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佛光大學 1
Introduction to Data Envelopment Analysis
and Its Applications
Shinn Sun
Department of Management
Fo Guang University
6/10/2015
佛光大學 2
Professor W. W. Cooper-Founder of DEA andShinn photoed at EURO XIV Conference on July 6, 1995
佛光大學 3
V. Krivonozhko, J. C. Paradi, C. Chen, Rajiv Banker, Shinn, Hsihu Changphotoed at 5th International Symposium on DEA, January 6, 2007
佛光大學 4
Lawrence M. Seiford
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Tsutsui, Tone, Fukuyama, Morita, Shinn, Hirotsu
DEA Symposium 2012, Feb 20-21
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Thanassoulis, Yu, Tone,
DEA Symposium 2012, Feb 20-21
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魏權齡(左三)與孫遜
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Joe Zhu
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Outline What is Data Envelopment Analysis (DEA) Efficiency Measures The Use of DEA DEA Linear Programming Model Example: Car Manufacturing DEA Models DEA Research 1996-2006 DEA Model Development Evolution of DEA Application Areas Future for DEA DEA Software
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Outline-continued
DEA Books Conclusions
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What is DEA Evaluating the productivity of Decision Making Units
(DMUs) Initially designed for non-profits where operating
ratios may not be appropriate schools public utilities vehicle maintenance of the Tactical Air Command (TAC)
Has been adopted for evaluating for-profit branches Airline, Banking, Health Care, Hotels, Service Industry,
Transportation, etc. Recently, Hi-Tech Industry
How can you compare various DMUs Determine appropriate inputs Determine appropriate outputs Measure relationships between these inputs and outputs
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Efficiency Measures
• However, with multiple inputs and outputs, it becomes more difficult to evaluate the efficiency of DMUs.
OutputEfficiency =
Input
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• Clearly, process A is more efficient than process B, but...
• A new assessment based on office space shows that process B is more efficient than process A, so…
Process Labor Cost ($/week)
Throughput (jobs/week)
Efficiency (jobs/$)
A 2,000 1,500 0.750B 1,500 1,100 0.733
Process Office Area
(ft2)
Throughput (jobs/week)
Efficiency
(jobs/ft2)A 10,000 1,500 0.15B 6,900 1,100 0.16
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The Use of DEA
Multiple inputs, multiple outputs. Measure efficiency relative to other DMUs. Linear Programming is used to determine
which DMUs are 100% efficient relative to the other units.
Determine relatively inefficient units. Provide ways of determining how to reduce
inefficiencies.
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DEA Linear Programming Model
Let Ek with k=1, 2, ... , K be the efficiency ratios of DMU k, where there are K total branch units.
Let uj, with j=1, 2, ... , M be the weight given for output j, where M is the total number of output types.
Let vi, with i=1, 2, ... , N be the weight given for input i, where N is the total number of input types.
Let Ojk be the number of observed units of output j generated by DMU k during one time period.
Let Iik be the number of actual units of input i used by DMU k during one time period
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DEA Efficiency Measure
Consider a single DMU B whose efficiency we want to measure.
Want to maximize its efficiency by choosing uj's and vi's.
However, in choosing, no other unit can exceed 100% efficiency. So we have the constraints
EB
u1O1B u2O2 B uMOMB
v1I1B v2I2 B vN INB
Ek
u1O1k u2O2k uMOMk
v1I1k v2I2 k vN INk
100%, k 1,2,K
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DEA Linear Program
Max EB u1O1B u2O2B uMOMB
v1I1B v2I2B vN INB 1
u1O1k u2O2k uMOMk v1I1k v2I2k vN INk 0
uj 0, j 1,2,, M
vi 0, i 1,2,, N
k 1,2,, K
Generally K ≥ 2(N+M)
subject to
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Example: Car Manufacturing Make-to-stock only Six units 3-door, 4-door, and 5-door cars only. Assume output 100 cars at each Inputs vary
Unit # Cars Labor Costs 1 100 2 200 2 100 4 150 3 100 4 100 4 100 6 100 5 100 8 80 6 100 10 50
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Productivity Frontier
0
50
100
150
200
0 2 4 6 8 10
Labor Hours
Mate
rial C
ost
s
For each DMU (unit) we need to solve a linear program to determine its efficiency.
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Unit #1
We see from its solutionthat it is 100% efficientrelative to the other units.
