GMAT Diagnostic Test Q2 - Problem Solving - Number Properties : Indices

48
GMAT QUANTITATIVE REASONING NUMBER PROPERTIES: INDICES PROBLEM SOLVING Diagnostic Test

Transcript of GMAT Diagnostic Test Q2 - Problem Solving - Number Properties : Indices

GMAT QUANTITATIVE REASONING

NUMBER PROPERTIES:

INDICES

PROBLEM SOLVING

Diagnostic Test

Question

For integer n > 1, which of the following expressions will have

the least value?

A.1

5

𝑛

B. 2-n

C. 10-2n

D. 4𝑛

2

E. (0.05)-n

Part 1

Theory Recap : Important Rules relating

to indices

Indices Rules

Rule Example

Indices Rules

π‘Žπ‘₯ Γ— π‘Žπ‘¦ = π‘Žπ‘₯+𝑦

Rule Example

Indices Rules

π‘Žπ‘₯ Γ— π‘Žπ‘¦ = π‘Žπ‘₯+𝑦 102 Γ— 103 = 105

Rule Example

Indices Rules

π‘Žπ‘₯ Γ— π‘Žπ‘¦ = π‘Žπ‘₯+𝑦 102 Γ— 103 = 105

Rule Example

π‘Žπ‘₯ 𝑦 = π‘Žπ‘₯𝑦

Indices Rules

π‘Žπ‘₯ Γ— π‘Žπ‘¦ = π‘Žπ‘₯+𝑦 102 Γ— 103 = 105

Rule Example

π‘Žπ‘₯ 𝑦 = π‘Žπ‘₯𝑦 102 3 = 106

Indices Rules

π‘Žπ‘₯ Γ— π‘Žπ‘¦ = π‘Žπ‘₯+𝑦 102 Γ— 103 = 105

Rule Example

π‘Žπ‘₯ 𝑦 = π‘Žπ‘₯𝑦 102 3 = 106

π‘Žπ‘₯

π‘Žπ‘¦= π‘Žπ‘₯βˆ’π‘¦

Indices Rules

π‘Žπ‘₯ Γ— π‘Žπ‘¦ = π‘Žπ‘₯+𝑦 102 Γ— 103 = 105

Rule Example

π‘Žπ‘₯ 𝑦 = π‘Žπ‘₯𝑦 102 3 = 106

π‘Žπ‘₯

π‘Žπ‘¦= π‘Žπ‘₯βˆ’π‘¦

105

103= 102

Indices Rules

π‘Žπ‘₯ Γ— π‘Žπ‘¦ = π‘Žπ‘₯+𝑦 102 Γ— 103 = 105

Rule Example

π‘Žπ‘₯ 𝑦 = π‘Žπ‘₯𝑦 102 3 = 106

π‘Žπ‘₯

π‘Žπ‘¦= π‘Žπ‘₯βˆ’π‘¦

105

103= 102

π‘Žπ‘₯1𝑦 = π‘Ž

π‘₯𝑦 =

π‘¦π‘Žπ‘₯

Indices Rules

π‘Žπ‘₯ Γ— π‘Žπ‘¦ = π‘Žπ‘₯+𝑦 102 Γ— 103 = 105

Rule Example

π‘Žπ‘₯ 𝑦 = π‘Žπ‘₯𝑦 102 3 = 106

π‘Žπ‘₯

π‘Žπ‘¦= π‘Žπ‘₯βˆ’π‘¦

105

103= 102

π‘Žπ‘₯1𝑦 = π‘Ž

π‘₯𝑦 =

π‘¦π‘Žπ‘₯ 106

13 = 10

63 = 102

Indices Rules

π‘Žπ‘₯ Γ— π‘Žπ‘¦ = π‘Žπ‘₯+𝑦 102 Γ— 103 = 105

Rule Example

π‘Žπ‘₯ 𝑦 = π‘Žπ‘₯𝑦 102 3 = 106

π‘Žπ‘₯

π‘Žπ‘¦= π‘Žπ‘₯βˆ’π‘¦

105

103= 102

π‘Žπ‘₯1𝑦 = π‘Ž

π‘₯𝑦 =

π‘¦π‘Žπ‘₯ 106

13 = 10

63 = 102

10613 =

3106 = 102

4th rule can also be

expressed as

Indices Rules

π‘Žπ‘₯ Γ— π‘Žπ‘¦ = π‘Žπ‘₯+𝑦 102 Γ— 103 = 105

Rule Example

π‘Žπ‘₯ 𝑦 = π‘Žπ‘₯𝑦 102 3 = 106

π‘Žπ‘₯

π‘Žπ‘¦= π‘Žπ‘₯βˆ’π‘¦

105

103= 102

π‘Žπ‘₯1𝑦 = π‘Ž

π‘₯𝑦 =

π‘¦π‘Žπ‘₯

Rule Example

10613 = 10

63 = 102

10613 =

3106 = 102

4th rule can also be

expressed as

Indices Rules

π‘Žπ‘₯ Γ— π‘Žπ‘¦ = π‘Žπ‘₯+𝑦 102 Γ— 103 = 105

Rule Example

π‘Žπ‘₯ 𝑦 = π‘Žπ‘₯𝑦 102 3 = 106

π‘Žπ‘₯

π‘Žπ‘¦= π‘Žπ‘₯βˆ’π‘¦

105

103= 102

π‘Žπ‘₯1𝑦 = π‘Ž

π‘₯𝑦 =

π‘¦π‘Žπ‘₯

Rule Example

10613 = 10

63 = 102

π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯

10613 =

3106 = 102

4th rule can also be

expressed as

Indices Rules

π‘Žπ‘₯ Γ— π‘Žπ‘¦ = π‘Žπ‘₯+𝑦 102 Γ— 103 = 105

Rule Example

π‘Žπ‘₯ 𝑦 = π‘Žπ‘₯𝑦 102 3 = 106

π‘Žπ‘₯

π‘Žπ‘¦= π‘Žπ‘₯βˆ’π‘¦

105

103= 102

π‘Žπ‘₯1𝑦 = π‘Ž

π‘₯𝑦 =

π‘¦π‘Žπ‘₯

Rule Example

10613 = 10

63 = 102

π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯2βˆ’3 =

1

23

10613 =

3106 = 102

4th rule can also be

expressed as

Indices Rules

π‘Žπ‘₯ Γ— π‘Žπ‘¦ = π‘Žπ‘₯+𝑦 102 Γ— 103 = 105

