# G.C.E. (A.L.) Examination

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G.C.E. (A.L.) ExaminationDecember 2006Mathematics I(Q1-Q5)Model Solutions*We conduct individual classes upon request.Contact us at: home.video.tutor@gmail.com for more informationG.C.E. (O.L.) Examination

G.C.E.(O.L.)-Mathematics December 2006Paper I Q1 (Model Solutions)Q1. The price of a pencil is Rs. 3.50. What is the price of 5 such pencils? Rs. 3.50 X 5 = Rs 15 + Rs 2.50 = Rs 17.50Ans:

G.C.E.(O.L.)-Mathematics December 2006Paper I Q1S1 (Model Solutions)Q1S1. The price of a pencil is Rs. 13. What is the price of 12 such pencils? 13 X 12 = 15_13 + 2 = 153 X 2 = 6 6156Supplementary question 1 (Q1S1) to show a faster method of multiplying two numbers between 10 and 20. Ans:

G.C.E.(O.L.)-Mathematics December 2006Paper I Q1S2 (Model Solutions)Q1S2. The price of a pencil is Rs. 13. What is the price of 19 such pencils? 13 X 19 = 22_13 + 9 = 223 X 9 = 27 27247 27Supplementary question 2 (Q1S2) to show a faster method of multiplying two numbers between 10 and 20. Ans:

G.C.E.(O.L.)-Mathematics December 2006Paper I Q1S3 (Model Solutions)Q1S3. The price of a pen is Rs. 95. What is the price of 98 such pens? Rs. 95 X 98 = 9310 (-5) X (-2) Supplementary question 3 (Q1S3) to show a faster method of multiplying two numbers closer to 100. Ans:

G.C.E.(O.L.)-Mathematics December 2006 Paper I Q2 (Model Solutions)Q2. Simplify: 62.36-7.83 62.36 7.83--------54.53Ans:

G.C.E.(O.L.)-Mathematics December 2006 Paper I Q3 (Model Solutions)Q3. What is the value of ? 9=3 X 3 Therefore, Ans:

G.C.E.(O.L.)-Mathematics December 2006 Paper I Q4 (Model Solutions)Q4. Solve: a-5=3Ans:

G.C.E.(O.L.)-Mathematics December 2006 Paper I Q5 (Model Solutions)Q5. The number of vehicles sold by a certain company on 5 days of the week is shown in the picture graph. How many vehicles were sold on Wednesday? = 4 vehiclesNo of vehiclesDayFridayThursdayWednesdayTuesdayMondayAns:Cars sold on Wednesday = 3 units x 4 vehicles per unit = 12

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