Lecture 20 – Chapter 17, Sections 4-5 More weak acids and...

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Lecture 20 – Chapter 17, Sections 4-5 More weak acids and bases Identifying acids and bases • Conjugate acids and bases Salts of weak acids and bases

Transcript of Lecture 20 – Chapter 17, Sections 4-5 More weak acids and...

  • Lecture 20 – Chapter 17, Sections 4-5 More weak acids and bases

    • Identifying acids and bases

    • Conjugate acids and bases

    • Salts of weak acids and bases

  • Acids and Bases

    • Strong vs. Weak

    • Ka vs. Kb• pH = -log([H])

    • pH + pOH = 14

    • Conjugate acids and bases

    • Should be able to calculate pH (or pOH) of some solution given that you have some concentration of some weak acid.

  • Sulfuric acidH2SO4

    Perchloric acidHClO4

    Calcium hydroxideCa(OH)2Nitric acidHNO3

    Potassium hydroxideKOHHydroiodic acidHI

    Sodium hydroxideNaOHHydrobromic acidHBr

    Lithium hydroxideLiOHHydrochloric acidHCl

    Strong Bases (Strong Electrolytes)

    Strong Acids (Strong Electrolytes)

    Common Strong Acids & Strong Bases

    • Strong acids will donate a proton to water to form hydronium ion. The hydronium ion concentration will be equal to the acid concentration.

    • Strong bases will dissociate in solution to form hydroxide ion, the concentration of which can be calculated from the base’s molarity.

  • Recognizing Acids and Bases

    • Oxoacids– an acid that contains an inner atom bonded to some oxygen atoms and acidic OH groups.

    • HxEOy

    (Labels are reversed)

  • Carboxylic Acids

    • RCO2H

    • All carboxylic acids are weak acids.

  • Other Weak Acids

  • Polyprotic Acids

    Have multiple acidic protons (more later)

  • Identify the molecule as a strong acid, a weak acid, or neither

    Cl3CCO2H

    54321

    33%33%33% 1. Strong acid

    2. Weak acid

    3. Neither

  • Identify the molecule as a strong acid, a weak acid, or neither

    CH3CH2CH2OH

    54321

    33%33%33% 1. Strong acid

    2. Weak acid

    3. Neither

  • Identify the molecule as a strong acid, a weak acid, or neither

    HCN

    54321

    33%33%33% 1. Strong acid

    2. Weak acid

    3. Neither

  • Identify the molecule as a strong acid, a weak acid, or neither

    HClO4

    54321

    33%33%33% 1. Strong acid

    2. Weak acid

    3. Neither

  • Weak Bases

    • Water is a weak base

    • Another common weak base is NH3• Many other weak bases are derivatives of ammonia called

    amines. (Hey, we’ve seen them before!)

    • Some of the N – H bonds have been replaced with C –H bonds.

  • Representative Organic Bases

  • Conjugate Acid – Base Pairs

    • An aciddonates an H+ when in water. The resulting species could accept an H+ from water to yield hydroxide.

    – That resulting species is the conjugate baseof the original acid

    HA + H2O � A– + H3O+

    acid conj. base

    A– + H2O � HA + OH–

  • HF is a weak acid. What is its conjugate base?

    54321

    20%20%20%20%20% 1. OH –

    2. H3O +

    3. H2O

    4. F –

    5. H2F +

  • Is NaF an acid or a base?

    • Neither at first glance

    • But notice that in aqueous solution two ions are formed

    Na+ and F –

    • Since F – is a base (the conjugate base of HF) NaF must act as a base.

    NaF(s) + H2O � Na+(aq) + F –(aq)F –(aq) + H2O � HF(aq) + OH–(aq)

  • What about Na+

    • NaOH is a base, so Na+ must be a conjugate acid

    Na+(aq) + 2H2O � NaOH(aq) + H3O+(aq)

    • Why doesn’t this matter?

    • Because NaOH is a strong base, Na+ is essentially not acidic at all

    • F – acts as a base because HF is a weak acid

  • Ka and Kb are related

    • Note the two equilibria related to hydrofluoric acid

    HF(aq) + H2O � F –(aq) + H3O+(aq)

    F –(aq) + H2O � HF(aq) + OH–(aq)

    [ ][ ][ ]HF

    OHFKa

    +−

    = 3

    [ ][ ][ ]−

    =F

    OHHFKb

  • Ka and Kb are related (ii)

    • If we add these two equations…

    HF(aq) + H2O � F –(aq) + H3O+(aq)

    F –(aq) + H2O � HF(aq) + OH–(aq)

    2 H2O � OH –(aq) + H3O+(aq)

    • If we add equations, we multiply equilibrium constants

    [ ][ ][ ]

    [ ][ ][ ] [ ][ ] wba KOHOHF

    OHHF

    HF

    OHFKK === −+−

    −+−

    33

  • Ka and Kb are related (iii)

    14ppp then

    If

    ==+

    =

    wba

    wba

    KKK

    KKK

    (for a conjugate acid-base pair)

  • Important points about Ka and Kb

    >1Strong< 10-16Very Weak

    < 10-16Very Weak>1Strong

    10-16 to 1

    Kb

    Weak

    Conjugate Base Strength

    10-16 to 1

    Ka

    Weak

    Acid Strength

    Of course, we could also have a similar table with Base Strength and Conjugate Acid Strength

  • Example: Bleach

    • The bleach we used for the kinetics demos was standard

    5 % NaOCl solution (aqueous) approx. 0.67 M

    • What are the concentrations of ALL species in this solution?

    – Identify all species

    – Recognize conjugate base and find Kb– Set up equilibrium table

    – Solve for species concentrations

  • Table 17-5 p.746

  • What makes an acid stronger or weaker?

    • Charge• Strength of X-H bond

    • Charge is pretty simple– Something positive is a good acid, lousy base– Something negative is a lousy acid, good base– Something neutral is somewhere between

  • Acid strength?

    • More polar bond � stronger acid

    – HF stronger acid than CH4• Weaker X-H bond � stronger acid

    – HCl stronger acid than HF

    – HClO4 stronger acid than HOCl

  • How acidic is the bold proton in oxalic acid compared to formic acid?

    54321

    33%33%33% 1. Oxalic is more acidic than formic

    2. Oxalic is less acidic than formic

    3. They are essentially the same

    FormicOxalic

  • How acidic is the second proton in oxalic acid compared to formic acid?

    54321

    33%33%33% 1. 2nd Oxalic proton is more acidic than formic acid

    2. 2nd Oxalic proton is less acidic than formic acid

    3. They are essentially the same

    Formic Oxalic

  • Polyprotic Acids form Multiple Equilibria

    • H2SO4 has two protons that can come off

    • Three species are all in equilibrium along with H3O+ and OH–

    – H2SO4– HSO4–

    – SO42–

    • Two pairs of conjugate acids and bases

    • See Example 17-14

    – Solve equilibrium problem for first proton

    – Plug answers in as starting point for second equilibrium problem

    – Continue if there are still more acidic protons

  • Today• Finish CAPA #12 (due tomorrow)

    Friday• Seminar (student-invited speaker)

    • We’ll finish up Chapt 17

    • It’s not too early to start thinking about exam 2…