Rule Example

π‘Žπ‘₯ 𝑦 = π‘Žπ‘₯𝑦 102 3 = 106

π‘Žπ‘₯

π‘Žπ‘¦= π‘Žπ‘₯βˆ’π‘¦

105

103= 102

π‘Žπ‘₯1𝑦 = π‘Ž

π‘₯𝑦 =

π‘¦π‘Žπ‘₯

Rule Example

10613 = 10

63 = 102

π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯2βˆ’3 =

1

23

π‘Žπ‘₯ Γ— 𝑏π‘₯ = π‘Žπ‘ π‘₯

10613 =

3106 = 102

4th rule can also be

expressed as

Indices Rules

π‘Žπ‘₯ Γ— π‘Žπ‘¦ = π‘Žπ‘₯+𝑦 102 Γ— 103 = 105

Rule Example

π‘Žπ‘₯ 𝑦 = π‘Žπ‘₯𝑦 102 3 = 106

π‘Žπ‘₯

π‘Žπ‘¦= π‘Žπ‘₯βˆ’π‘¦

105

103= 102

π‘Žπ‘₯1𝑦 = π‘Ž

π‘₯𝑦 =

π‘¦π‘Žπ‘₯

Rule Example

10613 = 10

63 = 102

π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯2βˆ’3 =

1

23

π‘Žπ‘₯ Γ— 𝑏π‘₯ = π‘Žπ‘ π‘₯ 23 Γ— 33 = 63

10613 =

3106 = 102

4th rule can also be

expressed as

Part 2

Apply the Rules to solve the question

Which will have the least value?A.

1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

Which will have the least value?A.

1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

All of the answer choices have an β€˜n’ term in their index.

Which will have the least value?

Step 1: To make comparison meaningful rewrite all expressions to have the same power

A.1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

All of the answer choices have an β€˜n’ term in their index.

Which will have the least value?

Step 1: To make comparison meaningful rewrite all expressions to have the same power

A.1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

All of the answer choices have an β€˜n’ term in their index.

1

5

𝑛A.

Which will have the least value?

Step 1: To make comparison meaningful rewrite all expressions to have the same power

A.1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

All of the answer choices have an β€˜n’ term in their index.

1

5

𝑛The power is β€˜n’. So, nothing needs to be doneA.

Which will have the least value?

Step 1: To make comparison meaningful rewrite all expressions to have the same power

A.1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

All of the answer choices have an β€˜n’ term in their index.

1

5

𝑛The power is β€˜n’. So, nothing needs to be done

B. 2-n

A.

Which will have the least value?

Step 1: To make comparison meaningful rewrite all expressions to have the same power

A.1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

All of the answer choices have an β€˜n’ term in their index.

1

5

𝑛The power is β€˜n’. So, nothing needs to be done

B. 2-n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯.

A.

Which will have the least value?

Step 1: To make comparison meaningful rewrite all expressions to have the same power

A.1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

All of the answer choices have an β€˜n’ term in their index.

1

5

𝑛The power is β€˜n’. So, nothing needs to be done

B. 2-n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯. So, 2βˆ’π‘› =

1

2𝑛=

1

2

𝑛

A.

