Kx Ex 2162 Lecture 11

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    1

    Understand nominal and effective Interestrates statements

    Determine equivalence calculations fordifferent payment and compoundingperiods

    How commercial loans and mortgages arestructured in terms of interest andprincipal payments.

    The basic of investing in financial assets

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    Nominal Versus Effective Interest Rates

    Nominal InterestRate:Interest rate quoted

    based on an annualperiod.( Annual percentagerate-APR )

    Effective InterestRate:Actual interest earned

    or paid in a year orsome other timeperiod

    Ex: 18% compoundedmonthly

    12 12$1(1 ) $1(1 0.015)

    $1.1956

    $1.1956 $1.00 $0.1956

    F i

    I

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    Effective Annual Interest Rate (Yield) Formula:

    r = nominal interest rate per yeari a = effective annual interest rate

    M = number of interest periods peryear

    Example :18% compoundedmonthly

    What It really Means

    1.5% per month for 12months or19.56% compoundedonce per year

    (1 ) 1M

    a

    r i M

    120.18

    1 1 19.56%12a

    i

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    Practice

    ProblemSuppose your savingsaccount pays 9% interestcompounded quarterly .(a) Interest rate per

    quarter(b) Annual effective

    interest rate ( i a)(c) If you deposit

    $10,000 for one year,

    how much wouldyou have?

    Solution:

    Contemporary Engineering Economics, 5th edition, 2010

    4

    (a) Interest rate per quarter:

    9% 2.25%

    4(b) Annual effective interest rate:

    (1 0.0225) 1 9.31%

    (c) Balance at the end of one year (after 4 quarters)

    $10,000( / ,2.

    a

    i

    i

    F F P

    25%,4)

    $10,000( / ,9.31%,1)

    $10,931

    F P

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    Contemporary Engineering Economics, 5th edition, 2010

    Nominal and Effective Interest Rates withDifferent Compounding Periods

    Effective RatesNominal

    RateCompounding

    AnnuallyCompoundingSemi-annually

    CompoundingQuarterly

    CompoundingMonthly

    CompoundingDaily

    4% 4.00% 4.04% 4.06% 4.07% 4.08%

    5 5.00 5.06 5.09 5.12 5.136 6.00 6.09 6.14 6.17 6.18

    7 7.00 7.12 7.19 7.23 7.25

    8 8.00 8.16 8.24 8.30 8.33

    9 9.00 9.20 9.31 9.38 9.42

    10 10.00 10.25 10.38 10.47 10.52

    11 11.00 11.30 11.46 11.57 11.62

    12 12.00 12.36 12.55 12.68 12.74

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    Why Do We Need an Effective Interest Rate

    per Payment Period?

    Contemporary Engineering Economics, 5th edition, 2010

    Payment period

    Interest period

    Payment period

    Interest period

    Whenever payment and compounding periods differ fromeach other, one or the other must be transformed so thatboth conform to the same unit of time.

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    Effective InterestRate per Payment

    Period ( i ) Formula:

    C = number ofinterest periods perpayment period

    K = number ofpayment periods peryear

    CK =total number ofinterest periods peryear, or M

    r / K = nominal interestrate per payment period

    Functional Relationships among r , i , and i a , where interest is calculated based on 9% compoundedmonthly and payments occur quarterly

    Contemporary Engineering Economics, 5th edition, 2010

    1 1C

    r i

    CK

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    Effective Interest Rate perPayment Period with

    Continuous Compounding Formula: With continuous

    compoundingExample : 12% compoundedcontinuously

    (a) effective interest rate per quarter

    (b) effective annual interest rate

    Contemporary Engineering Economics, 5th edition, 2010

    C

    /

    lim 1 1

    1r K

    C

    C

    r i

    CK

    e

    0.12/4 1

    3.045% per quarter

    i e

    0.12/1 1

    12.75% per yearai e

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    Case 0 : 8% compounded quarterly

