made and sold to generate $500 profit.to generate $500 profit.
P = P = – 2x– 2x2 2 + + 116 x116 x - 400- 400
500 =500 = -2x -2x2 2 + 116x+ 116x - 400- 400 Subtract 500 from Subtract 500 from both sidesboth sides
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Lecture 32Lecture 32 3535
How many items must be made and sold How many items must be made and sold to generate $500 profit.to generate $500 profit.
P = P = – 2x– 2x2 2 + + 116 x116 x - 400- 400
500 =500 = -2x -2x2 2 + 116x+ 116x - 400- 400
0 =0 = -2x -2x2 2 + 116x+ 116x - 900- 900
Subtract 500 from Subtract 500 from both sidesboth sides
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Lecture 32Lecture 32 3636
Use the Quadratic Formula to solve:Use the Quadratic Formula to solve:
0 =0 = -2x -2x2 2 + 116x+ 116x - 900- 900
0 =0 = a axx22 ++ b bx +x + c c2 4
2x
cb b a
a
![Page 37: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/37.jpg)
Lecture 32Lecture 32 3737
Use the Quadratic Formula to solve:Use the Quadratic Formula to solve:
0 =0 = -2x -2x2 2 + 116x+ 116x - 900- 900
a = -2a = -2 b = 116b = 116 c = -900c = -900
0 =0 = a axx22 ++ b bx +x + c c2 4
2x
cb b a
a
![Page 38: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/38.jpg)
Lecture 32Lecture 32 3838
Use the Quadratic Formula to solve:Use the Quadratic Formula to solve:
0 =0 = -2x -2x2 2 + 116x+ 116x - 900- 900
a = -2a = -2 b = 116b = 116 c = -900c = -900
0 =0 = a axx22 ++ b bx +x + c c2 4
2x
cb b a
a
2 4
2
( 2)
( 2
116 11
)
006 ( 9 )x
![Page 39: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/39.jpg)
Lecture 32Lecture 32 3939
Use the Quadratic Formula to solve:Use the Quadratic Formula to solve:
0 =0 = -2x -2x2 2 + 116x+ 116x - 900- 900
a = -2a = -2 b = 116b = 116 c = -900c = -900
0 =0 = a axx22 ++ b bx +x + c c2 4
2x
cb b a
a
2 4
2
( 2)
( 2
116 11
)
006 ( 9 )x
116 13456 7200
4x
![Page 40: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/40.jpg)
Lecture 32Lecture 32 4040
Use the Quadratic Formula to solve:Use the Quadratic Formula to solve:
0 =0 = -2x -2x2 2 + 116x+ 116x - 900- 900
0 =0 = a axx22 ++ b bx +x + c c2 4
2x
cb b a
a
2 4
2
( 2)
( 2
116 11
)
006 ( 9 )x
116 13456 7200
4x
116 6256
4x
![Page 41: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/41.jpg)
Lecture 32Lecture 32 4141
Use the Quadratic Formula to solve:Use the Quadratic Formula to solve:
0 =0 = -2x -2x2 2 + 116x+ 116x - 900- 900
0 =0 = a axx22 ++ b bx +x + c c2 4
2x
cb b a
a
2 4
2
( 2)
( 2
116 11
)
006 ( 9 )x
116 13456 7200
4x
116 6256
4x
116 79.1
4x
![Page 42: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/42.jpg)
Lecture 32Lecture 32 4242
Use the Quadratic Formula to solve:Use the Quadratic Formula to solve:
0 =0 = -2x -2x2 2 + 116x+ 116x - 900- 900
116 79.1 36.99.2116 79.1
4 44
x
116 79.1
4x
![Page 43: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/43.jpg)
Lecture 32Lecture 32 4343
Use the Quadratic Formula to solve:Use the Quadratic Formula to solve:
0 =0 = -2x -2x2 2 + 116x+ 116x - 900- 900116 79.1
