Chuyn III : Amin Amino Axit - Peptit

Chng III: amin Axit aminI. nh ngha Cng thc tng qut Tn gi: 1. Khi nim : Khi thay th mt hay nhiu nguyn t hidro trong phn t NH3 bng 1 hay nhiu gchidrocacbon ta c amin . VD: CH3 NH2 ; CH3 NH CH3 . 2. Cng thc . R-NH2 (Amin) ; R-CH-COOH(Amino axit); H2N-CH-CO--NH-CH-COOH(Peptit) Nng cao : n li CT tng qut : CnH2n + 2 2a x (Chc)x CT tng qut ca amino axit : CnH2n + 2 2a x (NH2)x vi a l s lin kt pi v x l s nhm chc. T CT trn => CT amin n chc : CnH2n + 1 2a (NH2) => amin n chc no => a = 0 : CnH2n + 1 NH2 , c 1 lk pi => a = 1 : CnH2n 1NH2 Thay a vo => CT tng ng. CT tng qut ca amino Axit : (H2N)n R (COOH)n : n , n 1 : R l gc hidrocacbon ha tr (n + n) Hoc ( H2N)n CxHy (COOH)n : n , n 1 , x 1 , y + n + n 2x + 2 Amino axit thng gp : Amino axt cha 1 nhm amino (NH2) v mt nhm chc axit (COOH) no mch h : R-COOH NH2 Bc ca amin bng s nguyn t H trong amin b thay th bi gc hidrocabon VD: CH3 NH2 (Bc 1) CH3 NH CH3(Bc 2) (CH3)3N (Bc 3) 3. Tn gi : Tn gc hidrocacbon + amin CH3 NH CH3 : imetyl amin. 4. Tnh cht a) Tnh cht ca nhm NH2 63. Tnh baz: R-NH2 + H2O => [R-NH3]+OHTc dng vi axit cho mui: R-NH2 + HCl => [R-NH3]+Cl64. Tc dng vi HNO2 Amin bo bc I to thnh ancol v kh N2 : R-NH2 + HONO => R-OH + N2 + H2O Amin thm bc I: ArNH2 + HNO2 + HCl => ArN2+Cl hay ArN2Cl Tc dng vi dn xut Halogen R-NH2 + CH3I => R-NHCH3 + HI b) Amino axit c tnh cht ca nhm COOH 65. Tnh axit: RCH(NH2)COOH + NaOH => RCH(NH2)COONa + H2O 66. Phn ng este ho: RCH(NH2)COOH + ROH => RCH(NH2)COOR + H2O c) Amino axit c phn ng gia nhm COOH v nhm NH2 To mui ni H2N-CH-COOH => H3N+-CH-COO Phn ng trng ngng ca cc v amino axit to poliamit: nH2N-[CH2]5-COOH => ( NH-[CH2]5-CO )n + nH2O axit - aminocaproic policaproamit d) Protein c phn ng ca nhm peptit CO-NH Phn ng thu phn: Phn ng mu: Tc dng vi Cu(OH)2 cho dung dch mu xanh tm. e) Anilin c phn ng th d dng 3 nguyn t H ca vng benzen(o , p) => kt ta trng (dng nhn bit anilin) Ch cc cht sau : anilin (C6H5NH2) v amino axit thng dng. II) Cc dng bi tp thng gp Dng 1: S ng phn ca amin n : CTPT Tng s ng Bc 1 phn Bc 2 Bc3 1

Chuyn luyn thi i hc

Chuyn III : Amin Amino Axit - Peptit C3H9N 4 2 1 1 C4H11N 8 4 3 1 C5H13N 17 8 6 3 C6H15N 7 C7H9N 5 4 1 0 VD1:Cho amin no n chc c %N = 23,72% . Tm s ng phn bc 3 ca amin A. 1 B.2 C.3 D.4 PP: amin no n chc => CT : CnH2n+1NH2 MN .100% 14.100% = = 23,72% Gii ra c n = 3 %N = Ma min 14n + 17 CT : C3H7N2 => C ng phn bc 3 l 1 ( Bng trn C3H9N) Dng2 : So snh tnh baz ca cc amin Nguyn tc : Amin cn d i e cha lin kt trn nguyn t Nit nn th hin tnh baz => c trng cho kh nng nhn proton H+ Nhm ankyl c nh hng lm tng mt e nguyn t Nit =>lm tng tnh baz. >NH3 Nhm phenyl (C6H5-) lm gim mt e trn nguyn t Nit =>lm gim tnh baz. NH3 > C6H5-NH2 Amin bc 2 > Amin bc 1 Gii thch: Do amin bc 2 (R-NH-R) c hai gc HC nn mt y e vo nguyn t N trung tm ln hn amin bc 1 (R-NH2). Amin cng c nhiu gc ankyl, gc ankyl cng ln => tnh baz cng mnh. gc phenyl => tnh baz cng yu. *V D: So snh tnh baz ca cc hp cht hu c sau: NH3 , C2H5NH2 , CH3NH2 , C6H5NH2 , (C6H5)2NH , (C2H5)2NH , C6H5 CH2NH2 ? (C2H5)2NH > C2H5NH2 > CH3NH2 > NH3 > C6H5> CH2NH2 > C6H5NH2 > (C6H5)2NH VD1: Cho cc cht: (1) amoniac. (2) metylamin. (3) anilin. (4) dimetylamin. Tnh baz tng dn theo th t no sau y? A. (1) < (3) < (2) < (4). B. (3) < (1) < (2) < (4). C. (1) < (2) < (3) < (4). D. (3) < (1) < (4) < (2). Amoniac : NH3 ; metyamin : CH3NH2 ; anilin : C6H5NH2 ; dimetyl amin : CH3 NH CH3 Da vo tnh cht trn : anilin c vng benzen(gc phenyl) => Tnh bazo yu nht NH3 mc trung gian > C6H5NH2 Amin bc I (CH3NH2) < Amin bc 2 (NH3 NH NH3) => Th t : C6H5NH2 < CH3 < CH3NH2 s chc = 1 VD: trung ha 50 ml dd amin no , (trong amin c 2 nguyn t Nito ) cn 40 ml dd HCl 0,1 M . CM ca imetyl amin dng l : A.0,08M B.0,04M C.0,02M D.0,06M Amin c 2 N => amin c s chc = 2 ADCT : namin = nHCl/2 = 0,002 mol => CM amin = 0,04 M Dng 4 : Xc inh s mol ca ca amin nu bit s mol ca CO2 & H2O : Nu bi cha cho amin no, n chc th ta c gi s l amin no, n. Khi t chy nH2O > nCO2 ,ta ly : nH2O - nCO2 = 1,5namin Cch chng minh nh phn hidrocacbon CT amin no n chc : CnH2n+1NH2 PT : CnH2n+3N2 + O2 => nCO2 + (n+3/2)H2O + N2 x mol n.x mol (n+3/2).x mol Ta ly nH2O nCO2 = 3/2x = 3/2n amin Chuyn luyn thi i hc 2

Chuyn III : Amin Amino Axit - Peptit nCO 2 1,5.nCO 2 = na min nH 2O nCO 2 Tng t c CT i vi amin khng no , n chc + C 1 lk pi , C 2 lk pi , Chng minh tng t Nu bi cho amin n chc, m khi t chy to ra bit n CO2 v nN2 . th ta c CT sau V amin n chc => c 1 N . AD LBT nguyn t N => n amin = 2nN2 nCO 2 nCO 2 n( n) = M n hoc n = na min 2nN 2 VD1: t chy hon ton amol hh X gm 2 amin no n chc lim tip nhau thu c 5,6 lt CO2 (ktc) v 7,2 g H2O . Gi tr ca a l : A. 0,05 mol B.0,1 mol C.0,15 mol D.0,2 mol Tm CT 2 amin ? AD CT : namin = (nH2O nCO2)/1,5 ( i vi amin no n chc) = (0,4 0,25)/1,5 = 0,1 mol nCO 2 0,25 = = 2,5 => Amin c CT : CnH2n+1NH2 CT amin : n = na min 0,1 n = 2 v n = 3 :C2H5NH2 v C3H7NH2 VD2: Aminoaxit X cha mt nhm chc amin bc nht trong phn t. t chy hon ton mt lng X thu c v theo t l th tch l 4 : 1. X c cng thc cu to l: A.H2N CH2 CH2 COOH B.H2N (CH2)3 COOH C.H2N CH2 COOH D. H2N (CH2)4 COOH Da vo p n => amin X ch c 1 N => 2nN2 = namin (BT NT Nito) nCO 2 nCO 2 4 n= = = 2 => X Ch c 2 C => C M n = na min 2nN 2 2 Dng 5: tm CTPT ca amin n, nu bit % khi lng N hoc %H hay %C cng c: Gi R l gc hidrocacbon ca amin cn tm . VD amin n chc CT : R-NH2 Mt s gc hidrocacbon thng gp : 15 : CH3; 27 : CH2=CH; 29 : C2H5-; 43 :C3H7; 57 : C4H9VD 1: Cho amin no , n chc bc 1 c %N = 31,11% . Tm CT ca amin NH li CT tng qut : CnH2n+2 2a m(CHc)m ( a l tng pi tnh phn trn) y v amin n chc => m = 1 , V amin no => a = 0 => CT: CnH2n+2 1 NH2 = CnH2n+1NH2 14.100% = 31,11% Gii ra c n = 2 => CT: C2H5NH2 => %N = 14n + 17 Dng 6: Cho amin tc dng vi dd FeCl3, Cu(NO3)2 to kt ta : Amin c kh nng tc dng vi dd FeCl3 , Cu(NO3)2 xy ra theo phng trnh : 3RNH2 + FeCl3 + 3H2O => Fe(OH)3 + 3RNH3Cl 2RNH2 + Cu(NO3)2 + 2H2O => Cu(OH)2 + 2RNH2NO3 Thng th bi hay cho m kt ta : Fe(OH)3 hoc Cu(OH)2 Dng 7: tm CTPT ca amin da theo phn ng chy -Cng thc : AD CT : Tm CT bt k : CnH2n+2 2a m(Chc)m Ta c Amin bt k : CxHyNz vi y 2x + 2 +z y chn th z chn, y l th z l Amin n chc : CxHyN Amin n chc no : CnH2n+1NH2 , CnH2n+3NH2 Amin a chc no : CnH2n+2-z(NH2)z , CnH2n+2+zNz Nu cho phn trm khi lng tng nguyn t th lp CT n gin nht, da vo gi thuyt bin lun. Theo T l : x : y : z Nu bi cho s mol sn phm th lm tng t dng 3, tm c s ngt C trung bnh, da vo yu cu a ra CT ng Nu bi cho m g amin n chc t chy hon ton trong khng kh va (cha 20% oxi, 80% nit) thu c ch k mol CO2 hoc c k mol CO2 ln x mol nit , ta c th lm nh v d: T => n (s C trong amin) hoc n = Chuyn luyn thi i hc 3

