Geometry Basketball Reviewing Circles. Find the arc or angle.
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Transcript of Geometry Basketball Reviewing Circles. Find the arc or angle.
Geometry Basketball
Reviewing Circles
Find the arc or angle.
Solution
55 +65 = 120
180-120=60
Find the arc or angle.
Solution
55º
Vertical Angles
are congruent!
Find the arc or angle.
Solution
Semicircle + Arc NB
180 +55 =235
Find the arc or angle.
Solution
Inscribed Angle is ½ of its intercepted arc
<ABC = ½(84)
=42
Find the arc or angle.
Solution
Inscribed Angle is ½ its intercepted arc
<ABC= ½ (arc AC)
65 = ½ (arc AC)
130 = arc AC
Find the arc or angle.
Solution
When the lines intersect ON THE CIRCLE, the angle is
½ of the arc.
135= ½ (MLK)
270 = MLK
Find the arc or angle.
Solution
When the lines intersect ON THE CIRCLE, the angle is
½ of the arc.
m<1= ½ (260)
m<1 = 130
Find the arc or angle.
Solution
When the lines intersect IN THE CIRCLE, the angle is the sum of the arcs divided by 2.
Wrong arcs 125+105=230
360-230=130 Sum of correct arcs
m<1=130/2
m<1 = 65
Find the arc or angle.
Solution
When the lines intersect OUTSIDE THE CIRCLE, the angle is the
bigger arc –smaller arc divided by 2.
m<1= (122-64)/2
m<1 = 58/2
m<1 = 29
Find the arc or angle.
Solution
When the lines intersect OUTSIDE THE CIRCLE, the angle is the
bigger arc –smaller arc divided by 2.
m<1= (135-55)/2
m<1 = 80/2
m<1 = 40
Find the arc or angle.
Solution
When the lines intersect OUTSIDE THE CIRCLE,
Outside segmet (whole segment) = Outside segment (whole segment)
8(x+8) = 9 (9)
8(x+8) = 9²
8x+64=81
8x=17
X=17/8
Find the arc or angle.
Solution
When the lines intersect OUTSIDE THE CIRCLE,
Outside segmet (whole segment) = Outside segment (whole segment)
5(3x+5) = 10 (10)
5(3x+5) = 10²
15x+25=100
15x=75
X=5
Find the center and radius of the circle.
Solution
Center : (-3,4)
Radius: 6
Find the arc or angle.
Solution
m<KMX = 75
Vertical Angles are Congruent!
Find the arc or angle.
Solution
Semicircle = 180
90 +75 = 165
180 – 165 = 15
Find the arc or angle.
Solution
Semicircle + Arc LY
180 + 75
255
Find the arc or angle.
Solution
Inscribed Angle is ½ its intercepted arc
m<TUV= ½ (arc TV)
m<TUV = ½ (240)
m<TUV = 120
Find the arc or angle.
Solution
When the lines intersect ON THE CIRCLE, the angle is ½ of the arc.
53= ½ (arcAB)
106 = arc AB
Find the arc or angle.
Solution
When the lines intersect IN THE CIRCLE, the angle is the sum of the
arcs divided by 2.
Use Semicircle 180 – 147 = 33
m<1= (67+33)/2
m<1=100/2
m<1=50
Find the arc or angle.
Solution
When the lines intersect ON THE CIRCLE, the angle is ½ of the arc.
Use full circle 360-150=210
m<1= ½ (210)
m<1=105
Find the arc or angle.
Solution
When the lines intersect OUTSIDE THE CIRCLE, the angle is the
bigger arc –smaller arc divided by 2.
Use full Circle 360-234 =126m<1= (234-126)/2
m<1 = 108/2m<1 = 54
Find x.
Solution
When the lines intersect IN THE CIRCLE, (part)(part) = (part)(part)
(2x)(2x) = (5)(20)4x²=100
x²=25x= 5 or -5
(the lengths can’t be negative, so…)x=5
Find x.
Solution
When the lines intersect OUTSIDE THE CIRCLE,
(part)(part) = (part)(part)(2x)(2x) = (5)(20)
4x²=100x²=25
x= 5 or -5 (the lengths can’t be negative, so…)
x=5
Find x.
Find x.
Find the angle.
Find the angle.
Find the angle.