Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y...

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Transcript of Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y...

Page 1: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 2: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 3: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 4: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 5: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 6: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 7: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.

Internal Column Balances

Feed tray

F

V

V L

L

Feed Equation:

y = -{(L - L)/(V - V)}x + Fzf/(V-V)

y = -(Lf/Vf)x + (F/Vf)zf

y = {q/(q-1)}x + zf/(1-q)

q = (L-L)/F = (H-hf)/(H-h)

Page 8: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.

Example 19: Find the value of q and draw the feed line for a feedcontaining 0.4 pentane and 0.6 toluene:

(a) the feed is a saturated liquid,(b) the feed contains 0.5 fraction of vapor,(c) the feed was superheated so that each mole of feed vaporizes 10 moles of liquid,(d) the feed was subcooled so that each mole of feed condenses 2 moles of vapor.

Page 9: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 10: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 11: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 12: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.

Example 19: Find the value of q and draw the feed line for a feedcontaining 0.4 pentane and 0.6 toluene:

(a) the feed is a saturated liquid,(b) the feed contains 0.5 fraction of vapor,(c) the feed was superheated so that each mole of feed vaporizes 10 moles of liquid,(d) the feed was subcooled so that each mole of feed condenses 2 moles of vapor.

Page 13: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 14: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 15: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 16: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.

Example 20: The distillation column shown in the figure below was used for the separation of 0.4 mole fraction pentane in toluene. The desired distillate and bottom products are 0.1 and 0.9, respectively. The feed enters the column as a superheated vapor that vaporizes 2 moles of liquid per mole of feed.

QC

QR

F, z, hf

D, xD= 0.9, hD

B, xB= 0.1, hB

Q=0

Reflux ratio = L0/D

Boilup ratio = Vn+1/D

(n)

Reboiler

Condenser

10 Kmole/min,0.4superheated vapor

= 3 Rmin

(a) What is q-value of the feed? Plot the feed line.(b) What is the minimum reflux ratio for the separation?(c) If the column reflux was operated at 3 Rmin, where is the optimum feed-plate location?

(d) What is the boil-up ratio needed for the separation?(e) How many equilibrium stages is needed to accomplish the desired separation?(f) How much distillate and bottom are produced if the feed rate is 10 kmole/min?(g) What is the minimum number of trays needed for achieve the desired separation?

Page 17: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 18: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 19: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 20: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 21: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 22: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 23: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 24: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 25: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 26: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 27: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.

Example 21: The distillation column shown in the figure below was used for the separation of 0.25 mole pentane from heptane. The desired distillate and bottom products are 0.05 and 0.95, respectively. The vapor flowrate in the enriching and stripping sections of the column are 2 D and 3B, respectively.

QC

QR

F, z, hf

D, yD= 0.95, hD

B, xB= 0.05, hB

Q=0

Reflux ratio = L0/D

Boilup ratio = Vn+1/D

(n)

Reboiler

Condenser

1 Kmole/min,0.25

(a) What are the flowrates of distillate and bottom?(b) What is the (L/V)enriching and plot the top operating line?(c) Express the the operation reflux ratio, R as n Rmin

(d) What is the boil-up ratio? Plot the bottom operating line.(e) Is the feed subcooled, saturated liquid, mixture, saturated vapor or superheated vapor? (f) How many equilibrium stages is needed to accomplish the desired separation?(g) Where is the optimum location of the feed plate?

Page 28: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 29: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 30: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 31: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 32: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 33: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 34: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 35: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 36: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.

Example 22: A stripping column shown in the figure below was used to remove oil from contaminated water. The water leaving the bottom must be at least 99.7 % pure. The VLE data is plotted in the figure below.

QR B, xB= 0.003, hB

Q=0

Boilup ratio = Vn+1/D = 4

(n)

Reboiler

F, z, hf

15 Kmole/min,0.10

(a) Derive the top and bottom operating equation for the stripping column.(b) Plot the top and bottom operating line(c) Plot the feed line and determine the q-value of the feed.

(d) What are the allowable feed in a stripping section i.e., subcooled, saturated liquid, mixture, saturated vapor and superheated vapor? and why?(e) Determine the number of stages needed for the separation.(f) What is the minimum reflux ratio for this separation column?

D, yD= 0.6, hD

Page 37: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 38: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 39: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 40: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 41: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 42: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.

Example 23: Crude oil could be extracted from sand found in Canadian province of Saskatchewan. Steam is used in the extraction process and the oil-water mixture is send through a series of distillation column. The final column known as the dehydrating column is employed for removing the final traces of water from the crude to meet the industrial maximum tolerance level of 0.01 mole fraction water. Instead of a condenser saturated liquid water was used directly as coolant. This arrangement has the added benefit of diluting the oil that remains in the water recovered at the distillate. The water from the distillate is then sent to settling tank to remove the final traces of oil before discharge.

QR B, xB= 0.01, hB

Q=0

Boilup ratio = Vn+1/D = 3

(n)

Reboiler

C, xc, hc

(a) Derive the top operating equation for dehydration column.(b) Derive the bottom operating equation(c) Derive the feed equation(d) Plot the respective top and bottom operating line as well as the feedline

(e) Determine the number of stages needed for the separation and the optimumfeed plate location if the total tray efficiency is 0.25.

D, yD= 0.8, hD

F, z, hf

75 Kmole/min,0.20, 25 % vapor

Page 43: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 44: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 45: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 46: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.

Example 24: The distillation column shown in the figure below was used for the separation of 0.5 mole fraction methanol-water solution. The desired distillate and bottom products are 0.10 and 0.95, respectively. The feed enters the column as a superheated vapor that vaporizes 2 moles of liquid per mole of feed.

QC

QR

F, z, hf

D, xD= 0.9, hD

B, xB= 0.1, hB

Q=0

Reflux ratio = L0/D

Boilup ratio = Vn+1/D

(n)

Reboiler

Condenser

10 Kmole/min,0.4superheated vapor

= 2 Rmin

(a) What is q-value of the feed? Plot the feed line.(b) What will happen if the feed condition changes from superheated to sat. vapor to sat. liquid and subcooled liquid.

(c) What is the minimum reflux ratio?(d) What is the minimum number of plates?

Page 47: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 48: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 49: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 50: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.
Page 51: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.

Column Efficiency

Overall Column Efficiency

Eo = Nequil/Nactual

Murphree Efficiency

EMV = actual change in vapor

change in vapor for equilibrium stage

= yj - yj+1

yj* - yj+1

Page 52: Internal Column Balances Feed tray F V V L L Feed Equation: y = -{(L - L)/(V - V)}x + Fz f /(V-V) y = -(L f /V f )x + (F/V f )z f y = {q/(q-1)}x.

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