Chuyn III : Amin Amino Axit - Peptit VD1: t chy hon ton 1,18 g amin n chc B bng mt lng oxi va . Dn ton b sn phm wa bnh ng nc vi trong d thu c 6 gam kt ta .CTPT ca B l : Gi cng thc l CxHyN CxHyN + O2 => x CO2 Ta c t l : x.namin =nCO2 1,18 0,46 x 0,84 x. = 0,06 = > y = 2x +2+1 x 3 12 x + y + 14 0,06 Cho x chy t 1=>3 : ch c gi tr x=3 v y=9 l tho k . Vy CTPT l C3H9N VD2:t chy hon ton 1,18 g amin n chc B bng mt lng khng kh va u (cha 20% oxi, 80% nit). Dn ton b sn phm wa bnh ng nc vi trong d thu c 6 gam kt ta v c 9,632 lt kh duy nht thot ra .CTPT ca B l : Gi cng thc l CxHyN . nCO2 = 0,06 mol CxHyN + (x + y/4) O2 => x CO2 + y/2 H2O + N2 y y 0,06( x + ) 0,06( x + ) 4 nN 2kk = 4. 4 nO 2 = x x y 0,06( x + ) 0,03 4 + 0,03 = 0,43 0,19 x 0,06 y = 0,03(1) Theo pt : nN 2 = nN 2 = 4. x x x 1,18 0,06 = 0,46 x 0,06 y = 0,84(2) 12 x + y + 14 x Giai (1) & (2) x = 3; y = 9 Vy CTPT l C3H9N Nu bi ton cho t chy mt amin bng khng kh ,ri thu a mol CO2 ; b mol H2O ; c mol N2.ta lm nh sau : Tm khi lng O trong CO2 ;H2O = khi lng Oxi tham gia phn ng ( BT Nguyn t O) => s mol oxi => s mol Nit trong kk = 4nO2 (Nu bi tp cho t trong khng kh cn Nu t trong O2 th khng phi tnh) => s mol Nit sinh ra trong phn ng chy. T ta s c s mol C, H, N trong amin => Tm CTGN => CTPT VD1: Mt amino axit cha 46,6% C, 8,74% H, 13,59% N,cn li l oxi. Cng thc n gin nht trng vi cng thc phn t. Cng thc phn t ng ca amino axit l A.C3H7O2N B.C4H9O2N C.C5H9O2N D.C6H10O2N % O = 100 - (46,6 + 8,74 + 13,59) = 31,07 % %C % H %O % N 46,6 8,74 31,07 13,59 : : : = : : : C:H:O:N= = 3,88 : 8,74 : 1,94 : 0,97 = 4 : 9 : 2 12 1 16 14 12 1 16 14 : 1 => CTG : C4H9O2N => Chn B Nu lm trc nghim nh th th hi lu. Mo dp n: S C u khc nhau v s N ging nhau ( bi hay cho kiu ny) Ch cn xt t l gia C v N thi khng cn O v H Xt t l ta c C : O = 4 : 1 => B VD2: Khi t chy hon ton mt amin n chc X, thu c 8,4 lt kh CO2, 1,4 lt kh N2 (cc th tch kh o ktc) v 10,125 gam H2O. Cng thc phn t ca X l (cho H = 1, O = 16)Chn mt p n di y A. C3H7N B. C3H9N C. C4H9N D. C2H7N Cu ny khc xt t l C : H hay hn Tm c t l 1 : 3 => B V p n A v B t l C : N = 3: 1 Dng 8: Cho amin tc dng vi HCl: (PP Gii bi tp dng tng gim khi lng) VD amin bc 1: Aminno axit : NH2 R COOH + HCl => CLNH3-R-COOH Gii s 1mol 1mol => 1mol => m tng = m mui m amin = 36,5 g (v P cng HCL) Chuyn luyn thi i hc 4

Chuyn III : Amin Amino Axit - Peptit Vi xmol => xmol => xmol => m Tng = 36,5x g m mui = mamin + namin (HCl hoc mui).36,5 Hoc dng BT Khi lng : m amin + mHCl = m mui (Chnh l CT trn) Cn nu amino Axit tc dng vi NaOH(Kim) (Hoc Na,K) Th xem li phn Axit nh. CT: m mui = mAmino Axit + m.nNaOH.22 ( m l s chc COOH) i vi Amino Axit c 1 nhm COOH => nNaOH = nAmino Axit = n Mui VD1: Cho 0,01 mol amino axit A tc dng va vi 80 mldung dch HCl 0,125 M. C cn dung dch thu c1,835 gam mui. Khi lng phn t ca A (Tc l M ca A)l A.97 B.120 C.147 D.150 ADCT: m mui = mamin + nHCL .36,5 1,835 =Mamoni . 0, 01 + 0,01.36,5 M amino = 147 VD2: Cho 0,01 mol aminoaxit X phn ng ht vi 40ml dung dch HCl 0,25M to thnh 1,115g mui khan. X c cng thc cu to no sau y: A.NH2 CH2 COOH B.NH2 (CH2)2 COOH C.CH3COONH4 D.NH2 (CH2)3 COOH Da vo p n hoc Xt t l : nHCL / namin = 1 => amino axit c 1 gc chC. p t l 1 :1 => Loi p n C. AD CT : m mui =Mamino axit . 0,01 + nHCL . 36,5 1,115 = MX.0,01 + 0,01.36,5 MX = 75 CT : amino axit : NH2 CnH2n COOH => MR = 14n + 61 = 75 => n = 1 CT : NH2 CH2 COOH VD3: A l mt -amino axit no ch cha mt nhm -NH2 v mt nhm COOH. Cho 3 gam A tc dng vi NaOH d thu c 3,88 gam mui. Cng thc phn t ca A l A.CH3-CH2-CHNH2-COOH B.CH2NH2-CH2-COOH C.CH3-CHNH2-COOH D.H2N-CH2-COOH Cch gii bnh thng : Theo bi ta c gc hirocacbono l CnH2n H2NCnH2nCOOH + NaOH => H2NCnH2nCOONa + H2O bi 3 gam 3,88 gam Theo PT => nH2NCnH2nCOOH = nH2NCnH2nCOONa 3 3,88 = Gii ra c : n = 1 => CTCT ca A l H2N-CH2-COOH Chn D 14n +61 14n + 83 mmuoi ma min o 3,88 3 = = 0,04mol ADCT trn => nH2NCnH2nCOOH = 22 22 3 = 75 n = 1 MH2NCnH2nCOOH = 14n +61 = 0,04 Dang 9: Trn hn hp gm amin v hirocacbon ri em t chy Xt v d sau : VD5: t chy hon ton hn hp gm 100 ml hh gm imetylamin v hai hirocacbon ng ng k tip thu c 140 ml CO2 v 250 ml nc ( cc V cng iu kin). CTPT ca hai hirocacbon? Ta thy : Hh gm (C2H5)2NH v CxHy (x l s ngt C trung bnh ca hai HC). 140 = 1,4 Gi n l s nguyn t C trung bnh => n = 100 Vy mt trong hai cht phi c 1 cht c s ngt C > 1,4 , l (C2H5)2NH. Cht cn li c s ngt C nh hn 1,4 => x hai hirocacbon ng ng k tip trn phi thuc dy ng ng ca ankan. Vy 2 hirocacbon cn tm l CH4 v C2H6

Bi tp vn dng :Chuyn luyn thi i hc 5

Chuyn III : Amin Amino Axit - Peptit Cu 1: Anilin v phenol u p vi: A.dd HCl B.dd NaOH CH3I HNO2 Cu 2: Cho s : NH3 X 1:1

