Lecture 25 - Department of Physics &...
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Transcript of Lecture 25 - Department of Physics &...
Lecture 25
Thermodynamics
Today’s Topics:
• 0th and 1st and Laws of Thermodynamics• Thermal Processes and Ideal Gases• Heat Capacities
Thermodynamic Systems
Thermodynamics is the branch of physics that is built upon the fundamental laws that heat and work obey.
The collection of objects on which attention is being focused is called the system, while everything elsein the environment is called the surroundings.
Walls that permit heat flow are called diathermal walls,while walls that do not permit heat flow are calledadiabatic walls.
To understand thermodynamics, it is necessary to describe the state of a system.
The 0th LawTwo systems are said to be in thermal equilibrium if there is no heat flowbetween them when they are brought into contact.
Temperature is the indicator of thermal equilibrium in the sense that there is nonet flow of heat between two systems in thermal contact that have the sametemperature.
THE ZEROTH LAW OF THERMODYNAMICS
Two systems individually in thermal equilibriumwith a third system are in thermal equilibriumwith each other.
The 1st Law – Energy Conservation
Suppose that a system gains heat Q and that is the only effect occurring.
Consistent with the law of conservation of energy, the internal energy of the system changes:
QUUU if =-=D
Q > 0,when the system gains heat and Q < 0,when the system loses heat.
If a system does work Won its surroundings and there is no heat flow, conservation of energy indicates that the internal energy of the system will decrease:
WUUU if -=-=D
W > 0, when done by the systemand W < 0, when done on the system.
THE FIRST LAW OF THERMODYNAMICS
The internal energy of a system changes due to heat and work:
WQUUU if -=-=D
Work is positive when it is done by the system and negative when it is doneon the system.
Heat is positive when the system gains heat and negative when the systemloses heat.
Positive and Negative Work
In part a of the figure, the system gains 1500J of heatand 2200J of work is done by the system on its surroundings.
In part b, the system also gains 1500J of heat, but2200J of work is done on the system.
In each case, determine the change in internal energyof the system.
(a)
( ) ( ) J J J 70022001500 -=+-+=-=D WQU
(b)
( ) ( ) J J J 370022001500 +=--+=-=D WQU
ExampleAn ideal gas absorbs 750 J of heat as it performs 625 J of work. What is the resulting change in temperature if there are 1.3 moles of an ideal gas in the system?
J 750+=Q
J 625+=W
Thermal Processes
A quasi-static process is one that occurs slowly enough that a uniformtemperature and pressure exist throughout all regions of the system at alltimes.
isobaric: constant pressure
isochoric: constant volume
isothermal: constant temperature
adiabatic: no transfer of heat
An isobaric process is one that occurs at constant pressure.
VPPAsFsW D===
W
An isochoric process is one that occurs at constant volume.
QWQU =-=D
0=W
Thermal processes using an ideal gasISOTHERMAL EXPANSION OR COMPRESSION
The hot water provides a reservoir of heat that maintains the cylinder at a constant temperature
As the force holding the piston is reduced, the gas expands from an initial volume Vi to a final volume Vf
ExampleA system containing an ideal gas at a constant pressure of 1.22 × 105 Pa gains 2140 J of heat. During the process, the internal energy of the system increases by 2320 J. What is the change in volume of the gas?
Pa 51022.1 ´=PJ 2140+=Q
J 2320+=DU
ExampleA fixed amount of ideal gas is compressed isothermally. Which entry in the table below correctly depicts the signs of the work done, the change in the internal energy, and the heat exchanged with the environment?
work done change in internal energy heat exchanged(a) negative zero negative(b) positive negative zero(c) negative zero positive(d) negative negative zero(e) positive zero positive
For an isothermal process:
Compression means work is done on gas:
Using the 1st Law:
Specific Heat CapacitiesTo relate heat and temperature change in solids and liquids, we used:
TmcQ D=
specific heatcapacity
The amount of a gas is conveniently expressed in moles, so we write thefollowing analogous expression:
TnCQ D=
molar specificheat capacity
For gases we distinguish between the molar specific heat capacities which apply to the conditions of constant pressure and constant volume:
PV CC ,
Why?
In a constant volume process, all of the heat added goes towards changing the temperature of the system.
In a constant pressure process, the heat added to the system increases the temperature and doing mechanical work.
( ) TnRTTnRWUQ if D=+-=+D= 23
23
olumeconstant v 0!"!#$
!!!! %!!!! &'First law ofthermodynamics
constant volumefor a monatomicideal gas
CV
CP
( ) ( ) TnRTTnRTTnRWUQ ifif D=-+-=+D= 25
23
pressureconstant !"!#$
!%!&'
!!!! "!!!! #$
First law ofthermodynamics
constant pressurefor a monatomicideal gas
For an Ideal Gas
Adiabaticexpansion orcompression ofa monatomicideal gas ( )fi TTnRW
WΔUQSince
-=-==
23
,0
Adiabaticexpansion orcompression ofa monatomicideal gas
ggffii VPVP =
VP cc=g
ADIABATIC EXPANSION OR COMPRESSION
DEMO: Adiabatic compression