Lecture 01 - Di Prisco
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Transcript of Lecture 01 - Di Prisco
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DESIGN OF ENVIRONMENTAL AND PROTECTIVE
STRUCTURES
Prof. Marco di PriscoDepartment of Civil and Environmental Engineering,
Politecnico di Milano
Master Course in
Civil Engineering for Risk Mitigation
Academic year 2014-2015
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Constitutive and design laws of steel , concrete, fibre
reinforced concrete employed in steel, reinforced -
prestressed concrete structures (4h)
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13 October 2014 3
Model Code: design for
sustainabilityConcrete’s Level I Method
Comparison of green house gas emission:
material substitution: BREAM (UK), HQE
(France), LEED (USA), CASBEE (Japan), GreenStar (Netherlands)
Level II Method
Environmental Impact Calculation (EIC):
- Measure of Embodied Energy
- Measure of CO2- Calculation of Global Warming Potential
(GWP)
-Level III Method
Full life cycle assessment (LCA), including
durability and maintenance considerations, recyle
and reuse
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13 October 2014 4
EIC: Environmental Impact
Calculation
- CO2 Emission
- EE = Embodied Energy
Energy consumed in the production of Portland Cement is estimated to be 4.88
MJ/kg and the total energy in the production of steel 23.7 MJ/kg
(Struble and Godfrey (2004)
- GWP = Global Warning PotentialContribution of CO2 on global warming, calculated through the equivalence of the
effect of greenhouse gas (Elrod, 1999):for simplicity:
100 – year GWP = CO2 + 298 Nox + 25CH4
Courtesy Joost Walraven
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by fib Bulletin 67
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STEEL
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von Mises - Huber yield criterion
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STEEL FOR METALLIC STRUCTURES
For design, the following nominal values can be adopted for the material properties:
Elastic modulus
Transverse elasticity modulus
Poisson ratio
Thermal expansion coifficient
(T< 100°C)
density
Steels for flat and hot-rolled long products
The possible supply conditions are related to the manufacturing process used:
crude steel rolling "as rolled“
steel rolling normalized
steel thermomechanical rolling
steel with improved atmospheric corrosion resistance (ex Corten)
steel with high tensile strength reclaimed "Quench and tempered"
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Nominal thickness of the elementSteel standards
Hot rolled with open cross section profiles
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Hot rolled with hollow section profiles
Nominal thickness of the elementSteel standards
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P
δδy δu
µδ = δu / δy
Homogeneous
steel bar (Φ)
δ
P
σσσσ
εεεεεuεy
µε = εu / εy
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P
δ
Steel bar
δ
P
δy δu
µ = δu / δy
defect
σσσσ
εεεεεuεy
µε = εu / εy
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Steel for High Bond bars
s
sd yd
E
f =ε
L
susd ε ε
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B450C
Characteristic yielding strength
Characteristic failure strength
Characteristics Requirementsfractile
Max. elongation
Mandrel diameter for bend tests at 90° and
subsequent straightening without cracks
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B450A
Characteristics Requirements
fractile
Characteristic yielding strength
Characteristic failure strength
Max. elongation
Mandrel diameter for bend tests at 90° and
subsequent straightening without cracks
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Limits of acceptability
Nominal diameter
Tolerance % on cross section
admitted for the use
characteristic Limit value
for steel
minimum
maximum
minimum
minimumfailure/yielding
failure/yielding
bending / straightening lack of cracks for all
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(*)
(*) after the 90 ° bend keeps the bar for 30 minutes in boiling water and proceeding, after cooling in air,to the partial straightening for at least 20 °. After the test the specimen shall not exhibit cracks.