C.dd Br2 CuO Y Z to

D. dd NaCL

Bit Z c kh nng tham gia p trng gng. Y v Z ln lt l A.C2H5OH, HCHO B.C2H5OH, CH3CHO C.CH3OH, HCHO D.CH3OH, HCOOH Cu 3: Dy gm cc cht u lm qu tm m chuyn sang mu xanh l A. anilin, metyl amin, amoniac B.amoni clorua, metyl amin, natri hidroxit C. anilin, aminiac, natri hidroxit D. metyl amin , amoniac, natri axetat. Cu 4: C 3 cht lng: benzen , anilin, stiren ng ring bit trong 3 l mt nhn . Thuc th phn bit 3 cht lng trn l : A. dd phenolphtalein B.dd Br2 C.dd NaOH D. Qu tm Cu 5: Cho cc cht: etyl axetat, etanol , axit acrylic , phenol , anilin , phenyl amoni clorua, ancol benzylic, p crezol. Trong cc cht trn , s cht p vi NaOH l : A.3 B.4 C.5. D.6 Cu 6: NHn nh no sau y ko ng ? A.cc amin u c kh nng nhn proton. B.Tnh bazo ca cc amin u mnh hn NH3. C.Metyl amin c tnh bazo mnh hn anilin D.CT TQ ca amino , mnh h l : CnH2n+2+2Nk Cu 7: dd metyl amin khng tc dng vi cht no sau y? A.dd HCl B.dd Br2/CCL4 C.dd FeCL3 D. HNO2 Cu 8: tch ring hh kh CH4 v CH3NH2 ta dng : A.HCL B. HCl, NaOH C. NaOH , HCL D.HNO2 Cu 9: phn bit cc dd : CH3NH2, C6H5OH , CH3COOH , CH3CHO khng th dng A.qu tm , dd Br2 B.Qu tm , AgNO3/NH3 C.dd Br2 , phenolphtalein D. Qu tm, Na kim loi Cu 10: Cho anilin tc dng vi cc cht sau: dd Br2 , H2 , CH3I , dd HCl , dd NaOH , HNO2. S p xy ra l : A.3 B.4 C.5 D.6 Cu 11: Cho cc cht sau: (1) NH3 ; (2) CH3NH2; (3) (CH3)2NH ; (4) C6H5NH2 ; (5) (C6H5)2NH . Th t tng dn tnh bazo ca cc cht trn l : A.(4) < (5) < (1) < (2) < (3) B.(1) < (4) < (5) < (2) < (3) C.(5) < (4) < (1) < (2) < (3) D.(1) < (5) < (2) < (3) < (4) Cu 12: Cho s chuyn ha sau : +CH3OH/HCL +NH3 +HNO2 Alanin X Y Z Cht A l : A.CH3 CH(OH) COOH B.H2N CH2 COOCH3 C.CH3 CH(OH) COOCH3 D.H2N CH(CH3) COOCH3 Cu 13: chng minh glyxin C2H5O2N l mt amino axit , ch cn cho p vi A.NaOH B.HCL C.CH3OH/HCL D. HCL v NaOH Cu 14: ng vi CT C3H7O2N c bao nhiu ng phn amino axit ? A.2 B.3 C.4 D.5 Cu 15: Hp cht khng lm i mu giy qu m l : A.CH3NH2 B.C6H5ONa C.H2N CH2 CH(NH2) COOH D. H2NCH2 COOH Cu 16: Cht X c CT l C3H7O2N . X c th tc dng vi NaOH , HCl v lm mt mu dd Br. CT ca X l: A.CH2 = CH COONH4 B.CH3CH(NH2)COOH C.H2NCH2CH2COOH D.CH3CH2CH2NO2 Cu 17: dd cht no sau y ko lm chuyn mu qu tm. ? A.H2N(CH2)2CH(NH2)COOH. B.CH3CH(OH)COOH C.H2NCH2COOH D.C6H5NH3Cl Cu 18: Axit glutamic (HCOO(CH2)2CH(NH2)COOH) l cht A. Ch c tnh axit B.ch c tnh bazo C.Lng tnh D.trung tnh. Chuyn luyn thi i hc 6

Chuyn III : Amin Amino Axit - Peptit Cu 19: Cho cc loi hp cht : amino axit(X) , mui amoni ca axit cacboxylic(Y) , amin(Z) este ca amino axit(T) , dy gm cc hp cht u p vi NaOH v dd HCl l : A.X, Y,Z , T B.X,Y,T C.X,Y,Z D.Y,Z,T Cu 20: Trong cc cht sau cht no c lin kt peptit? A.alanin B.Protein C.Xenlulozo D.Glucozo Bi 21: Cho 0,1 mol A ( amino axit H2N-R-COOH) phn ng ht vi HCl to 11,15 gam mui. A l A.Valin B.Phenylalani C.Alanin D.Glyxin Bi 22: Amino axit X cha mt nhm COOH v 2 nhm NH2.Cho 1 mol X tc dng ht vi dung dch NaOH, thu c 154 gam mui. Cng thc phn t ca X l: A.C4H10N2O2 B.C5H10N2O2 C.C5H12N2O2 D.C6H14N2O2 Bi 23: Hp cht no sau y khng phi l Amino axit A.H2NCH2COOH B.CH3CH2CONH2 C.CH3NHCH2COOH D.HCOOCCH2CH(NH2)COOH Bi 24: C 3 cht: butylamin, anilin v amoniaC. Th t tng dn lc baz l A.NH3 < C6H5NH2 < C4H9NH2 B.C6H5NH2 < NH3 < C4H9NH2 C.C4H9NH2 < NH3 < C6H5NH2 D.C4H9NH2 < C6H5NH2 < NH3 Bi 25: Hp cht hu c X c mch cacbon khng phn nhnh, bc nht (cha C, H, N), trong nit chim 23,73% v khi lng. Bit X tc dng c vi HCl vi t l s mol . Cng thc phn t ca X l A. CH3 NH2 B.CH3 CH2 NH CH3 C.CH3 CH(CH3) NH2 D.CH3 CH2 CH2 NH2 Bi 26: Cho 20 gam hn hp gm 3 amin no, n chc l ng ng k tip nhau tc dng va vi dung dch 1M, c cn dung dch thu c 31,68 gam mui. Th tch dung dch dng l A.16ml B.32ml C.160ml D.320ml Bi 27: t chy hon ton 1 amin no n chc, bc 2, mch h X thu c v hi nc theo t l s mol tng ng l 2 : 3. Cng thc cu to ca X l A.CH3 NH CH3 B.CH3 NH C2H5 C.CH3 CH2 CH2 NH2 D.C2H5 NH C2H5 Bi 28: t chy hon ton hn hp 2 amin no n chc ng ng lin tip, thu c . Hai amin c cng thc phn t l: A.C2H5NH2 v C3H7NH2 B.CH3NH2 v C2H5NH2 C.C3H7NH2 v C4H9NH2 D.C4H9NH2 v C5H11NH2 Bi 29: T l th tch ca CO2 : H2O khi t chy hon ton mt ng ng X ca glixin l 6 : 7 (phn ng chy sinh ra ). X tc dng vi glixin cho sn phm ipeptit. Cng thc cu to ca X l: A.CH3CH(NH2)COOH B.NH2CH2CH2COOH C.C2H5CH(NH2)COOH D. A v B ng Bi 30: Hy chn trnh t tin hnh no trong cc trnh t sau phn bit dung dch cc cht: CH3NH2, H2NCOOH, CH3COONH4, anbumin. A..Dng qu tm, dng dd HNO3 c , dng dd NaOH B.Dng qu tm, dng Ca(OH)2 C.Dng Cu(OH)2 , dng phenolphtalein, dng dd NaOH D.Dng qu tm, dng dd CuSO4, dng dd NaOH Bi 31: X l mt no ch cha mt nhm -NH2v mt nhm COOH. Cho 13,1g X tc dng vi dung dch HCl d, ta thu c 16,75g mui clohirat ca X. X c cng thc cu to no sau y? A.CH3CH2(NH2)COOH B.H2N(CH2)3COOH C.CH3(CH2)4(NH2)COOH D.H2N(CH2)5COOH Bi 32: Mt hp cht hu c X c cng thc C3H7O2N. X phn ng vi dung dch brom, X tc dng vi dung dch NaOH v HCl. Cht hu c X c cng thc cu to l: A.H2N CH = CH COOH B.CH2 = CH COONH4 C.H2N CH2 CH2 COOH D. A v B ng Bi 33: Hp cht hu c X c phn t khi nh hn phn t khi ca benzen, ch cha C, H, O, N trong H chim 9,09%, N chim 18,18%. t chy 7,7g X, thu c 4,928 lt kh o , 1 atm. X tc dng vi dung dch NaOH cho mui ca axit hu c. X c cng thc cu to no sau y? Chuyn luyn thi i hc 7