Final Reduced Objective Allowable AllowableCell Name Value Cost Coefficient Increase Decrease
$D$2 u1 0.01 0 100 1E+30 99.99143199$E$2 v1 0.166666667 0 0 0 3$F$2 v2 0.003333333 0 0 300 0
Constraints
Final Shadow Constraint Allowable AllowableCell Name Value Price R.H. Side Increase Decrease
$C$11 1 1 1 1E+30 1$C$5 S1 0 1 0 1 0.384615385$C$6 S2 -0.166666667 0 0 1E+30 0.166666667$C$7 S3 0 0 0 0.2 1$C$8 S4 -0.333333333 0 0 1E+30 0.333333333$C$9 S5 -0.6 0 0 1E+30 0.6$C$10 S6 -0.833333333 0 0 1E+30 0.833333333
Linear programMax 100 u1
subject to 100u1 - 2 v1 -200 v2 ≤ 0100u1 - 4 v1 -150 v2 ≤ 0100u1 - 4 v1 -100 v2 ≤ 0100u1 – 6 v1 -100 v2 ≤ 0100u1 - 8 v1 -80 v2 ≤ 0100u1 - 10 v1 -50 v2 ≤ 02v1 + 200 v2 = 1
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Consider Unit #4
• Here we find that unit 4 is relatively inefficient.• The shadow prices presented imply that the unit's
efficiency reference set are units 3 and 6. • Compare with the graph
Final Reduced Objective Allowable AllowableName Value Cost Coefficient Increase Decrease
u1 0.008888889 0 100 1E+30 100v1 0.055555556 0 0 2 7v2 0.006666667 0 0 116.6666667 33.33333333
Constraints
Final Shadow Constraint Allowable AllowableName Value Price R.H. Side Increase Decrease
1 0.888888889 1 1E+30 1S1 -0.555555556 0 0 1E+30 0.555555556S2 -0.333333333 0 0 1E+30 0.333333333S3 0 0.777777778 0 0.142857143 0.5S4 -0.111111111 0 0 1E+30 0.111111111S5 -0.088888889 0 0 1E+30 0.088888889S6 0 0.222222222 0 0.153846154 0.625
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Composite Reference Unit
• One efficient outcome can be obtained by combining the units in the efficiency set using the relative weight assigned to each in calculating the relative efficiency of unit 4.
• These weights turn out to be just the shadow prices on the efficiency constraints.
Calculation of composite unit and excess inputs usedReference
Set Composite ExcessOutputs and Reference Inputs
Inputs S3 S6 Unit C Unit 4 Used
Cars 0.7778 x 100 + 0.2222 x 100 = 100 100 0Labor Hours 0.7778 x 4 + 0.2222 x 10 = 5.3 6 0.7
Material Costs 0.7778 x 100 + 0.2222 x 50 = 88.9 100 11.1
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Alternate Efficient Changes The values for v1 and v2 measure the relative weight
given to the inputs labor-hours and material costs, respectively, in determining the efficiency.
For unit 4, each unit decrease in labor-hours, results in an efficiency increase of 5.55%.
An efficient firm is found by reducing labor-hours by
Also, for each unit decrease in material costs we increase efficiency by 0.67 % so unit 4 can become efficient by reducing costs by
.
100% 88.88%
5.55%2 hours
100% 88.88%
0.67%$16.67
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DEA Models
Traditional models: Charnes, Cooper and Rhodes Model (CCR) Banker, Charnes and Rhodes Model (BCC) Alternative models: Additive Model Slack-based Model Free Disposal Hull Multiplicative Model
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Cross Efficiency Model Window Analysis Models under weights restrictions Assurance Region Model Cone-Ratio Model Variable Models Non-controllable Model Categorical Model Bilateral Model
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Allocation Models
Profit Objective Model
Cost efficiency Model
Revenue Efficiency Model
Profit Efficiency Model
Revenue/Cost Efficiency Model
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DEA Research 1996-2006
A total of 1,030 journal articles is selected. (Theoretical Articles: 382, Applications: 648)
0
20
40
60
80
100
120
140
160
180
1996 1997 1998 1999 2000 2001 2002 2003 2004 2005 2006
年代
篇數
整體文獻
理論文獻
應用文獻
