Formula Cal Culo Diferencia l
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FormulΓ‘rio - CΓ‘lculo Diferencial =β 2 =β β 4 . = + = β ( ) = . = log () β = log = log log ln = log log () = log + log log ( ) = log β log log ( ) = log 2 () + cos 2 () = 1 sec 2 () = 1 + 2 () 2 () = 1 + 2 () ( + ) = cos cos β ( β ) = cos cos + ( + ) = sen cos + cos ( β ) = sen cos β cos (2) = 2cos 2 β 2 (2) = 2sen cos β² () = lim ββ0 ( + β) β () β β () = β² () β ( β ) Sejam funçáes e constante. EntΓ£o: () β² =0 () β² = β² ( + ) β² = β² + β² ( β ) β² = β² β β² () β² = β² + β² ( ) β² = β² β β² 2 Sejam uma função e uma constante. EntΓ£o: ( ) β² = β² ( ) β² = Β΄ () β² = β² ( ) β² = β² cos (cos )β² = ββ² ( ) β² = β² sec 2 (sec )β² =β²sec ( ) β² = β β² 2 ( ) β² = β β²
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Transcript of Formula Cal Culo Diferencia l
FormulΓ‘rio - CΓ‘lculo Diferencial
π₯π£ = βπ
2π π¦π£ = β
β
4π
ππ . ππ = ππ+π ππ
ππ= ππβπ
(ππ)π = ππ.π
π¦ = logπ(π₯) β ππ¦ = π₯ logπ π₯ =
logπ π₯
logπ π
ln π₯ = logπ π₯
logπ(π₯π¦) = logπ π₯ + logπ π¦ logπ (π₯
π¦) = logπ π₯ β logπ π¦ logπ(π₯π) = π logπ π₯
π ππ2(π₯) + cos2(π₯) = 1 sec2(π₯) = 1 + π‘π2(π₯) πππ π ππ2(π₯) = 1 + πππ‘π2(π₯)
πππ (π + π) = cos π cos π β π ππ π π ππ π πππ (π β π) = cos π cos π + π ππ π π ππ π
π ππ(π + π) = sen π cos π + π ππ π cos π π ππ(π β π) = sen π cos π β π ππ π cos π
πππ (2π) = 2cos2 π β π ππ2 π π ππ(2π) = 2sen π cos π
πβ²(π₯) = limββ0
π(π₯ + β) β π(π₯)
β
π¦ β π(π) = π β²(π) β (π₯ β π)
Sejam π π π funçáes e π constante. EntΓ£o:
(π)β² = 0 (ππ)β² = ππ β² (π + π)β² = π β² + πβ²
(π β π)β² = π β² β πβ² (ππ)β² = ππβ² + π β²π (
π
π)β²
=ππ β² β πβ²π
π2
Sejam π uma função e π uma constante. EntΓ£o:
(ππ’)β² = π’β²ππ’ (ππ’)β² = π’Β΄ππ’πππ (πππ’)β² =
π’β²
π’
(π ππ π’)β² = π’β² cos π’ (cos π’)β² = βπ’β²π ππ π’ (π‘π π’)β² = π’β² sec2 π’
(sec π’)β² = π’β²sec π’ π‘π π’ (πππ‘π π’)β² = βπ’β²πππ π ππ2π’ (πππ π ππ π’)β² = βπ’β²πππ π ππ π’ πππ‘π π’
