Geometric Models & Camera Calibration

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1 Geometric Models & Camera Calibration Reading: Chap. 2 & 3

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Geometric Models & Camera Calibration. Reading: Chap. 2 & 3. Introduction. We have seen that a camera captures both geometric and photometric information of a 3D scene. Geometric: shape, e.g. lines, angles, curves Photometric: color, intensity - PowerPoint PPT Presentation

Transcript of Geometric Models & Camera Calibration

Page 1: Geometric Models &  Camera Calibration

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Geometric Models & Camera Calibration

Reading: Chap. 2 & 3

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CS4243: Geometric Models

Introduction

We have seen that a camera captures both geometric and photometric information of a 3D scene. Geometric: shape, e.g. lines, angles, curves Photometric: color, intensity

What is the geometric and photometric relationship between a 3D scene and its 2D image?

We will understand these in terms of models.

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CS4243: Geometric Models

Models

Models are approximations of reality. “Reality” is often too complex, or computationally

intractable, to handle. Examples:

Newton’s Laws of Motion vs. Einstein’s Theory of Relativity

Light: waves or particles?

No model is perfect. Need to understand its strengths & limitations.

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CS4243: Geometric Models

Camera Projection Models

3D scenes project to 2D images Most common model: pinhole camera model

From this we may derive several types of projections: orthographic weak-perspective para-perspective perspective

least accurate

most accurate

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CS4243: Geometric Models

f f

YZ

object

virtual image planereal image plane

image is not invertedimage is inverted

optical centre

Pinhole Camera Model

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CS4243: Geometric Models

Real vs. Virtual Image Plane

The image is physically formed on the real image plane (retina).

The image is vertically and laterally inverted. We can imagine a virtual image plane at a distance of f

in front of the camera optical center, where f is the focal length.

The image on this virtual image plane is not inverted. This is actually more convenient.

Henceforth, when we say “image plane” we will mean the virtual image plane.

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CS4243: Geometric Models

Perspective Projection

1

Z

Y

X

'

'

y

x

f

u

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CS4243: Geometric Models

Perspective Projection The imaging process is a many-to-one mapping

all points on the 3D ray map to a single image point.

Therefore, depth information is lost

From similar triangles, can write down the perspective equation:

,'

,'

Z

Y

f

y

Z

X

f

x

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CS4243: Geometric Models

Perspective Projection

MPu

Z

Y

X

f

f

w

v

u

y

x

or

10

0

0

100

00

00

'

'

This assumes coordinate axes is at the pinhole.

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CS4243: Geometric Models

t

X

Y

Z

fi

fj

fk

World coordinatesystem

Camera coordinatesystem

3D Scene point P

t : World origin w.r.t. camera coordinate axes

P : 3D position of scene point w.r.t world coordinate axes

Rotation R

R : Rotation matrix to align world coordinate axes to camera axes

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CS4243: Geometric Models

Perspective Projection

100sin0

cot-

matrixparameterintrinsic33:

matrixprojection43:

0

0

v

u

K

tRK

M

MPu

α, β : scaling in image u, v axes, respectively Θ : skew angle, that is, angle between u, v axesu0, v0 : origin offsetNote: α=kf, β=lf where k, l are the magnification factors

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CS4243: Geometric Models

Intrinsic vs. Extrinsic parameters Intrinsic: internal camera parameters.

6 of them (5 if you don’t care about focal length) Focal length, horiz. & vert. magnification, horiz. & vert. offset,

skew angle

Extrinsic: external parameters 6 of them 3 rotation angles, 3 translation param

Imposing assumptions will reduce # params. Estimating params is called camera calibration.

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Representing Rotations

Euler angles

pitch: rotation about x axis :

yaw: rotation about y axis:

roll: rotation about z axis: X

Y

Z

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Rotation Matrix

)cos()cos()sin()cos()sin(

)sin()cos()cos()sin()sin()cos()cos()sin()sin()sin()cos()sin(

)sin()sin()cos()sin()cos()cos()sin()sin()sin()cos(cos)cos(

xyz RRRR

Two properties of rotation matrix:

R is orthogonal: RTR = Idet(R) = 1

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Camera centre

opticalaxis

Image plane

Parallel lines

Projection rays are parallel

Orthographic Projection

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Orthographic Projection Equations

10

101

0

0

000

010

001

2

1

y

x

T

T

T

T

t

t

r

r

tRM

TT rr 21 ,

yx tt ,: first two rows of R

: first two elements of t

This projection has 5 degrees of freedom.