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DEA Model Development方法論: 1996 1997 1998 1999 2000 2001 2002 2003 2004 2005 2006 總計 百分比 排名
Parametric & Nonparametric 5 3 4 4 2 3 4 4 8 5 4 46 12.04% 1T
Restricting Multipliers 2 3 4 5 3 5 1 6 8 5 3 45 11.78% 2
RTS 2 2 1 5 4 2 3 3 10 3 3 38 9.95% 3
Ranking 2 2 0 2 2 2 4 4 6 7 5 36 9.42% 4
Stochastic & Alternate Frontiers 2 2 4 7 3 5 2 1 2 2 6 36 9.42% 4T
Discretionary & Nondiscretionary 3 2 5 0 1 4 3 2 2 5 5 32 8.38% 6
Allocative 1 0 0 2 4 1 4 1 4 4 3 24 6.28% 7
Sensitivity Analysis 2 0 3 4 0 3 1 1 3 3 2 22 5.76% 8
CCR 0 0 2 4 2 2 1 1 1 4 2 19 4.97% 9
Fuzzy Intervals 0 0 0 1 1 1 1 3 2 4 3 16 4.19% 10
Congestion 1 0 0 0 1 4 1 0 3 0 3 13 3.40% 11T
FDH 0 1 1 0 2 1 0 0 4 1 2 12 3.14% 12
Cone Ratio 0 0 0 2 1 1 1 2 0 0 1 8 2.09% 13T
Supper-efficiency 0 0 0 1 0 1 2 0 1 2 1 8 2.09% 13T
Malmquist Index 0 0 0 1 1 1 0 0 3 0 2 8 2.09% 13T
Discriminant Analysis 0 0 0 2 0 1 0 1 1 0 0 5 1.31% 16
Chance Constrained DEA 0 0 1 0 0 1 1 0 1 0 1 5 1.31% 16T
Noise 0 0 0 0 0 0 0 0 2 1 1 4 1.05% 18
RAM 0 0 0 1 0 2 0 0 0 0 0 3 0.79% 19
CFA 1 0 0 0 0 0 0 0 0 0 1 2 0.52% 20
總計 21 15 25 41 27 40 29 29 61 46 48 382 100.00%
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Evolution of DEA
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Application Areas
主題: 1996 1997 1998 1999 2000 2001 2002 2003 2004 2005 2006 總計 百分比 排名
Banking 4 11 5 15 7 8 18 14 19 12 14 127 19.96% 1
Health Care 2 1 5 5 7 6 5 11 13 5 13 73 10.60% 2
Other 5 3 7 3 7 3 3 12 5 8 12 68 9.89% 3
Transportation 3 3 1 4 1 9 5 7 9 5 9 56 8.30% 4
Public Administration 3 2 3 1 5 2 6 3 5 7 3 40 6.54% 5
Energy 1 1 3 3 6 4 5 1 2 7 2 35 5.83% 6
Education 3 2 0 2 6 6 6 2 0 5 2 34 5.65% 7
Manufacturing 1 0 1 2 3 2 5 5 6 4 4 33 5.12% 8
Agriculture 0 2 3 2 4 0 1 1 8 3 5 29 4.24% 9
Telecommunication 2 2 2 1 3 4 1 1 5 2 1 24 4.06% 10
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# Seiford (1996) Gattoufi et al. (2004a) 本研究
1 農業
2 礦業
3 食品業
4 能源業
5 紡織業
6 製造業
7 營造業
8 鋼鐵業
9 銀行業
10 運輸業
11 通信業
12 電腦業
13 保險業
14 零售業
15 高科技業
16 國防
17 教育
18 環境
19 醫療保健
20 總體經濟
21 公共部門
22 公共財政
23 娛樂業
24 其他
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Future for DEA
Theoretical limitation Research Extended DEA models Information Science Statistics Stochastic DEA Dynamic DEA Network DEA Comparison of various DEA models Introduction to quality variables New Application area
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DEA Software
Commercial available software:
DEA Solver
Frontier Analyst
DEA Excel Solver
OnFront
Warwick DEA
MaxDEA, DEAOS Free Software: DEAP, EMS
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DEA Books
Charnes et al. (1994) Data Envelopment Analysis: Theory, Methodology and Applications.
Coelli et al. (1997) An Introduction to Efficiency and Productivity Analysis.
Cooper et al. (2000, 2007) Data Envelopment Analysis: A Comprehensive Text with Models, Application, References and DEA Solver.
孫遜 ( 民 93) 資料包絡分析法—理論與應用,揚智文化公司。
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Conclusions Can understate the inefficiency because
it is calculated by trying to put the inefficient DMU in the best light.
May correct by forcing one DMU, known to be efficient in general, to be explicitly efficient.
Much care must be taken in determining the input and output variables.
Can fail to give significant information if too few points available.
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Conclusions-continued
Serves as a tool for - productivity analysis; - performance measurement; - technology forecasting; - capacity planning; - process re-design; - R&D project evaluation; - strategy alliances selection; and - resources allocation.