JABATAN PELAJARAN NEGERI MELAKAPEPERIKSAAN PERCUBAAN SPM 2008

PHYSICS PAPER 1

SKEMA JAWAPAN

1 B 6 D 11 D 16 B 21 C 26 D 31 D 36 C 41 A 46 A2 A 7 C 12 B 17 A 22 A 27 D 32 A 37 A 42 D 47 C3 B 8 A 13 B 18 A 23 A 28 A 33 C 38 A 43 D 48 C4 C 9 C 14 B 19 C 24 C 29 D 34 D 39 B 44 A 49 B5 B 10 D 15 D 20 C 25 B 30 B 35 C 40 B 45 A 50 E

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PEPERIKSAAN PERCUBAAN MELAKA 2008MARKING SCHEME : PAPER 2

1(a) Racet 1

(b) The ratchet knob prevents over tightening // avoid extra pressure 1

(c) 1st : 1.5 + 0.35 = 1.85 mm2nd : 1.85 – (- 0.02) = 1.87 mm

11

TOTAL 4

2(a)(i) Bernoulli’s principle 1

(a)(ii) Y 1

(b) The air moves with a high speed 1

(c) 1st: The atmospheric pressure which is higher pushes the liquid up through thenarrow tube.

2nd : The jet air will force the liquid to be sprayed as fine spray liquid

1

1

TOTAL 5

3(a) Velocity = displacementTime

1

(b) Region AB 1

(c)(i) a = 10 – 010 – 0

= 1 ms-2

1

1

(c)(ii) s = ½ (10)(10) + (10)(10)= 150 m

11

TOTAL 6

4(a)(i) α / β / γ 1(a)(ii) 1st: The radioactive emission enters the tube through the mica window

2nd :ionizes the neon gas.3rd : The electron and positive ion are attracted towards the anode and cathode

respectively thus produces a pulse of current.Any two marks

1

2

(b) Background readings // natural radioactivity in the ground, bricks or buildings and 1

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cosmic radiation.

(c) 1st : show on the graph2nd : half life = 4 hours

2

(d) Industries : smoke detectors / detect thickness of papers / detect leaks inunderground pipe waterMedicine : radioactive tracers/ sterilization,/cancer treatment

1

TOTAL 7

5(a) Attraction force 1

(b)(i) same magnitude // opposite direction 1

(b)(ii) Same forces / equal in magnitudes // opposite direction 1

(c)(i) Zero 1

(c)(ii) Equal 1

(d)(i) 1st : The nett force is zero, the object is stationary2nd : The nett force is zero, moves with uniform velocity

11

(d)(ii) Equilibrium of forces 1

TOTAL 8

6(a) Heat is a form of energy 1

6(b)(i) Diagram 6.2 is higher // vice versa 1

(b)(ii) The temperature in Diagram 6.2 is higher // vice versa 1

(b)(iii) Volume 1

(b)(iv) When volume is higher, the temperature is higher // directly proportional 1

(c) Charles Law 1

(c)(i) θ = absolute zero 1

(c)(ii) Volume of air is zero // the air molecules is at rest //kinetic energy is zero 1

TOTAL 8

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7(a)(i) Transverse wave // mechanical wave 1

(a)(ii) The gap is bigger than the wavelength 1(b) 1st : smaller amplitude

2nd : same wavelength2

(c)(i) 1st : made of concrete2nd : because concrete is strong

2

(c)(ii) 1st : make many holes on the wall2nd : diffraction // spread of energy

2

(d) 1st : The water is shallow2nd : load and unload by using small boats

2

TOTAL 10

8(a) Power = the rate of work done / the rate of energy transformed@ P = W

T

1

(b)(i) 1st : R2 is located at the base terminal2nd : to limit the base current

11

(b)(ii) 1st : R1 and LDR are in series2nd : to function as potential divider

11

(b)(iii) 1st : the collector terminal is connected to positive terminal of the battery2nd : reverse bias

11

(c) Circuit K 1

(d) Light controlled switch/ switches on the bulb at night, switches off the bulb atdaytime.

1

(e)(i) 5 V 1

(e)(ii) VRY = Ry x V

( Rx + Ry)

1000

610001

RR = 6000 – 1000 = 5000 Ω

1

1

TOTAL 12

State the meaning of symbols

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9(a)(i) Magnetic field is a region of magnetic force. 1

(a)(ii) 1st : The direction of the magnetic field on the left coil is counter/anti clockwise,/diagram

2nd : The direction of the magnetic field on the right coil is clockwise // diagram

3rd : As the result the magnetic fields in the middle of the coil are in the samedirection, upward. So the magnetic field will be stronger in the middle

11

1

(b)(i) 1st : Both diagram 9.2 and diagram 9.3 have the same pattern of the magneticfield,ie, circular with the wire in the middle

2nd: The direction of the magnetic field for Diagram 9.2 is clockwise, while inDiagram9.3 is counter clockwise/ anti-clockwise.