4x
116 79.1 36.9
9.2116 79.1 4 4
4 116 79.1 195.148.8
4 4
x
![Page 44: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/44.jpg)
Lecture 32Lecture 32 4444
Use the Quadratic Formula to solve:Use the Quadratic Formula to solve:
0 =0 = -2x -2x2 2 + 116x+ 116x - 900- 900116 79.1
4x
116 79.1 36.9
9.2116 79.1 4 4
4 116 79.1 195.148.8
4 4
x
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Lecture 32Lecture 32 4545
Use the Quadratic Formula to solve:Use the Quadratic Formula to solve:
0 =0 = -2x -2x2 2 + 116x+ 116x - 900- 900116 79.1
4x
116 79.1 36.9
9.2116 79.1 4 4
4 116 79.1 195.148.8
4 4
x
Two solutions to make P = $500: Two solutions to make P = $500: x = 9.2 and x = 48.8 itemsx = 9.2 and x = 48.8 items
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Lecture 32Lecture 32 4646
10 20 30 40 50 60
400
800
1200
-400
-800
Graph:Graph: P = P = – 2x– 2x2 2 + 116 x - 400+ 116 x - 400
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Lecture 32Lecture 32 4747
10 20 30 40 50 60
400
800
1200
-400
-800
Graph:Graph: P = P = – 2x– 2x2 2 + 116 x - 400+ 116 x - 400
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Lecture 32Lecture 32 4848
10 20 30 40 50 60
400
800
1200
-400
-800
Graph:Graph: P = P = – 2x– 2x2 2 + 116 x - 400+ 116 x - 400
(9.2,500) (48.8,500)
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Lecture 32Lecture 32 4949
An angry student stands on the top of a 250 foot cliff An angry student stands on the top of a 250 foot cliff and throws his book upward with a velocity of 46 feet and throws his book upward with a velocity of 46 feet per second. The height of the book from the ground is per second. The height of the book from the ground is given by the equation: h = -16tgiven by the equation: h = -16t22 + 46t + 250 + 46t + 250h is in feet and t is in seconds. Graph the equation.h is in feet and t is in seconds. Graph the equation.
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Lecture 32Lecture 32 5050
Graph:Graph:
Vertex: Vertex:
h = -16th = -16t22 + 46t + 250 + 46t + 250
2x
ab
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Lecture 32Lecture 32 5151
Graph:Graph:
Vertex: Vertex:
h = -16th = -16t22 + 46t + 250 + 46t + 250
2x
ab 46
1.432( 16)
462
t
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Lecture 32Lecture 32 5252
Graph:Graph:
Vertex: Vertex:
h = -16th = -16t22 + 46t + 250 + 46t + 250
2x
ab 46
1.432( 16)
462
t
h = h = – 16– 16(1.4)(1.4)2 2 + + 4646 (1.4) + 250 = 283 (1.4) + 250 = 283
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Lecture 32Lecture 32 5353
Graph:Graph:
Vertex: Vertex:
h = -16th = -16t22 + 46t + 250 + 46t + 250
2x
ab 46
1.432( 16)
462
t
h = h = – 16– 16(1.4)(1.4)2 2 + + 4646 (1.4) + 250 = 283 (1.4) + 250 = 283
Vertex: (1.4, 283) Vertex: (1.4, 283)
x=1.4 sec, h = 283 feetx=1.4 sec, h = 283 feet
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Lecture 32Lecture 32 5454
Graph:Graph:
t-Intercepts: when h = 0, what is t?t-Intercepts: when h = 0, what is t?