In Model Code 2010 :
duttilità mediante prova di piegamento
mandrino
Φ!mm" #eB$%k #eB&&k
≤ 12
12'1%
1%'2(
2( ' $0
$Φ
)Φ
%Φ
10Φ
&Φ
%Φ
10Φ
12Φ
*iegamento a 1%0+
*iegamento e raddri,,amento
a -0+ a./20+±(+
ductility measure by bending test
bending and straightening
mandrel
Bending at 180°
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steel in bars steel in roll
load load
displacement displacement
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CEB MC’90
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Prestressing steel
D.M. 2008 εuk ≥ 3.5% (MC90)
Control in plant
sn ≤ 0.03 f ptk e sn ≤ 0.04 f p..k
Control on site
at failure (f pt) gmn ≥ 1.03 f ptk ; sn ≤ 0.05 f ptk
at serv.ice (f py f p(0.2) f p1) gmn ≥ 1.04 f p..k ; sn ≤ 0.07 f p..k
Ep = 195 - 205 MPa
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REINFORCEDCONCRETE
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The uniaxial compression test
UNI EN12390-1
UNI EN12390-3:
• planarity error< 0.0006d mm
• size tolerance < ± 0.5%• tolerance shaven face and opposite < 1%d
• perpendicularity corners < 0.5mm
• tests at 24,72h;7,14,28,90,180,365d
• (tests for at least 48h in room at 20 ± 2 °C eRH 95% until 2h before)
• 0.2 < dσ /dt < 1MPa/s
max-. aggregate size (mm)
specimen side (mm)
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Cubic compression test
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YES
NO
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Resistance classes for normal concrete
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Conversion factors of compressive strengths for cubes
Conversion factors of compressive strengths for cylinders
For different slenderness h/d
Strength indexes
and cylinders
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Conversion factors for compressive strengths
measured on cubes of different sizes
Conversion factors for compressive strengths
measured on cylinders of different sizes and equal
slenderness h/d = 2.00
side
slenderness h/d
Proposed
index
Proposed
Index h/d
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Sargin urve
1
2
11
1
)2(1
)(
)(
1,1
c
cccc
c
k
k
f
fc
E k
ε
ε
ε ε
ε ε
ε σ
ε
−+
−⋅−=
−
⋅⋅=
y ax bx cx d
CC
x y
x y E
x y fc
x y
fc E fc E E
c
c
c
c c c c
= + + +
= =
= =
= =
= =
= + + −
− +
3 2
1
1
1
3
1
2
3
1
2
1
2
0 0
0
0
2 3 2
:'
'
( ) ( ) ( )
ε
ε
σ ε ε ε
ε ε ε
ε ε
Saen, urve
l d l f C
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niaial onstitutive model for Conrete
ε
σ
εcu1.5‰
ε
σ
εcu0.7‰
ε
σ
f c1
εcuεc1
arc
tg(1000f cd)
εc1=.002εcu=.0035f c1 = 0.85 f cd =
0.85f ck / γ c
Stress-strain relation for short-term loading – compression -
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Parameters of the strain relation:
( )
2
1 2
c
c
k
f k
σ η η
η
⋅ −= −
+ − ⋅ c c ,lim
ε ε <
1
cε η ε
=
with:
Stress-strain relation for short-term loading – compression -
MC2010
Bilinear stress-crack opening relation for short-term loading
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Bilinear stress crack opening relation for short term loading
1
1 0 80
= ⋅ − ⋅ ct ctm
w f .
wσ
1
0 25 0 05
= ⋅ − ⋅
ct ctm
w f . .
wσ
1 for w w≤
1 c for w w w< ≤
1
1 0 85
= ⋅ − ⋅
ct ctm
w f .
wσ
( )1
0 15= −
−ctm
ct c
c
. f w w
w wσ
1 for w w≤
1 c for w w w< ≤
= F c F
ctm
Gw
f α
1 2 0 15= −
F
cctm
G
w . w f ( )=
F max
f d α
Dependency on maximum aggregate size is not
significant
5= ⋅
F
cctm
G
w f 1 =
F
ctm
G
w f
MC 2010MC 90
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Kupfer et al.
