In the two cases shown below identical ladders are leaning against frictionless walls. In which case...
-
Upload
stephany-kennedy -
Category
Documents
-
view
296 -
download
0
Transcript of In the two cases shown below identical ladders are leaning against frictionless walls. In which case...
In the two cases shown below identical ladders are leaning against frictionless walls. In which case is the force of friction between the ladder and the ground bigger?
A) Case 1 B) Case 2 C) Same
Catching up from Yesterday
Case 1 Case 2Mechanics Lecture 18, Slide 1
In the two cases shown below identical ladders are leaning against frictionless walls. In which case is the force of friction between the ladder and the ground bigger?
A) Case 1 B) Case 2 C) Same
Case 1 Case 2A) Because the bottom of the ladder is further away from the wall.
B) The angle is steeper, which means there is more normal force and thus more friction.
C) Both have same mass.
Mechanics Lecture 18, Slide 2
CheckPoint
CheckPoint
Suppose you hang one end of a beam from the ceiling by a rope and the bottom of the beam rests on a frictionless sheet of ice. The center of mass of the beam is marked with an black spot. Which of the following configurations best represents the equilibrium condition of this setup?
A) B) C)
Mechanics Lecture 18, Slide 3
CheckPointWhich of the following configurations best represents the equilibrium condition of this setup?
A) B) C)
If the tension has any horizontal component, the beam will accelerate in the horizontal direction.
Objects tend to attempt to minimize their potential energy as much as possible. In Case C, the center of mass is lowest.
Mechanics Lecture 18, Slide 4
DemoDemo
footprint
footprint
Stability & Potential Energy
Mechanics Lecture 18, Slide 5
CM DemosCM Demos
Physics 211Lecture 19
Today’s Concepts:Angular Momentum
Mechanics Lecture 19, Slide 6
Linear and Rotation
Mechanics Lecture 19, Slide 7
New Cast of Characters with Old Theme
Remember
Mechanics Lecture 19, Slide 8
Angular Momentum
We have shown that for a system of particles
What is the rotational version of this?
Momentum is conserved ifEXT
dpF
dt
0EXTF
The rotational analogue of force F is torque r F
Define the rotational analogue of momentum p to be Angular Momentum: L r p
For a symmetric solid object L I
Mechanics Lecture 19, Slide 9
Torque & Angular Momentum
where and
Total angular momentum is conserved
EXT
dL
dt
L r p
L I ext EXTr F
In the absence of external torques 0EXT
dL
dt
Mechanics Lecture 19, Slide 10
Example – Disk dropped on Disk
Mechanics Lecture 19, Slide 11
0, initialbottom
oinitialtop ,
ffinalbottomfinaltop ,,
Friction is an “internal force” because it is “internal” to the “system”. Friction is between two parts of the “system”.Friction may change the Kinetic Energy.But friction, being an internal force, does not change the Angular Momentum (nor the linear momentum in linear situations).
DemoDemo
Example – Disk dropped on Disk
02
1 2 oinitial MRL fffinal MRMRL 22
2
1
2
1
fo MRMR 22
2
1 02
1 f
Mechanics Lecture 19, Slide 12
0, initialbottom
oinitialtop ,
ffinalbottomfinaltop ,,
2
2afterafter
LK
I
2
2beforebefore
LK
I same
x2
What about Kinetic Energy?
221
2 2
LK I
I
Mechanics Lecture 19, Slide 13
0, initialbottom
oinitialtop ,
ffinalbottomfinaltop ,,
Case 1 Case 2
A) Case 1B) Case 2C) Same
In both cases shown below a solid disk of mass M, radius R, and initial angular velocity o is dropped onto an initially stationary second disk having the same radius. In Case 2 the mass of the bottom disk is twice as big as in Case 1. If there are no external torques acting on either system, in which case is the final kinetic energy of the system bigger?
Same initial L
CheckPoint
Mechanics Lecture 19, Slide 14
0, initialbottom
oinitialtop ,
M
M
0, initialbottom
oinitialtop ,
2M
M
Case 1 Case 2
A) Case 1B) Case 2C) Same
In which case is the final kinetic energy of the system bigger?
A) L is equal but bigger mass in case 2
B) Case 2 has greater mass
C) Conservation of angular momentum
CheckPoint
2
2
LK
I
Mechanics Lecture 19, Slide 15
M 2MM M
Demo: wheel rim dropDemo: wheel rim drop
Your Comments
Mechanics Lecture 19, Slide 16
This doesn’t mean anything.This doesn’t mean anything.
Sort of . . .Sort of . . .Work is done by friction so KE is Work is done by friction so KE is notnot conserved. conserved.
Okay; now Okay; now whatwhat does that mean? does that mean?
Find the Find the finalfinal KE in both cases. KE in both cases.
True but what about the True but what about the finalfinal KE? KE?
That’s for omega but what about the That’s for omega but what about the finalfinal KE? KE?True but what about the True but what about the finalfinal KE? KE?
True but what about the True but what about the finalfinal KE? KE?? ? ? ? ? ? ? ?
