Full Report 5 Crosstabs
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Transcript of Full Report 5 Crosstabs
![Page 1: Full Report 5 Crosstabs](https://reader035.fdocuments.net/reader035/viewer/2022071709/55cf9208550346f57b92f4f2/html5/thumbnails/1.jpg)
Motivation48. Marital Status X 10g. When considering the flexibility of flight schedules only: Ultra Long-haul flights in Full-Fledged Airline
Chi-Square Calculations
Case Processing SummaryCases
Valid Missing TotalN Percent N Percent N Percent
48. Marital Status * 10g. Consider Schedules (Ultra/ Full)
39 100.0% 0 0.0% 39 100.0%
48. Marital Status * 10g. Consider Schedules (Ultra/ Full) Crosstabulation10g. Consider Schedules (Ultra/ Full) Total
Very Reluctant
Reluctant Neutral Willing Very Willing
48. Marital Status
SingleCount 1 0 3 5 6 15Expected Count .4 1.2 3.5 4.6 5.4 15.0
PartneredCount 0 3 1 1 0 5Expected Count .1 .4 1.2 1.5 1.8 5.0
MarriedCount 0 0 5 6 8 19Expected Count .5 1.5 4.4 5.8 6.8 19.0
TotalCount 1 3 9 12 14 39Expected Count 1.0 3.0 9.0 12.0 14.0 39.0
Chi-Square TestsValue df Asymp. Sig.
(2-sided)Pearson Chi-Square 24.462a 8 .002Likelihood Ratio 18.506 8 .018Linear-by-Linear Association
.302 1 .583
N of Valid Cases 39
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a. 12 cells (80.0%) have expected count less than 5. The minimum expected count is .13.
A Pearson’s chi-square test of contingencies (with α = .05) was used to evaluate whether marital status is important
when considering the flexibility of flight schedules only for ultra-long-haul flights in full-fledged airlines. The chi-square
test was statistically significant, x² (1, N = 39) = 24.5, with significant level of 0.002.
T-Test Calculations
Group Statistics48. Marital Status N Mean Std. Deviation Std. Error
Mean
10g. Consider Schedules (Ultra/ Full)
Single 15 4.00 1.134 .293Married 19 4.16 .834 .191
Independent Samples TestLevene's Test for
Equality of Variances
t-test for Equality of Means
F Sig. t df Sig. (2-tailed)
Mean Difference
Std. Error Difference
95% Confidence Interval of the
DifferenceLower Upper
10g. Consider Schedules (Ultra/ Full)
Equal variances assumed
.195 .662 -.468
32 .643 -.158 .337 -.845 .529
Equal variances not assumed
-.451
24.974 .656 -.158 .350 -.878 .563
Levere test, 0.662 > 0.05, assume equal variances. Significance 0.643 >0.05 the means are not significantly different. The null hypothesis is accepted.
Correlation calculations
Correlations
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10g. Consider Schedules
(Ultra/ Full)
48. Marital Status
10g. Consider Schedules (Ultra/ Full)
Pearson Correlation
1 .089
Sig. (2-tailed) .590N 39 39
48. Marital Status
Pearson Correlation
.089 1
Sig. (2-tailed) .590N 39 39
0.89 is referred to as a positive linear relationship and of high correlation.
Commercial Influences 50. Income range X 18. How long before hand you would book air tickets
Case Processing SummaryCases
Valid Missing TotalN Percent N Percent N Percent
50. Income Range * 18. How long beforehand you would book air tickets.
39 100.0% 0 0.0% 39 100.0%
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50. Income Range * 18. How long beforehand you would book air tickets. Crosstabulation
