Hardy-Weinberg Equilibrium
date post
19-Feb-2016Category
Documents
view
30download
1
Embed Size (px)
description
Transcript of Hardy-Weinberg Equilibrium
Hardy-Weinberg Equilibrium
Hardy-Weinberg Equilibrium
What Darwin didnt Get Darwin couldnt figure out why there was so much GENETIC VARIATION in natural populations.
Darwin thought that selection should ALWAYS favor the optimal form and eliminate vaiation hmmm. But.
The reality is, there is A LOT of variation in populationsSo how could this be?Hardy and Weinberg (1908) Independently solved WHY this genetic variation exists
Hardy was a mathematician
Weinberg was a physician
They showed that the frequency of genotypes in a population will stay the same from one generation to the next.
That is if : SEVEN conditions are met
We call this HARDY-WEINBERG EQUILIBRIUMTHE BIG SEVENMutation is not occurring
Natural selection is not occurring
The population is very large
All members of a population breed
All mating is totally random
Everyone produces the same number of offspring
There is no immigration or emigration happening in the populationOk, so how realistic is this???Not very, but we can use an equation as a model for population geneticsFirst you need to know that:
ALLELES represent GENES
Individuals receive one allele from each parent
This makes up an individuals genes
The genes determine the phenotype
Therefore an individual will receive a combination of alleles in the form of :
Dominant Dominant
Recessive Recessive
Dominant Recessive
The alleles are represented as letters
Capital letter = DominantLowercase Letter = Recessive
AAaaAa
AA is called: HOMOZYGOUS DOMINANT
Aa is called: HETEROZYGOUS DOMINANT
aa is called: HOMOZYGOUS RECESSIVE
The HARDY- WEINBERG Equation (s)
p + q = 1 p2 + 2pq + q2 = 1
BREATH DEEP.here we goThese equations figure out:
ALLELE FREQUENCY
GENOTYPE FREQUENCY
AA + Aa + aa = 1p2 + 2pq + q2 = 1
Formula for GENOTYPE Frequency
A + a = 1 p + q = 1
Formula for ALLELE frequency
Now that we know what each formula represents, figuring out each problem is easy!!!!!!You will ALWAYS be givenThat the characteristic is either DOMINANT or RECESSIVE
Example: the problem will tell you that
RED = RWHITE = rTHEN you will be GIVENA VALUE of one of these:
A a AA aa
And you already know that:
A = p a = q AA = p2 Aa = 2pq aa = q2
NOW all you have to do is..Plug the values in!!!
But its kind of like a maze
Sooooooooo STEP 1: write out both formulas
AA + Aa + aa = 1p2 + 2pq + q2 = 1
AND
A + a = 1 p + q = 1
Step 2: Figure out what youve been given and plug it in
Example: if you are given the value of aa as 50% or .5o
Plug .50 into the q2 spot
AA + Aa + aa = 1p2 + 2pq + q2 = 1p2 + 2pq + .50 = 1
Now you can figure out q
.50=.71A + a = 1p+ q = 1
P + .71 = 1.29 + .71 = 1
AA + Aa + aa = 1p2 + 2pq + q2 = 1
.084 + 2 (.29)(.71) + .50 = 1.084 + .41 + .50 = 1
Lets look at a problemThe gene for an intelligent dolphin is dominant to a gene for an aggressive dolphin. In a population there are 25% that have the gene for homozygous recessive aggressiveness. Figure out the gene frequency for the heterozygous intelligent. OK, so we know that:
Were looking or GENE FREQUENCY
Intelligent = A
Aggressive = a
Homozygous recessive = aa = 25% = .25
Heterozygous = Aa