Law of Sines and Law of Cosines Examples / Practice.

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Law of Sines and Law of Cosines Examples / Practice

Transcript of Law of Sines and Law of Cosines Examples / Practice.

Page 1: Law of Sines and Law of Cosines Examples / Practice.

Law of Sines and

Law of Cosines Examples / Practice

Page 2: Law of Sines and Law of Cosines Examples / Practice.

Find p. Round to the nearest tenth.

Page 3: Law of Sines and Law of Cosines Examples / Practice.

Law of Sines

Cross products

Divide each side by 7.

to the nearest degree in ,

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a. Find c.

b. Find mT to the nearest degree in RST if r = 12, t = 7, and mT = 76.

Answer:

Answer:

Page 5: Law of Sines and Law of Cosines Examples / Practice.

We know the measures of two angles of the triangle. Use the Angle Sum Theorem to find

. Round angle measures to the nearest degree and side measures to the nearest tenth.

Page 6: Law of Sines and Law of Cosines Examples / Practice.

We know the measure of two sides and an angle opposite one of the sides.

Law of Sines

Cross products

Round angle measures to the nearest degree and side measures to the nearest tenth.

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Answer:

a. Solve Round angle measures to the nearest degree and side measures to the nearest tenth.

b. Round angle measures to the nearest degree and side measures to the nearest tenth.

Answer:

Page 8: Law of Sines and Law of Cosines Examples / Practice.

A 46-foot telephone pole tilted at an angle of from the vertical casts a shadow on the ground. Find the length of the shadow to the nearest foot when the angle of elevation to the sun is

Draw a diagram Draw Then find the

Page 9: Law of Sines and Law of Cosines Examples / Practice.

A 5-foot fishing pole is anchored to the edge of a dock. If the distance from the foot of the pole to the point where the fishing line meets the water is 45 feet, about how much fishing line that is cast out is above the surface of the water?

Answer: About 42 feet of the fishing line that is cast out is above the surface of the water.

Page 10: Law of Sines and Law of Cosines Examples / Practice.

Use the Law of Cosines since the measures of two sides and the included angle are known.

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Simplify.

Take the square root of each side.

Law of Cosines

Use a calculator.

Answer:

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Answer:

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Law of Cosines

Simplify.

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Solve for L.

Use a calculator.

Subtract 754 from each side.

Divide each side by –270.

Answer:

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Answer:

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Determine whether the Law of Sines or the Law of Cosines should be used first to solve Then solve Round angle measures to the nearest degree and side measures to the nearest tenth.

Since we know the measures of two sides and the included angle, use the Law of Cosines.

Page 17: Law of Sines and Law of Cosines Examples / Practice.

Take the square root of each side.

Use a calculator.

Law of Cosines

Next, we can find If we decide to find we can use either the Law of Sines or the Law of Cosines to find this value. In this case, we will use the Law of Sines.

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Cross products

Divide each side by 46.9.

Law of Sines

Take the inverse of each side.

Use a calculator.

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Use the Angle Sum Theorem to find

Angle Sum Theorem

Subtract 168 from each side.

Answer:

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Determine whether the Law of Sines or the Law of Cosines should be used first to solve Then solve Round angle measures to the nearest degree and side measures to the nearest tenth.

Answer:

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Since is an isosceles triangle,

AIRCRAFT From the diagram of the plane shown, determine the approximate exterior perimeter of each wing. Round to the nearest tenth meter.

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Cross products

Law of Sines

Simplify.

Divide each side by sin .

Use the Law of Sines to find KJ.

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Use the Law of Sines to find .

Cross products

Law of Sines

Solve for H.

Divide each side by 9.

Use a calculator.

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Use the Angle Sum Theorem to find

Subtract 95 from each side.

Angle Sum Theorem

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Use the Law of Sines to find HK.

Cross products

Law of Sines

Use a calculator.

Divide each side by sin

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Answer: The perimeter is about or about 67.1 meters.

The perimeter of the wing is equal to

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The rear side window of a station wagon has the shape shown in the figure. Find the perimeter of the window if the length of DB is 31 inches.

Answer: about 93.5 in.