Final Exam Review Knowledge questions True or false statement (explain why) Protocol Calculation...

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Final Exam Review Knowledge questions True or false statement (explain why) • Protocol • Calculation Cover the contents after midterm coverage

Transcript of Final Exam Review Knowledge questions True or false statement (explain why) Protocol Calculation...

Final Exam Review• Knowledge questions

• True or false statement (explain why)

• Protocol

• Calculation

• Cover the contents after midterm coverage

Knowledge Question Examples• Three classes of switch fabric, speed relationship

– What is Head-of-the-line (HOL) blocking?• Where can queue occur in router? • TCP header size? IP header size? UDP header size?• How many bits in IP of IPv6? Address space size? Why it is very slow

to be deployed? (enough IP space, hard upgrading and compatible)• Routing: what are Link state, distance vector? • Internet two-level routing? (inter-AS, intra-AS)• RIP, OSPF, BGP? Used where?

– OSPF uses link state, BGP/RIP uses distance vector• Which is better? pure ALOHA, slotted ALOHA, CSMA/CD?

– What are their assumptions? (collision detection, time syn)• CSMA/CD? CSMA/CA? Why wireless use CSMA/CA?

Knowledge Question Examples• Ethernet Broadcast MAC addr.? What the broadcast address for? What is

ARP?• Why Ethernet is much better than aloha in efficiency? (homework 3)• Hub vs. Switch? (homework 3)• 802.11a, b, g: speed? Working frequency?• 802.15? (personal area network, example: bluetooth)• Wireless no collision detection?

– listen while sending, fading, hidden terminal• Network security three elements:

– Confidentiality, authentication, integrity• What is public/symmetric key cryptography? Pro vs. con?• Why use “nonce” in security? (replay attack) What is man-in-the-middle

attack?• Usage of firewall? (block outside active traffic to inside)• IP spoofing? SYN flood DoS attack? UDP flood?• What is a botnet? • Different between email virus vs. worm?

– Vulnerability, user interaction to propagate, speed• IPSec vs. SSL? (different layers, tcp vs. udp)

Protocol Problem Examples

• NAT address translation procedure

• Digital signature procedure

• HTTPS connection procedure– CA, public key

• Secure email (assume known public key)– Confidentiality– Integrity

Calculation Examples

• Homework 3 prob. 7 (subnet addressing)• Homework 2, prob. 9-11 (link state, distance vector)• Homework 3, prob. 4 (parity checking)• Homework 3, prob. 5 (CRC calculation)• Homework 3, prob. 11 (wireless MAC protocol)• Caesar cipher decrypt, Vigenere cipher, one-time pad

decrypt (given the pad)

Three types of switching fabrics

Property? Speed order?

• Head-of-the-Line (HOL) blocking: queued datagram at front of queue prevents others in queue from moving forward

• Queue can occur at both input port and output port of a router

Intra-AS and Inter-AS routing

Host h2

a

b

b

aaC

A

Bd c

A.a

A.c

C.bB.a

cb

Hosth1

Intra-AS routingwithin AS A

Inter-AS routingbetween A and B

Intra-AS routingwithin AS B

• We’ll examine specific inter-AS and intra-AS Internet routing protocols shortly

Routing Algorithm classification

Global or decentralized information?Global:• all routers have complete topology, link cost info• “link state” algorithms

Decentralized: • router knows physically-connected neighbors, link costs

to neighbors• iterative process of computation, exchange of info with

neighbors• “distance vector” algorithms

NAT: Network Address Translation

10.0.0.1

10.0.0.2

10.0.0.3

S: 10.0.0.1, 3345D: 128.119.40.186, 80

1

10.0.0.4

138.76.29.7

1: host 10.0.0.1 sends datagram to 128.119.40.186, 80

NAT translation tableWAN side addr LAN side addr

138.76.29.7, 5001 10.0.0.1, 3345…… ……

S: 128.119.40.186, 80 D: 10.0.0.1, 3345

4

S: 138.76.29.7, 5001D: 128.119.40.186, 80

2

2: NAT routerchanges datagramsource addr from10.0.0.1, 3345 to138.76.29.7, 5001,updates table

S: 128.119.40.186, 80 D: 138.76.29.7, 5001

3

3: Reply arrives dest. address: 138.76.29.7, 5001

4: NAT routerchanges datagramdest addr from138.76.29.7, 5001 to 10.0.0.1, 3345

Intra-AS and Inter-AS routing

Host h2

a

b

b

aaC

A

Bd c

A.a

A.c

C.bB.a

cb

Hosth1

Intra-AS routingwithin AS A

Inter-AS routingbetween A and B

Intra-AS routingwithin AS B

– RIP: Routing Information Protocol

– OSPF: Open Shortest Path First– BGP: Border Gateway Protocol (Inter-AS)

ARP protocol: Same LAN (network)

• A wants to send datagram to B, and B’s MAC address not in A’s ARP table.