Chuyn III : Amin Amino Axit - Peptit A.CH3COONH4 B.HCOONH3CH3 C.H2NCH2CH2COOH D. A v B ng Bi 34: Hy sp xp cc cht sau y theo trnh t tnh baz tng dn t tri sang phi: amoniac, anilin, pnitroanilin, p-nitrotoluen, metylamin, imetylamin. A.C6H5NH2 < O2NC6H4NH2 < H3CC6H4NH2 < NH3 < CH3NH2 < (CH3)2NH B.O2NC6H4NH2 < C6H5NH2 < H3CC6H4NH2 < NH3 < CH3NH2 < (CH3)2NH C.O2NC6H4NH2 < H3CC6H4NH2 < C6H5NH2 < NH3 < CH3NH2 < (CH3)2NH D. Tt c u sai Bi 35: t chy ht a mol mt aminoaxit c 2a mol CO2v a/2mol N2. Aminoaxit trn c cng thc cu to l: A.H2NCH2COOH B.H2N(CH2)2COOH C.H2N(CH2)3COOH D.H2NCH(COOH)2 Bi 36: t chy mt amin X n chc no, thu c v c t l s mol nCO2:nH2O = 2:3 . Amin X c tn gi l: A.Etyl amin B. Metyl etyl amin C. Trimetyl amin D.Kt qu khc Bi 37: C hai amin bc mt: X (ng ng ca anilin) v Y (ng ng ca metylamin). t chy hon ton 3,21g amin X sinh ra kh CO2 v hi nc v 336 cm3 kh nit (ktc). Khi t chy hon ton amin Y cho nCO2: nH2O = 2:3 Cng thc phn t ca amin l: A.CH3C6H4NH2, CH3CH2CH2NH2 B.C2H5C6H4NH2 , CH3CH2CH2NH2 C.CH3C6H4NH2 , CH3(CH2)4 NH2 D. A v B ng Bi 38: t chy hon ton mt amin thm X thu c 3,08g CO2v 0,9g H2Ov 336ml N2(o ktc). trung ho 0,1 mol X cn dng 600ml HCl 0,5M. Cng thc phn t ca X l cng thc no sau y: A.C7H11N B.C7H8NH2 C.C7H11N3 D.C8H9NH2 Bi 39: t chy hon ton 6,2g mt amin no n chc cn dng 10,08 lt kh oxi (ktc). Cng thc phn t ca amin l: A.C2H5NH2 B.C3H7NH2 C.CH3NH2 D.C4H9NH2 Bi 40: t chy hon ton m gam mt amin X bng lng khng kh va thu c 17,6g CO2v 12,6g H2O v 69,44 lt nit. Gi thit khng kh ch gm nit v xi, trong oxi chim 20% th tch. Cc th tch o ktc. Amin X c cng thc phn t l: A.C2H5NH2 B.C3H7NH2 C.CH3NH2 D.C4H9NH2 Bi 41: Cho 20 gam hn hp 3 amin no, n chc, ng ng k tip, tc dng vi dung dch va , sau c cn thu c 31,68 hn hp mui. Nu 3 amin trn trn theo th t khi lng mol tng dn vi s mol c t l 1: 10: 5 th amin c khi lng phn t nh nht c cng thc phn t l: ACH3NH2 B.C2H5NH2 C.C3H7NH2 D.C4H11NH2 Bi 42: Cng thc phn t ca amin cha 23,73% khi lng nit? A.C2H5NH2 B.C6H5NH2 C.(CH3)2NH D.(CH3)3N Bi 43: Cho 9,85 gam hn hp 2 amin, n chc, bc 1 tc dng va vi dung dch HCl thu c 18,975 gam mui. Khi lng HCl phi dng l A.9,521 B.9,125 C.9,215 D.9,512 Bi 44: X l hp cht hu c mch h, cha cc nguyn t C, H, N, trong N chim 31,11%% v khi lng. X tc dng vi dung dch HCl theo t l 1:1. X c s ng phn l: A.2 B.3 C.4 D.5 Bi 45: trung ha 200ml dung dch aminoaxit X 0,5M cn 100g dung dch NaOH 8%. C cn dung dch thu c 16,3g mui khan. X c cng thc cu to l: A.H2NCH(COOH)2 B.H2NCH2CH(COOH)2 C.(H2N)2CHCH2(COOH)2 D.Av B ng Bi 46: Hp cht X gm cc nguyn t C, H, O, N vi t l khi lng tng ng l 3:1:4:7. Bit phn t ch c 2 nguyn t nit. X c cng thc phn t l: A.CH4ON2 B.C3H8ON2 C.C3H10O2N2 D.C4H12O2N2 Bi 47: A l -amioaxit (c cha 1 nhm NH2). t chy 8,9g A bng O2va c 13,2g CO2; 6,3g H2Ov 1,12 lt N2(ktc). A c cng thc phn t l : A.C2H5NO2 B.C3H7NO2 C.C4H9NO2 D.C6H9NO4 Chuyn luyn thi i hc 8

Chuyn III : Amin Amino Axit - Peptit Bi 48: -aminoaxit X cha mt nhm -NH2. Cho 10,3 gam X tc dng vi axit HCl (d), thu c 13,95 gam mui khan. Cng thc cu to thu gn ca X l A.H2NCH2CH2COOOH B.CH3CH(NH2)COOH C.H2NCH2COOH D.CH3CH2CH(NH2)COOH Bi 49: C7H9N c s ng phn cha nhn thm la. A. 6. B. 5. C. 4. D. 3. Bi 50: Hp cht Y l mt amin n chc cha 20,89% N theo khi lng. Y c cng thc phn t l A.C4H5N B.C4H7N C.C4H9N D.C4H11N Bi 51: A l hp cht hu c cha C,H,O,N . t chy 1 mol A c 2 mol CO2 ; 2,5 mol H2O; 0,5 mol N2. ng thi phi dng 2,25 mol O2. A c CT phn t: A.C2H5NO2 B.C3H5NO2 C.C6H5NO2 D.C3H7NO2 Bi 52: t chy hon ton mt amin thm X thu c 0,07 mol CO2 , 0,99g H2O v 336 ml N2(ktc). trung ha 0,1 mol X cn 600 mldd HCl 0,5M. Bit X l amin bc 1 . X c cng thc l, A.CH3-C6H2(NH2)3 B.C6H3(NH2)3 C.CH3 NH C6H3(NH2) D.NH2 C6H2(NH2)2 Bi 53: trung ha ht 3,1 g mt amin n chc cn dng 100ml dd HCl 1M. amin l; A.CH5N B.C2H7N C.C3H3N D.C3H9N Bi 54: C 3 dd sau.H2N CH2 CH2 COOH ; CH3 CH2 COOH ; CH3 (CH2)3 NH2 phn bit cc dd trn ch cn dng thuc th l: A.dd NaOH B.dd HCl C. Qu tm D. phenolphtalein Bi 55: Mt este c CT C3H7O2N, bit este c iu ch t amino axit X v ru metylic. Cng thc cu to ca amino axit X l: A.CH3 CH2 COOH B.H2N CH2 COOH C.NH2 CH2 CH2 COOH D. CH3 CH(NH2) COOH Bi 56: Amin c cha 15,05% N v khi lng c CT l : A.C2H5NH2 B.CH3 CH2 NH2 C.C6H5NH2 D.(CH3)3N Bi 57: Cho 9,3 g mt ankyl amin X tc dng vi dd FeCl3 d thu c 10,7g kt tA. Cng thc cu to ca X l: A.CH3NH2 B.C2H5NH2 C.C3H7NH2 D.C4H9NH2 Bi 58: Ba cht A, B, C (CxHyNz) c thnh phn % theo khi lng N trong A, B, C ln lt l 45,16%; 23,73% ; 15,05% ;A , B, C tc dng vi axit cho mui amoni R NH3Cl CT ca A, B, C ln lt l: A.CH3NH2 , C3H7NH2, C4H9NH2 B.CH3NH2, C3H7NH2, C6H5NH2 C.CH3NH2 , C4H9NH2, C6H5NH2 D.CH3NH2 , C6H5NH2 , C2H5NH2 Bi 59: Hp cht C3H7O2N tc dng vi NaOH , H2SO4 v lm mt mu dd Br2 nn CT cu to hp l ca hp cht l: A.CH3 CH(NH2) COOH B.CH2(NH2) CH2 COOH C. CH2 = CH COONH4 D.CH3 CH2 COONH4 Bi 60: Cht X c %C = 40,45% ; %H = 7,86% ; %N = 15,73% cn li Oxi. MX H3N+- CH2 - COOH Cl-. H2N - CH2 - COOH + NaOH => H2N - CH2 - COONa + H2O. Hai phn ng trn chng t axit aminoaxetic A. c tnh cht lng tnh. B. ch c tnh axit. C. ch c tnh baz. D. va c tnh oxi ho, va c tnh kh. Bi 70: Anilin (C6H5NH2) c phn ng vi dung dch A. NaOH. B. Na2CO3. C. NaCl. D. HCl. Bi 71: Cho 8,9 gam mt hp cht hu c X c cng thc phn t C3H7O2N phn ng vi 100 ml dung dch NaOH 1,5M. Sau khi phn ng xy ra hon ton, c cn dung dch thu c 11,7 gam cht rn. Cng thc cu to thu gn ca X l A. HCOOH3NCH=CH2. B. H2NCH2CH2COOH. C. CH2=CHCOONH4. D. H2NCH2COOCH3. Bi 72: Cho dy cc cht: C6H5OH (phenol), C6H5NH2 (anilin), H2NCH2COOH, CH3CH2COOH, CH3CH2CH2NH2. S cht trong dy tc dng c vi dung dch HCl l A.4. B. 2. C. 3. D. 5. Bi 73: Cht no sau y khng kh nng tham gia phn ng trng ngng : A. CH3CH(NH2)COOH B. HCOOCH2CH2CH2NH2 C. CH3CH(OH)COOH D. HOCH2 - CH2OH Bi 74: Cho 12,55 gam mui CH3CH(NH3Cl)COOH tc dng vi 150 ml dung dch Ba(OH)2 1M. C cn dung dch sau phn ng thu c m gam cht rn. Gi tr ca m l : A. 15,65 g B. 26,05 g C. 34,6 g D. Kt qu khc CH3CH(NH3Cl)COOH + Ba(OH)2 => (CH3CH(NH3)COO)2Ba + BaCL2 + H2O Bi 75: Cho 22,15 g mui gm CH2NH2COONa v CH2NH2CH2COONa tc dng va vi 250 ml dung dch H2SO4 1M. Sau phn ng c cn dung dch th lng cht rn thu c l : A. 46,65 g B. 45,66 g C. 65,46 g D. Kt qu khc Bi 76: Cho 13,35 g hn hp X gm CH2NH2CH2COOH v CH3CHNH2COOH tc dng vi V ml dung dch NaOH 1M thu c dung dch Y. Bit dung dch Y tc dng va vi 250 ml dung dch HCl 1M. Gi tr ca V l A. 100 ml B. 150 ml C. 200 ml D. 250 ml Bi 77: Cho 20,15 g hn hp X gm (CH2NH2COOH v CH3CHNH2COOH) tc dng vi 450 ml dung dch HCl 1M thu c dung dch Y. Y tc dng va vi 200 ml dung dch NaOH. Phn trm khi lng ca mi cht trong X l: A. 55,83 % v 44,17 % B. 53,58 % v 46,42 % C. 58,53 % v 41,47 % D. 52,59 % v 47,41% Bi 78: Mt amino axit (X) c cng thc tng qut NH2RCOOH. t chy hon ton a mol X thu c 6,72 (l) CO2 (ktc) v 6,75 g H2O. CTCT ca X l : A. CH2NH2COOH B. CH2NH2CH2COOH C. CH3CH(NH2)COOH D. C B v CChuyn luyn thi i hc 10

