expresii-algebrice
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Transcript of expresii-algebrice
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EXPRESII ALGEBRICE1) Efectua]i calculeleiobineiformaceamaisimpl:
5 4 29 1
3 x3 2 3x+6 4x x3
a) E(x) = + : 1
b) E(x) = + + + :
x3 x+3 9x 2 x 2 6x+9
4 4 x+1 x 2 +x2 1x 2 x1
x 2 9 18x + 36 x 2 x 2 2) Fie expresia: E(x) = ( ) ( x )
x 2 6x + 9 18 + 9x 2x 2 x 3 x 2 + 3x 3
a)ArtaicE(x)=3x
b)DeterminaivalorilerealealeluixpentrucareexpresiaE(x)nuestedefnit.
c)ArtaicE(1)+E(2)+E(3)+............................+E(20)estedivizibilcu6
x x2x+24x2
3) FieexpresiaE(x)=++:x2x24x+4x2x2+x6
a)Artaicx2+x6=(x2)(x+3)
2b)ArtaicE(x)=
x2
2x2+16x +32 2x2x8x2x84)FieexpresiaE(x)=: [(++):() ]
3x248x+263xx24x2
x+4a)ArataicE(x)=
x
b)Pentrucevalorialeluix,expresiaaresens
c)DeterminaielementelemulimiiA={xN| E(x)N}
1
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x2 x+3 x2 15) Fieexpresia:E(x)=(++):
x3x2 3+x3x2x3 x2+xx21
a)ArtaicE(x)=x2
b)DeterminaivalorileluixpentrucareexpresiaE(x)nuestedefinit
x+214x2
6)FieexpresiaE(x)=(1+):x11x2
x+1b)ArtaicE(x)=
2x1
c)Pentrucevalorialeluia, E(a)nuestedefinitna?
x+2x24x+3x2+4x+47)Fieexpresia:()2 :
x3 x2+4x+3x2 9
x1a)VerificaidacE(x)=
x+1
b)DeterminaivalorileluixpentrucareexpresiaE(x) estedefinit
1 12x2
8)FieexpresiileF(x)=1 siE(x)=[F(x):(1)](4x24x+1)1x 1x
a)CalculatiF(2)F(1)
b)ArataticaE(x)=2x1
2
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