18. How long beforehand you would book air tickets.
TotalMore
than 6
months
More than 2
- 5 month
s
More than
1 mont
h
More than
2 week
s
More
than 1
week
Less than
a wee
k
50. Income Range
< $1000 per month
Count
0 3 6 2 2 1 14
Expected Count
.4 3.9 4.7 2.9 1.1 1.1 14.0
$1000 - $1999 per month
Count
0 3 3 0 0 0 6
Expected Count
.2 1.7 2.0 1.2 .5 .5 6.0
$2000 - $2999 per month
Count
1 0 1 0 0 0 2
Expected Count
.1 .6 .7 .4 .2 .2 2.0
$3000 - $3999 per month
Count
0 4 3 2 0 0 9
Expected Count
.2 2.5 3.0 1.8 .7 .7 9.0
$4000 - $4999 per month
Count
0 0 0 1 1 0 2
Expected Count
.1 .6 .7 .4 .2 .2 2.0
$6000 - $6999 per month
Count
0 1 0 0 0 0 1
Expected Count
.0 .3 .3 .2 .1 .1 1.0
> Count
0 0 0 2 0 2 4
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Value df Asymp. Sig. (2-sided)
Pearson Chi-Square 54.550a 35 .019Likelihood Ratio 41.102 35 .221Linear-by-Linear Association
4.064 1 .044
N of Valid Cases 39a. 48 cells (100.0%) have expected count less than 5. The minimum expected count is .03.
A Pearson’s chi-square test of contingencies (with α = .05) was used to evaluate whether income range is important
when considering how long beforehand one would book air tickets. The chi-square test was statistically significant, x² (1,
N = 39) = 54.6, with significant level of 0.019.
T-Test Calculations
Group Statistics50. Income Range N Mean Std. Deviation Std. Error
Mean18. How long beforehand you would book air tickets.
< $1000 per month 14 2.43 1.222 .327
> $8000 per month 4 4.00 1.155 .577
Independent Samples TestLevene's Test for
Equality of Variances
t-test for Equality of Means
F Sig. t df Sig. (2-tailed)
Mean Difference
Std. Error Difference
95% Confidence Interval of the
DifferenceLower Upper
18. How long beforehand you would book air tickets.
Equal variances assumed
.003 .954 -2.291
16 .036 -1.571 .686 -3.026 -.117
Equal variances not assumed
-2.369
5.108 .063 -1.571 .663 -3.266 .123
50. Income Range * 18. How long beforehand you would book air tickets. Crosstabulation
18. How long beforehand you would book air tickets.
TotalMore
than 6
months
More than 2
- 5 month
s
More than
1 mont
h
More than
2 week
s
More
than 1
week
Less than
a wee
k
50. Income Range
< $1000 per month
Count
0 3 6 2 2 1 14
Expected Count
.4 3.9 4.7 2.9 1.1 1.1 14.0
$1000 - $1999 per month
Count
0 3 3 0 0 0 6
Expected Count
.2 1.7 2.0 1.2 .5 .5 6.0
$2000 - $2999 per month
Count
1 0 1 0 0 0 2
Expected Count
.1 .6 .7 .4 .2 .2 2.0
$3000 - $3999 per month
Count
0 4 3 2 0 0 9
Expected Count
.2 2.5 3.0 1.8 .7 .7 9.0
$4000 - $4999 per month
Count
0 0 0 1 1 0 2
Expected Count
.1 .6 .7 .4 .2 .2 2.0
$6000 - $6999 per month
Count
0 1 0 0 0 0 1
Expected Count
.0 .3 .3 .2 .1 .1 1.0
> Count
0 0 0 2 0 2 4
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Levere test, 0.954 > 0.05, assume equal variances. Significance 0.036 < 0.05 the means are significantly different. The
null hypothesis is rejected.
Pre-flight Services45. Gender X 26. The maximum check-in luggage weight allowance is sufficient for me.
Case Processing SummaryCases
Valid Missing TotalN Percent N Percent N Percent
45. Gender * 26. The maximum check-in luggage weight allowance is sufficient for me.
36 92.3% 3 7.7% 39 100.0%
45. Gender * 26. The maximum check-in luggage weight allowance is sufficient for me. Crosstabulation26. The maximum check-in luggage weight allowance is sufficient for
me.Total
Strongly Disagree
Disagree Neutral Agree Strongly Agree
45. GenderMale
Count 1 2 8 5 4 20Expected Count 3.3 3.9 5.0 5.0 2.8 20.0
FemaleCount 5 5 1 4 1 16Expected Count 2.7 3.1 4.0 4.0 2.2 16.0
TotalCount 6 7 9 9 5 36Expected Count 6.0 7.0 9.0 9.0 5.0 36.0
Chi-Square TestsValue df Asymp. Sig.