Chuyn III : Amin Amino Axit - PeptitBi 79: Xc nh th tch O2 (ktc) cn t chy ht 22,455 g hn hp X gm

(CH3CH(NH2)COOH v CH3COOCH(NH2)CH3. Bit sn phm chy c hp th ht vo bnh ng dung dch NaOH th khi lng bnh tng 85,655 g. A. 44,24 (l) B. 42,8275 (l) C. 128,4825 (l) D. Kt qu khc Bi 80: Mt amino axit no X ch cha mt nhm -NH2 v mt nhm -COOH. Cho 0,89 g X phn ng va vi HCl to ra 1,255 g mui. CTCT ca X l: A. H2N-CH2-COOH B. CH3-CH(NH2)-CH2-COOH C. H2N-CH2-CH2-COOH D. B, C, u ng. Bi 81: Nhng cht no sau y lng tnh : A. NaHCO3 B. H2N-CH2-COOH C. CH3COONH4 D. C A, B, CBi 82: Cho qu tm vo dung dch mi hp cht di y, dung dch no s lm qu tm ho :

(1) H2N - CH2 COOH; (4) H2N(CH2)2CH(NH2)-COOH; (2) Cl.NH3+- CH2COOH; (5) HOOC(CH2)2CH(NH2) COOH; (3) H2N - CH2 - COONa A. (2), (5) B. (1), (4) C. (1), (5) D. (2) Bi 83: l mt hp cht hu c c CTPT C5H11O2N. un (A) vi dung dch NaOH thu c mt hp cht c CTPT C2H4O2NNa v cht hu c (B). Cho hi qua CuO/t0 thu c cht hu c (D) c kh nng cho phn ng trng gng. CTCT ca A l : A. CH2 = CH-COONH3-C2H5 B. CH3(CH2)4NO2 C. H2NCH2-CH2-COOC2H5 D. NH2CH2COO-CH2- CH2-CH3 Bi 84: Bit rng khi t chy hon ton 0,1 mol X thu c 1,12 lt N2; 6,72 lt CO2 v 6,3 gam H2O. CTPT ca X A. C3H5O2N B. C3H7O2N C. C3H5O2N D. C4H9O2N Bi 85: cho 0,1 mol cht X (C2H8O3N2) tc dng vi dd cha 0,2 mol NaOH un nng thu c cht kh lm xanh giy qu tm m t v dd Y. c cn dd Y thu c m gam cht rn khan. Gi tr ca m l A. 5,7 B. 12,5 C. 15 D. 21,8 Bi 86: aminoaxit X cha 1 nhm COOH v 2 nhm NH2. cho 1 mol X tc dng ht vi dd NaOH thu c 154 gam mui. CTCT ca X l A. H2NCH2CH(NH2)CH2COOH B. H2NCH2CH2CH2(NH2)COOH C. H2N(CH2)3CH(NH2)COOH D. H2NCH=CHCH(NH2)COOH Bi 87: t chy ht a mol mt aminoaxit c 2a mol CO2 v a/2 mol N2. amonoaxit trn c CTPT l A. H2NCH2COOH B. H2N(CH2)2COOH C. H2N[CH2]3COOH D. H2NCH[COOOH]2 Bi 88: A l mt -aminoaxit no, c mch cacbon khng phn nhnh, cha mt nhm-NH2 v 2 nhm COOH. Khi t chy hon ton 1 mol A th thu c hh kh trong c 4,5 mol CH2 = CH COO Na + CH3NH2 + H2O Bi 124: Pht biu no sau y l ng? A. Anilin tc dng vi axit nitr khi un nng, thu c mui iazoni. B. Benzen lm mt mu nc brom nhit thng. C. Etylamin phn ng vi axit nitr nhit thng, sinh ra bt kh. D. Cc ancol a chc u phn ng vi Cu(OH)2 to dung dch mu xanh lam. Bi 125: Cho hai hp cht hu c X, Y c cng cng thc phn t l C3H7NO2 . Khi phn ng vi dung dch NaOH, X to ra H2NCH2COONa v cht hu c Z ; cn Y to ra CH2=CHCOONa v kh T. Cc cht Z v T ln lt l A. CH3OH v CH3NH2 B. C2H5OH v N2 C. CH3OH v NH3 D. CH3NH2 v NH3 Bi 126: : Cht X c cng thc phn t C4H9O2N . Bit : X + NaOH Y + CH4O; Y + HCl (d) Z + NaCl Cng thc cu to ca X v Z ln lt l A. H2NCH2CH2COOCH3 v CH3CH(NH3Cl)COOH B. CH3CH(NH2)COOCH3 v CH3CH(NH3Cl)COOH C. H2NCH2COOC2H5 v ClH3NCH2COOH D. CH3CH(NH2)COOCH3 v CH3CH(NH2)COOH Bi 127: S ng phn cu to ca amin bc mt c cng cng thc phn t C4H11N l A. 2 B. 5 C. 4 D. 3 Bi 128: Cht X c cng thc phn t C3H7O2N v lm mt mu dung dch brom. Tn gi ca X l A. axit -aminopropionic B. mety aminoaxetat C. axit - aminopropionic D. amoni acrylat Bi 129: Thu phn 1250 gam protein X thu c 425 gam alanin. Nu phn t khi ca X bng 100.000 vc th s mt xch alanin c trong phn t X l A. 453 B. 382 C. 328 D. 479 Bi 130: Cho 1,82 gam hp cht hu c n chc, mch h X c cng thc phn t C3H9O2N tc dng va vi dung dch NaOH, un nng thu c kh Y v dung dch Z. C cn Z thu c 1,64 gam mui khan. Cng thc cu to thu gn ca X l A. CH3CH2COONH4. B. CH3COONH3CH3. C. HCOONH2(CH3)2. D. HCOONH3CH2CH3. Bi 131: Cho 5,9 gam amin n chc X tc dng va vi dung dch HCl, sau khi phn ng xy ra hon ton thu c dung dch Y. Lm bay hi dung dch Y c 9,55 gam mui khan. S cng thc cu to ng vi cng thc phn t ca X l A. 2. B. 4. C. 5. D. 3. Bi 132: Trong phn t aminoaxit X c mt nhm amino v mt nhm cacboxyl. Cho 15,0 gam X tc dng va vi dung dch NaOH, c cn dung dch sau phn ng thu c 19,4 gam mui khan. Cng thc ca X l A. H2NC3H6COOH. B. H2NC2H4COOH. C. H2NC4H8COOH. D. H2NCH2COOH. Bi 133: un nng cht H2N-CH2-CONH-CH(CH3)-CONH-CH2-COOH trong dung dch HCl (d), sau khi cc phn ng kt thc thu c sn phm l : A. H2N-CH2-COOH, H2H-CH2-CH2-COOHChuyn luyn thi i hc 14

Chuyn III : Amin Amino Axit - Peptit

B. H3N+-CH2-C, H3N+-CH2-CH2-COOHClOOHCl C. H3N+-CH2-C, H3N+-CH(CH3)-COOOHClOHCl D. H2N-CH2-COOH, H2N-CH(CH3)-COOH Bi 134: Cho 8,9 gam mt hp cht hu c X c cng thc phn t C3H7O2N phn ng vi 100 ml dung dch NaOH 1,5M. Sau khi phn ng xy ra hon ton, c cn dung dch thu c 11,7 gam cht rn. Cng thc cu to thu gn ca X l : A. HCOOH3NCH=CH2 B. H2NCH2CH2COOH C. CH2=CHCOONH4 D. H2NCH2COOCH3 Bi 135: Khi t chy cc ng ng ca metylamin, t l s mol a = nCO2 / nH2O bin i trong khong no A. 0,4 < a < 1,2. B. 1 < a< 2,5. C. 0,4 < a < 1. D. 0,75 < a < 1. Bi 136: Amino axit X cha mt nhm chc amino trong phn t. t chy han tan mt lng X thu c CO2 v N2 theo t l th tch 4:1. X c tn gi l A. Axit aminoetanonic. B. Axit 3-amino propanoic. C. Axit 2,2-iaminoetanoic. D. Axit -4-aminobutanoic. Bi 137: Hp cht X cha cc nguyn t C, H, O, N v c phn t khi l 89. Khi t chy han ton 1 mol X thu c hi nc, 3mol CO2 v 0,5mol N2. Bit rng X l hp cht lng tnh v tc dng c vi nc Br2. X c CTCT l A. H2N-CH=CH-COOH. B. CH2=CH(NH2)COOH. C. CH2=CH-COONH4. D. CH3-CH(NH2)COOH. Bi 138: Hai hp cht hu c X v Y c cng CTPT l C2H7NO2. Bit X + NaOH => A + NH3 + H2O Y + NaOH => B + CH3-NH2 + H2O. A v B c th l A. HCOONa v CH3COONa. B. CH3COONa v HCOONa. C. CH3NH2 v HCOONa. D. CH3COONa v NH3. Bi 139: X l mt -aminoaxit no ch cha mt nhm NH2 v mt nhm COOH. Cho 14,5gam X tc dng vi dung dch HCl d thu c 18,15gam mui clorua ca X. CTCT ca X c th l A. CH3CH(NH2)COOH. B. H2NCH2COOH. C.CH3CH2CH(NH2)COOH. D. CH3[CH2]4CH(NH2)COOH. Bi 140: X l mt -aminoaxit. Cho 0,01mol X tc dng va vi 80ml dung dch HCl 0,125M, sau em c cn dung dch thu c 1,835gam mui. Phn t khi ca X l A. 174. B. 147. C. 197. D. 187. Bi 141: Cho cc cht : (1)C6H5-NH2; (2) C2H5NH2; (3) (C2H5)2NH; (4) NaOH; (5): NH3. Dy c sp xp theo chiu tng ca lc baz l A. (1)< (5)< (2)< (3)< (4). B. (1)< (2)< (5)< (3)< (4). C. (1)< (5)< (3)< (2)< (4). D. (2)< (1)< (3)< (5)< (4). Bi 142: trung ha 200ml dung dch amino axit X cn 100g dung dch NaOH 8%, c cn dung dch c 16,3g mui khan. X c CTCT l A. NH2CH2CH2COOH. B. H2NCH(COOH)2. C. (H2N)2CHCOOH. D. H2NCH2CH(COOH)2. Bi 143: Cho cht hu c X c cng thc phn t C2H8O3N2 tc dng vi dung dch NaOH, thu c cht hu c n chc Y v cc cht v c. Khi lng phn t (theo vC) ca Y l A. 85 B. 68 C. 45 D. 46 Bi 144: Hp cht X c cng thc phn t trng vi cng thc n gin nht, va tc dng c vi axit va tc dng c vi kim trong iu kin thch hp. Trong phn t X, thnh phn phn trm khi lng ca cc nguyn t C, H, N ln lt bng 40,449%; 7,865% v 15,73%; cn li l oxi. Khi cho 4,45 gam X phn ng hon ton vi mt lng va dung dch NaOH (un nng) thu c 4,85 gam mui khan. Cng thc cu to thu gn ca X l A. CH2=CHCOONH4. B. H2NCOO-CH2CH3. C. H2NCH2COO-CH3. D. H2NC2H4COOH.Chuyn luyn thi i hc 15