1969
Biaxial failure domain for concrete
Strength under multiaxial states of stress
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g
no continuous transition
between triaxial and
biaxial states of stress
triaxial criteria does not
exactly describe the
uniaxial compressive
strength
Inconsistencies in MC 90:
New in MC 2010:
One failure
criteria for all
states of stress-1,6
-1,4
-1,2
-1,0
-0,8
-0,6
-0,4
-0,2
0,0
0,2
-1,6 -1,4 -1,2 -1,0 -0,8 -0,6 -0,4 -0,2 0,0 0,2
MC 90
C12
C20
C30
C40
C50C60
C70
C80
C90
C100
C110
C120
σ 2 f /f cm
σ 3 f /f cm
σ 3 f /f cm
σ 2 f /f cm
σ 1 f /f cm
σ 1 f /f cm
σ 1 f /f cm
σ 3 f /f cm
with f cm > 0 and
f cm = f ck + 8 N/mm²
triaxial criteria forbiaxial states of stress
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Nelissen, 1972
σ2 J2J33
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θθ = 60
θ = 0
modello a 5 parametri (Willam-Warnke,1975)
σ1
σ3
σ2P(σ1,σ2,σ3)
asse idrostatiooct3τ
oct3σ
( ) ( ) ( )[ ]2132
32
2
212oct
9
1J
3
2σ−σ+σ−σ+σ−σ==τ
σ+σ+σ==σ
3I
3
1 3211oct
rξ 2321
3
oct
3
2 / 3
2
3
J322cos
J2
J
J
2
333cos
σ−σ−σ=θ
τ==θ
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#I*3C4B
Bull5206
7oal strength
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Conr5
7oal strength
steel
ck ck
cd
ck 1
0
ck
cd
f
40
3
5.12
f
f
40
A
A
3
7.0
f
=σ
=σ
splittingA0 /A1≤ 320
A0 /A1≥ 320spalling
σu /f
c
γ m
splitting
spalling
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oppure
• In columns with steel liners [O.3274; 11.3.4.2] or in the main
columns [EC8; 5.4.3.2.2. (7)] the action of confinement onconcrete can be considered:
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8hih strength9
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Material strength potential strength / ompressive strength of onretefrom ubes or ;linders made and matured in thelaborator; aording to standard onditions !
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>ualit; variation due to: omponent materials
related mi design
environment onditions !thermo'higrometrial"
oasional ad?ustements !plant manteinane"
ast eeution !ompation= uring"
normal !or @aussian" log'normal
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5% 5%
x
0.05
0.95F(x)
f(x)
x1
x'k
k's k''s
x''k
0.50
x0
5% 5%
x
0.05
0.50
0.95F(x)
f(x)
x = x01x'k
ks ks
x''k
f (x) = 2
2
2s
)x-(x-
esπ 2
1
'kx = x – ks per F('kx ) = 0,05
"kx = x – ks per F("kx ) = 0.95
con k = 1,645 .
! " g
'kx = x – k's per F(
'kx ) = 0,05
"kx = x + k''s per F(
"kx ) = 0,95
δ = 0,05 k' = 1,578 k'' = 1,713 δ = 0,10 k' = 1,513 k'' = 1,783 δ = 0,15 k' = 1,450 k'' = 1,854
( )2s2
2
ex2
1)x(f
ξ−ξ−
σπ=
( )( )2f
xln
ξ−ξξ=σ
=ξ
∫
Aeliabilit; inde
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x
f(x)MODELLOANALITIC
xx'k
k's
MODELLO
AFFIDABILE
CODA DA
TRONCARE
VALORI
IMPOSSIBILI
SENZA SIGNIFICATO
FISICO
RANGO DEI VALORI POSSIBILI
βs
x'0
PROBABILITA'
FORMALE
Aeliabilit; inde
c1 =c
c
δ β
δ
β -1
k'-1
s-x
sk'-x
x
x
'
0
'
k ==
CONTROLLO DELLA PRODUZIONE CO NTINUA TIVA DEL CALCESTRUZZO (MOD. UNI 10025/98)
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CLASSE C55 MISCELA R2 LINEA:Planar STABILIMENTO: Larco Astori - Carvico (BG)
CEMENTO: TIPO I 52.5 R DOSE: 400 kg A/C = 0.45 SUPERFL. 3% INERTI ≤ 15 mm
MATURAZIONE: Forzata a vapore β = 0,08 anno : 97 mese : novembre
Data Data RESISTENZE PROVA UNIFORMAZ. VALORI VALORI LOTTO MOBILE (21gg)
Prelievo Prova R1 R2 fj= 0.83Rm ETA' g fj/f f n f m s f k