? ? ? ? ? ? ? ?
axis
Point Particle Moving in a Straight Line
L R p
pRL
11
1
)sin( 11 pRpRL
22
2
)sin( 22 pRpD pD pD
3
)sin( 33 pRpRL
33
Mechanics Lecture 19, Slide 17
2R
3R
1R
p
p
p
D
Direction given by right hand rule(out of the page in this case)
L R p
L mvD pD
Mechanics Lecture 19, Slide 18
axis
p
D
Demo: train on bike wheelDemo: train on bike wheel
R
M
mv
Before
Top View
Disk Kid
Playground Example
mvRLBefore )2
1( 22 mRMRILAfter
Before AfterL L mMR
v
21
1
Mechanics Lecture 19, Slide 19
After
Disk Kid
Algebra Details
mvRLBefore
Before AfterL L mMR
v
21
1
Mechanics Lecture 19, Slide 20
)2
1( 22 mRMRILAfter
The magnitude of the angular momentum of a freely rotating disk around its center is L. You toss a heavy block onto the disk along the direction shown. Friction acts between the disk and the block so that eventually the block is at rest on the disk and rotates with it. What is the magnitude of the final angular momentum of the disk-block system:
A) LB) LC) L
Instead of a block, imagine it’s a kid hopping onto a merry go round
CheckPoint
Mechanics Lecture 19, Slide 21
Top View
The block provides no angular momentum since its perpendicular distance from the axis of rotation is 0. No external forces act on this systems, so angular momentum is conserved.
What is the magnitude of the final angular momentum of the disk-block system:
A) LB) LC) L
CheckPoint
Mechanics Lecture 19, Slide 22
Top View
The block provides no angular momentum since its perpendicular distance from the axis of rotation is 0. No external forces act on this systems, so angular momentum is conserved.
Your Comments
Mechanics Lecture 19, Slide 23
Zero!>!>! Zero!>!>! HowHow can that be? can that be?
Will it be conserved in the Will it be conserved in the nextnext CheckPoint? CheckPoint?Good! Altho’ I wouldn’t call it an external force.Good! Altho’ I wouldn’t call it an external force.
Good! The block’s Good! The block’s perpendicularperpendicular distance from the axis of rotation is zero. . distance from the axis of rotation is zero. .
But the block is But the block is NOTNOT at rest. at rest.
What is the final angular momentum?What is the final angular momentum?What does that mean for the final angular momentum?What does that mean for the final angular momentum?
What about the What about the nextnext CheckPoint?CheckPoint?
! ! ! ! !! ! ! ! !
okayokay
Tell me more.Tell me more.
What about the block?What about the block?Tell me more.Tell me more.
Top View
ACT
Mechanics Lecture 19, Slide 24
The magnitude of the angular momentum of a freely rotating disk around its center is L. You toss a heavy block onto the disk along the direction shown. Friction acts between the disk and the block so that eventually the block is at rest on the disk and rotates with it. Is the total angular momentum of the disk-block system conserved during this?
A) Yes
B) No
Friction decreases the angular momentum of the disk
But the TOTAL angular momentum of the block+disk is CONSTANT!
Top View
CheckPoint
Mechanics Lecture 19, Slide 25
The magnitude of the angular momentum of a freely rotating disk around its center is L. You toss a heavy block onto the disk along the direction shown. Friction acts between the disk and the block so that eventually the block is at rest on the disk and rotates with it. What is the magnitude of the final angular momentum of the disk-block system:
Instead of a block, imagine it’s a kid hopping onto a merry go round
A) LB) LC) L
CheckPoint
What is the magnitude of the final angular momentum of the disk-block system:
B) L is conserved so Linitial=Lfinal
A) Since the block has angular momentum to begin with, that is added into L.
C) The block adds momentum going in the opposite direction, so the total momentum is smaller than the momentum of the disk.
A) LB) LC) L
Top View
Mechanics Lecture 19, Slide 26
Your Comments
Mechanics Lecture 19, Slide 27
Tell me more.Tell me more.
Smaller than what? In the previous CheckPoint, the lever arm was Smaller than what? In the previous CheckPoint, the lever arm was zerozero..
Okay but tell me more.Okay but tell me more.Good.Good.
What about the angular momentum of the What about the angular momentum of the blockblock??
No, not this time.No, not this time.
Any better by now?Any better by now?
Why bigger? Angular momentum has a Why bigger? Angular momentum has a directiondirection connected to it. connected to it.
What about the block?What about the block?
What about the block?What about the block?Bravo!Bravo!
Bravo!Bravo!
ACT
A student holding a heavy ball sits on the outer edge a merry go round which is initially rotating counterclockwise. Which way should she throw the ball so that she stops the rotation?
A) To her leftB) To her rightC) Radially outward
top view: initial final
A B
C
Mechanics Lecture 19, Slide 28
ACT
A student is riding on the outside edge of a merry-go-round rotating about a frictionless pivot. She holds a heavy ball at rest in her hand. If she releases the ball, the angular velocity of the merry-go-round will:
A) Increase B) Decrease C) Stay the same
Mechanics Lecture 19, Slide 29
Mechanics Lecture 19, Slide 30
m2
m10
21
1
2diskI m R
Mechanics Lecture 19, Slide 31
odiskinitial IL
m2
m1o
21
1
2diskI m R
Mechanics Lecture 19, Slide 32
2
2
1odiskinitial IK
( )final disk rod fL I I
f
Solve for f
m2
m10
0initial diskL I
22
1
12rodI m Lfinal initialL L
Mechanics Lecture 19, Slide 33
final initialL L
Mechanics Lecture 19, Slide 34
f
M
21( )2final disk rod fK I I
Mechanics Lecture 19, Slide 35
f
M
Just like
for linear momentum
average
PF
t
for angular momentumaverage
L
t
0( )rod rod fL I 0( )rod faverage
I
t
Mechanics Lecture 19, Slide 36
Mechanics Lecture 19, Slide 37
Conservation IdeasConservation Ideas
Internal forces do not change the momentum.Internal forces do not change the momentum.Internal torques do not change the angular Internal torques do not change the angular momentum.momentum.
However, internal forces or internal torques However, internal forces or internal torques can still do work and, thus, can still do work and, thus, change the Kinetic Energy.change the Kinetic Energy.
Heads Up! for next preLectureHeads Up! for next preLecture
Mechanics Lecture 19, Slide 38