Faal KBK Ginjal.ppt
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Transcript of Faal KBK Ginjal.ppt
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The Kidney Function
ByM. Rasjad Indra
Retty RatnawatiEndang SriwahyuniEdwin Widodo
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Clinical Case:
A 10 year boy has some symptoms: dark red urine andswollen/puffy face. This patient also complains about pain duringswallowing, high fever and respiratory tract inflammation. Now, all
symptomps are relieved.
From physical analysis: increased blood pressure and edema on face
and foot.
From blood analysis: increased creatinin and urea and reducedplasma albumin. Also foundproteinuria and gross hematuria.
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Based on those anamneses and physical analysis, this patient is
suspected to sufferglumerulonephritis, a disease of immune system
with failure ofglumerulus. This disease is self-relieved, with loss
of signs and symptomps. Some patients can have worse outcome,
the diseases becomes persistent and develop as permanent renal
failure.These signs and symptoms are the effect of glumerolus function
failure leading to renal failure.
Human kidney plays important roles on maintainingvolume and
composition ofextracelluler fluid. This organ maintains internalbody environments. As a result, failure of structure and function of
this organ will dysharmonize humanbody homeostasis.
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Main function
Excretion of metabolic waste products &foreign chemicals
Regulation of: water & electrolyte balances.
body fluid osmolarity & electrolyteconcentration.
acid-base balance.
arterial pressure.
Secretion, metabolism, and excretion ofhormones
Gluconeogenesis
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Slide 6
Blood Clearance
Efective Efficient
What and how
much should beremoved
Space
Time
EnergyFiltration
Still needed
Unsufficient
Reabsorption Secretion
Pore Pressure
Na
K
Cl
HydrogenGlucose
Protein
Creatinine
Urea
Glomerulus
Tub. Proks.
Ansa Henle
Tub. distalis
Peritubular I
Vasa recta
Peritubular II
Difusion
Osmosis
Bioche
mistry
ExcretionSELESAI
Slide 11
Slide 16
Slide 28
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Renal Blood Flow (RBF)
1200 ml/minute or 20-25% of cardiac out put
Both kidney weigh: 300 gr or 0.5% b.w. Blood flow per grams of kidney tissue: 4 ml /
minute => 1200 ml / 300 gr, why?
Blood flow is highest in the renal cortex, why? RBF & GFR change relatively little if arterial blood
pressure between 80 - 180 mmHg, why?
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The nephron ~ Functional Unit
Each kidney contains about 1 million nephrons
The kidney cannot regenerate new nephrons.
After age 49 the number usually decrease 10 %
every 10 years.
Regional differences in nephron structure:
Cortical nephrons: they have short loops.
Juxtamedullary nephrons: they have long loops. Urine formation results from: Glumerular filtration,
tubular reabsorption, and tubular secretion.
Urinary excretion rate = Filtration rate- Reabsorption rate + Secretion rate
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Ke Counter Current
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Two capillary beds: The glomerular & Peritubularcapillaries
Are arranged in series
Separated by the efferent arterioles
Regulate the hydrostatic pressures in both sets of capillaries.
Hydrostatic pressure: The glomerular (high ~ 60 mmHg) => for filtration.
The peritubular (low ~ 13 mm Hg) => for reabsorption.
By adjusting the resistances of afferent and efferent arterioles
The kidneys regulate the hydrostatic pressure of the glomerular &
peritubular capilaries.
Changing the rate of filtration and / or tubular reabsorption.
Response to body homeostatic demands.
KEMBALI
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Urine formation start with the filtration of plasma inthe glomeruli:
Glomerular Filtration Rate (GFR) determined by: The balance of hydrostatic & colloid osmotic forces across the
glomerular membrane
The glomerular filtration coefficient (Kf)Net Filtr.Pressure= PG - PB - G+ B.
GFR= Kfx Net Filtration Pressure
Glomerular filtration is rather non selective: Protein are mostly retained in the plasma
Low-molecular weight substance are freely filtered(excepts that are bound to the plasma protein).