(2-sided)Pearson Chi-Square 10.999a 4 .027
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Likelihood Ratio 12.030 4 .017Linear-by-Linear Association
5.316 1 .021
N of Valid Cases 36a. 8 cells (80.0%) have expected count less than 5. The minimum expected count is 2.22.
A Pearson’s chi-square test of contingencies (with α = .05) was used to evaluate whether gender is important when
considering if the maximum check-in luggage weight allowance is sufficient for one. The chi-square test was statistically
significant, x² (1, N = 36) = 11, with significant level of 0.027.
T-Test Calculations
Group Statistics45. Gender N Mean Std. Deviation Std. Error
Mean26. The maximum check-in luggage weight allowance is sufficient for me.
Male 20 3.45 1.099 .246
Female16 2.44 1.365 .341
Independent Samples TestLevene's Test for
Equality of Variances
t-test for Equality of Means
F Sig. t df Sig. (2-tailed)
Mean Difference
Std. Error Difference
95% Confidence Interval of the
DifferenceLower Upper
26. The maximum check-in luggage weight allowance is sufficient for me.
Equal variances assumed
1.797 .189 2.467 34 .019 1.013 .410 .179 1.846
Equal variances not assumed
2.408 28.538 .023 1.013 .420 .152 1.873
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Levere test, 0.189 > 0.05, assume equal variances. Significance 0.019 < 0.05 the means are significantly different. The
null hypothesis is rejected.
In-flight Services46. Age Group X 29b. Presence of in-flight entertainment devices in medium-haul flights
Case Processing SummaryCases
Valid Missing TotalN Percent N Percent N Percent
46. Age Group * 29b. Presence of in-flight entertainment devices (Medium-haul)
39 100.0% 0 0.0% 39 100.0%
46. Age Group * 29b. Presence of in-flight entertainment devices (Medium-haul) Crosstabulation29b. Presence of in-flight entertainment devices (Medium-haul) Total
Least Important
Not So Important
Neutral Quite Important
Very Important
46. Age Group
Below 18Count 0 1 1 0 1 3Expected Count .4 .7 .6 .8 .5 3.0
18 – 27Count 0 2 1 6 4 13Expected Count 1.7 3.0 2.7 3.3 2.3 13.0
28 – 37Count 0 1 3 1 2 7Expected Count .9 1.6 1.4 1.8 1.3 7.0
38 – 47Count 1 2 1 3 0 7Expected Count .9 1.6 1.4 1.8 1.3 7.0
48 – 57Count 2 3 2 0 0 7Expected Count .9 1.6 1.4 1.8 1.3 7.0
58 – 67Count 2 0 0 0 0 2Expected Count .3 .5 .4 .5 .4 2.0
Total Count 5 9 8 10 7 39
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Expected Count 5.0 9.0 8.0 10.0 7.0 39.0
Chi-Square TestsValue df Asymp. Sig. (2-
sided)Pearson Chi-Square 33.635a 20 .029Likelihood Ratio 34.769 20 .021Linear-by-Linear Association
13.245 1 .000
N of Valid Cases 39a. 30 cells (100.0%) have expected count less than 5. The minimum expected count is .26.
A Pearson’s chi-square test of contingencies (with α = .05) was used to evaluate whether age group is important when
considering the presence of in-flight entertainment devices in medium flights. The chi-square test was statistically
significant, x² (1, N = 39) = 33.6, with significant level of 0.029.