    Payment Period = QuarterInterest Period = Quarterly

    1 interest period Given r = 8%,

    K = 4 payments per yearC = 1 interest period per quarterM = 4 interest periods per year

    2nd Q 3 rd Q 5th Q1st Q

    1

    [1 / ] 1

    [1 0.08 / (1)(4)] 1

    2.000% per quarter

    C i r CK

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    Case 1 : 8% compounded monthly

    Payment Period = QuarterInterest Period = Monthly

    3 interest periods Given r = 8%,K = 4 payments per yearC = 3 interest periods per quarterM = 12 interest periods per year

    2nd Q 3 rd Q 5th Q1st Q

    3

    [1 / ] 1

    [1 0.08 / (3)(4)] 1

    2.013% per quarter

    C i r CK

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    Case 2 : 8% compounded weekly

    Payment Period = QuarterInterest Period = Weekly

    13 interest periods Given r = 8%,K = 4 payments per yearC = 13 interest periods per quarterM = 52 interest periods per year

    2nd Q 3 rd Q 5th Q1st Q

    i r CK C

    [ / ]

    [ . / ( )( )]

    .

    1 1

    1 0 08 13 4 1

    2 0186%

    13

    per quarter

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    Case 3 : 8% compounded continuously

    Payment Period = QuarterInterest Period = Continuously

    interest periods Given r = 8%,K = 4 payments per year

    2nd Q 3 rd Q 5th Q1st Q

    /

    0.02

    1

    1

    2.0201% per quarter

    r K i e

    e

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    Contemporary Engineering Economics, 5th edition, 2010

    Summary: Effective Interest Rates per Quarter atVarying Compounding Frequencies

    Case 0 Case 1 Case 2 Case 3

    8%compoundedquarterly

    8%compoundedmonthly

    8%compoundedweekly

    8%compoundedcontinuously

    Payments occurquarterly

    Payments occurquarterly

    Payments occurquarterly

    Payments occurquarterly

    2.000% perquarter

    2.013% perquarter

    2.0186% perquarter

    2.0201% perquarter

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    Contemporary Engineering Economics, 5th edition, 2010

    Equivalence Analysis Using Effective Interest Rates.

    Frequency of cash flows may or may notequal the frequency of interest compounding If the frequency of the cash flow equals thefrequency of the interest compounding NoProblem!When payment period and compoundingperiod differ, calculate an effective interestrate that covers the payment period. Thenuse the appropriate interest formulas todetermine the equivalent values

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    Equivalence Calculations using Effective

    Interest RatesStep 1: Identify the payment period (e.g., annual,quarter, month, week, etc)

    Step 2: Identify the compounding period (e.g.,annually, quarterly, monthly, etc)

    Step 3: Find the effective interest rate that coversthe payment period.

    Contemporary Engineering Economics, 5th edition, 2010

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    Dollars Down

    in the DrainSuppose you drink a cupof coffee ($3.00 a cup) onthe way to work everymorning for 30 years. If youput the money in the bank

    for the same period, howmuch would you have,assuming your accountsearns a 5% interestcompounded daily.

    NOTE: Assume you drink acup of coffee every dayincluding weekends.

    Solution:Payment period = dailyCompounding period = daily

    Contemporary Engineering Economics, 5th edition, 2010

    5%0.0137% per day

    36530 365 10,950 days

    $3( / ,0.0137%,10950)

    $76,246

    i

    N

    F F A

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    Case II: When Payment Periods Differ from

    Compounding PeriodsStep 1: Identify the following parameters.

    M = No. of compounding periodsK = No. of payment periods per yearC = No. of interest periods per payment period

    Step 2: Compute the effective interest rate per paymentperiod.

    For discrete compounding

    For continuous compounding

    Step 3: Find the total no. of payment periods.N = K (no. of years)

    Step 4: Use i and N in the appropriate equivalence formula.

    Contemporary Engineering Economics, 5th edition, 2010

    [1 / ] 1C i r CK

    / 1r K i e

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    Compounding Occurs More Frequently than Payments are Made .