1
2
3 01.12 75,9 76,5 63,2 28 1 63,2 17 64,1 1,74 61,5
4 02.12 78,9 79,2 65,6 28 1 65,6 17 64,2 1,78 61,6
5 03.12 79,2 78,4 65,4 28 1 65,4 17 64,3 1,79 61,7
6 04.12 77,6 79,1 65,0 28 1 65,0 17 64,4 1,79 61,7
7 05.12 81,3 79,3 66,6 28 1 66,6 17 64,6 1,86 61,8
8 06.12 80,2 81,3 67,0 28 1 67,0 17 64,9 1,89 62,1
9
10 09.12 77,1 78,8 64,7 29 1,001 64,6 17 65,0 1,87 62,2
11 09.12 80,2 78,2 65,7 28 1 65,7 17 65,2 1,83 62,5
12 10.12 79,2 77,6 65,1 28 1 65,1 17 65,1 1,75 62,6
13 11.12 80,2 80,4 66,6 28 1 66,6 17 65,2 1,77 62,6
14 12.12 81,2 80,4 67,1 28 1 67,1 17 65,4 1,80 62,7
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PRESTRESSED
CONCRETE
Prestressed concrete
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constRHconstT ==compatibility
ε
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)(
const RH ,const T
cr ,csh ,crel , p0 pel , pel ,c
rel , p0 pel , pcr ,csh ,cel ,c
0 p pc
ε ε ε ε ε ε
ε ε ε ε ε ε
ε ε ε
−−−−=
+−=−−
−=
i
red
p
c
red
p
red
p p p pcc
i
lossi p p pelc p p
c
ccc
i
lossi pelc p pelccc
el p p pelccc
p
A
pc
A
c
A
N N
N N N A A A
N A E A E E
E A
N A E A E N A E A E
N dAdA
pc
+−=
+−=+−=+
+−−=+
=−++=+
=+
∑
∑
∫∫
0
00
,0,
,0,,
,,
)(
)(
)(
σ
σ α σ
ε ε ε σ
ε ε ε ε ε ε
σ σ
equilibrium
εP
εP0
εc
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Fibre Reinforced Concrete
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Equivalent
diameter
[mm]
Minimum tensile strength
[N/mm2]
Alternated
bending test
R1 R2 R3 All theclass1) 2) 1) 2) 1) 2)
Rm Rp0,2 Rm Rp0,2 Rm Rp0,2 Rm Rp0,2 Rm Rp0,2 Rm Rp0,2 Not failure
0.15≤ d f <
0.50
400 320 480 400 800 720 1080 900 1700 1360 2040 1700
0.50≤ d f <
0.80
350 280 450 350 800 640 1040 800 1550 1240 2015 1550
0.80≤ d f ≤
1.20
300 240 390 300 700 560 910 700 1400 1120 1820 1400
1) For straight fibres
2) For shaped fibres
Table 2-1 – Resistance classes for steel fibres.
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CNR DT 204
30 mm
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1 4 0 °
30 mm.
2 . 0 m m
2.0 mm.
l / df = 48
0 , 6
2
fiber ontent (0kg3m$
F
lb= βl ≅ l/4
τα=τππ
α=τπ=f
f f bf 2
f
f bf
dlVld
dV4ldNF
F = Fy lf =lcr
5.0zoom w = 0.20 mm
TRA0 med
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0.00 0.10 0.20displacement w (mm)
0.0
1.0
2.0
3.0
4.0
a v e r a g e t e n s i o n σ t
( M P a
)
TRA4 med
TRA8 med
0.00 2.50 5.00deflection f (mm)
0.0
4.0
8.0
12.0
l o a d P
( K N )
zoomw = 5.00 mm
FLE0 med
FLE4 med
FLE8 med
60
Redundant structure behaviour
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P
[kN]
0 5 1 0
60
440
60
30
0
w [mm]
P
w
by di Prisco & Felicetti, 1997
Vf = 0.8 [%]
Vf = 0 [%]
Redundant structure behaviour
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0 5 10 15 20
displacement wt (mm)
0
10
20
30
40
load(kN)
sandrubber
0.4%
Vf = 0.8%
0.4%
0.8%
plain concrete
Pusplain
23.4 kN
by di Prisco & Felicetti, 2004
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P
P P
PPcr crP
crack formationcrack
crack formation
localization
Softening material Hardening material
δu
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Behavior in compression Behavior in compression Behavior in compression Behavior in compression
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EN 14651
Reference testReference testReference testReference test
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2
sp
j
,
2
3
hb
lF f j R =
hsp = 125 mm
b = 150 mm
S.L.E.