Which will have the least value?

Step 1: To make comparison meaningful rewrite all expressions to have the same power

A.1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

All of the answer choices have an β€˜n’ term in their index.

1

5

𝑛The power is β€˜n’. So, nothing needs to be done

B. 2-n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯. So, 2βˆ’π‘› =

1

2𝑛=

1

2

𝑛

C. 10-2n

A.

Which will have the least value?

Step 1: To make comparison meaningful rewrite all expressions to have the same power

A.1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

All of the answer choices have an β€˜n’ term in their index.

1

5

𝑛The power is β€˜n’. So, nothing needs to be done

B. 2-n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯. So, 2βˆ’π‘› =

1

2𝑛=

1

2

𝑛

C. 10-2n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯.

A.

Which will have the least value?

Step 1: To make comparison meaningful rewrite all expressions to have the same power

A.1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

All of the answer choices have an β€˜n’ term in their index.

1

5

𝑛The power is β€˜n’. So, nothing needs to be done

B. 2-n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯. So, 2βˆ’π‘› =

1

2𝑛=

1

2

𝑛

C. 10-2n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯. So, 10βˆ’2𝑛 =

1

102𝑛=

1

102

𝑛.

A.

Which will have the least value?

Step 1: To make comparison meaningful rewrite all expressions to have the same power

A.1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

All of the answer choices have an β€˜n’ term in their index.

1

5

𝑛The power is β€˜n’. So, nothing needs to be done

B. 2-n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯. So, 2βˆ’π‘› =

1

2𝑛=

1

2

𝑛

C. 10-2n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯. So, 10βˆ’2𝑛 =

1

102𝑛=

1

102

𝑛. Which is

1

100

𝑛

A.

Which will have the least value?

Step 1: To make comparison meaningful rewrite all expressions to have the same power

A.1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

All of the answer choices have an β€˜n’ term in their index.

1

5

𝑛The power is β€˜n’. So, nothing needs to be done

B. 2-n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯. So, 2βˆ’π‘› =

1

2𝑛=

1

2

𝑛

C. 10-2n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯. So, 10βˆ’2𝑛 =

1

102𝑛=

1

102

𝑛. Which is

1

100

𝑛

A.

D. 4𝑛

2

Which will have the least value?

Step 1: To make comparison meaningful rewrite all expressions to have the same power

A.1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

All of the answer choices have an β€˜n’ term in their index.

1

5

𝑛The power is β€˜n’. So, nothing needs to be done

B. 2-n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯. So, 2βˆ’π‘› =

1

2𝑛=

1

2

𝑛

C. 10-2n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯. So, 10βˆ’2𝑛 =

1

102𝑛=

1

102

𝑛. Which is

1

100

𝑛

A.

D. 4𝑛

2 Rule: π‘Žπ‘₯1

𝑦 = π‘Žπ‘₯

𝑦 =π‘¦π‘Žπ‘₯.

Which will have the least value?

Step 1: To make comparison meaningful rewrite all expressions to have the same power

A.1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

All of the answer choices have an β€˜n’ term in their index.

1

5

𝑛The power is β€˜n’. So, nothing needs to be done

B. 2-n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯. So, 2βˆ’π‘› =

1

2𝑛=

1

2

𝑛

C. 10-2n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯. So, 10βˆ’2𝑛 =

1

102𝑛=

1

102

𝑛. Which is

1

100

𝑛

A.

D. 4𝑛

2 Rule: π‘Žπ‘₯1

𝑦 = π‘Žπ‘₯

𝑦 =π‘¦π‘Žπ‘₯. So, 4

𝑛

2 =24

𝑛= 2𝑛

Which will have the least value?

Step 1: To make comparison meaningful rewrite all expressions to have the same power

A.1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

All of the answer choices have an β€˜n’ term in their index.

1

5

𝑛The power is β€˜n’. So, nothing needs to be done

B. 2-n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯. So, 2βˆ’π‘› =

1

2𝑛=

1

2

𝑛

C. 10-2n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯. So, 10βˆ’2𝑛 =

1

102𝑛=

1

102

𝑛. Which is

1

100

𝑛

A.

D. 4𝑛

2 Rule: π‘Žπ‘₯1

𝑦 = π‘Žπ‘₯

𝑦 =π‘¦π‘Žπ‘₯. So, 4

𝑛

2 =24

𝑛= 2𝑛

E. (0.05)-n

Which will have the least value?

Step 1: To make comparison meaningful rewrite all expressions to have the same power

A.1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

All of the answer choices have an β€˜n’ term in their index.

1

5

𝑛The power is β€˜n’. So, nothing needs to be done

B. 2-n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯. So, 2βˆ’π‘› =

1

2𝑛=

1

2

𝑛

C. 10-2n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯. So, 10βˆ’2𝑛 =

1

102𝑛=

1

102

𝑛. Which is

1

100

𝑛

A.