h = -16th = -16t22 + 46t + 250 + 46t + 250
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Lecture 32Lecture 32 5555
Graph:Graph:
t-Intercepts: when h = 0, what is t?t-Intercepts: when h = 0, what is t?h = h = – 16– 16tt2 2 + + 4646 t + 250 t + 250
h = -16th = -16t22 + 46t + 250 + 46t + 250
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Lecture 32Lecture 32 5656
Graph:Graph:
t-Intercepts: when h = 0, what is t?t-Intercepts: when h = 0, what is t?h = h = – 16– 16tt2 2 + + 4646 t + 250 t + 250
h = -16th = -16t22 + 46t + 250 + 46t + 250
0 = 0 = – 16– 16tt2 2 + + 4646 t + 250 t + 250
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Lecture 32Lecture 32 5757
Graph:Graph:
t-Intercepts: when h = 0, what is t?t-Intercepts: when h = 0, what is t?h = h = – 16– 16tt2 2 + + 4646 t + 250 t + 250
2 4
2x
cb b a
a
h = -16th = -16t22 + 46t + 250 + 46t + 250
0 = 0 = – 16– 16tt2 2 + + 4646 t + 250 t + 250
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Lecture 32Lecture 32 5858
Graph:Graph:
t-Intercepts: when h = 0, what is t?t-Intercepts: when h = 0, what is t?h = h = – 16– 16tt2 2 + + 4646 t + 250 t + 250
2 4
2x
cb b a
a
2 ( 16)(4
2
46
( 16
)
)
46 250t
h = -16th = -16t22 + 46t + 250 + 46t + 250
0 = 0 = – 16– 16tt2 2 + + 4646 t + 250 t + 250
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Lecture 32Lecture 32 5959
Graph:Graph:
t-Intercepts: when P = 0, what is t?t-Intercepts: when P = 0, what is t?2 ( 16)(4
2
46
( 16
)
)
46 250t
h = -16th = -16t22 + 46t + 250 + 46t + 250
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Lecture 32Lecture 32 6060
Graph:Graph:
t-Intercepts: when P = 0, what is t?t-Intercepts: when P = 0, what is t?
46 2116 16000
32t
2 ( 16)(4
2
46
( 16
)
)
46 250t
h = -16th = -16t22 + 46t + 250 + 46t + 250
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Lecture 32Lecture 32 6161
Graph:Graph:
t-Intercepts: when P = 0, what is t?t-Intercepts: when P = 0, what is t?
46 2116 16000
32t
46 18116
32t
2 ( 16)(4
2
46
( 16
)
)
46 250t
h = -16th = -16t22 + 46t + 250 + 46t + 250
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Lecture 32Lecture 32 6262
Graph:Graph:
t-Intercepts: when P = 0, what is t?t-Intercepts: when P = 0, what is t?
46 2116 16000
32t
46 18116
32t
46 134.6
32t
2 ( 16)(4
2
46
( 16
)
)
46 250t
h = -16th = -16t22 + 46t + 250 + 46t + 250
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Lecture 32Lecture 32 6363
Graph:Graph:
t-Intercepts: when P = 0, what is t?t-Intercepts: when P = 0, what is t?
46 2116 16000
32t
46 18116
32t
46 134.6
32t
2 ( 16)(4
2
46
( 16
)
)
46 250t
h = -16th = -16t22 + 46t + 250 + 46t + 250
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Lecture 32Lecture 32 6464
46 134.6 88.62.846 134.6
32 3232
t
Use the Quadratic Formula to solve:Use the Quadratic Formula to solve:
0 = -16t0 = -16t22 + 46t + 250 + 46t + 25046 134.6
32t
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Lecture 32Lecture 32 6565
46 134.6 88.62.8
46 134.6 32 3232 46 134.6 180.6
5.632 32
t
Use the Quadratic Formula to solve:Use the Quadratic Formula to solve:0 = -16t0 = -16t22 + 46t + 250 + 46t + 250
46 134.6
32t
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Lecture 32Lecture 32 6666
Use the Quadratic Formula to solve:Use the Quadratic Formula to solve:
Two solutions to make h = 0: Two solutions to make h = 0: t = -2.8 and t = 5.6 seconds t = -2.8 and t = 5.6 seconds t = -2.8 does not make senset = -2.8 does not make sense
0 = -16t0 = -16t22 + 46t + 250 + 46t + 25046 134.6
32t
46 134.6 88.62.8
46 134.6 32 3232 46 134.6 180.6
5.632 32
t
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Lecture 32Lecture 32 6767
Graph:Graph:
h-Intercept: when t = 0, what is h?h-Intercept: when t = 0, what is h?
h = -16th = -16t22 + 46t + 250 + 46t + 250
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Lecture 32Lecture 32 6868
Graph:Graph:
h-Intercept: when t = 0, what is h?h-Intercept: when t = 0, what is h?