1

1

(b)(ii) The pattern of the magnetic field in Diagram 9.4 is not uniform compared toDiagram 9.2 and Diagram 9.3

1

(b)(iii) The resultant force acting on the left wire is downward while the resultant forceacting on the right wire is upward / opposite to each other.

1

(b)(iv) 1st : Instrument which uses the same principle is electrical motor.2nd : The electric motor has 2 forces acting on the opposite side caused by the

counter react between a current carrying conductor in a magnetic field/diagram

11

(c)(i) 1st : The shape of the magnet is cylindrical2nd : It will produce uniform magnetic field

11

(c)(ii) 1st : The coil is placed surrounding/fit to the magnet and it is attached to a cone2nd : to increase the effectiveness of the counter react between the magnetic fields

.

11

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(c)(iii) 1st : The cone is made from a light material / paper2nd : It can easily vibrate

2

(c)(iv) 1st : Type of electrical supply is alternate current power supply2nd: The audio signal varies with the current.

2

(c)(v) 1st : material used for the body of the loudspeaker is metal / wood2nd : to ensure the loudspeaker is strong 2

TOTAL 20

10(a)(i) Real image is an image which can be seen on a screen. 1

(a)(ii) 1st : the object distance in diagram 10.1 is longer than diagram 10.22nd : the image distance in diagram 10.2 is longer than diagram 10.13rd : the size of the image in diagram 10.2 is larger4th : the longer the image distance, the bigger the size of the image5th : The smaller the object distance the larger the size of the image / the object

distance is inversely proportional to size of the image.

5

(b) 1st : The convex lens with its holder is aimed at a distant object like a tree.2nd : Adjust a screen until you see a very sharp and clear image of the distant

object.3rd :When parallel light rays from a distant object pass through a convex lens, they

will converge to a point called focal point/ label on a diagram4th : Measure the distance between the convex lens and screen./ label on a diagram

4

(c)(i) 1st : draws the objective and eyepiece lenses.2nd : correct label of objective and eyepiece3rd : label fO and fe correctly4th : draw the correct position for the object ( fo < u1 < 2fo)5th : draw ray diagrams to show the position of image 16th : draw ray diagrams to show the final image

6

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(c)(ii) 1st : Use a concave mirror2nd : converge light to the microscope.

2

(c)(iii) 1st : Decrease the object distance / decrease the focal length of the eyepiece lens /decrease the focal length of the objective lens.2nd : increase the magnification factor.

2

TOTAL 20

11(a)(i) “240 V, 80 W” means the bulb transforms energy of 80 J/s if connected to 240 Vpower supply.

1

(a)(ii) 1st : the resistance of metal Z is constant / The resistance of metal Y is increasing2nd : The suitable material to be used as filament of the bulb is metal Y3rd : resistance increases as the temperature increases4th : the higher the resistance the brighter the bulb.

4

(b)(i) 1st : The cross-sectional area is small2nd : because it can release more heat/ resistance is higher3rd : Melting point is high4th : so it cannot be melt easily at high temperature.5th : The specific heat capacity is low6th : so it can release heat in a shorter time7th : length of the heating element is long8th : it can be shaped as a coil and release more heat.

8

(b)(ii) 1st : The best heating element is L2nd : It has a small cross-sectional area, high melting point, low specific heat

capacity and long.2

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(c) (i)

5.1

3

1

3

11

R

R

1

1

(c) (ii)AI 2

3

62 / V = 46)

12

2(

V

P = )2()2( 22 RI / P =2

422

R

V

= 8 W

1

1

1

TOTAL 20

12(a) Buoyant force is an upward force resulting from an object being wholly orpartially immerse in fluid.

1

(b) 1st : When the ballast tank is filled with water,2nd: The buoyant force is smaller than the weight of the submarine. It will

sink/submerges3rd : When the ballast tank is filled with air / when the water pumps out,4th : the buoyant force is larger than the weight of the submarine, and it will float.

