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  • Lecture 3

    Activated sludge and lagoons

  • ACTIVATED SLUDGE PROCESS

    Activated sludge process is used during secondary treatment of wastewater. Activated

    sludge is a mixture of bacteria, fungi, protozoa and rotifers maintained in suspension by aeration

    and mixing [1].

    In this process, a biomass of aerobic organisms is grown in large aerated basins. These

    organisms breakdown the waste and use it as their food to grow themselves.

    Activated sludge processes return settled sludge to the aeration basins in order to

    maintain the right amount of organisms to handle the incoming "food".

    Activated sludge processes have removal efficiencies in the range (95-98%) than

    trickling filters (80-85%). [2]

    WORKING OF ACTIVATED SLUDGE SYSTEM [3]

    A primary settler (or primary clarifier) may be introduced to remove part of the suspended solids present in the influent and this reduces the organic load to the activated

    sludge system.

    The biological reactor or aeration tank is filled with a mixture of activated sludge and influent, known as mixed liquor. It is necessary to maintain certain mixed liquor

    suspended solid (MLSS) in the aerated tank maintain good removal efficiency.

    The aeration equipment transfers the oxygen necessary for the oxidation of organic material into the reactor, while simultaneously introducing enough turbulence to keep the

    sludge flocs in suspension.

    The continuous introduction of new influent results in a continuous discharge of mixed liquor to the secondary settler where separation of solids and liquid takes place.

    The liquid leaves the system as treated effluent, whereas some part of the sludge is recirculated to the aeration tank called as return sludge and rest of sludge is taken for

    anaerobic digestion.

    DESIGNING OF ACTIVATED SLUDGE SYSTEM

    Suppose, Q is the flow rate of influent (m3/d), QW is the flow rate of waste sludge (m3/d),

    Qr is the flow rate of return activated sludge (m3/d), V is the volume of aeration tank (m3), S0 is

    the influent soluble substrate concentration (BOD g/m3), S is the effluent soluble substrate

    concentration (BOD g/m3), Xo is the concentration of biomass in influent (g VSS/m3), XR is the

    concentration of biomass in return line from clarifier (g VSS/m3), Xr is the concentration of

  • biomass

    VSS/m3)

    (a) E

    (b) M

    F

    R

    X

    X

    Q

    in sludge d

    [4]. VSS sta

    Equations us

    Mass balanc

    or Xe =0

    Recycle ratio

    CW r

    VXQ X

    0C

    QY S1VX

    rQQX

    rX Q Q r

    r

    QX QQX

    drain (g VS

    ands for vola

    Figu

    sed for desig

    e around cl

    =

    0d

    Sk

    X

    eW XQQ

    r WQ Q X W rQ XX

    QQr

    SS/m3) and

    atile suspend

    ure 4.3.1. Ac

    gn of aerati

    arifier

    rWe QQX

    rX

    Xe is the c

    ded solids.

    ctivated slu

    ion tank

    rr XQ

    concentration

    udge process

    n of biomas

    s

    ss in efflueent (g

  • Problem 4.3.1: An activated-sludge system is to be used for secondary treatment of 15,000 m3/d

    of municipal wastewater. After primary clarification, the BOD is 170 mg/L, and it is desired to

    have not more than 25 mg/L of soluble BOD in the effluent. A completely mixed reactor is to be

    used, and pilot-plant analysis has established the following values: hydraulic detention time

    ( )=10 d yield coefficient (Y)=0.5 kg/kg, kd=0.05 d-1. Assuming an MLSS concentration of

    4500 mg/L and an underflow concentration of 12,000 mg/L from the secondary clarifier,

    determine (1) the volume of the reactor, (2) the mass and volume of solids that must be wasted

    each day, and (3) the recycle ratio.

    Solution: Given that Q=10,000 m3/d, =10 d

    Using

    V=1611 m3

    Using =10

    If the concentration of solids in the underflow is 12,000 mg/L

    For Xe =0

    C

    C

    0d

    C

    QY S S1 kVX

    3 3 31 -1

    3

    15,000 m /d 0.17 kg/m 0.025 kg/m0.1 0.05 d

    4.5 kg/m d V

    CW r

    VXQ X

    W rQ X =724.95 kg/d

    33

    724.95 kg/d 60.41 m /d12 kg/m

    WQ

    3 33

    3 3

    15,000 m / 4.5 kg/m 724.95 kg/d 8903.34 m /d12 kg/m 4.5 kg/m

    W rr

    r

    QX Q X dQX X

    rQ 8903.34Recycle ratio 0.59Q 15,000

  • PONDS AND LAGOONS

    Other than activated sludge processes, ponds and lagoons are most common suspended-

    culture biological systems used for the treatment of wastewater.

    A wastewater pond, alternatively known as a stabilization pond, oxidation pond, and

    sewage lagoon, consists of a large, shallow earthen basin in which wastewater is retained long

    enough for natural purification processes.

    Classification of lagoons is based on degree of mechanical mixing provided.

    Aerobic lagoon: The reactor is called an aerobic lagoon, when sufficient energy is supplied to

    keep the entire contents, including the sewage solids, mixed and aerated. To meet suspended-

    solids effluent standards, solids are removed from the effluent coming from an aerobic lagoon.

