Genome closure and finishing. Clone walking Already sequenced Unsequenced primer locations...
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Transcript of Genome closure and finishing. Clone walking Already sequenced Unsequenced primer locations...
![Page 1: Genome closure and finishing. Clone walking Already sequenced Unsequenced primer locations tgcatgatcgtgatcat acgtactagcactagtactgtagtcgatgcactgatcgatcgatcgatgctacgatgcatgct...](https://reader036.fdocuments.net/reader036/viewer/2022062716/56649dbc5503460f94aadb90/html5/thumbnails/1.jpg)
Genome closure and finishing
![Page 2: Genome closure and finishing. Clone walking Already sequenced Unsequenced primer locations tgcatgatcgtgatcat acgtactagcactagtactgtagtcgatgcactgatcgatcgatcgatgctacgatgcatgct...](https://reader036.fdocuments.net/reader036/viewer/2022062716/56649dbc5503460f94aadb90/html5/thumbnails/2.jpg)
Clone walking
Already sequenced
Unsequenced
primer locations
tgcatgatcgtgatcatacgtactagcactagtactgtagtcgatgcactgatcgatcgatcgatgctacgatgcatgct...
clone insert (from shotgun library)
sequencing primer
direction of extension
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PCR to close gapsScaffold
Design primers at these locations
• Run PCR for each pair of primers• Primers must be in non-repeat sequences• Primers must be as close as possible to each gap• PCR works best if primers are less than 2kb apart
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What about physical gaps?
How to order and orient all scaffolds?
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Traditional strategy: combinatorial PCR
• Design primers for each end of each scaffold
• With N/2 scaffolds and N “ends”, run a separate PCR reaction for every pair of ends
• (N choose 2) reactions = N(N-1)/2• Example: 24 physical gaps, 48 ends,
PCR experiments will be:
€
48
2
⎛
⎝ ⎜
⎞
⎠ ⎟=1128
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Multiplex PCR
actgagatatacgttgagatataa
gcgacgctgctc ccagcgctgttc
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Multiplexing more primers
• Up to 12 primers per tube
• If any two primers surround the same gap, they produce a product
• If more than 2 pairs react, we get multiple products
• Let N = number of primers = 48
• K = max primers/tube = 12
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POMP:pipette optimized multiplex PCR
• minimize number of laboratory reactions
• with N=48, number of combinatorial PCRs is 1128
• number of pipettings = 2256
• POMP: 28 reactions, 104 pipettings
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POMP
• Create pools of size K/2 = 6
• Each of N=48 primers put into 1 pool
• So we create N/(K/2) = 8 pools, P1...P8
• Now create multiplex PCR reactions with all pairs of pools
• (8 choose 2) = 28 reactions needed
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POMP
• Guarantees that all primers are tested against all others
• Each reaction tests (12 choose 2) = 66 pairs
• Protocol tests 66*28 = 1848 pairs• Only 1128 distinct pairs, so POMP has
some redundancy - some pairs appear in more than one reaction
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Pooling primersACGTCGATGCATCGA
ACGTCGATGCATCGA
ACGTCGATGCATCGA
ACGTCGATGCATCGA
ACGTCGATGCATCGA
GCATGCTCGTACGAT
GCATGCTCGTACGAT
GCATGCTCGTACGAT
GCATGCTCGTACGAT
GCATGCTCGTACGAT
GCATGCTCGTACGATACGTCGATGCATCGA
ATCGTGACAGTGAAC GCATCGATGCATGT
GCATCGATGCATGT
GCATCGATGCATGT
GCATCGATGCATGT
GCATCGATGCATGT
GCATCGATGCATGT
ATCGTGACAGTGAAC
ATCGTGACAGTGAAC
ATCGTGACAGTGAAC
ATCGTGACAGTGAAC
ATCGTGACAGTGAAC
GCATCGATGCATGT
GCATCGATGCATGT
GCATCGATGCATGT
GCATCGATGCATGT
GCATCGATGCATGT
GCATCGATGCATGT
GCATCGATGCATGT
GCATCGATGCATGT
GCATCGATGCATGT
GCATCGATGCATGT
GCATCGATGCATGT
GCATCGATGCATGT
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Testing all Pools
P1
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How many pipette operations?
• 48 pipettings to create the pools (one for each primer)
• 2 pipettings to create each multiplex reaction mix
• Total: 48 + 2(28) = 104
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Results: Streptococcus pneumoniae
• N=48 primers, N/2 = 24 scaffolds, 24 gaps• 19 products observed in the first experiment
• Q: how many gaps closed?
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Interpreting results
• Case 1: product appears with Pi and Pj, but not in any other lane containing Pi– see P2P6 or P7P8 on previous slide– purify and sequence product directly
• Case 2: product appears in Pi and Pj and also in other lanes containing Pi– thus two primers within Pi reacted– see pool P5 on previous slide
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A: Deconvoluting pool P5: eliminate each of the six primers from the pool and run 6 standard PCRs
Answer: p25 and p29
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B: Pools P2 and P3 gave two products
• Could run 12 more PCRs: eliminate each of 12 primers and re-run multiplex PCR
• However, 5 of the 12 were eliminated by other results• For example, primer p10 was eliminated by results from P1-P2
•Answers:•p11 in Pool 2 pairs with p13 in Pool 3•p16 in Pool 3 pairs with p8 in Pool 2
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POMP requirements• (Ideally) If no restriction on K, choose K
based on N (where N = 2 x (#gaps))• Make pools of size K/2
Reactions:
Pipettings:
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POMP summary for S. pneumoniae
• Out of 48 gaps, 42 were closed
• Strategy employs slightly under N/2 reactions, thus expected number of products per tube is ~1
• This was borne out in experiments
• This became a standard lab technique at TIGR
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