Kx Ex 2162 Lecture 11
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Transcript of Kx Ex 2162 Lecture 11
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1
Understand nominal and effective Interestrates statements
Determine equivalence calculations fordifferent payment and compoundingperiods
How commercial loans and mortgages arestructured in terms of interest andprincipal payments.
The basic of investing in financial assets
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Nominal Versus Effective Interest Rates
Nominal InterestRate:Interest rate quoted
based on an annualperiod.( Annual percentagerate-APR )
Effective InterestRate:Actual interest earned
or paid in a year orsome other timeperiod
Ex: 18% compoundedmonthly
12 12$1(1 ) $1(1 0.015)
$1.1956
$1.1956 $1.00 $0.1956
F i
I
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Effective Annual Interest Rate (Yield) Formula:
r = nominal interest rate per yeari a = effective annual interest rate
M = number of interest periods peryear
Example :18% compoundedmonthly
What It really Means
1.5% per month for 12months or19.56% compoundedonce per year
(1 ) 1M
a
r i M
120.18
1 1 19.56%12a
i
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Practice
ProblemSuppose your savingsaccount pays 9% interestcompounded quarterly .(a) Interest rate per
quarter(b) Annual effective
interest rate ( i a)(c) If you deposit
$10,000 for one year,
how much wouldyou have?
Solution:
Contemporary Engineering Economics, 5th edition, 2010
4
(a) Interest rate per quarter:
9% 2.25%
4(b) Annual effective interest rate:
(1 0.0225) 1 9.31%
(c) Balance at the end of one year (after 4 quarters)
$10,000( / ,2.
a
i
i
F F P
25%,4)
$10,000( / ,9.31%,1)
$10,931
F P
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Contemporary Engineering Economics, 5th edition, 2010
Nominal and Effective Interest Rates withDifferent Compounding Periods
Effective RatesNominal
RateCompounding
AnnuallyCompoundingSemi-annually
CompoundingQuarterly
CompoundingMonthly
CompoundingDaily
4% 4.00% 4.04% 4.06% 4.07% 4.08%
5 5.00 5.06 5.09 5.12 5.136 6.00 6.09 6.14 6.17 6.18
7 7.00 7.12 7.19 7.23 7.25
8 8.00 8.16 8.24 8.30 8.33
9 9.00 9.20 9.31 9.38 9.42
10 10.00 10.25 10.38 10.47 10.52
11 11.00 11.30 11.46 11.57 11.62
12 12.00 12.36 12.55 12.68 12.74
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Why Do We Need an Effective Interest Rate
per Payment Period?
Contemporary Engineering Economics, 5th edition, 2010
Payment period
Interest period
Payment period
Interest period
Whenever payment and compounding periods differ fromeach other, one or the other must be transformed so thatboth conform to the same unit of time.
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Effective InterestRate per Payment
Period ( i ) Formula:
C = number ofinterest periods perpayment period
K = number ofpayment periods peryear
CK =total number ofinterest periods peryear, or M
r / K = nominal interestrate per payment period
Functional Relationships among r , i , and i a , where interest is calculated based on 9% compoundedmonthly and payments occur quarterly
Contemporary Engineering Economics, 5th edition, 2010
1 1C
r i
CK
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Effective Interest Rate perPayment Period with
Continuous Compounding Formula: With continuous
compoundingExample : 12% compoundedcontinuously
(a) effective interest rate per quarter
(b) effective annual interest rate
Contemporary Engineering Economics, 5th edition, 2010
C
/
lim 1 1
1r K
C
C
r i
CK
e
0.12/4 1
3.045% per quarter
i e
0.12/1 1
12.75% per yearai e
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Case 0 : 8% compounded quarterly
Payment Period = QuarterInterest Period = Quarterly
1 interest period Given r = 8%,
K = 4 payments per yearC = 1 interest period per quarterM = 4 interest periods per year
2nd Q 3 rd Q 5th Q1st Q
1
[1 / ] 1
[1 0.08 / (1)(4)] 1
2.000% per quarter
C i r CK
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Case 1 : 8% compounded monthly
Payment Period = QuarterInterest Period = Monthly
3 interest periods Given r = 8%,K = 4 payments per yearC = 3 interest periods per quarterM = 12 interest periods per year
2nd Q 3 rd Q 5th Q1st Q
3
[1 / ] 1
[1 0.08 / (3)(4)] 1
2.013% per quarter
C i r CK
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Case 2 : 8% compounded weekly
Payment Period = QuarterInterest Period = Weekly
13 interest periods Given r = 8%,K = 4 payments per yearC = 13 interest periods per quarterM = 52 interest periods per year
2nd Q 3 rd Q 5th Q1st Q
i r CK C
[ / ]
[ . / ( )( )]
.
1 1
1 0 08 13 4 1
2 0186%
13
per quarter
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Case 3 : 8% compounded continuously
Payment Period = QuarterInterest Period = Continuously
interest periods Given r = 8%,K = 4 payments per year
2nd Q 3 rd Q 5th Q1st Q
/
0.02
1
1
2.0201% per quarter
r K i e
e
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Contemporary Engineering Economics, 5th edition, 2010
Summary: Effective Interest Rates per Quarter atVarying Compounding Frequencies
Case 0 Case 1 Case 2 Case 3
8%compoundedquarterly
8%compoundedmonthly
8%compoundedweekly
8%compoundedcontinuously
Payments occurquarterly
Payments occurquarterly
Payments occurquarterly
Payments occurquarterly
2.000% perquarter
2.013% perquarter
2.0186% perquarter
2.0201% perquarter
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Contemporary Engineering Economics, 5th edition, 2010
Equivalence Analysis Using Effective Interest Rates.
