Excel 3

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K= Excel x f(x) 1 45 2022.04424 1 2 12 140.97852 2 3 36 1291.4247 3 4 15 222.942238 4 5 47 2205.27343 5 6 51 2597.7384 6 7 36 1291.4247 7 8 145 21020.491 8 9 36 1291.4247 9 10 25 621.648772 10 Nro 1 2 3 4 5 6 A= 1 7 B= 2 K= 1.5 ( )=sin( )+ ^2−ln( ) ( )=s ( )= ^2+cos( )− ^( ) =( + )/2

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Transcript of Excel 3

Page 1: Excel 3

K= 1Excel

Nº x f(x) Nº x1 45 2022.04424 1 452 12 140.97852 2 123 36 1291.4247 3 364 15 222.942238 4 155 47 2205.27343 5 476 51 2597.7384 6 517 36 1291.4247 7 368 145 21020.491 8 1459 36 1291.4247 9 36

10 25 621.648772 10 25

Nro x1 0.12 0.23 0.54 0.0155 0.1156 0.3

A= 1 7 0.54B= 2K= 1.5

𝑓(𝑥)=sin(𝑥)+𝑥^2−ln(𝑥) 𝑓(𝑥)=sin〖 (𝑥)∗𝐾〗− ln(𝑥)∗K

𝑓(𝑥)=𝑥^2+cos(𝑘)−𝑒^(𝑥∗𝑘)𝐾=(𝐴+𝐵)/2

Page 2: Excel 3

Excelf(x)

-2.95575897-3.02147957-4.57529779-2.05776236-3.72657448-3.26159646-4.57529779-4.50898858-4.57529779-3.35122757

ExcelF(x)-1.08109704-1.23912161-1.79626281-0.95179283-1.10430962-1.40757498-1.88557079

𝑓(𝑥)=sin〖 (𝑥)∗𝐾〗− ln(𝑥)∗K