h = -16th = -16t22 + 46t + 250 + 46t + 250
h = h = – 16– 16tt2 2 + + 4646 t + 250 t + 250
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Lecture 32Lecture 32 6969
Graph:Graph:
h-Intercept: when t = 0, what is h?h-Intercept: when t = 0, what is h?
h = h = – 16– 16(0)(0)2 2 + + 4646 (0) + 250 (0) + 250
h = -16th = -16t22 + 46t + 250 + 46t + 250
h = h = – 16– 16tt2 2 + + 4646 t + 250 t + 250
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Lecture 32Lecture 32 7070
Graph:Graph:
h-Intercept: when t = 0, what is h?h-Intercept: when t = 0, what is h?
h = h = – 16– 16(0)(0)2 2 + + 4646 (0) + 250 (0) + 250
h = -16th = -16t22 + 46t + 250 + 46t + 250
h = h = – 16– 16tt2 2 + + 4646 t + 250 t + 250
h = h = 250 feet250 feet
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Lecture 32Lecture 32 7171
Graph:Graph:
1.1. Because a = -16, parabola opens downBecause a = -16, parabola opens down
2.2. Vertex: (Vertex: ( 1.4, 283)1.4, 283) 3.3. t-Intercept: (5.6, 0) t-Intercept: (5.6, 0)
4.4. h-Intercept: (0, 250)h-Intercept: (0, 250)
h = -16th = -16t22 + 46t + 250 + 46t + 250
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Lecture 32Lecture 32 7272
1 2 3 4 5 6
250
200
300
100
50
(1.4,283)
Graph:Graph: h = -16th = -16t22 + 46t + 250 + 46t + 250
150
Time (sec)
Height (feet)
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Lecture 32Lecture 32 7373
1 2 3 4 5 6
250
200
300
100
50
(1.4,283)
(5.6,0)
Graph:Graph: h = -16th = -16t22 + 46t + 250 + 46t + 250
150
Time (sec)
Height (feet)
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Lecture 32Lecture 32 7474
1 2 3 4 5 6
250
200
300
100
50
(1.4,283)
(5.6,0)
(0,250)
Graph:Graph: h = -16th = -16t22 + 46t + 250 + 46t + 250
150
Time (sec)
Height (feet)
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Lecture 32Lecture 32 7575
1 2 3 4 5 6
250
200
300
100
50
(1.4,283)
(5.6,0)
(0,250)
Graph:Graph: h = -16th = -16t22 + 46t + 250 + 46t + 250
150
Time (sec)
Height (feet)
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Lecture 32Lecture 32 7676
Ms. Piggie wants to enclose two adjacent chicken Ms. Piggie wants to enclose two adjacent chicken coops of equal size against the hen house wall. She coops of equal size against the hen house wall. She has 66 feet of chicken-wire fencing and would like to has 66 feet of chicken-wire fencing and would like to make the chicken coup as large as possible. Find the make the chicken coup as large as possible. Find the formula for the area of the chicken coops.formula for the area of the chicken coops. Wall
L
WW W
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Lecture 32Lecture 32 7777
Ms. Piggie wants to enclose two adjacent chicken Ms. Piggie wants to enclose two adjacent chicken coops of equal size against the hen house wall. She coops of equal size against the hen house wall. She has 66 feet of chicken-wire fencing and would like to has 66 feet of chicken-wire fencing and would like to make the chicken coup as large as possible. Find the make the chicken coup as large as possible. Find the formula for the area of the chicken coops.formula for the area of the chicken coops. Wall
L
WWWidthWidth LengthLength AreaArea
55
1010
1515
XX
W
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Lecture 32Lecture 32 7878
Ms. Piggie wants to enclose two adjacent chicken Ms. Piggie wants to enclose two adjacent chicken coops of equal size against the hen house wall. She coops of equal size against the hen house wall. She has 66 feet of chicken-wire fencing and would like to has 66 feet of chicken-wire fencing and would like to make the chicken coup as large as possible. Find the make the chicken coup as large as possible. Find the formula for the area of the chicken coops.formula for the area of the chicken coops. Wall