    Facultative lagoon: In facultative lagoon, only enough energy is supplied to mix the liquid

    portion of the lagoon, solids settle to the bottom in areas of low velocity gradients and proceed to

    degrade anaerobically and this process is different from facultative pond only in the method by

    which oxygen is supplied. Facultative lagoons are assumed to be completely mixed reactors

    without biomass recycle [5].

    Aerobic lagoons with solid recycle: The aerobic lagoon with solids recycle is same as extended

    aeration activated-sludge process, but an earthen (typically lined) basin is used in place of a

    reinforced-concrete reactor basin. It is necessary that the aeration requirement for an aerobic

    lagoon with recycle must be higher than the values for an aerobic flow-through lagoon to

    maintain the solids in suspension.

    DESIGN OF LAGOONS

    Process design considerations for flow-through lagoons [6]

    BOD removal Effluent characteristics Temperature effect Oxygen requirement Energy requirement for mixing Solids separation

  • AB

    W

    =hydrauIf

    the next.

    A

    relating t

    significan

    W

    coefficien

    Problem

    and 6600

    the avera

    Q

    SS

    SS

    k

    Applying ma

    BODin = BOD

    Where, S/S0=

    ulic detentio

    f several rea

    A substrate

    A wide rang

    to both the re

    ntly. k value

    Where, k20 =

    nt ranges fro

    m 4.3.2: Was

    0 m3/d durin

    age tempera

    0QS QS V

    0S 1S 1 k V

    n0S 1 S 1 k

    T-20T 20k k

    ss balance o

    Dout + BODco

    =fraction o

    n time (d-1),

    ctors are arr

    balance wri

    ge of values

    eactor and w

    e at any temp

    reaction rat

    om 1.03 to 1

    tewater flow

    ng the summ

    ature of the w

    V kS

    1V Q 1 k

    n1

    n

    0

    n lagoon giv

    onsumed

    f soluble B

    V= reactor

    ranged in ser

    itten across a

    for k is av

    wastewater af

    perature can

    te constant a

    .12.

    w from a sma

    mer. The ave

    warmest mo

    ven in above

    BOD remain

    volume (m3)

    ries, the efflu

    a series of n

    vailable in t

    ffect the valu

    be find out b

    at 20C (ran

    all communi

    erage temper

    onth is 30C

    e figure

    ning, k=rea

    ), and Q= flo

    uent of one p

    reactors resu

    the literatur

    ue of k, wate

    by following

    nges from 0.

    ity averages

    rature of the

    C. The avera

    action rate

    ow rate (m3/

    pond becom

    ults in follow

    re. Although

    er temperatu

    g equation:

    .2 to1.0) and

    3400 m3/d

    e coldest mo

    age BOD5 is

    coefficient

    /d).

    mes the influe

    wing equatio

    h many vari

    ure affects it

    d =temper

    during the w

    onth is 10C

    s 200 mg/L

    (d-1),

    ent to

    on:

    iables

    most

    rature

    winter

    C, and

    with

  • 70% being soluble. The reaction coefficient k is 0.23 d-1 at 20C, and the value of temperature

    coefficient is 1.06. Prepare a preliminary design for a facultative pond treatment system for the

    community to remove 90% of the soluble BOD.

    a) Find volume of facultative lagoon to remove 90% of the soluble of BOD.

    b) Find the dimensions of three square lagoons in series with depth 1.5 m.

    Solution:

    (a) Estimation of rate constants at given temperature

    Summer: 30 20 -125 0.23 1.06 0.411 d k Winter: 10 20 -110k 0.23 1.06 0.128 d (b) Estimation of volume of lagoon

    Summer: 0S 1 20 1 VS 200V 1 0.4111 k 6600Q V=144525.5 m3

    Winter: 20 1 V200 1 0.128 3400 V=239062 m3

    (c) Estimation of dimensions of three square lagoons in series

    Q, S0 Q,S1 Q,S2 Q,S3

    n

    QnVk1

    1 SS

    i0

    n

    :Summer 3

    i0.411 V200 120 3 6600

    355607.13 miV

    Winter: 30.128200 1

    20 3 3400

    iV

    3iV 91980.8 m

    Vi 1

    Vi 2

    Vi3

  • REFERENCES

    [1] http://dnr.wi.gov/org/es/science/opcert/doc/Activated_Sludge_intro.pdf

    [2] http://www.ragsdaleandassociates.com/WastewaterSystemOperatorsManual/Chapter%20

    8%20-%20Activated%20Sludge.pdf

    [3] http://www.wastewaterhandbook.com/documents/11_introduction.pdf

    [4] http://www.lenntech.com/wwtp/wwtp-activated-sludge-process.htm

    [5] Peavy, H. S., Rowe, D. R., Tchobanoglous, G. Environmental Engineering, McGraw-Hill,

    1985.

    [6] Tchobanoglous, G., burton, F. L., stensel, H.D. Wastewater Engineering: Treatment and

    Reuse-Metcalf&Eddy, Inc., Tata McGraw-Hill, 2003.