f R,1
f R,3
S.L.U.
Which difference with plain concrete ?Which difference with plain concrete ?Which difference with plain concrete ?Which difference with plain concrete ?
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slump flow diameter: 690 mm
T50 2 seccement 425: 472 kg fine sand 0/4 850kg
d 4/8 886 k
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ClassificationClassificationClassificationClassification
T50 2 sec
V-funnel time (0 min) 3.5 secV-funnel time (5 min) 4 sec
L-box (standard) h2/h1 = 1
fly ash: 45 kg
water 200 l (w/b =0.39)superplast. 1.3%
coarse sand 4/8 886 kg
hooked-end fibres 65/35 50 kg
4,33
4,47
3,77
σNf
Performance based designPerformance based designPerformance based designPerformance based design
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(5) Fibre reinforcement can substitute (also partially)conventional reinforcement at ultimate limit state if the
following relationships are fulfilled:
f R1k /f Lk > 0.4 Eq. 5.X2
f R3k /f R1k > 0.5 Eq. 5.X3
CMOD (mm)
f LK
0.5 2.50
f R1k f R3k
f gf gf gf g
Which models?Which models?Which models?Which models?
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f Ftu = f R3 /30)2.05.0( 13
3
≥+−−= R RFtsu
FtsFtu f f f CMOD
w f f
145.0 RFts f f =
σ σ
FromFromFromFrom σσσσ----w tow tow tow to σσσσ----εεεε 17/32
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ε = w / lcs σ
ε ε Fu ε ε Fu
f Fts
σ
incrudente
degradante
rigido-plastico f Ftu
f Ftu
f Ftu
f Ftu
Elastic-linear Rigid-plastic
wu
σ hardening
softening
w
f Fts
f Ftu
f Ftu
w
rigid-plastic f Ftu
f Ftu
wu
The characteristic structural lengthThe characteristic structural lengthThe characteristic structural lengthThe characteristic structural length
18/32
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lcs = min{srm, y},
srm is the average crack spacing
In sections without traditional reinforcement under
bending or under combined tensile – flexural andcompressive – flexural forces with resulting force external to
the section, y = h is assumed. The same assumption can be
taken for slabs.
Influenza orientamento fibre (by Ferrara et al. 2008)
Orientation factorOrientation factorOrientation factorOrientation factor
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b e a m .
1
b e a m .
2
b e a m .
$
50mm
150 mm150 mm150 mm 500 mm
beam 7$
beam 72
beam 71 1 5 0 m
m
1 5 0 m m
1 5 0 m m 5 0
m m
castingdirection
supposed flow lines
0 2 & ) % 10
CB !mm"
0
2000
&000
)000
%000
10000
l o a d ! < "
beam 7$
beam 71
beam 72
beam .2
beam .1
beam .$
Orientation factor Orientation factor Orientation factor Orientation factor
by Ferrara et al., 2009
23/32
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5.6.7 Orientation factor
f Ftsd,mod=⋅f Ftsd / K f Ftud,mod=⋅f Ftud / K
Isotropic fibre distribution is assumed K = 1.0For favourable effects K < 1.0
For unfavourable effects K > 1.0
Special tests can be used to determine the effect of fibre
orientation due to casting and compaction in real structuralelements, by using structural specimens which better
reproduce the material in the structural elements.