hanin bzizi 1234.docx

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The states with the largest pay gaps Between men & women Description Summary Based on data from the U.S. Census Bureau’s 2012 American Community Survey, shows the gap between the 2012 median earnings for a year-round full-time male worker and a similar female worker, as a percentage of the median female’s earnings. . The given data are as follows: name of states, how much men women get paid in each of the states, the difference between the payments, and the different between the payments in %. Problem Statement Table 1 shows the given data for this problem.

Transcript of hanin bzizi 1234.docx

The states with the largest pay gaps Between men & womenDescription SummaryBased on data from the U.S. Census Bureaus 2012 American Community Survey, shows the gap between the 2012 median earnings for a year-round full-time male worker and a similar female worker, as a percentage of the median females earnings. . The given data are as follows: name of states, how much men women get paid in each of the states, the difference between the payments, and the different between the payments in %.Problem StatementTable 1 shows the given data for this problem.

Table 1: date

The desired results are as follows from chapter 1 to chapter 2: The nature of date Summarizing date with frequency tables & graphs probability Binomial probability distributionChapter one:As shown in Table 1, in statistics we use the terms population USA.A census is the collection of date from every state in the USA.A parameter is numerical measurement. A quantitative and qualitative date: income of both Female &Male A continuous data: number of male or female in every state in USA.

Chapter two:I have worked with date sets that I have organized and summarized the date by constructing a frequency table. Table (2) shows frequency table of women who got paid in 2012.WomensFrequencyCumulative freq.Relative freq.

30,287-34,365212121/335 = 6%

34,366-38,444133434/335 = 10%

38,445-42,52394343/335 = 12%

42,524-46,60214444/335 = 13%

46,603-50,68144848/335 = 14%

50,682-54,76004848/335 = 14%

54,761-58,83904848/335 = 14%

58,840-62,91814933549/335 = 14%

Table (2) shows frequency table of womenClass midpoint: 1. 32,3262. 36,4053. 40,4844. 44,5635. 48,6426. 52,7217. 56,8008. 60,879 Class boundary: 30,286.5 34,365.5 38,444.5 42,523.5 46,602.5 50,681.5 54,760.5 58,839.5 62,918.5 I have drawing the graph by using MICROSOFT EXCEL.1. Entering the date.2. for the x-axis: classes using class midpoint.3 . The y-axis: frequency going to the highest frequency value.4. Go to the insert and choose the kind of polygon from the insert chart

Graph (1) Table (3) shows frequency table of women who got paid in 2012.MensFrequencyCumulative freq.Relative freq.

40,081-44,159191919/290 = 6%

44,160-48,238123131/290 = 10%

48,239-52,317124343/290 = 14%

52,318-56,39634646/290 = 15%

56,397-60,47524848/290 = 16%

60,476-64,554 35151/290 = 17%

64,555-68,63315229052/290 = 17%

Class midpoint:1.42,1202.46,1993.50,2784.54,3575.58,4366.62,5157.66,594Class boundary: 40,080.5 44,159.5 48,238.5 56,396.5 60,475.5 64,554.5 68,633.5 Draw a frequency polygon by using the mens frequency tale from above graph (2):

Graph (2) Draw a pie chart by using the mens frequency table from seeing graph 3: Drawing the pie chart by using the MICROSOFT EXCEL Enter the data: label using categories of data with their respective percentages Go to insert and choose what kind of pie chart you want from the insert chart

Graph (3)

Chapter 3From the table 1 show how many men and women in every state get paid there is 51 men and woman. The potential consists that there is 6 men and 6 women that get paid 41 thousand dollars. If two of those people were selected, find the probability that the first one is a man and the second one is a man. If the two people are selected (A) with replacement; (B) without replacement.With replacementP (first one is a man and the second one is a man) = 0.083Without replacementP (first one is a man and the second one is a man) = = 0.227

Chapter 4I have worked in chapter 4 to describes the probability for the number of women in table (3) two coulmes at left describe the probability .i have create three column to Calculating , 2, and for a probability distributionxp(x)x.p(x)x2x2*p(x)

00.372549000

10.2352940.23529410.235294

20.2156860.43137240.862744

30.0588240.17647290.529416

40.0392160.156864160.627456

50.088240.4412252.206

60.0196080.117648360.705888

Using the range rule of thumb, we can now find the maximum and minimum usual value as follows:

*To solve this problem we used MICROSOFT EXCEL*