Fourier Theory in Seismic Processing
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Transcript of Fourier Theory in Seismic Processing
Fourier Theory in Seismic Processing
(From Liner and Ikelle and Amundsen)
• Temporal aliasing• Spatial aliasing
Sample Rates
What is the fewest number of times I need to sample this waveform per second?
?
?
?
Sample Rates
Sample Rates
Sample Rates
Sample Rates
What is the fewest number of times I need to sample this waveform per second?
At least twice per wavelength or period!
OTHERWISE ….
Undersampled waveforms
True frequency (f -true)
Am
plit
ud
e
Reconstructed frequency
(f -aliased)
ff
Oversampled waveforms
= True frequency (f -true)
Am
plit
ud
e
Reconstructed frequency
frequency is unaliased
Nyquist frequency
Nyquist frequency = 1 / twice the sampling rate
Minimum sampling rate must be at least twice the desired frequency
E.g., 1000 samples per second for 500Hz,
2000 samples per second for 1000 Hz
Oversampled waveformsA
mp
litu
de Nyquist frequency
In practice we are best oversampling by double the required minimum
i.e. 1000 samples per second for a maximum of 500 Hz
i.e., 2000 samples per second for a maximum of 1000 Hz
Oversampling is relatively cheap.
Spatial frequency, or wavenumber (k) is the number of cycles per unit distance.
One spatial cycle or wavenumber = frequency/velocity.
Each wavenumber must be sampled at least twice per wavelength
(two CMP’s per wavelength)
Spatial aliasing
1
2( )kN CMPspacing
IN PRACTICE each wavenumber must be sampled at least four times per minimum
wavelength (two CMP’s per wavelength)
Spatial aliasing
However, dip (theta) as well as frequency and velocity event changes the number of cycles per distance, so
4sin
lambdaCMPinterval
Liner, 9.7,p.192
Spatial aliasing
4sin
lambdaCMPinterval
x
V t
limitsinV t
x
For aliasing NOT to occur, delta(t) must be less than T/2
Spatial aliasing
limitsin2
VT
x
lim 2sinit
VTx
Geophone Spacing and Spatial Aliasing
K=0
1/4 wavelength shift per trace
total shift across array=3/4 wavelength
K=+ or -ve?
1/4 wavelength shift per trace
total shift across array=3/4 wavelength
K=?
1/2 wavelength shift per trace
total shift across array=3/2 wavelength
K=0
3/4 wavelength shift per trace
total shift across array=2 1/4 wavelength