Chuyn III : Amin Amino Axit - PeptitBi 145: -aminoaxit X cha mt nhm -NH2. Cho 10,3 gam X tc dng vi axit HCl (d), thu c

13,95 gam mui khan. Cng thc cu to thu gn ca X l A. H2NCH2CH2COOH. B. H2NCH2COOH. C. CH3CH(NH2)COOH. D. CH3CH2CH(NH2)COOH. Bi 146: Cho hn hp X gm hai cht hu c c cng cng thc phn t C2H7NO2 tc dng va vi dung dch NaOH v un nng, thu c dung dch Y v 4,48 lt hn hp Z ( ktc) gm hai kh (u lm xanh giy qu m). T khi hi ca Z i vi H2 bng 13,75. C cn dung dch Y thu c khi lng mui khan l : A. 8,9 gam. B. 15,7 gam. C. 16,5 gam. D. 14,3 gam. Bi 147: t chy hon ton mt lng cht hu c X thu c 3,36 lt kh CO2, 0,56 lt kh N2 (cc kh o ktc) v 3,15 gam H2O. Khi X tc dng vi dung dch NaOH thu c sn phm c mui H2N-CH2-COONa. Cng thc cu to thu gn ca X l A. H2N-CH2-COO-C3H7. B. H2N-CH2-COO-CH3. C. H2N-CH2-COO-C2H5. D. H2N-CH2-CH2-COOH. Bi 148: Mt trong nhng im khc nhau ca protit so vi lipit v glucoz l A. protit lun cha chc hiroxyl. B. protit lun cha nit. C. protit lun l cht hu c no. D. protit c khi lng phn t ln hn. Bi 149: Cho cc loi hp cht: aminoaxit (X), mui amoni ca axit cacboxylic (Y), amin (Z), este ca aminoaxit (T). Dy gm cc loi hp cht u tc dng c vi dung dch NaOH v u tc dng c vi dung dch HCl l A. X, Y, Z, T. B. X, Y, T. C. X, Y, Z. D. Y, Z, T. Bi 150: Thuc th c dng phn bit Gly-Ala-Gly vi Gly-Ala l A.. dung dch NaCl. B. dung dch HCl. C. Cu(OH)2 trong mi trng kim. D. dung dch NaOH. Bi 151: Este A c iu ch t amino axit B v ru metylic. T khi hi ca A so vi hiro l 44,5. t chy hon ton 8,9gam este A thu c 13,2gam kh CO2, 6,3gam H2O v 1,12 lit N2(ktc). CTCT ca A v B l A. NH2-CH2-COOCH3 v NH2-CH2-COOH. B. NH2-CH2-CH2-COOCH3 v NH2-CH2-COOH C. CH3COOCH3 v NH2-CH2-COOH. D. NH2-CH2-COOH v NH2-CH2-CH2-COOH Bi 152: Cho qu tm vo mi dung dch hn hp di y, dung dch no lm qu tm ha ? (1) H2N - CH2 COOH; (2) Cl - NH3+ . CH2 COOH; (3) NH2 - CH2 COONa (4) H2N- CH2-CH2-CHNH2- COOH; (5) HOOC- CH2-CH2-CHNH2- COOH A. (2), (4) B. (3), (1) C. (1), (5) D. (2), (5). Bi 153: Cho dung dch cha cc cht sau :X1 : C6H5 - NH2; X2 : CH3 - NH2; X3 : NH2 - CH2 COOH; X4 : HOOC-CH2-CH2-CHNH2COOH; X5 : H2N- CH2-CH2-CH2-CHNH2COOH. Dung dch no lm qu tm ha xanh ? A. X1, X2, X5 B. X2, X3, X4 C. X2, X5 D. X1, X3, X5 Bi 154: Hp cht C3H7O2N tc dng c vi NaOH, H2SO4 v lm mt mu dd brom, CTCT ca n l A. CH3-CHNH2 -COOH B. H2N-CH2 - CH2 COOH C. CH2 = CH - COONH4 D. A v B ng. Bi 155: X l mt amino axit no ch cha mt nhm NH2 v mt nhm -COOH. Cho 0,89 gam X phn ng va vi HCl to ra 1,255 gam mui. CTCT ca X l : A. NH2-CH2-COOH B. CH3-CHNH2COOH C. CH3-CHNH2-CH2- COOH D. CH3-CH2-CH2-CHNH2COOH Bi 156: T l VCO2 : VH2O sinh ra khi t chy hon ton mt ng ng X ca glixin l 6 : 7 (phn ng sinh ra kh N2). X tc dng vi glixin cho sn phm l ipeptit. X l : A. NH2-CH2-COOH B. NH2-CH2-CH2-COOH C. CH3-CH2-CH2-CHNH2COOH D. Kt qu khcChuyn luyn thi i hc 16

Chuyn III : Amin Amino Axit - PeptitBi 157: Dung dch ca cht no sau y khng lm i mu qu tm :

A. Glixin (CH2NH2-COOH) B. Lizin (H2NCH2-[CH2]3CH(NH2)-COOH) C. Axit glutamic (HOOCCH2CHNH2COOH) D. Natriphenolat (C6H5ONa) Bi 158: Cht no sau y ng thi tc dng c vi dung dch HCl v dung dch NaOH. A. C2H3COOC2H5 B. CH3COONH4 C. CH3CH(NH2)COOH D. C A, B, C Bi 159: Cc cht X, Y, Z c cng CTPT C2H5O2N. X tc dng c c vi HCl v Na2O. Y tc dng c vi H mi sinh to ra Y1. Y1 tc dng vi H2SO4 to ra mui Y2. Y2 tc dng vi NaOH ti to li Y1. Z tc dng vi NaOH to ra mt mui v kh NH3. CTCT ng ca X, Y, Z l : A.X (HCOOCH2NH2), Y (CH3COONH4), Z (CH2NH2COOH) B.X(CH3COONH4), Y (HCOOCH2NH2), Z (CH2NH2COOH) C.X (CH3COONH4), Y (CH2NH2COOH), Z (HCOOCH2NH2) D.X (CH2NH2COOH), Y (CH3CH2NO2), Z (CH3COONH4) Bi 160: Mt cht hu c X c CTPT C3H9O2N. Cho tc dng vi dung dch NaOH un nh, thu c mui Y v kh lm xanh giy qu tm t. Nung Y vi vi ti xt thu c kh etan. Cho bit CTCT ph hp ca X ? A. CH3COOCH2NH2 B. C2H5COONH4. C. CH3COONH3CH3 D. C A, B, C Bi 161: Tng ng vi CTPT C2H5O2N c bao nhiu ng phn c cha 3 nhm chc : A. 1 B. 2 C. 3 D. 4 Bi 162: Mt hp cht hu c X c CTPT C3H7O2N. X phn ng c vi dung dch Br2, X tc dng c vi NaOH v HCl. CTCT ng ca X l : A. CH(NH2)=CHCOOH B. CH2= C(NH2)COOH D. CH2=CHCOONH4 D. C A, B, C Bi 163: Cho cc cht: (1) amoniac. (2) metylamin. (3) anilin. (4) dimetylamin. Tnh baz tng dn theo th t no sau y? A. (1) < (3) < (2) < (4). B. (3) < (1) < (2) < (4). C. (1) < (2) < (3) < (4). D. (3) < (1) < (4) < (2). Bi 164: Cho 0,76 gam hn hp gm amin ng ng lin tip tc dung va u vi V ml dung dich HNO3 0,5M th thu c 2,02 gam hn hp mui khan. Hai amin trn l A.Etylamin v propylamin B. Metylamin v etylamin C.Anilin va benzylamin D.Anilinva metametylanilin Bi 165: -aminoaxit X cha mt nhm -NH2. Cho 10,3 gam X tc dng vi axit HCl (d), thu c 13,95 gam mui khan. Cng thc cu to thu gn ca X l A. NH2CH2CH2COOH B. CH3CH(NH2)COOH C. NH2CH2COOH D. CH3CH2CH(NH2)COOH Bi 166: Dy gm cc cht u lm giy qu tm m chuyn sang mu xanh l A. metyl amin, amoniac, natri axetat B. anilin, metyl amin, amoniac C. anilin, amoniac, natri hiroxit D. amoni clorua, metyl amin, natri hiroxit Bi 167: Amin ng vi cng thc phn t C4H11N c my ng phn mch khng phn nhnh ? A. 4 B.5 C. 6 D.7 Bi 168: Amin thm ng vi cng thc phn t C7H9N c my ng phn ? A. 3 B. 4 C. 5 D. 6 Bi 169: Cho cc cht c cu to nh sau : (1) CH3 - CH2 - NH2 (2) CH3 - NH - CH3 (3) CH3 - CO - NH2 (4) NH2 - CO - NH2 (5) NH2 - CH2 - COOH(6) C6H5 - NH2 (7) C6H5NH3Cl (8) C6H5 - NH - CH3 (9) CH2 = CH - NH2. Cht no l amin ? A. (1); (2); (6); (7); (8) B. (1); (3); (4); (5); (6); (9) C. (3); (4); (5) D. (1); (2); (6); (8); (9). Bi 170: Anilin tc dng c vi nhng cht no sau y ? (1) dung dch HCl (2) dung dch H2SO4 (3) dung dch NaOH (4) dung dch brom (5) dung dch CH3 - CH2 - OH (6) dung dch CH3COOC2H5 A. (1), (2), (3) B. (4), (5), (6) C. (3), (4), (5) D. (1), (2), (4)Chuyn luyn thi i hc 17

Chuyn III : Amin Amino Axit - PeptitBi 171: Pht biu no sau y sai ?