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Image plane Parallel lines

Weak-perspective Projection

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Weak-perspective Projection

10100

00

00

2

1

y

x

T

T

T

t

t

r

r

M

This projection has 7 degrees of freedom.

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Parallel lines

Image plane

Para-perspective Projection

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Para-perspective Projection

Camera matrix given in textbook Table 2.1, page 36.

Note: Written a bit differently. This has 9 d.o.f.

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Real cameras

Real cameras use lenses Lens distortion causes distortion in image

Lines may project into curves See Chap 1.2, 3.3 for details

Change of focal length (zooming) scales the image not true if assuming orthographic projection)

Color distortions too

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Color Aberration

Bad White Balance

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Color Aberration

Purple Fringing

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Color Aberration

Vignetting

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Geometric Camera Calibration

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Recap

A general projective matrix:

This has 11 d.o.f. , i.e. 11 parameters 5 intrinsic, 6 extrinsic

How to estimate all of these? Geometric camera calibration

PtRKu

MPu

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Key Idea

Capture image of a known 3D object (calibration object).

Establish correspondences between 3D points and their 2D image projections.

Estimate M Estimate K, R, and t from M Estimation can be done using linear or non-

linear methods. We will study linear methods first.

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Setting things up

Calibration object: 3D object, or 2D planar object captured at different locations

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Setting it up

Suppose we have N point correspondences: P1, P2, … PN are 3D scene points

u1, u2, … uN are corresponding image points

Let mT1, mT

2, mT3 be the 3 rows of M

Let (ui, vi) be the (non-homogeneous) coords of the i th image point.

Let Pi be the homogeneous coords of i th scene point.

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Math

For the i th point

Each point gives 2 equations.

Using all N points gives 2N equations:

0)(

0)(

32

31

iT

i

iT

i

Pmvm

Pmum

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Math

0

0

0

0

0

3

2

1111

111

m

m

m

Pv

Pu

P

P

PvP

PuP

TNN

TNN

TN

T

T

TN

TTT

TTT

A m = 0

A : 2N x 12 matrix, rank is 11m : 12 x 1 column vectorNote that m has only 11 d.o.f.

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Math

Solution? m is in the Nullspace of A !

Use SVD: A = U ∑ VT

m = last column of V m is only up to an unknown scale In this case, SVD solution makes || m || = 1

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Estimating K, R, t

Now that we have M (3x4 matrix)

c is the 3D coords of camera center wrt World axes Let ĉ be homogeneous coords of c It can be shown that M ĉ = 0

So ĉ is in the Nullspace of M And t is computed from –Rc, once R is known.

Rct

pBtRKM

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Estimating K, R, t

B, the left 3x3 submatrix of M is KR Perform “RQ” decomposition on B. The “Q” is the required rotation matrix R And the upper triangular “R” is our K matrix !

Impose the condition that diagonals of K are positive

We are done!

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RQ factorization

Any n x n matrix A can be factored into A = RQ Where both R, Q are n x n R is upper triangular, Q is orthogonal

Not the same as QR factorization Trick: post multiply A by Givens rotation

matrices: Qx ,Qy, Qz

sin,coswhere

100

0

0

,

0

010

0

,

0

0

001

sc

cs

sc

Q

cs

sc

Q

cs

scQ zyx

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RQ factorization

c, s chosen to make a particular entry of A zero For example, to make a21 = 0, we solve

Choose Qx ,Qy, Qz such that

222

221

21

222

221

22

2221

,

0

aa

as

aa

ac

saca

RQQQRQA

RQQAQTx

Ty

Tz

zyx

ngularupper tria

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Degeneracy

Caution: The 3D scene points should not all lie on a plane. Otherwise no solution

In practice, choose N >= 6 points in “general position”

Note: the above assumes no lens distortion. See Chap 3.3 for how to deal with lens distortion.

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Summary

Presented pinhole camera model From this we get hierarchy of projection types Perspective, Para-perspective, Weak-perspective,

Orthographic

Showed how to calibrate camera to estimate intrinsic + extrinsic parameters.