Negative charged large molecules are filtered less easilythan positively charged molecules of equal molecules size
Glomerular Filtration
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Macula densa
Juxtaglomerular cells
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Autoregulation of Glomerular Filtration Rate (GFR)& Renal Blood Flow (RBF)
Sympathetic activation decrease RBF & GFR Hormonal & Autocoid:
Norepinephrine, epinephrine & Endothelin decreasesRBF & GFR
Angiotensin II : Constricts Efferent arteriolincreasesGFR
Endothelial-derived Nitric Oxide (NO), Prostaglandin, &Bradykinin: increases RBF & GFR
Role of Tubuloglomerular Feedback: Macula densa (Sodium Chloride level in Macula Densa)
Renin-Angiotensin Efferent arteriolar resistance & Afferent arteriolar
resistance
Myogenic Autoregulation
High protein intake & High blood sugar => increase RBF& GFR
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Arterial Pressure
Glomerular hydrostatic
pressure
Macula Densa
Na Cl
Proximal Na Cl
reabsorption
Efferent Arteriolar
resistance
Afferent Arteriolar
resistance
Angiotensin II
Renin
GFR
KEMBALI
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Reabsorption & Secretion Tubular reabsorption includes Passive & Active
mechanism.1.Across the tubular epithelial cells into interstitiel
2.Through the peritubular capillary membrane back intothe blood
Active transport (against electrochemical gradient& requires energy.1.Primary active transport
Expl: Sodium transport in luminal membrane prox. Tub.
2.Secondary active reabsorption Expl.: Glucose & amino acid reabs.
Secondary active Secretion: Expl: Hydrogen ion: Counter-transport with sodium
reabsorption in luminal membrane
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Glucose:All of the filtered are activelyreabsorbed and sodium dependent.
Urea & Chloride arepassively reabsorb.
Active absorb. of Na+
--> the driving forcefor tubular reabsorb. of water, glucose,amino acids, chloride and phosphate.
Some organic compounds are secreted
from the blood into the tubular urine.
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Transport Maximum
Transport maximum for substances that are activelyreabsorbed:
Glucose 320 mg/min.
Phosphate 0.10 mM/min.
Sulfate 0.06 mM/min.
Amino acid 1.5 mM/min. Uric acid 15 mg/min.
Lactate 75 mg/min
Plasma protein 30 mg/min
Transport maximum for substances that are actively
secreted:
Creatinin 16 ng/min
Para-aminohipuric acid 80 ng/min
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Constituent Filtered Reabsorbed Excreted
Water 167.5 liters 166 liters 1.5 liters
Sodium 24,000 mmoles 23,900 mmoles 100 mmoles
Potasium 720 mmoles 630 mmoles 90 mmoles
Chloride 19,500 mmoles 19,400 mmoles 100 mmoles
Bicarbonate 4,500 mmoles 4,498 mmoles 2 mmolesPhosphate 6 g 5 g 1 g
Glucose 150 g 150 g 0 g
Urea 50 g 25 g 25 g
Uric acid 8 g 7.2 g 0.8 g
Creatinine** 1.5 g 0 g 1.8 g
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Reabsorption of glucose
Glucose is cotransport with sodiumacross the luminal cell membrane(uphill)
the energy from:
the sodium gradient, how?
the electrical gradient
Glucose leave the cell membrane to
peritubular capillary blood byfacilitated difussion
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Glucose Threshold
The ability to reabsorb is limited
At normal plasma glucose levels(65-90 mg/dl) => completely
reabsorb.
At 180-200 mg/dl => glucose firstappear in the urine (threshold).
Tubular transport maximum (Tm)for glucose: the maximal rate ofglucose reabsorption.
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Sodium (Na+):
Most filtered sodium is reabsorbed. The proximal tubules: 70%.
The loop of Henle: 20%
The distal tub. and collecting duct: 9%
The quantity of Na+ excreted =>importantrole in body sodium balance.
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CountercurrentMechanism
Loop of Henle (countercurrent multipliers)&Vasa recta (countercurrent ex-changers)
Loops of Henle: establish an osmotic gradientin the medulla.