L
WWWidthWidth LengthLength AreaArea
55 66-3(66-3(55)=56)=56 5(51)=2515(51)=251
1010
1515
XX
W
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Lecture 32Lecture 32 7979
Ms. Piggie wants to enclose two adjacent chicken Ms. Piggie wants to enclose two adjacent chicken coops of equal size against the hen house wall. She coops of equal size against the hen house wall. She has 66 feet of chicken-wire fencing and would like to has 66 feet of chicken-wire fencing and would like to make the chicken coup as large as possible. Find the make the chicken coup as large as possible. Find the formula for the area of the chicken coops.formula for the area of the chicken coops. Wall
L
WWWidthWidth LengthLength AreaArea
55 66-3(66-3(55)=56)=56 5(51)=2515(51)=251
1010 66-3(66-3(1010)=36)=36 10(36)=36010(36)=360
1515
XX
W
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Lecture 32Lecture 32 8080
Ms. Piggie wants to enclose two adjacent chicken Ms. Piggie wants to enclose two adjacent chicken coops of equal size against the hen house wall. She coops of equal size against the hen house wall. She has 66 feet of chicken-wire fencing and would like to has 66 feet of chicken-wire fencing and would like to make the chicken coup as large as possible. Find the make the chicken coup as large as possible. Find the formula for the area of the chicken coops.formula for the area of the chicken coops. Wall
L
WWWidthWidth LengthLength AreaArea
55 66-3(66-3(55)=56)=56 5(51)=2515(51)=251
1010 66-3(66-3(1010)=36)=36 10(36)=36010(36)=360
1515 66-3(66-3(1515)=21)=21 15(21)=31515(21)=315
XX
W
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Lecture 32Lecture 32 8181
Ms. Piggie wants to enclose two adjacent chicken Ms. Piggie wants to enclose two adjacent chicken coops of equal size against the hen house wall. She coops of equal size against the hen house wall. She has 66 feet of chicken-wire fencing and would like to has 66 feet of chicken-wire fencing and would like to make the chicken coup as large as possible. Find the make the chicken coup as large as possible. Find the formula for the area of the chicken coops.formula for the area of the chicken coops. Wall
L
WWWidthWidth LengthLength AreaArea
55 66-3(66-3(55)=56)=56 5(51)=2515(51)=251
1010 66-3(66-3(1010)=36)=36 10(36)=36010(36)=360
1515 66-3(66-3(1515)=21)=21 15(21)=31515(21)=315
XX 66-3(66-3(XX)) X(66-3X)=X(66-3X)=
66X-3X66X-3X22
W
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Lecture 32Lecture 32 8282
Graph:Graph:
Vertex: Vertex:
A = - 3XA = - 3X22 + + 66X66X
2x
ab
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Lecture 32Lecture 32 8383
Graph:Graph:
Vertex: Vertex:
A = - 3XA = - 3X22 + + 66X66X
2x
ab 66
116( 3)
662
x
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Lecture 32Lecture 32 8484
Graph:Graph:
Vertex: Vertex:
A = - 3XA = - 3X22 + + 66X66X
2x
ab 66
116( 3)
662
x
A = A = – 3– 3(11)(11)2 2 + + 6666 (11) = 363 (11) = 363
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Lecture 32Lecture 32 8585
Graph:Graph:
Vertex: Vertex:
A = - 3XA = - 3X22 + + 66X66X
2x
ab 66
116( 3)
662
x
A = A = – 3– 3(11)(11)2 2 + + 6666 (11) = 363 (11) = 363
Vertex: (11, 363) Vertex: (11, 363)
x=11 feet, A = 363 sq. feetx=11 feet, A = 363 sq. feet
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Lecture 32Lecture 32 8686
Graph:Graph:
Vertex: Vertex:
A = - 3XA = - 3X22 + + 66X66X
2x
ab 66
116( 3)
662
x
A = A = – 3– 3(11)(11)2 2 + + 6666 (11) = 363 (11) = 363
Vertex: (11, 363) Vertex: (11, 363)
x=11 feet, A = 363 sq. feetx=11 feet, A = 363 sq. feet
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Lecture 32Lecture 32 8787
Graph:Graph:
x-Intercepts: when A = 0, what is x?x-Intercepts: when A = 0, what is x?
