Fluid Mechanics 07. Hydraulic and Energy Grade Lines.
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Transcript of Fluid Mechanics 07. Hydraulic and Energy Grade Lines.
![Page 1: Fluid Mechanics 07. Hydraulic and Energy Grade Lines.](https://reader033.fdocuments.net/reader033/viewer/2022061401/56649cbb5503460f94982fc3/html5/thumbnails/1.jpg)
Fluid Mechanics 07
![Page 2: Fluid Mechanics 07. Hydraulic and Energy Grade Lines.](https://reader033.fdocuments.net/reader033/viewer/2022061401/56649cbb5503460f94982fc3/html5/thumbnails/2.jpg)
Hydraulic and Energy Grade LinesEGL:- Energy Grade line indicate the total head at any point in the system.
HGL:- Hydraulic Grade Line indicate the piezometric head at any point in the system
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Hydraulic and Energy Grade Lines
![Page 4: Fluid Mechanics 07. Hydraulic and Energy Grade Lines.](https://reader033.fdocuments.net/reader033/viewer/2022061401/56649cbb5503460f94982fc3/html5/thumbnails/4.jpg)
Pump Add head to the System
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Turbine
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Nozzle
Nozzle increase the velocity and if discharge to atmospheric the term of pressure head will be zero
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Change in pipe diameter
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Negative Pressure
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ExampleA pump draws water (50°F) from a reservoir, where the water-surface elevation is 520 ft, and forces the water through a pipe 5000 ft long and 1 ft in diameter. This pipe then discharges the water into a reservoir with water-surface elevation of 620 ft. The flow rate is 7.85 cfs, and the head loss in the pipe is given by
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Determine the head supplied by the pump, hp, and the power supplied to the flow, and draw the HGL and EGL for the system. Assume that the pipe is horizontal and is 510 ft in elevation.
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Solution WhereP1=P2=Patm=zeroV1=v2=zeroHt=zero, z1=520 ft, z2=620 ft
hL= 0)==77.6 ft
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=178 ft