The descending limb: water permeable
The ascending limb:
Active sodium transport
Low water permeability The vasa recta: remove water from the
medulla.
Ke Slide 9
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The collecting ducts:
Final regul. of Na+
excretion.Aldosterone andADH: increase Na+ and
water reabs. by the collecting duct.
Potasium (K+):
Filtered, reabsorb and secreted
The cortical collecting tubules:important site of K+ secretion.
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Ke Slide 5
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Clearance(CX)= UX x V (ml plasma/ minute) U: urine, V: Volume of urine
PX P: Plasma, x: substance
The Inulin clearance (CIN) = GFR .....Why ?
Endogenous Creatinine Clearance also = GFR ..... Why ?
Clearance Ratio = Cx
CInulin
PAH : para-amino hipuric acidPAH clearance (CPAH)=Effective Renal Plasma Flow (ERPF)
Renal Plasma Flow (RPF) = CPAH EPAH =PPAH-VPAH (Extraction Ratio)
EPAH PPAH
Renal Blood Flow (RBF) = RPF1-Hematocrit
Excretion Rate = Ux x V
Reabsorption Rate = Filtered Load Excretion Rate
= (GFR x Px) (Ux x V)
Secretion Rate = Excretion Rate Filtered Load
The Clearance Concept (CX) to Quantify Kidney Function
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Inulin:
Not be reabsorbed or secreted by the kidney
Not be metabolized, synthesized, or stored
Pass through the glomerular filtration
barrier unhindered
Nontoxic
Be able to measure in plasma and urine
Clearance Inulin ~ GFR (Glomerular Filtration rate)
Para-amino hipuric acid (PAH) is avidly secreted by tubules
that it is almost completely cleared from all of the plasma in
one passage of blood through the kidneys
Clearance PAH ~ ERPF (Effective Renal Plasma Flow)
uteplasmaml
plasmamlxmg
uteurineXmlurinemlxmgCx min/)(
)(/)(
min/)()(/)(
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Factor affecting urinaryconcentrating ability are:
Anti Diuretic Hormone
The length of Henles loop. Tubule fluid and blood flow
Urea.
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Urea Recirculation in RenalTubules
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The two ureters are muscular tubesthat carry the urine from the
kidneys to the bladder. The urinary blader functions as a
reservoir for urine and is
periodically emptied (micturition).
MICTURITION
A complex act involving autonomicand somatic nerves, spinal reflexes,and higher brain centers.
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Ke slide 5
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Kalium intake
Increase
[K+] plasmaEffect to
adrenal cortex
Increase
[K+] intracell
(including kidneyepithelial cell)
Secretion of aldosteron
Increase
Plasma aldosteron
Increase natrium pump / kalium in
tubulus distalis and ductus kolektivus
Increase
Kalium secretion
Increase
Kalium excretion
Normalkalium level
Kembali ke 26
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Reduce
Effective
Blood volume
Kidney
Angiotensinogen
Renin
Angiotensin I
Liver
Angiotensin II
Pembuluh darah Korteks Adrenal Hipotalamus
Vasokonstriksi Sekresi Aldosteron
Reabsorbsi NatriumBlood pressure > Reabsorbsi H2O
Sekresi ADH
Volume darah arterial efektif normal
Converting enzyme
Paru
Pusat Haus
Minum
Kembali ke 15
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Based on this data :
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Based on this data :
Konsentrasi inulin plasma = 0,3 mg / ml
Konsentrasi inulin urine = 6,0 mg / ml
Konsentrasi glukosa plasma = 4,0 mg / ml
Konsentrasi glukosa urine = 20,0 mg / ml
Konsentrasi PAH plasma = 0,02 mg / ml
Konsentrasi PAH urine = 2,4 mg / ml
Aliran urine rata-rata = 5 ml / minute
Hematokrit darah = 45 %
Answer these following questions :
Glomerular Filtration Rate (GFR) = ...........ml / minute
Clearance PAH = ml plasma / minute
Clearance glucose = ml plasma / minute
Glucose reabsorbsi rate = ...........mg / minute
Renal blood flow (RBF) = ..............l / minute