FALLSEM2013-14_CP1630_24-Jul-2013_RM01_L5-L5_FS-2013-14-review-of-TL
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Transcript of FALLSEM2013-14_CP1630_24-Jul-2013_RM01_L5-L5_FS-2013-14-review-of-TL
8/12/2019 FALLSEM2013-14_CP1630_24-Jul-2013_RM01_L5-L5_FS-2013-14-review-of-TL
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R vi w f Tr n mi i n Lin
SENSE
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Coaxial cable is an exam le of TL Transmission lines usually consist of 2 parallel
Lumped Element Model for a Transmission Line
conductors.
A short segment ∆ z of transmission line can be
modeled as a lumped-element circuit.
Conduction current incentre conductor
R, and L
z, t
V (z, t)
Displacement current
(conductance, capitance)
I
E
+ + + +
I + I I H
I + I
V
I - - - -
V + V
I + I
V
I H
V + V
I + I
SENSE
The voltage and current vary along the structure in time t and distance z.
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e can
consider on a
small section of
TL ∆
z. It is sosmall that
are occurring
instantaneouslyan we can
simply use
lumped circuit
theory.
SENSE
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I
+ + + +
I + I I H
I + I
na ys s L j R ω +),( t z I
dI I δ +
V
I - - - -
V + V
I + I
V
I H
V + V
I + I
dz
),( t zV C jG ω +dz
dV zV δ +
From Kirchoff Volta e Law Kirchoff current law
zdt
dV C zGV z
dz
dI I I δ δ δ +=⎟
⎠
⎞⎜⎝
⎛ +− zdt
dI L z RI z
dz
dV V V δ δ δ +=⎟
⎠
⎞⎜⎝
⎛ +−
zdt
dI L z RI z
dz
dV δ δ δ +=− z
dt
dV C zGV z
dz
dI δ δ δ +=−
dt
dI L RI
dz
dV +=−
dt
dV C GV
dz
dI +=−(a) (b)
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dI
Let’s V=Voe jωt , I = Ioe
jωt
Therefore
V j
dt
ω =dt
=en
( ) I L j Rdz
dV ω +=− ( )V C jG
dz
dI ω +=−
a
b
Differentiate with respect to z
( )dI
L j RV d
ω +=−2
2 ( )dz
dV C jG
dz
I d ω +=−
2
2
z z( )( )V C jG L j R
dz
V d ω ω ++=
2
2
( )( ) I C jG L j Rdz
I d ω ω ++=
2
2
V
dz
V d 2
2 γ = I
dz
I d 2
2
2
γ =
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The solution of V and I can be written in the form of
c d z z Be AeV γ γ +− +=o
z z
Z Be Ae I
γ γ +−
−=
where
⎥⎦
⎤
⎢⎣
⎡
+
+=
C jG
L j R Z
o ω
ω
( )( )C jG L j R j ω ω β α γ ++=+=and
Let say at z=0 , V=VL , I=IL and Z=ZL
ef
B AV L +=o
L Z
B A I −=
and L
L
L Z
I
=
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o L L Z I V A
+=
o L L Z I V B
−=
Inserting in equations ( c) and (d) we have
⎥⎥⎤
⎢⎢⎡ −
−⎥⎥⎤
⎢⎢⎡ +
=−+−+
22)(
z z
o L
z z
L
ee Z I
eeV zV
γ γ γ γ
⎥⎤
⎢⎡ −
−⎥⎤
⎢⎡ +
=−+−+
)( z z
L z z
L
eeV ee I z I
γ γ γ γ
o
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⎤⎡ + − z zee
γ γ ⎤⎡ − − z zee
γ γ
⎥⎦⎢⎣
=
2
cos zγ u
⎥⎦⎢⎣ 2
Then we have
)sinh()cosh()( z Z I zV zV o L L
γ γ −= *
)sinh()cosh()( z Z
V z I z I
o
L L γ γ −= **
⎟⎟
⎜⎜
−
−==)sinh()cosh(
)sinh()cosh(
)(
)()(
zV
z I
z Z I zV
z I
zV z Z
L L
o L L
γ γ
γ γ and
o
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⎟⎟ ⎠⎜⎜⎝ −−
= )sinh()cosh(
)sinh()cosh(
)( z Z z Z
z Z z Z
Z z Z Lo
o Lo γ γ
γ γ or
⎟⎟
⎠
⎜⎜
⎝
⎛
−
−=
)tanh(
)tanh()(
z Z Z
z Z Z Z z Z
Lo
o Lo
γ
γ Or further reduce
For lossless transmission line , γ= jβ since α=0
⎟⎟ ⎞
⎜⎜⎛ +
= )tan(
)( z jZ Z