4

(c) 1st : Horizontal cross section: front side is narrow and pointed2nd : reduce the water resistance3rd : The hull material is made of aluminium4th : It is lighter and strong5th : Hull ability : hydrodynamic6th : The ability to withstand shock waves, weather collisions and groundings.7th : Fuel used is diesel8th : The cost is cheaper9th : The best watercraft is Q10th : because the horizontal cross section of front side is narrow and pointed, the

hull material is made of aluminium, the hull ability is hydrodynamic and thefuel used is diesel.

1111111111

(d)(i) W = mg= (200) (10) = 2000 N

11

(d)(ii) W (boat) + W(load) = ρVg2000 + W = (1000) (4) (10)

W = 38 000 Nm = 3,800 kg

111

TOTAL 20END OF MARKING SCHEME

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Marking Scheme K3 Fizik Peperiksaan Percubaan SPM 2008

No Marking Criteria Mark1 (a) (i) Mass//m 1

(ii) Temperature// θ2 //Δθ 1

(iii) Type of liquid// time 1

m/g 1/m/g-1 θ2/0C Δθ/0C

50 0.020 46.0 16.0

100 0.010 38.0 8.0

150 0.007 35.5 5.5

200 0.005 34.0 4.0

250 0.004 33.0 3.0

(b)

1. label for all the quantities 12. state the unit for m, 1/m, θ2 and Δθ 13. all value for 1/m correct 14. all value for θ2 correct 15. all value for Δθ correct 16. value for 1/m, θ2, and Δθ consistent decimal point 1

Total 6

(c) 1. Δθ at axis-y and at 1/m axis-x √2 correct unit for both axes √3. suitable scale – both axes start from zero and

uniform scale4. all the values plotted correctly √ √

5 or 4 values plotted correctly √5. best straight line √6. size – min scale (10 x 8 ) cm √7 ticks 55-6 ticks 43-4 ticks 32 ticks 21 tick 1

Total 5

(d)Δθ is directly proportional to

m

1 1

(e) Stir the water constantly// position of the eyeperpendicular to the scale of thermometer

1

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Total 16No Marking Criteria Mark2 (a) (i) A1 1

(ii) A2 1

(b) (i) IB = 0 1

(ii) Ic = 0 1

(c) IB is directly proportional to IC 1

(d) Show on the graph 1

64 mA 1

(e) Draw a large triangle min (4 x 5) cm 1

Correct substitution (follow student’s triangle)80 x 10-3

0.5 x 10-6

1

State the answer without unit1.6 x 105

1

(f) 1. Eyes must be perpendicular to the scale of ammeter 1

2. Switch off the circuit when not taking any reading 1

Total 12

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No Marking Criteria Mark3 (a)

(b)

(c)(i)

(ii)

(iii)

(iv)(v)

(vi)

(vii)

(viii)

(ix)

The length of catapult rubber depends on the force

The bigger the force, the longer the extension of the catapultrubberTo investigate the relationship between the force and extension ofa spring

Manipulated variable : ForceResponding variable : ExtensionConstant variable : Length of the spring//diameter of the spring

//type of spring

Spring, retort stand, ruler, slotted weight

State a functionable arrangement of the apparatusMeasure the initial length of the spring, l1

Put one slotted mass, 20 g/m1 at the end of the spring.

Measure the length of the spring, l2

Calculate extension of the spring, x = l2 – l1

Repeat the experiment for the mass 40 g, 60 g, 80 g, 100 g.(Repeat at least 4 times)

Tabulate the data

Force(N)/Mass(g) Extension(cm)/Length ofthe spring (cm)

Plot graph of extension /length of spring against force/mass//graphExtension (cm)

1

1

1

1

1

1

1

1

1

1

1

1

Total12

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Force(N)

No Marking Criteria Mark4 (a)

(b)(c)(i)

(ii)

(iii)(iv)

(v)

(vi)(vii)(viii)

(ix)

The amount of lifted scrap metal depends on the currentThe higher the current, the stronger the electromagnetism.To investigate the relationship between the current and theelectromagnetism.Manipulated variable : CurrentResponding variable : ElectromagnetismConstant variable : Number of turnsCopper wire, soft iron, ammater, rheostat, batteries, pins/paperclips

State a functionable arrangement of the apparatus

Adjust the rheostat to supply a current, I1 / 0.1ACount the number of pins/paper clips attract by the electromagnetAdjust the rheostat for 4 different current 0.2A, 0.3A, 0.4A and0.5A.(Repeat at least 4 times)Tabulate the data

Current(A) Number of pins/paperclips

Plot graph of number of pins against current // graphNumber of pins

11

1

11

1

1

11

1

1

1

Total12

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Current(A)

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