A = - 3XA = - 3X22 + + 66X66X
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Lecture 32Lecture 32 8888
Graph:Graph:
x-Intercepts: when A = 0, what is x?x-Intercepts: when A = 0, what is x?
A = - 3XA = - 3X22 + + 66X66X
A = - 3XA = - 3X22 + + 66X66X
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Lecture 32Lecture 32 8989
Graph:Graph:
x-Intercepts: when A = 0, what is x?x-Intercepts: when A = 0, what is x?
A = - 3XA = - 3X22 + + 66X66X
A = - 3XA = - 3X22 + + 66X66X
0 = - 3X0 = - 3X22 + + 66X66X
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Lecture 32Lecture 32 9090
Graph:Graph:
x-Intercepts: when A = 0, what is x?x-Intercepts: when A = 0, what is x?
A = - 3XA = - 3X22 + + 66X66X
A = - 3XA = - 3X22 + + 66X66X
0 = - 3X0 = - 3X22 + + 66X66X
0 = - 3X(X - 22)0 = - 3X(X - 22)
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Lecture 32Lecture 32 9191
Graph:Graph:
x-Intercepts: when A = 0, what is x?x-Intercepts: when A = 0, what is x?
A = - 3XA = - 3X22 + + 66X66X
A = - 3XA = - 3X22 + + 66X66X
0 = - 3X0 = - 3X22 + + 66X66X
0 = - 3X(X - 22)0 = - 3X(X - 22)
0 = - 3X or0 = - 3X or
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Lecture 32Lecture 32 9292
Graph:Graph:
x-Intercepts: when A = 0, what is x?x-Intercepts: when A = 0, what is x?
A = - 3XA = - 3X22 + + 66X66X
A = - 3XA = - 3X22 + + 66X66X
0 = - 3X0 = - 3X22 + + 66X66X
0 = - 3X(X - 22)0 = - 3X(X - 22)
0 = - 3X or0 = - 3X or 0 = (X - 22)0 = (X - 22)
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Lecture 32Lecture 32 9393
Graph:Graph:
x-Intercepts: when A = 0, what is x?x-Intercepts: when A = 0, what is x?
A = - 3XA = - 3X22 + + 66X66X
A = - 3XA = - 3X22 + + 66X66X
0 = - 3X0 = - 3X22 + + 66X66X
0 = - 3X(X - 22)0 = - 3X(X - 22)
0 = - 3X or0 = - 3X or 0 = (X - 22)0 = (X - 22)
0 = X or X = 220 = X or X = 22
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Lecture 32Lecture 32 9494
Graph:Graph:
A-Intercept: when x = 0, what is A?A-Intercept: when x = 0, what is A?
A = - 3XA = - 3X22 + + 66X66X
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Lecture 32Lecture 32 9595
Graph:Graph:
A-Intercept: when x = 0, what is A?A-Intercept: when x = 0, what is A?
A = - 3XA = - 3X22 + + 66X66X
A = - 3XA = - 3X22 + + 66X66X
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Lecture 32Lecture 32 9696
Graph:Graph:
A-Intercept: when x = 0, what is A?A-Intercept: when x = 0, what is A?
A = A = – 3– 3(0)(0)2 2 + + 6666 (0) (0)
A = - 3XA = - 3X22 + + 66X66X
A = - 3XA = - 3X22 + + 66X66X
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Lecture 32Lecture 32 9797
Graph:Graph:
A-Intercept: when x = 0, what is A?A-Intercept: when x = 0, what is A?