D. 4𝑛

2 Rule: π‘Žπ‘₯1

𝑦 = π‘Žπ‘₯

𝑦 =π‘¦π‘Žπ‘₯. So, 4

𝑛

2 =24

𝑛= 2𝑛

E. (0.05)-n = 5

100

βˆ’π‘›

Which will have the least value?

Step 1: To make comparison meaningful rewrite all expressions to have the same power

A.1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

All of the answer choices have an β€˜n’ term in their index.

1

5

𝑛The power is β€˜n’. So, nothing needs to be done

B. 2-n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯. So, 2βˆ’π‘› =

1

2𝑛=

1

2

𝑛

C. 10-2n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯. So, 10βˆ’2𝑛 =

1

102𝑛=

1

102

𝑛. Which is

1

100

𝑛

A.

D. 4𝑛

2 Rule: π‘Žπ‘₯1

𝑦 = π‘Žπ‘₯

𝑦 =π‘¦π‘Žπ‘₯. So, 4

𝑛

2 =24

𝑛= 2𝑛

E. (0.05)-n = 5

100

βˆ’π‘›=

1

20

βˆ’π‘›.

Which will have the least value?

Step 1: To make comparison meaningful rewrite all expressions to have the same power

A.1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

All of the answer choices have an β€˜n’ term in their index.

1

5

𝑛The power is β€˜n’. So, nothing needs to be done

B. 2-n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯. So, 2βˆ’π‘› =

1

2𝑛=

1

2

𝑛

C. 10-2n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯. So, 10βˆ’2𝑛 =

1

102𝑛=

1

102

𝑛. Which is

1

100

𝑛

A.

D. 4𝑛

2 Rule: π‘Žπ‘₯1

𝑦 = π‘Žπ‘₯

𝑦 =π‘¦π‘Žπ‘₯. So, 4

𝑛

2 =24

𝑛= 2𝑛

E. (0.05)-n = 5

100

βˆ’π‘›=

1

20

βˆ’π‘›. Rule: π‘Žβˆ’π‘₯ =

1

π‘Žπ‘₯.

Which will have the least value?

Step 1: To make comparison meaningful rewrite all expressions to have the same power

A.1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

All of the answer choices have an β€˜n’ term in their index.

1

5

𝑛The power is β€˜n’. So, nothing needs to be done

B. 2-n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯. So, 2βˆ’π‘› =

1

2𝑛=

1

2

𝑛

C. 10-2n Rule: π‘Žβˆ’π‘₯ =1

π‘Žπ‘₯. So, 10βˆ’2𝑛 =

1

102𝑛=

1

102

𝑛. Which is

1

100

𝑛

A.

D. 4𝑛

2 Rule: π‘Žπ‘₯1

𝑦 = π‘Žπ‘₯

𝑦 =π‘¦π‘Žπ‘₯. So, 4

𝑛

2 =24

𝑛= 2𝑛

E. (0.05)-n = 5

100

βˆ’π‘›=

1

20

βˆ’π‘›. Rule: π‘Žβˆ’π‘₯ =

1

π‘Žπ‘₯. So,

1

20

βˆ’π‘›= 20n

Which will have the least value?A.

1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

Step 2: Now that we have expressed all choices to power β€˜n’, just compare the bases

Which will have the least value?A.

1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

Step 2: Now that we have expressed all choices to power β€˜n’, just compare the bases

Which will have the least value?A.

1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

Listing down only the bases for all 5 choices

Step 2: Now that we have expressed all choices to power β€˜n’, just compare the bases

Which will have the least value?A.

1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

Listing down only the bases for all 5 choices

A.1

5B.

1

2C.

1

100D. 2 E. 20

Step 2: Now that we have expressed all choices to power β€˜n’, just compare the bases

Which will have the least value?A.

1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

Listing down only the bases for all 5 choices

A.1

5B.

1

2C.

1

100D. 2 E. 20

Of the 5 choices, the smallest number is 1

100

Step 2: Now that we have expressed all choices to power β€˜n’, just compare the bases

Which will have the least value?A.

1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

Listing down only the bases for all 5 choices

A.1

5B.

1

2C.

1

100D. 2 E. 20

Of the 5 choices, the smallest number is 1

100

10-2n is the least value

Step 2: Now that we have expressed all choices to power β€˜n’, just compare the bases

Which will have the least value?A.

1

5

𝑛B. 2-n C. 10-2n D. 4

𝑛

2 E. (0.05)-n

Listing down only the bases for all 5 choices

A.1

5B.

1

2C.

1

100D. 2 E. 20

Of the 5 choices, the smallest number is 1

100

Choices C is the answer.

10-2n is the least value

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