T-Test Calculations
Group Statistics46. Age Group N Mean Std. Deviation Std. Error
Mean29b. Presence of in-flight entertainment devices (Medium-haul)
Below 18 3 3.33 1.528 .882
58 - 67 2 1.00 .000 .000
Independent Samples TestLevene's Test for
Equality of Variances
t-test for Equality of Means
F Sig. T df Sig. (2-tailed)
Mean Difference
Std. Error Difference
95% Confidence Interval of the
Difference
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Lower Upper29b. Presence of in-flight entertainment devices (Medium-haul)
Equal variances assumed
4.615 .121 2.049 3 .133 2.333 1.139 -1.290 5.957
Equal variances not assumed
2.646 2.000 .118 2.333 .882 -1.461 6.128
Levere test 0.121 > 0.05 assume equal variances significance 0.133 > 0.05 the means are not significant different. The null hypothesis is accepted.
Correlation Calculation
Correlations46. Age Group
29b. Presence of
in-flight entertainmen
t devices (Medium-
haul)
46. Age Group
Pearson Correlation
1 -.590**
Sig. (2-tailed) .000N 39 39
29b. Presence of in-flight entertainment devices (Medium-haul)
Pearson Correlation
-.590** 1
Sig. (2-tailed) .000N 39 39
**. Correlation is significant at the 0.01 level (2-tailed).
0.59 is referred to as a negative linear relationship and of low correlation.
Ergonomics 46. Age group X 44c. Level of importance for a full flat bed in a long-haul flight
Case Processing SummaryCases
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Valid Missing TotalN Percent N Percent N Percent
46. Age Group * 44c. Full-flat bed (Long-haul)
39 100.0% 0 0.0% 39 100.0%
46. Age Group * 44c. Full-flat bed (Long-haul) Crosstabulation44c. Full-flat bed (Long-haul) Total
Least Important
Not So Important
Neutral Quite Important
Very Important
46. Age Group
Below 18Count 0 0 2 1 0 3Expected Count .2 .5 .7 .8 .8 3.0
18 – 27Count 0 2 2 5 4 13Expected Count 1.0 2.3 3.0 3.3 3.3 13.0
28 - 37Count 1 2 1 1 2 7Expected Count .5 1.3 1.6 1.8 1.8 7.0
38 - 47Count 0 2 1 1 3 7Expected Count .5 1.3 1.6 1.8 1.8 7.0
48 - 57Count 0 1 3 2 1 7Expected Count .5 1.3 1.6 1.8 1.8 7.0
58 - 67Count 2 0 0 0 0 2Expected Count .2 .4 .5 .5 .5 2.0
TotalCount 3 7 9 10 10 39Expected Count 3.0 7.0 9.0 10.0 10.0 39.0
Chi-Square TestsValue df Asymp. Sig. (2-
sided)Pearson Chi-Square 36.398a 20 .014Likelihood Ratio 25.038 20 .200Linear-by-Linear Association
2.471 1 .116
N of Valid Cases 39a. 30 cells (100.0%) have expected count less than 5. The minimum expected count is .15.
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A Pearson’s chi-square test of contingencies (with α = .05) was used to evaluate whether age group is important when
considering the level of importance for a full flat bed in a long-haul flight. The chi-square test was statistically significant,
x² (1, N = 39) = 36.4, with significant level of 0.014.
T-Test Calculations
Group Statistics46. Age Group N Mean Std. Deviation Std. Error
Mean
44c. Full-flat bed (Long-haul)
Below 18 3 3.33 .577 .33358 - 67 2 1.00 .000 .000
Independent Samples TestLevene's Test for
Equality of Variances
t-test for Equality of Means
F Sig. t df Sig. (2-tailed)
Mean Difference
Std. Error Difference
95% Confidence Interval of the
DifferenceLower Upper
44c. Full-flat bed (Long-haul)
Equal variances assumed
9.600 .053 5.422 3 .012 2.333 .430 .964 3.703
Equal variances not assumed
7.000 2.000 .020 2.333 .333 .899 3.768
Levere test, 0.053 > 0.05, assume equal variances. Significance 0.012 < 0.05 the means are significantly different. The
null hypothesis is rejected.