Growth of a Green Bean

34
Green bean project Jason Koh MHF4U

Transcript of Growth of a Green Bean

Page 1: Growth of a Green Bean

Green bean projectJason KohMHF4U

Page 2: Growth of a Green Bean

Under direct sun(table)

Days Height

1 0

2 2.8

3 6

4 9

5 11

6 13.6

7 15

8 16.8

9 17.6

10 18.4

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Scatter plot

Page 4: Growth of a Green Bean

Linear

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Quadratic

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Cubic

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Quartic

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Quintic

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Exponential

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Logarithmic

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Best fit function Model R2

Linear 0.9592

Quadratic 0.9982

Cubic 0.9992

Quartic 0.9992

Quintic 0.9993

Exponential 0.6341

Logarithmic 0.9687

The model that best fits Quintic regression

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Graph for best fit

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Properties of regression y = -0.0006x5 + 0.0169x4 - 0.1926x3 + 0.859x2 + 1.4509x - 2.16 R² = 0.9993

Domain: {XER|X≥0} Range: {YER|Y≥0} X-intercept: Y-intercept: -2.16

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3 sets of Intervals   2.

==2

3.

=0.8

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Centered interval y = -0.0006x5 + 0.0169x4 - 0.1926x3 +

0.859x2 + 1.4509x - 2.16 X=5 4≤x≤6

X=48.7732

X=613.1046

1. ==2.1657

The instantaneous rate of change is 2.1657

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Verifying the degree of the function

Days Height

1 0

2 2.8

3 6

4 9

5 11

6 13.6

7 15

8 16.8

9 17.6

10 18.4

2.8

3.2

3

2

2.6

1.4

1.8

0.8

0.8

1

0.2

-1

0.6

-1.2

0.4

-1

0

-0.8

-1.2

1.6

-1.8

1.6

0.6

1

-0.4

2.8

-3.4

3.4

-1

0.4

3.2

-6.2

6.8

-2.4

1.4

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Prediction f(11)= 12.191f(12)= 7.2732f(13)= -1.364f(15)= -37.21f(20)= -386.3

The prediction is wrong because there is no such way that a plant can grow shorter as day passes.

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No direct sunlight(table)days height

1 0

2 0.2

3 0.5

4 2

5 4.5

6 9.3

7 10.2

8 12

9 13.6

10 15.8

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Scatter plot

Page 20: Growth of a Green Bean

Linear

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Quadratic

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Cubic

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Quartic

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Quintic

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Exponential

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Logarithmic

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Best fit function Model R2

Linear 0.9577

Quadratic 0.9652

Cubic 0.9853

Quartic 0.9883

Quintic 0.9938

Exponential 0.8824

Logarithmic 0.793

The model that best fits is Quintic regression

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Graph for best fit

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Properties of regression y = 0.0048x5 - 0.1252x4 + 1.1201x3 -

3.8987x2 + 5.6573x - 2.62 Domain: Range: X-intercept: Y-intercept:

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3 sets of intervals 

==1.5

==0.9

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Centered interval y = 0.0048x5 - 0.1252x4 + 1.1201x3 -

3.8987x2 + 5.6573x - 2.62 X=5 4≤x≤6

X=4-43.078

X=6-59.9098

== -8.4159

The instantaneous rate of change is -8.4159

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Verifying the degree of the function Days Heig

ht

1 0.1

2 0.3

3 0.6

4 2.1

5 4.6

6 9.4

7 10.3

8 12.1

9 13.7

10 15.9

0.2

0.3

1.5

2.5

4.8

0.9

1.8

1.6

2.2

0.1

1.2

1

2.3

-3.9

0.9

-0.2

0.6

1.1

-0.2

1.3

-6.2

4.8

-1.1

0.8

-1.3

1.5

-7.5

11

-5.9

1.9

2.8

-9

18.5

-16.9

-4

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Prediction f(11)= 18.712f(12)= 37.634f(13)= 79.374f(15)= 292.12f(20)= 2839.8

The prediction is unacceptable in real life situation because green beans cannot grow that much in just 20 days.

Page 34: Growth of a Green Bean

Conclusion Based on the analysis, the quartic regression is the best fit for the growth of the green bean with or without direct sunlight.