Gears Review

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    Gear trains (Chapter 6)

    Change torque, speed Why we need gears

    Example: engine of a containership

    Optimum operating speed of the engine about400 RPM

    Optimum operating speed of the propellerabout 100 RPM

    Need reduction gear

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    Types of gears

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    Gear box

    Synchronizers

    Stick shift

    The gear box is in first gear, second gear

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    Gear Nomenclature (6.1)

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    Important definitions Velocity ratio=mV=angular velocity of output

    gear/ angular velocity of input gear=pitch diameter

    of input gear/pitch diameter of output gear

    Torque ratio=mT=torque at output gear/torque atinput gear

    mT=1/mV

    Gear ratio=mG=Ngear/Npinion,mG is almost alwaysgreater than one

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    Fundamental law oftooth gearing (6.2 and 6.3):velocity ratio must be constant as gears rotate

    Angular velocity ratio= ratio

    of distances of P from centers

    of rotation of input and output

    gear.

    If common normal werefixed then the velocity ratio

    would be constant.

    PO

    PO

    3

    2

    2

    3

    3

    T

    3

    2

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    Generating gear teeth profile

    P

    Steps:Select base circles

    Bring common normal AB

    Draw involutes CD, EF

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    Gear action

    Angular velocity of

    Gear 3 / angular

    Velocity of gear 2 =

    O2P/O3P = constant

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    Fundamental law of gearing:The common normal of the tooth profiles

    at all points within the mesh must always

    pass through a fixed point on the line ofthe centers calledpitch point. Then the

    gearsets velocity ratio will be constant

    through the mesh and be equal to the ratioof the gear radii.

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    Base circle radius =

    Pitch circle radius cos

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    Path of approach: BP=ua=[(r3+a)2-rb3

    2]1/2-r3sin

    Path of recess: PC=ur=[(r2+a)2-rb2

    2]1/2-r2sin

    Final contact: CInitial contact: B

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    Standard gears: American Association of Gear

    Manufacturers (AGMA) (6.4)

    Teeth of different gears have same profile as long as the

    angle of action and pitch is the same.

    Can use same tools to cut different gears. Faster and

    cheaper product. Follow standards unless there is a very

    good reasons not to do so.

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    Template for teeth of standard gears

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    AGMA Specifications

    Diametral pitch, pd=1, 1.25, 1.5,,120

    Addendum of pinion = addendum gear

    Observations

    The larger the pitch, the smaller the gear

    The larger the angle of action: the larger the

    difference between the base and pitch circles,the steeper the tooth profile, the smaller the

    transmitted force.

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    AGMA Standard Gear Specifications

    Parameter Coarse pitch

    (pd=N/d20)Pressure angle, 200 or 250 (not common) 200

    Addendum, a 1/pd 1/pd

    Dedendum, b 1.25/pd 1.25/pd

    Working depth 2.00/pd 2.00/pd

    Whole depth 2.25/pd 2.2/pd+0.002

    Circular tooth thickness 1.571/pd (circular pitch/2) 1.571/pd

    Fillet radius 0.30/pd Not standardized

    Clearance 0.25/pd 0.25/pd+0.002

    Minimum width at top

    land

    0.25/pd Not standardized

    Circular pitch /pd /pd

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    1/pd

    1.25/pd 1.571/pd

    /pd

    Min: 0.25/pd

    0.3/pd

    0.25/pd

    d=N/pd

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    Planetary (or Epicyclic) Gears (10.4)

    Gears whose centers can move

    Used to achieve large speed reductions in

    compact space

    Can achieve different reduction ratios by

    holding different combinations of gears

    fixed

    Used in automatic transmissions of cars

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    Planetary gear

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    Planet

    CarrierInput shaft

    Sun gear

    Ring gear

    Components of a planetary gear

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    A variant of a planetary gear

    Carrier

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    Planetary gears

    Planetary gears in automotive

    transmission

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    Velocity Analysis Of Planetary Gears (10.6, 10.7)

    Two degrees of freedom

    Given the velocities of two gears (e.g. sun

    and carrier) find velocities of other gears

    Approach

    Start from gear whose speed is given

    Use equation gear = car+ gear/car

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    Velocity analysis of planetary gear

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    This program finds the velocities of the remaining links giventhe velocities of two links in a planetary gear.

    Input:Number of teeth of sun, planet and ring gears, N1, N3, N4,respectively.

    N1 30

    N3 35

    N4 100

    Velocities of two links: specify the known values of the inputsand guess the values of the outputs:

    3 100

    4 120

    1 100

    2 100

    12 100

    Given

    3 0

    4 1

    1 2 12

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    1224

    1223

    1221

    4

    1

    3

    1

    N

    N

    N

    N

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    Find

    1 2 3 4 12

    3.333

    1.538

    0

    1

    1.795