A. Anilin l baz yu hn NH3 v nh hng ht electron ca nhn benzen ln nhm - NH2 bng hiu ng lin hp. B. Anilin khng lm thay i mu giy qu tm m. C. Anilin t tan trong H2O v gc C6H5 - k nc. D. Nh c tnh baz , anilin tc dng c vi dung dch brom. Bi 172: Phng php no thng dng iu ch amin ? A. Cho dn xut halogen tc dng vi NH3 B. Cho ru tc dng vi NH3 C. Hiro ho hp cht nitrin D. Kh hp cht nitro bng hiro nguyn t . Bi 173: Ru v amin no sau y cng bc ? A. (CH3)3COH v (CH3)3CNH2 B. C6H5NHCH3 v C6H5CHOHCH3 C. (CH3)2CHOH v (CH3)2CHNH2 D. (CH3)2CHOH v (CH3)2CHCH2NH2. Bi 174: Tm pht biu sai trong cc pht biu sau ? A. Etylamin d tan trong H2O do c to lin kt H vi nc B. Nhit si ca ru cao hn so vi hirocacbon c phn t khi tng ng do c lin kt H gia cc phn t ru. C. Phenol tan trong H2O v c to lin kt H vi nc. D. Metylamin l cht lng c mi khai, tng t nh amoniac. Bi 175: Trong s cc cht sau : C2H6 ; C2H5Cl; C2H5NH2; CH3COOC2H5; CH3COOH; CH3CHO; CH3OCH3 cht no to c lin kt H lin phn t ? A. C2H6 B. CH3COOCH3 C. CH3CHO ; C2H5Cl D. CH3COOH ; C2H5NH2 Bi 176: Metylamin d tan trong H2O do nguyn nhn no sau y ? A. Do nguyn t N cn cp electron t do d nhn H+ ca H2O. B. Do metylamin c lin kt H lin phn t. C. Do phn t metylamin phn cc mnh. D. Do phn t metylamin to c lin kt H vi H2O. Bi 177: Nguyn nhn gy nn tnh baz ca amin l : A. Do amin tan nhiu trong H2O. B. Do phn t amin b phn cc mnh. C. Do nguyn t N c m in ln nn cp e chung ca nguyn t N v H b ht v pha N. D. Do nguyn t N cn cp eletron t do nn phn t amin c th nhn proton. Bi 178: Dy sp xp ng theo th t gim dn tnh baz l dy no ? (1) C6H5NH2 (2) C2H5NH2 (3) (C6H5)2NH (4) (C2H5)2NH (5) NaOH (6) NH3 A. (1) > (3) > (5) > (4) > (2) > (6) B. (5) > (6) > (2) > (1) > (2) > (4) C. (5) > (4) > (3) > (5) > (1) > (2) D. (5) > (4) > (2) > (6) > (1) > (3) Bi 179: Trong bnh kn cha 35 ml hn hp gm H2, mt amin n chc v 40 ml O2. Bt tia la in phn ng chy xy ra hon ton ri a hn hp v iu kin ban u, th tch cc cht to thnh bng 20 ml gm 50% l CO2, 25% l N2 v 25% l O2. CTPT no sau y l ca amin cho ? A. CH5N B. C2H7N C. C3H6N D. C3H5N Bi 180: Nhiu phn t amino axit kt hp c vi nhau bng cch tch -OH ca nhm - COOH v -H ca nhm -NH2 to ra cht polime (gi l phn ng trng ngng). Polime c cu to mch : (- HN - CH2 - CH2 - COO - HN - CH2 - CH2 - COO - )n Monome to ra polime trn l : A. H2N - CH2 - COOH B. H2N - CH2 - CH2COOH C. H2N - CH2 - CH2 - CH2 - COOH D. Khng xc nh c Bi 181: S ng phn ca amino axit, phn t cha 3 nguyn t C l : A. 1 B. 2 C. 3 D. 4 Bi 182: X l mt amino axit no ch cha mt nhm NH2 v mt nhm -COOH. Cho 0,89 gam X phn ng va vi HCl to ra 1,255 gam mui. CTCT ca X l :Chuyn luyn thi i hc 18

Chuyn III : Amin Amino Axit - Peptit

A. NH2-CH2-COOHCH3 CH CH2 COOH | C. NH2

B.

CH3 CH COOH | NH2

CH3 CH 2 CH 2 CH COOH | D. NH2

Bi 183: T l sinh ra khi t chy hon ton mt ng ng X ca glixin l 6 : 7 (phn ng sinh ra kh

N2). X tc dng vi glixin cho sn phm l ipeptit. X l :

CH3 CH COOH CH3 CH 2 CH COOH | | A. B. NH2-CH2-CH2-COOH C. D. Kt qu khc NH2 NH2Bi 184: Gi tn hp cht c CTCT nh sau theo danh php thng thng.

CH3 CH 2 CH 2 CH 2 N CH 2 CH 3 | CH3

A. Etylmetyl amino butan C. n-butyletyl metyl amin B. Metyletyl amino butan D. metyletylbutylamin Bi 185: Gi tn hp cht c CTCT nh sau theo danh php thng thng :

A. 1-amino-3-metyl benzen. C. m-toludin. B. m-metylanilin. D. C B, C. Bi 186: Amin no sau y c tnh baz ln nht : A. CH3CH=CH-NH2 C. CH3CH2CH2NH2 B.CH3C = C-NH2 D. CH3CH2NH2 Bi 187: Cho cc cht sau : CH3CH2NHCH3(1), CH3CH2CH2NH2(2), (CH3)3N (3). Tnh baz tng dn theo dy : A. (1) < (2) < (3) B. (2) < (3) < (1) C. (3) < (2) < (1) D. (3) < (1) < (2) Bi 188: Cho cc cht sau: p-CH3C6H5NH2(1), m-CH3C6H5NH2 (2), C6H5NHCH3 (3), C6H5NH2 (4). Tnh baz tng dn theo dy : A. (1) < (2) < (4) < (3) B. (4) < (2) < (1) < (3) C. (4) < (3) < (2) < (1) D. (4) < (3) < (1) < (2) Bi 189: Cho cc cht sau : p-NO2C6H4NH2 (1), p-ClC6H5NH2 (2), p-CH3C6H5NH2 (3). Tnh baz tng dn theo dy : A. (1) < (2) < (3) B. (2) < (1) < (3) C. (1) < (3) < (2) D. (3) < (2) < (1) Bi 190: C bao nhiu ng phn amin ng vi CTPT C4H11N ? A. 5 B. 6 C. 7 D. 8 Bi 191: Cho cc cht sau : Ru etylic (1), etylamim (2), metylamim (3), axit axetic (4). Sp sp theo chiu c nhit si tng dn : A. (2) < (3) < (4) < (1) B. (2) < (3) < (4) < (1) C. (3) < (2) < (1) < (4) D. (1) < (3) < (2) < (4) Bi 192: Cho cc dung dch : 1) HNO2 2) FeCl2 3) CH3COOH 4) Br2 Cc dung dch tc dng c vi anilin l : A. (1), (4) B. (1), (3) C. (1), (3), (4) D. C 4 cht Bi 193: Cho phn ng : X + Y => C6H5NH3Cl X + Y c th l : A. C6H5NH2 + Cl2. C. C6H5NH2 + HCl B. (C6H5)2NH + HCl. D. C A, B, C Bi 194: Cho s : (X) => (Y) => (Z) => M (trng). Cc cht X, Y, Z ph hp s trn l :Chuyn luyn thi i hc 19

Chuyn III : Amin Amino Axit - Peptit

A. X (C6H6), Y (C6H5NO2), Z (C6H5NH2) B. X (C6H5CH(CH3)2), Y (C6H5OH), Z (C6H5NH2) C. X (C6H5NO2), Y (C6H5NH2), Z (C6H5OH) D. C A v C Bi 195: Hy chn thuc th thch hp phn bit 3 cht kh sau : imetyl amin, metylamin, trimetyl amin. A. Dung dch HCl B. Dung dch FeCl3 C. Dung dch HNO2 D. C B v C Bi 196: Thuc th thch hp phn bit 3 cht lng : phenol, anilin, benzen l : A. Dung dch HNO2 B. Dung dch FeCl3 C. Dung dch H2SO4 D. Nc Br2 Bi 197: Phn ng no sau y sai ? C6H5NH2 + H2O => C6H5NH3OH (1) (CH3)2NH + HNO2 => 2CH3OH + N2 (2) C6H5NO2 + 3Fe + 7 HCl => C6H5NH3Cl + 3FeCl2 + 2H2O. (3)

