Honors Geometry Section 5.2 Use Perpendicular Bisectors.

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Honors Geometry Section 5.2 Use Perpendicular Bisectors

Transcript of Honors Geometry Section 5.2 Use Perpendicular Bisectors.

Page 1: Honors Geometry Section 5.2 Use Perpendicular Bisectors.

Honors Geometry

Section 5.2

Use Perpendicular Bisectors

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Perpendicular Bisector

• A segment, ray, line, or plane that is perpendicular to a segment at its midpoint.

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Equidistant

•A point that is the same distance from each figure.

•Points on the perpendicular bisector of a segment are equidistant from the segment’s endpoints.

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THEOREM 5.2 Perpendicular Bisector Theorem

In a plane, if a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment.

If is the bisector of , then CA = CB.

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THEOREM 5.3 Converse: Perpendicular Bisector Theorem

In a plane, if a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of the segment.

If DA = DB, then D lies on the bisector of .

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EXAMPLE 1 Use the Perpendicular Bisector Theorem

AD = CD Perpendicular Bisector Theorem

3x + 145x =

7x =

BD is the perpendicular bisector of AC . Find AD.

AD = 5x = 5(7) = 35.

ALGEBRA

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EXAMPLE 2 Use perpendicular bisectors

SOLUTION

a. WX bisects YZ , so XY = XZ.

Because W is on the perpendicular bisector of YZ, WY = WZ by Theorem 5.2.

The diagram shows that VY = VZ = 25.

In the diagram, is the perpendicular bisector of

a. What segment lengths in the diagram are equal?

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EXAMPLE 2 Use perpendicular bisectors

b. Is V on WX ?

b. Because VY = VZ, V is equidistant from Y and Z. So, by the Converse of the Perpendicular Bisector Theorem, V is on the perpendicular bisector of YZ , which is WX .

In the diagram, is the perpendicular bisector of

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Concurrent• When three or more lines, rays, or

segments intersect in the same point.

Point of Concurrency• The point of intersection of the lines,

rays, or segments.

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THEOREM 5.4 Concurrency of Perpendicular Bisectors of a Triangle

The perpendicular bisectors of a triangle intersect at a point that is equidistant from the vertices of the triangle.

If are perpendicular bisectors, then PA = PB = PC.

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EXAMPLE 3Use the concurrency of perpendicular bisectors

FROZEN YOGURT

Three snack carts sell frozen yogurt from points A, B, and C outside a city. Each of the three carts is the same distance from the frozen yogurt distributor.

Find a location for the distributor that is equidistant from the three carts.

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EXAMPLE 3Use the concurrency of perpendicular bisectors

Theorem 5.4 shows you that you can find a point equidistant from three points by using the perpendicular bisectors of the triangle formed by those points.

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EXAMPLE 3Use the concurrency of perpendicular bisectors

Copy the positions of points A, B, and C and connect those points to draw ∆ABC. Then use a ruler and protractor to draw the three perpendicular bisectors of ∆ABC. The point of concurrency D is the location of the distributor.

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• The point of concurrency of the three perpendicular bisectors of a triangle.

• The circumcenter P is equidistant from the three vertices, so P is the center of a circle that passes through all three vertices.

Circumcenter

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• The location of P depends on the type of triangle.