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Holt McDougal Algebra 1 Solving Special Systems Solving Systems by Graphing Holt Algebra 1 Unit 2...
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Transcript of Holt McDougal Algebra 1 Solving Special Systems Solving Systems by Graphing Holt Algebra 1 Unit 2...
Holt McDougal Algebra 1
Solving Special SystemsSolving Systems by Graphing
Holt Algebra 1
Unit 2Unit 2
Module 7Module 7
Lesson 1Lesson 1
Holt McDougal Algebra 1
Holt McDougal Algebra 1
Solving Special Systems
MCC9-12.A.REI.6 Solve systems of linear equations exactly and approximately (e.g., with graphs), focusing on pairs of linear equations in two variables.
MCC9-12.A.CED.2 Create equations in two or more variables to represent relationships between quantities; graph equations on coordinate axes with labels and scales.
MCC9-12.A.CED.3 Represent constraints by equations or inequalities, and by systems of equations and/or inequalities, and interpret solutions as viable or nonviable options in a modeling context.
Standards
Holt McDougal Algebra 1
Solving Special Systems
Solve special systems of linear equations in two variables.
Classify systems of linear equations and determine the number of solutions.
Objectives
Holt McDougal Algebra 1
Solving Special Systems
inconsistent systemconsistent systemindependent systemdependent system
Vocabulary
Holt McDougal Algebra 1
Solving Special Systems
In Lesson 6-1, you saw that when two lines intersect at a point, there is exactly one solution to the system. Systems with at least one solution are called consistent.
When the two lines in a system do not intersect they are parallel lines. There are no ordered pairs that satisfy both equations, so there is no solution. A system that has no solution is an inconsistent system. (SAME SLOPE, DIFFERENT Y-INTERCEPT)
Holt McDougal Algebra 1
Solving Special Systems
Example 1: Systems with No Solution
Method 1 Compare slopes and y-intercepts.
Show that has no solution.y = x – 4
–x + y = 3
Holt McDougal Algebra 1
Solving Special Systems
Example 1 Continued
Method 2 Solve the system algebraically. Use the substitution method because the first equation is solved for y.
Show that has no solution.y = x – 4
–x + y = 3
Holt McDougal Algebra 1
Solving Special Systems
Check It Out! Example 1
Method 1 Compare slopes and y-intercepts.
Show that has no solution.y = –2x + 5
2x + y = 1
Method 2 Solve the system algebraically. Use the substitution method because the first equation is solved for y.
Holt McDougal Algebra 1
Solving Special Systems
Show that has infinitely many solutions.
y = 3x + 2
3x – y + 2= 0
Example 2A: Systems with Infinitely Many Solutions
Method 1 Compare slopes and y-intercepts.
Holt McDougal Algebra 1
Solving Special Systems
Method 2 Solve the system algebraically. Use the elimination method.
Example 2A Continued
Show that has infinitely many solutions.
y = 3x + 2
3x – y + 2= 0
Holt McDougal Algebra 1
Solving Special Systems
Check It Out! Example 2
Show that has infinitely many solutions.
y = x – 3
x – y – 3 = 0
Method 1 Compare slopes and y-intercepts.
Method 2 Solve the system algebraically. Use the elimination method.
Holt McDougal Algebra 1
Solving Special Systems
Consistent systems can either be independent or dependent.
An independent system has exactly one solution. The graph of an independent system consists of two intersecting lines.(DIFFERENT SLOPE)A dependent system has infinitely many solutions. The graph of a dependent system consists of two coincident lines.(SAME SLOPE, SAME Y-INTERCEPT)
Holt McDougal Algebra 1
Solving Special Systems
Holt McDougal Algebra 1
Solving Special Systems
Example 3A: Classifying Systems of Linear Equations
Solve3y = x + 3
x + y = 1
Classify the system. Give the number of solutions.
Holt McDougal Algebra 1
Solving Special Systems
Example 3B: Classifying Systems of Linear equations
Solvex + y = 5
4 + y = –x
Classify the system. Give the number of solutions.
Holt McDougal Algebra 1
Solving Special Systems
Example 3C: Classifying Systems of Linear equations
Classify the system. Give the number of solutions.
Solvey = 4(x + 1)
y – 3 = x
Holt McDougal Algebra 1
Solving Special Systems
Check It Out! Example 3a
Classify the system. Give the number of solutions.
Solvex + 2y = –4
–2(y + 2) = x
Holt McDougal Algebra 1
Solving Special Systems
Check It Out! Example 3b
Classify the system. Give the number of solutions.
Solvey = –2(x – 1)
y = –x + 3
Write both equations in slope-intercept form.
The lines have different slopes. They intersect.
Holt McDougal Algebra 1
Solving Special Systems
Check It Out! Example 3c
Classify the system. Give the number of solutions.
Solve2x – 3y = 6
y = x
Holt McDougal Algebra 1
Solving Special Systems
Example 4: Application
Jared and David both started a savings account in January. If the pattern of savings in the table continues, when will the amount in Jared’s account equal the amount in David’s account?
Use the table to write a system of linear equations. Let y represent the savings total and x represent the number of months.
Holt McDougal Algebra 1
Solving Special Systems
Matt has $100 in a checking account and deposits $20 per month. Ben has $80 in a checking account and deposits $30 per month. Will the accounts ever have the same balance? Explain.
Check It Out! Example 4
Holt McDougal Algebra 1
Solving Special SystemsHomework
Pg. 161-163
12-30, 34