Isochronal Class Problem
6
TEST DURATION (HR) Pwf (psi) qg (MMSCFD) (P'^2 - Pwf^2) Initial Shut in 48 1952 0 Firs Flow 12 1761 2.6 191 First Shutin 15 1952 0 Second Flow 12 1694 3.3 258 Second Shutin 17 1952 0 Third Flow 12 1510 5 442 Third Shutin 18 1952 0 Fourth Flow 12 1320 6.3 632 Extended Flow 72 1151 6 801 Final Shutin 100 1952 0 Theoretical Method b (slope) 6.18 a 95 Empirical Method 1/n (slope) 105.26 n 0.009500285009 (1/n)logC (intercept) 80 C 5.754701490234
description
isochoronal test
Transcript of Isochronal Class Problem
TEST DURATION (HR) Pwf (psi) qg (MMSCFD) (P'^2 - Pwf^2) (P'^2 - Pwf^2)/qgInitial Shut in 48 1952 0
Firs Flow 12 1761 2.6 191 73.4615384615385First Shutin 15 1952 0
Second Flow 12 1694 3.3 258 78.1818181818182Second Shutin 17 1952 0
Third Flow 12 1510 5 442 88.4Third Shutin 18 1952 0Fourth Flow 12 1320 6.3 632 100.31746031746
Extended Flow 72 1151 6 801 133.5Final Shutin 100 1952 0
Theoretical Methodb (slope) 6.18
a 95
Empirical Method1/n (slope) 105.26
n 0.009500285009(1/n)logC (intercept) 80
C 5.754701490234
0.1615762
2.6 73.4615383.3 78.1818185 88.4
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f(x) = 105.262582056893 x − 85.4540481400438
(P'^2 - Pwf^2) Vs qgLinear ((P'^2 - Pwf^2) Vs qg)Stabilized
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f(x) = 105.262582056893 x − 85.4540481400438
(P'^2 - Pwf^2) Vs qgLinear ((P'^2 - Pwf^2) Vs qg)Stabilized
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f(x) = 6.18461844501232 x + 57.5436718642408TheoreticalLinear (Theoretical)Stabilized
qg (MMSCFD)
(P'^
2 - P
wf^
2)/q
g (p
si/M
MSC
FD)
2 2.5 3 3.5 4 4.5 5 5.5 6 6.50
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40
60
80
100
120
140
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f(x) = 6.18461844501232 x + 57.5436718642408TheoreticalLinear (Theoretical)Stabilized
qg (MMSCFD)
(P'^
2 - P
wf^
2)/q
g (p
si/M
MSC
FD)