• A broadcasts ARP query packet, containing B's IP address

– Dest MAC address =

FF-FF-FF-FF-FF-FF– all machines on LAN

receive ARP query

• B receives ARP packet, replies to A with its (B's) MAC address

– frame sent to A’s MAC address (unicast)

• A caches (saves) IP-to-MAC address pair in its ARP table until information becomes old (times out)

– soft state: information that times out (goes away) unless refreshed

• ARP is “plug-and-play”:– nodes create their ARP tables

without intervention from net administrator

What is network security?

Confidentiality: only sender, intended receiver should “understand” message contents– sender encrypts message– receiver decrypts message

Authentication: sender, receiver want to confirm identity of each other – Virus email really from your friends?– The website really belongs to the bank?

Message Integrity: sender, receiver want to ensure message not altered (in transit, or afterwards) without detection– Digital signature

Collision Avoidance: RTS-CTS exchange

APA B

time

RTS(A)RTS(B)

RTS(A)

CTS(A) CTS(A)

DATA (A)

ACK(A) ACK(A)

reservation collision

defer

Textbook Page 522 figure

DIFS

CIFS

CIFS

CIFS

Firewall

• Block outside-initiated traffic to inside of a local network

• Usually do not block any traffic initiated from inside to outside

administerednetwork

publicInternet

firewall

large message

mH: Hashfunction H(m)

digitalsignature(encrypt)

Bob’s private

key K B-

+

Bob sends digitally signed message:

Alice verifies signature and integrity of digitally signed message:

KB(H(m))-

encrypted msg digest

KB(H(m))-

encrypted msg digest

large message

m

H: Hashfunction

H(m)

digitalsignature(decrypt)

H(m)

Bob’s public

key K B+

equal ?

Digital signature = signed message digest

No confidentiality !No confidentiality !

Secure e-mail

Alice: generates random symmetric private key, KS. encrypts message with KS (for efficiency) also encrypts KS with Bob’s public key. sends both KS(m) and KB(KS) to Bob.

Alice wants to send confidential e-mail, m, to Bob.

KS( ).

KB( ).+

+

KS(m

)

KB(KS )+

m

KS

KB+

Internet

KS

Secure e-mail

Bob: uses his private key to decrypt and recover KS

uses KS to decrypt KS(m) to recover m

Alice wants to send confidential e-mail, m, to Bob.

KS( ).

KB( ).+

+ -

KS(m

)

KB(KS )+

m

KS

KS

KB+

Internet

KS( ).

KB( ).-

KB-

KS

mKS(m

)

KB(KS )+

Secure e-mail (continued)• Alice wants to provide message integrity (unchanged, really written by Alice).

• Alice digitally signs message.• sends both message (in the clear) and digital signature.

H( ). KA( ).-

+ -

H(m )KA(H(m))-

m

KA-

Internet

m

KA( ).+

KA+

KA(H(m))-

mH( ). H(m )

compare

How SSL (https) works?

K B+

ClientServer B

time

Three-way handshake

Request server certificate

K-CA(K+

B)

K+B(KA-B)

KA-B(m)

Symmetric session key

Certificate from CA

Distance table gives routing table

D ()

A

B

C

D

A

3

5

6

4

B

5

4

9

11

D

8

9

4

5

Ecost to destination via

dest

inat

ion

A

B

C

D

A,3

B,4

D,4

A,4

Outgoing link to use, cost

dest

inat

ion

Distance table Routing table

Distance Vector Algorithm: example

X Z12

7

Y

D (Y,Z)X

c(X,Z) + min {D (Y,w)}w=

= 7+1 = 8

Z

D (Z,Y)X

c(X,Y) + min {D (Z,w)}w=

= 2+1 = 3

Y

CRC ExampleWant:

D.2r XOR R = nG

equivalently:

D.2r = nG XOR R

equivalently:

if we divide D.2r by G, want remainder R

R = remainder[ ]D.2r

G

Dijkstra’s algorithm: example

Step012345

N D(B),p(B) D(C),p(C) D(D),p(D) D(E),p(E) D(F),p(F)

2

2

13

1

1

2

53

5

A 2,A 5,A 1,A infinity,- infinity,-AD 2,A 4,D 1,A 2,D infinity,-

ADE 2,A 3,E 1,A 2,D 4,EADEB 2,A 3,E 1,A 2,D 4,E

ADEBC 2,A 3,E 1,A 2,D 4,EADEBCF 2,A 3,E 1,A 2,D 4,E

ED

CB

FA

• Caesar cipher decrypt:– “welcome”, key= +2

• Vigenere cipher– “final exam” key=3,4,-1 (blank space does not change)