A = A = – 3– 3(0)(0)2 2 + + 6666 (0) (0)
A = A = 0 sq. feet0 sq. feet
A = - 3XA = - 3X22 + + 66X66X
A = - 3XA = - 3X22 + + 66X66X
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Lecture 32Lecture 32 9898
Graph:Graph:
1.1. Because a = -3, parabola opens downBecause a = -3, parabola opens down
2.2. Vertex: (Vertex: ( 11, 363)11, 363) 3.3. x-Intercepts: (0, 0) and (22, 0)x-Intercepts: (0, 0) and (22, 0)
4.4. A-Intercept: (0, 0)A-Intercept: (0, 0)
A = - 3XA = - 3X22 + + 66X66X
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Lecture 32Lecture 32 9999
3 6 9 12 15 18
250
200
300
100
50
(11,363)
Graph:Graph:
150
Width (feet)
Area (sq. feet)
A = - 3XA = - 3X22 + + 66X66X
21
350
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Lecture 32Lecture 32 100100
3 6 9 12 15 18
250
200
300
100
50
(11,363)
(22,0)(0,0)
Graph:Graph:
150
Width (feet)
Area (sq. feet)
A = - 3XA = - 3X22 + + 66X66X
21
350
![Page 101: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/101.jpg)
Lecture 32Lecture 32 101101
3 6 9 12 15 18
250
200
300
100
50
(11,363)
(22,0)(0,0)
Graph:Graph:
150
Width (feet)
Area (sq. feet)
A = - 3XA = - 3X22 + + 66X66X
21
350
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Lecture 32Lecture 32 102102
3 6 9 12 15 18
250
200
300
100
50
(11,363)
(22,0)(0,0)
Graph:Graph:
150
Width (feet)
Area (sq. feet)
A = - 3XA = - 3X22 + + 66X66X
21
350
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Lecture 32Lecture 32 103103
Find the dimensions of the coop if the area can Find the dimensions of the coop if the area can only be 360 sq feet.only be 360 sq feet.
When A = 360, what is x?When A = 360, what is x?
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Lecture 32Lecture 32 104104
Find the dimensions of the coop if the area can Find the dimensions of the coop if the area can only be 360 sq feet.only be 360 sq feet.
When A = 360, what is x?When A = 360, what is x?A = - 3XA = - 3X22 + + 66X66X
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Lecture 32Lecture 32 105105
Find the dimensions of the coop if the area can Find the dimensions of the coop if the area can only be 360 sq feet.only be 360 sq feet.
When A = 360, what is x?When A = 360, what is x?A = - 3XA = - 3X22 + + 66X66X
360 = - 3X360 = - 3X22 + + 66X66X
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Lecture 32Lecture 32 106106
Find the dimensions of the coop if the area can Find the dimensions of the coop if the area can only be 360 sq feet.only be 360 sq feet.
When A = 360, what is x?When A = 360, what is x?A = - 3XA = - 3X22 + + 66X66X
360 = - 3X360 = - 3X22 + + 66X66XSubtract 360 from Subtract 360 from both sidesboth sides
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Lecture 32Lecture 32 107107
Find the dimensions of the coop if the area can Find the dimensions of the coop if the area can only be 360 sq feet.only be 360 sq feet.
When A = 360, what is x?When A = 360, what is x?A = - 3XA = - 3X22 + + 66X66X
360 = - 3X360 = - 3X22 + + 66X66XSubtract 360 from Subtract 360 from both sidesboth sides
0 = - 3X0 = - 3X22 + + 66X - 36066X - 360
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Lecture 32Lecture 32 108108
Find the dimensions of the coop if the area can Find the dimensions of the coop if the area can only be 360 sq feet.only be 360 sq feet.
When A = 360, what is x?When A = 360, what is x?A = - 3XA = - 3X22 + + 66X66X
360 = - 3X360 = - 3X22 + + 66X66XSubtract 360 from Subtract 360 from both sidesboth sides
0 = - 3X0 = - 3X22 + + 66X - 36066X - 360
0 = - 3(X0 = - 3(X22 –– 22X + 120)22X + 120)
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Lecture 32Lecture 32 109109
Find the dimensions of the coop if the area can Find the dimensions of the coop if the area can only be 360 sq feet.only be 360 sq feet.