Frequency of cash flows may or may notequal the frequency of interest compounding If the frequency of the cash flow equals thefrequency of the interest compounding NoProblem!When payment period and compoundingperiod differ, calculate an effective interestrate that covers the payment period. Thenuse the appropriate interest formulas todetermine the equivalent values
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Equivalence Calculations using Effective
Interest RatesStep 1: Identify the payment period (e.g., annual,quarter, month, week, etc)
Step 2: Identify the compounding period (e.g.,annually, quarterly, monthly, etc)
Step 3: Find the effective interest rate that coversthe payment period.
Contemporary Engineering Economics, 5th edition, 2010
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Dollars Down
in the DrainSuppose you drink a cupof coffee ($3.00 a cup) onthe way to work everymorning for 30 years. If youput the money in the bank
for the same period, howmuch would you have,assuming your accountsearns a 5% interestcompounded daily.
NOTE: Assume you drink acup of coffee every dayincluding weekends.
Solution:Payment period = dailyCompounding period = daily
Contemporary Engineering Economics, 5th edition, 2010
5%0.0137% per day
36530 365 10,950 days
$3( / ,0.0137%,10950)
$76,246
i
N
F F A
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Case II: When Payment Periods Differ from
Compounding PeriodsStep 1: Identify the following parameters.
M = No. of compounding periodsK = No. of payment periods per yearC = No. of interest periods per payment period
Step 2: Compute the effective interest rate per paymentperiod.
For discrete compounding
For continuous compounding
Step 3: Find the total no. of payment periods.N = K (no. of years)
Step 4: Use i and N in the appropriate equivalence formula.
Contemporary Engineering Economics, 5th edition, 2010
[1 / ] 1C i r CK
/ 1r K i e
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Compounding Occurs More Frequently than Payments are Made .
Given : A = $1,500 per quarter, r = 6% per year, M = 12compounding periods per year,and N = 2 years
Find: F
Step 1: M = 12 compoundingperiods/year K = 4 payment
periods/year C = 3 interest periods
per quarter
Step 2:
Step 3: N = 4(2) = 8
F = $1,500 ( F/A , 1.5075%, 8)= $14,216.24
Contemporary Engineering Economics, 5th edition, 2010
30.06
1 112
1.5075% per quarter
i
Suppose you make equal quarterly deposits of $1500 into a fund thatpays interest at a rate of 6% compounded monthly. Find the balance
at the end of year 2.
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A Decision Flow Chart on How to Compute the
Effective Interest Rate per Payment Period
Contemporary Engineering Economics, 5th edition, 2010
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PracticeProblem
If you invest$1,000 in a savingsaccount that pays
6% annual interestcompoundedcontinuously, whatwould be the
balance at the endof 3 years?
Contemporary Engineering Economics, 5th edition, 2010
0.06 1
6.18%
$1,000( / , 6.18%,3)$1,197.09
ai e
F F P
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Contemporary Engineering Economics, 5th edition, 2010
Single-Payment Transactions with Continuous
Compounding Present Worth
F
0
N
P
(1 )(1 1)
N
r N
rN
P F i
F e
Fe
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Continuous-Funds Flow
Contemporary Engineering Economics, 5th edition, 2010
0
0
( )
( )
rt
t
Nrt
P f t t e
f t e dt
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Exercise: Daily Flows and Daily Compounding with ContinuousFlows and Continuous Compounding
Consider a situation in which money flows daily.Suppose you own a retail shop and generate $200cash each day. You establish a special businessaccount and deposit your daily cash flows in an
account for 15 months. This account earns aninterest rate at 6%. Compare the accumulated cashvalues at the end of 15 months a) daily compoundingb) Continuous compounding.
Contemporary Engineering Economics, 5th edition, 2010
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Given : A = $200 perday, r = 6% per year, M =365 compoundingperiods per year, and N =455 days
Find: F
Solution
Contemporary Engineering Economics, 5th edition, 2010
Note: A15-month period
Is 1.25 years .
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Example 4.12 LoanBalance, Principal, andInterest: TabularApproach
Given : P = $5,000, i = 12% APR,N = 24 months
Find: A, and loan repayment
schedule
A = $5,000(A/P, 1%, 24) = $235.37
Contemporary Engineering Economics, 5th edition, 2010
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Calculating the Remaining Loan Balance after
Making the n th Payment
Contemporary Engineering Economics, 5th edition, 2010
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Example 4.13 LoanBalance, Principal, and
Interest: Remaining Balance Method
Given : P = $5,000, i = 12%APR, N = 24 months
Find: Loan balance, principal,and interest payment for the 6 th payment
A = $5,000(A/P, 1%, 24) = $235.37
Contemporary Engineering Economics, 5th edition, 2010
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Example 4.15 Financing your VehicleGiven : Three financing options, r = 4.5%, paymentperiod = monthly, and compounding period =monthly Find: Which option?
Issue : Which interest rate to use in calculating theequivalent cost of financing for each option
Option A : Conventional Debt Financing:
P debt = $4,500 + $736.53( P/A , 4.5%/12, 42)- $17,817( P/F , 4.5%/12, 42)
= $17,847
Option B : Cash Financing:
P cash = $31,020 - $17,817( P / F ,4.5%/12,42)
= $15,845
Option C : Lease Financing:
P lease = $1,507.76 + $513.76( P/A , 4.5%/12, 42)+ $395( P/F , 4.5%/12, 42)
= $21,336
Contemporary Engineering Economics, 5th edition, 2010
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