Example problems · 2019. 4. 24. · a) Sketch a displacement-time graph for a ball thrown...
Transcript of Example problems · 2019. 4. 24. · a) Sketch a displacement-time graph for a ball thrown...
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Displacement-time graphs
Example problems:
www.mathscentre.ac.uk
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Credit: www.mathscentre.ac.uk
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AS Textbook p131 Example 1
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Ex 9A p132 AS Textbook
Q1
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Q2
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Q3
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Q4
Q5
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a) Sketch a displacement-time graph for a ball thrown vertically upwards with an initial
velocity +Ö5g ms-1,
b) Sketch a velocity-time graph to show this motion.
The ball is modelled as a particle moving freely under the influence of gravity alone.
c) Explain two additional factors which may be taken into account in a refinement of the above model to make it more realistic.
Solution overleaf.
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Q5 Solution
a) The s-t graph above shows the displacement increasing with time to its maximum value
(the maximum height of the ball), then decreasing back to 0 (when the ball hits the ground). Remember that the gradient is the velocity. And in this example the velocity is not constant, therefore the gradient of the graph will not be constant; instead, the gradient will be curved i.e. the line will be curved.
b) The v-t graph demonstrates that the velocity of the ball decreases to 0. Then the velocity increases back up to the initial velocity, however the ball is now travelling in the opposite direction so velocity will take a negative value, hence the graph. Note that the gradient of this graph represents acceleration (!"#
$). The ball has an
acceleration of -g ms-2 (because gravity acts downwards all of the time and the question states that upwards is the positive direction). Therefore, the gradient of this graph will be a straight line from v = +7 to v = -7.
c) Air resistance and rotation of ball. Air resistance will oppose the direction of travel, and
rotational forces will come into play if our ball is not modelled in this way. Thus, using SF = ma, we will find a different (varying) value for acceleration of the ball. (Assuming the ball is a particle we say that SF = -mg, so -mg = ma, so -g = a).
Mixed Exercise 9 AS Textbook
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Q1
Solution overleaf.
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Q2
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Exercise 11C AS Textbook Q5
Solution overleaf.
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Review Exercise 2 AS Textbook Q3
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References: www.mathscentre.ac.uk p1-2 Pearsonactivelearn AS Statistics and Mechanics textbook p2-17