Jawaban Soal Kimia Ksp
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1. Hitung kelarutan Ag2CO3 dalam air ! (Ksp = 3,2 . 10 -8)2. Larutan jenuh suatu basa L(OH)2 mempunyai pH = 9. Hitung Ksp L(OH)2 !3. Hitung kelarutan CaCO3 dalam 0,01 M Ca(NO3)2 jika kelarutan CaCO3 dalam air = 10 -4
M !4. Ramalkan, apakah terjadi pengendapan jika larutan 100 ml CaCl2 0,001 M direaksikan
dengan larutan 100 ml Na2SO4 0,002 M ! (Ksp CaSO4 = 9 . 10 -6)
1. Ksp = 4s3
s = = = =
= 2 . 10-3 M
2. pH = 9, pOH = 5, [OH-] = 10-5 M L(OH)2 ⇌ L2+ + 2OH-
½ . 10-5 M 10-5 M Ksp = [L2+] [OH-]2
= (½ . 10-5) x (10-5)2
= 5 . 10-16
3. Ksp CaCO3 = [10 -4]2 = 10-8
Ca(NO3)2 → Ca2+ + 2NO3-
0,01 M 0,01 M CaCO3 ⇌ Ca2+ + CO3
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Ksp = [Ca2+] [CO3-]
10-8 = 0,01 [CO3-]
[CO3-] = 10-6 M ∞ [CaCO3] = 10-6 M
4. CaCl2 + Na2SO4 → CaSO4 + NaCl 100 ml 0,001 M 100 ml 0,002 M 0,1 mmol 0,2 mmol [Ca2+] = 0,1/200 M [SO4
2-] = 0,2/200 M = 5 . 10 -4 M = 1 . 10 -3 M [Ca2+][SO4
2-] = 5 . 10 -4 x 1 . 10 -3 = 5 . 10-7 < Ksp CaSO4 = 9 . 10 -6
Tidak terjadi endapan.