    Given : A = $1,500 per quarter, r = 6% per year, M = 12compounding periods per year,and N = 2 years

    Find: F

    Step 1: M = 12 compoundingperiods/year K = 4 payment

    periods/year C = 3 interest periods

    per quarter

    Step 2:

    Step 3: N = 4(2) = 8

    F = $1,500 ( F/A , 1.5075%, 8)= $14,216.24

    Contemporary Engineering Economics, 5th edition, 2010

    30.06

    1 112

    1.5075% per quarter

    i

    Suppose you make equal quarterly deposits of $1500 into a fund thatpays interest at a rate of 6% compounded monthly. Find the balance

    at the end of year 2.

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    A Decision Flow Chart on How to Compute the

    Effective Interest Rate per Payment Period

    Contemporary Engineering Economics, 5th edition, 2010

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    PracticeProblem

    If you invest$1,000 in a savingsaccount that pays

    6% annual interestcompoundedcontinuously, whatwould be the

    balance at the endof 3 years?

    Contemporary Engineering Economics, 5th edition, 2010

    0.06 1

    6.18%

    $1,000( / , 6.18%,3)$1,197.09

    ai e

    F F P

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    Contemporary Engineering Economics, 5th edition, 2010

    Single-Payment Transactions with Continuous

    Compounding Present Worth

    F

    0

    N

    P

    (1 )(1 1)

    N

    r N

    rN

    P F i

    F e

    Fe

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    Continuous-Funds Flow

    Contemporary Engineering Economics, 5th edition, 2010

    0

    0

    ( )

    ( )

    rt

    t

    Nrt

    P f t t e

    f t e dt

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    Exercise: Daily Flows and Daily Compounding with ContinuousFlows and Continuous Compounding

    Consider a situation in which money flows daily.Suppose you own a retail shop and generate $200cash each day. You establish a special businessaccount and deposit your daily cash flows in an

    account for 15 months. This account earns aninterest rate at 6%. Compare the accumulated cashvalues at the end of 15 months a) daily compoundingb) Continuous compounding.

    Contemporary Engineering Economics, 5th edition, 2010

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    Given : A = $200 perday, r = 6% per year, M =365 compoundingperiods per year, and N =455 days

    Find: F

    Solution

    Contemporary Engineering Economics, 5th edition, 2010

    Note: A15-month period

    Is 1.25 years .

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    Example 4.12 LoanBalance, Principal, andInterest: TabularApproach

    Given : P = $5,000, i = 12% APR,N = 24 months

    Find: A, and loan repayment

    schedule

    A = $5,000(A/P, 1%, 24) = $235.37

    Contemporary Engineering Economics, 5th edition, 2010

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    Calculating the Remaining Loan Balance after

    Making the n th Payment

    Contemporary Engineering Economics, 5th edition, 2010

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    Example 4.13 LoanBalance, Principal, and

    Interest: Remaining Balance Method

    Given : P = $5,000, i = 12%APR, N = 24 months

    Find: Loan balance, principal,and interest payment for the 6 th payment

    A = $5,000(A/P, 1%, 24) = $235.37

    Contemporary Engineering Economics, 5th edition, 2010

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    Example 4.15 Financing your VehicleGiven : Three financing options, r = 4.5%, paymentperiod = monthly, and compounding period =monthly Find: Which option?

    Issue : Which interest rate to use in calculating theequivalent cost of financing for each option

    Option A : Conventional Debt Financing:

    P debt = $4,500 + $736.53( P/A , 4.5%/12, 42)- $17,817( P/F , 4.5%/12, 42)

    = $17,847

    Option B : Cash Financing:

    P cash = $31,020 - $17,817( P / F ,4.5%/12,42)

    = $15,845

    Option C : Lease Financing:

    P lease = $1,507.76 + $513.76( P/A , 4.5%/12, 42)+ $395( P/F , 4.5%/12, 42)

    = $21,336

    Contemporary Engineering Economics, 5th edition, 2010

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