When A = 360, what is x?When A = 360, what is x?A = - 3XA = - 3X22 + + 66X66X
360 = - 3X360 = - 3X22 + + 66X66XSubtract 360 from Subtract 360 from both sidesboth sides
0 = - 3X0 = - 3X22 + + 66X - 36066X - 360
0 = - 3(X0 = - 3(X22 –– 22X + 120)22X + 120)0 = - 3(X0 = - 3(X –– 10)(X – 12)10)(X – 12)
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Lecture 32Lecture 32 110110
Find the dimensions of the coop if the area can Find the dimensions of the coop if the area can only be 360 sq feet.only be 360 sq feet.
When A = 360, what is x?When A = 360, what is x?A = - 3XA = - 3X22 + + 66X66X
360 = - 3X360 = - 3X22 + + 66X66X
0 = (X - 10) or0 = (X - 10) or
Subtract 360 from Subtract 360 from both sidesboth sides
0 = - 3X0 = - 3X22 + + 66X - 36066X - 360
0 = - 3(X0 = - 3(X22 –– 22X + 120)22X + 120)0 = - 3(X0 = - 3(X –– 10)(X – 12)10)(X – 12)
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Lecture 32Lecture 32 111111
Find the dimensions of the coop if the area can Find the dimensions of the coop if the area can only be 360 sq feet.only be 360 sq feet.
When A = 360, what is x?When A = 360, what is x?A = - 3XA = - 3X22 + + 66X66X
360 = - 3X360 = - 3X22 + + 66X66X
0 = (X - 10) or0 = (X - 10) or 0 = (X - 12)0 = (X - 12)
Subtract 360 from Subtract 360 from both sidesboth sides
0 = - 3X0 = - 3X22 + + 66X - 36066X - 360
0 = - 3(X0 = - 3(X22 –– 22X + 120)22X + 120)0 = - 3(X0 = - 3(X –– 10)(X – 12)10)(X – 12)
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Lecture 32Lecture 32 112112
Find the dimensions of the coop if the area can Find the dimensions of the coop if the area can only be 360 sq feet.only be 360 sq feet.
When A = 360, what is x?When A = 360, what is x?A = - 3XA = - 3X22 + + 66X66X
360 = - 3X360 = - 3X22 + + 66X66X
0 = (X - 10) or0 = (X - 10) or 0 = (X - 12)0 = (X - 12)
X =10 or X = 12X =10 or X = 12
Subtract 360 from Subtract 360 from both sidesboth sides
0 = - 3X0 = - 3X22 + + 66X - 36066X - 360
0 = - 3(X0 = - 3(X22 –– 22X + 120)22X + 120)0 = - 3(X0 = - 3(X –– 10)(X – 12)10)(X – 12)
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Lecture 32Lecture 32 113113
3 6 9 12 15 18
250
200
300
100
50(22,0)(0,0)
Graph:Graph:
150
Width (feet)
Area (sq. feet)
A = - 3XA = - 3X22 + + 66X66X
21
350
(11,363)
![Page 114: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/114.jpg)
Lecture 32Lecture 32 114114
3 6 9 12 15 18
250
200
300
100
50
(12,360)
(22,0)(0,0)
Graph:Graph:
150
Width (feet)
Area (sq. feet)
A = - 3XA = - 3X22 + + 66X66X
21
350
(11,363)
(10,360)
![Page 115: Lecture 321 Unit 4 Lecture 32 Quadratics Applications & Their Graphs.](https://reader036.fdocuments.net/reader036/viewer/2022062321/56649ee85503460f94bf95cb/html5/thumbnails/115.jpg)
Lecture 32Lecture 32 115115
3 6 9 12 15 18
250
200
300
100
50
(12,360)
(22,0)(0,0)
Graph:Graph:
150
Width (feet)
Area (sq. feet)
A = - 3XA = - 3X22 + + 66X66X
21
350
(11,363)
(10,360)
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Lecture 32Lecture 32 116116
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Lecture 32Lecture 32 117117
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Lecture 32Lecture 32 118118
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Lecture 32Lecture 32 119119
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Lecture 32Lecture 32 120120
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Lecture 32Lecture 32 121121