Z z Z o Lo
β )cos()cosh( z z j β β =
sinsinh −=o
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Standin Wave Ratio SWRantinode
node z
Beγ
Reflection coefficient
Ae-γz
Beγz
z Ae
γ −=
Γ+=+= −− 1 z z ze Be AeV γ γ γ
Voltage and current in term of reflection coefficient
V ⎛ Γ+1
− −− z z z Ae Be Ae
γ γ γ
o L
L I ⎠⎝ Γ−== 1
⎛ Γ+1 Z −==oo
L Z Z ⎠⎝ Γ−
=1o Z
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For loss-less transmission line γ = jβ
By substituting in * and ** ,voltage and current amplitude are
2/12 gcos +++= z zV
2/1
2 )2cos(21)( θ β +Γ−Γ+= z A z I ho
Voltage at maximum and minimum points are
max = min −=Γ+
== 1Therefore L Z
Γ−1
o Z
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Other related equations
oo sZ Z I V Z =⎟⎟
⎠⎜⎜⎝
⎛
Γ− Γ+== 11
min
maxmax
s Z Z
I V Z o
o =⎟⎟ ⎠
⎜⎜⎝
⎛
Γ+ Γ−== 11
max
minmin
⎟⎟
⎞
⎜⎜
⎛ −
=Γ o L Z Z
o
From equations (g) and (h), we can find the max and min points
K,4,2,02 π π θ β ±±=+ zMaximum
K,, π π = z
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Zo ZLZin
lγ tanho L jZ Z +lγ tanh Lo
on jZ Z +
o L
o L
Z Z Z Z
+−=Γ
Γ−Γ+=
1
1SWR
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Various forms of Transmission Lines
Two wire
cable Coaxialcable
Microstripe
line
Rectangular
waveguideCircular
waveguideStripline
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Comparison of Waveguide and Transmission Line Characteristics
Transmission line
• -
wire, coaxial, microstrip, etc.).• Normal operating mode is the TEM or quasi-TEM mode (can support
.
• No cutoff frequency for the TEM mode. Transmission lines can
transmit signals from DC up to high frequency.• gn can s gna a enua on a g requenc es ue o con uc or
and dielectric losses.
• Small cross-section transmission lines (like coaxial cables) can only
ransm ow power eve s ue o e re a ve y g e s concen ra eat specific locations within the device (field levels are limited by
dielectric breakdown).
arge cross-sec on ransm ss on nes e power ransm ss on nes
can transmit high power levels.
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Comparison of Waveguide and Transmission Line Characteristics
Waveguide
• Metal waveguides are typically one enclosed conductor filled with an
,
consists of multiple dielectrics.
pera ng mo es are or mo es canno suppor a mo e .
• Must operate the waveguide at a frequency above the respective TE orTM mode cutoff frequency for that mode to propagate.
• Lower signal attenuation at high frequencies than transmission lines.
• Metal waveguides can transmit high power levels. The fields of thepropagating wave are spread more uniformly over a larger cross-
sectional area than the small cross-section transmission line.
• Large cross-section (low frequency) waveguides are impractical due to
large size and high cost.
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SENSE
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SENSE
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( )ab L /ln2π
µ
=a
ab
C
/ln
2 ε π = c
c
ck
f =( )ab Z o /ln
2
1
ε
µ
π =
r
k c = 2
Where a = radius of inner conductor
b = radius of outer conductor