(4) A. (1) (2) (4) B. (2) (3) (4) C. (2) (4) D. (1) (3) Bi 198: ti to li anilin t dung dch phenyl amoniclorua phi dng dung dch cht no sau y : A. Dung dch HCl B. Dung dch NaOH C. Dung dch Br2 D. C A, B, C Bi 199: t chy mt amin no n chc mch thng ta thu cCO2 v H2O c t l mol 8 : 11 .CTCT ca X l A. (C2H5)2NH B. CH3(CH2)3NH2 C. CH3NHCH2CH2CH3 D. C A , B , C Bi 200: Cho 11,8 g hn hp X gm 3 amin : n-propyl amin, etylmetylamin, trimetyl amin. Tc dng va vi V ml dung dch HCl 1M. Gi tr ca V l : A. 100ml B. 150 ml C. 200 ml D. Kt qu khc Bi 201: t chy hon ton a mol hn hp X gm 2 amin no n chc thu c 5,6 (l) CO2 (ktc) v 7,2 g H2O. Gi tr ca a l : A. 0 ,05 mol B. 0,1 mol C. 0,15 mol D. 0,2 mol Bi 202: t chy hon ton hn hp X gm 2 amin no n chc k tip nhau trong dy ng ng, thu c 22 g CO2 v 14,4 g H2O. CTPT ca hai amin l : A. CH3NH2 v C2H7N B. C3H9N v C4H11N C. C2H7N v C3H9N D. C4H11N v C5H13 N Bi 203: Cht no sau y ng thi tc dng c vi dung dch HCl v dung dch NaOH. A. C2H3COOC2H5 B. CH3COONH4 C. CH3CHNH2COOH D. C A, B, C Bi 204: Mt hp cht hu c X c CTPT C2H7O2N. X d dng phn ng vi dung dch NaOH v dung dch HCl. CTCT ph hp ca X l : A. CH2NH2COOH C. HCOONH3CH3 B. CH3COONH4 D. C A, B v C Bi 205: Tng ng vi CTPT C3H9O2N c bao nhiu ng phn cu to va tc dng c vi dung dch NaOH va tc dng vi dung dch HCl. A. 3 B. 9 C.12 D.15 Bi 206: Cho 12,55 gam mui CH3CH(NH3Cl)COOH tc dng vi 150 ml dung dch Ba(OH)2 1M. C cn dung dch sau phn ng thu c m gam cht rn. Gi tr ca m l : A. 15,65 g B. 26,05 g C. 34,6 g D. Kt qu khc Bi 207: Cho 22,15 g mui gm CH2NH2COONa v CH2NH2CH2COONa tc dng va vi 250 ml dung dch H2SO4 1M. Sau phn ng c cn dung dch th lng cht rn thu c l : A. 46,65 g B. 45,66 g C. 65,46 g D. Kt qu khc Bi 208: Cho 13,35 g hn hp X gm CH2NH2CH2COOH v CH3CHNH2COOH tc dng vi V ml dung dch NaOH 1M thu c dung dch Y. Bit dung dch Y tc dng va vi 250 ml dung dch HCl 1M. Gi tr ca V l :Chuyn luyn thi i hc 20

Chuyn III : Amin Amino Axit - Peptit

A. 100 ml B. 150 ml C. 200 ml D. 250 ml Bi 209: Cho 20,15 g hn hp X gm (CH2NH2COOH v CH3CHNH2COOH) tc dng vi 200 ml dung dch HCl 1M thu c dung dch Y. Y tc dng va vi 450 ml dung dch NaOH 1M . Phn trm khi lng ca mi cht trong X l: A. 55,83 % v 44,17 % C. 53,58 % v 46,42 % B. 58,53 % v 41,47 % D. 52,59 % v 47,41% Bi 210: Cho 4,41 g mt aminoaxit X tc dng vi dung dch NaOH d cho ra 5,73 g mui. Mt khc cng lng X nh trn nu cho tc dng vi dung dch HCl d thu c 5,505 g mui clorua. Xc nh CTCT ca X. A. HOOC-CH2CH2CH(NH2)COOH B. CH3CH(NH2)COOH C. HOOCCH2CH(NH2)CH2COOH D. C A v B Bi 211: Mt amino axit (X) c cng thc tng qut NH2RCOOH. t chy hon ton a mol X thu c 6,72 (l) CO2 (ktc) v 6,75 g H2O. CTCT ca X l : A. CH2NH2COOH B. CH2NH2CH2COOH C. CH3CH(NH2)COOH D. C B v C Bi 212: Cht no sau y c tnh baz mnh nht ? A. NH3 B. C6H5NH2 C. CH3-CH2-CH2-NH2 D. CH3-CH(CH3)-NH2 Bi 213: Mt amino axit no X ch cha mt nhm -NH2 v mt nhm -COOH. Cho 0,89 g X phn ng va vi HCl to ra 1,255 g mui. CTCT ca X l: A. H2N-CH2-COOH B. CH3-CH(NH2)-CH2-COOH C. H2N-CH2-CH2-COOH D. B, C, u ng. Bi 214: A + HCl => RNH3Cl. Trong ( A) (CxHyNt) c % N = 31,11% CTCT ca A l : A. CH3 - CH2 - CH2 - NH2 B. CH3 - NH - CH3 C. C2H5NH2D. C2H5NH2 v CH3 - NH CH3 Bi 215: L do no sau gii thch tnh baz ca monoetylamin mnh hn amoniac : A. Nguyn t N cn i electron cha to lin kt B. nh hng y electron ca nhm -C2H5 C. Nguyn t N c m in ln D. Nguyn t nit trng thi lai ho Bi 216: Nhng cht no sau y lng tnh : A. NaHCO3 B. H2N-CH2-COOH C. CH3COONH4 D. C A, B, C Bi 217: Ngi ta iu ch anilin bng cch nitro ho 500 g benzen ri kh hp cht nitro sinh ra. Khi lng anilin thu c l bao nhiu bit rng hiu sut mi giai on u t 78%. A. 362,7 g B. 463,4 g C. 358,7 g D. 346,7 g Bi 218: 9,3 g mt ankylamin cho tc dng vi dung dch FeCl3 d thu c 10,7 g kt tA. CTCT l : A. C2H5NH2 B. C3H7NH2 C. C4H9NH2 D. CH3NH2 Bi 219: (A) l mt hp cht hu c c CTPT C5H11O2N. un (A) vi dung dch NaOH thu c mt hp cht c CTPT C2H4O2NNa v cht hu c (B). Cho hi qua CuO/t0 thu c cht hu c (D) c kh nng cho phn ng trng gng. CTCT ca A l : A. CH2 = CH - COONH3 - C2H5 B. CH3(CH2)4NO2 C. H2N- CH2 - CH2 - COOC2H5 D. NH2 - CH2COO - CH2 - CH2 - CH3 Bi 220: Dung dch etylamin c tc dng vi dung dch ca mui no di y : A. FeCl3 B. NaCl C. Hai mui FeCl3 v NaCl D. AgNO3 Bi 221: Sp xp cc hp cht sau y theo th t gim dn tnh baz : (1) C6H5NH2 (2) C2H5NH2 (3) (C6H5)2NH (4) (C2H5)2NH (5) NaOH (6) NH3 A. (5) > (4) > (2) > (1) > ( 3) > (6) B. (1) > (3) > (5) > (4) > (2) > (6) C. (4) > (5) > ( 2) > (6) > ( 1) > (3) D. (5) > (4) > (2) > (6) > (1) > (3) Bi 222: Nhit si ca C4H10 (1), C2H5NH2 (2), C2H5OH (3) tng dn theo th t: A. (1) < (2) < (3) B. (1) < (3) < (2) C. (2) < ( 3) < (1) D. ( 2) < ( 1) < (3)

Chuyn luyn thi i hc

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Chuyn III : Amin Amino Axit - Peptit

1.C 9.D 17.C 25.D 33.D 41.B 49.B 57.A 65.A 73.A 81.D 89.A 97.A 105.A 113.B 121.C 129.C 137.C 145.D 153.C 161.A 169.D 177.D 185.D 193.C 201.B 209.A 217.A

2.C 10.C 18.C 26.D 34.B 42.D 50.A 58.B 66.D 74.C 82.A 90.C 98.A 106.C 114.B 122.D 130.B 138.B 146.D 154.C 162.D 170.D 178.D 186.C 194.A 202.C 210.D 218.D

3.D 11.C 19.B 27.B 35.A 43.B 51.A 59.C 67.D 75.A 83.D 91.D 99.A 107.B 115.A 123.C 131.B 139.D 147.B 155.B 163.B 171.D 179.A 187.C 195.D 203.D 211.A 219.D

4.B 12.B 20.B 28.B 36.C 44.A 52.A 60.B 68.A 76.D 84.B 92.A 100.D 108.D 116.B 124.C 132.D 140.B 148.B 156.B 164.B 172.A 180.B 188.B 196.B 204.A 212.C 220.A

5.C 13.D 21.D 29.A 37.A 45.A 53.A 61.A 69.A 77.A 85. 93.A 101.A 109.C 117.B 125.C 133. 141.A 149.B 157.A 165.D 173.B 181.D 189.A 197.D 205.A 213.C 221.D

6.B 14.A 22.C 30.A 38.C 46.A 54.C 62.D 70.A 78.A 86.C 94.D 102.B 110.A 118.D 126.D 134.D 142.B 150.C 158.C 166.A 174.D 182.B 190.D 198.B 206.C 214.C 222.B

7.B 15.D 23.B 31.A 39.C 47.B 55.B 63.A 71.D 79. 87.A 95.C 103.B 111.B 119.B 127.C 135.C 143. 151.A 159.D 167.B 175.D 183.A 191.C 199.D 207.A 215.B

8.B 16.A 24.B 32.B 40.A 48.D 56.C 64.C 72.A 80.C 88.D 96.C 104.D 112.D 120.A 128.D 136.A 144.C 152.D 160.C 168.C 176.A 184.C 192.A 200.B 208.D 216.D

Chuyn luyn thi i hc

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