Grade 11 elasticity
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Transcript of Grade 11 elasticity
ELASTICITYPhysics Grade XI2016
Aim of this lessonExplain the effect of the force to the elasticity character and vibration
Sub Chaptera. Elasticityb. Simple Harmonic Motion
Elasticity• the ability of an object or material to resume its normal
shape after being stretched or compressed
Inelasticity ?
Stress, Strain and Modulus of Elasticity
Stress• Stress is "force per unit area" - the ratio of applied force F
to cross section area - defined as "force per area".
• tensile stress - stress that tends to stretch or lengthen the material - acts normal to the stressed area
• compressive stress - stress that tends to compress or shorten the material - acts normal to the stressed area
• shearing stress - stress that tends to shear the material - acts in plane to the stressed area at right-angles to compressive or tensile stress
• Tensile or compressive stress normal to the plane is usually denoted "normal stress" or "direct stress" and can be expressed as
• σ = Fn / A (1)• where• σ = normal stress ((Pa) N/m2)• Fn = normal component force (N)• A = area (m2)
Example• A force of 10 kN is acting on a circular rod with diameter
10 mm. The stress in the rod can be calculated as• σ = (10 x103 N) / (π ((10 x10-3 m) / 2)2)• = 127388535 (N/m2) • = 127 (MPa)
Strain• Strain is defined as "deformation of a solid due to stress"
and can be expressed as
whereΔL = change of length (m)L = initial length (m)ε = strain - unitless
Cyberphysics.co.uk
Modulus of ElasticityE = Young's modulus (Modulus of Elasticity) (N/m2 (Pa)
Young's modulus can be used to predict the elongation or compression of an object.
• Elasticity Constant
Hooke’s LawHooke's law is a principle of physics that states that the force F needed to extend or compress a spring by some distance X is proportional to that distance.
where k is a constant factor characteristic of the spring X is small compared to the total possible deformation of the spring.
Example
Calculate the value of spring constant !
F = k Δx40 N = k (0.08 m)K = 500 N/m
SWTextbook “Exercise”Page 96Page 98Page 100
Simple Harmonic Motion
𝒂=𝒌𝑨𝒎 𝐜𝐨𝐬 (𝝎𝒕+𝜽𝟎)
𝑇=2𝜋 √ 𝑙𝑔
Hooke’s Law for the composition
Series
Parallel
Give us SW please....