Linear programming maximize x 1 + x 2 x 1 + 3x 2 3 3x 1 + x 2 5 x 1 0 x 2 0.
EXAMPLE 5 Verify a trigonometric identity Verify the identity cos 3x = 4 cos 3 x – 3 cos x....
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Transcript of EXAMPLE 5 Verify a trigonometric identity Verify the identity cos 3x = 4 cos 3 x – 3 cos x....
![Page 1: EXAMPLE 5 Verify a trigonometric identity Verify the identity cos 3x = 4 cos 3 x – 3 cos x. Rewrite cos 3x as cos (2x + x). cos 3x = cos (2x + x) Use a.](https://reader036.fdocuments.net/reader036/viewer/2022082319/56649da15503460f94a8c8bb/html5/thumbnails/1.jpg)
EXAMPLE 5 Verify a trigonometric identity
Verify the identity cos 3x = 4 cos3 x – 3 cos x.
Rewrite cos 3x as cos (2x + x).
cos 3x = cos (2x + x)
Use a sum formula.= cos 2x cos x – sin 2x sin x
Use double-angle formulas.
= (2 cos2 x – 1) cos x – (2 sin x cos x) sin x
Multiply.= 2 cos3 x – cos x – 2 sin2 x cos x
Use a Pythagorean identity.
= 2 cos3 x – cos x – 2(1 – cos2 x) cos x
Distributive property= 2 cos3 x – cos x – 2 cos x + 2 cos3 x
Combine like terms.
= 4 cos3 x – 3 cos x
![Page 2: EXAMPLE 5 Verify a trigonometric identity Verify the identity cos 3x = 4 cos 3 x – 3 cos x. Rewrite cos 3x as cos (2x + x). cos 3x = cos (2x + x) Use a.](https://reader036.fdocuments.net/reader036/viewer/2022082319/56649da15503460f94a8c8bb/html5/thumbnails/2.jpg)
EXAMPLE 6 Solve a trigonometric equation
Solve sin 2x + 2 cos x = 0 for 0 ≤ x <2π.
SOLUTION
Write original equation.sin 2x + 2 cos x = 0
Use a double-angle formula.2 sin x cos x + 2 cos x = 0
Factor.2 cos x (sin x + 1) = 0
Set each factor equal to 0 and solve for x.
2 cos x = 0
cos x = 0
x π2
3π2= ,
sin x + 1 = 0
sin x = –1
x3π2=
![Page 3: EXAMPLE 5 Verify a trigonometric identity Verify the identity cos 3x = 4 cos 3 x – 3 cos x. Rewrite cos 3x as cos (2x + x). cos 3x = cos (2x + x) Use a.](https://reader036.fdocuments.net/reader036/viewer/2022082319/56649da15503460f94a8c8bb/html5/thumbnails/3.jpg)
EXAMPLE 6 Solve a trigonometric equation
CHECK
Graph the function y = sin 2x + 2 cos x on a graphing calculator. Then use the zero feature to find the x– values on the interval 0 ≤ x <2π for which y = 0. The two x-values are:
x π2 = 1.57 xand 3π
2 = 4.71
![Page 4: EXAMPLE 5 Verify a trigonometric identity Verify the identity cos 3x = 4 cos 3 x – 3 cos x. Rewrite cos 3x as cos (2x + x). cos 3x = cos (2x + x) Use a.](https://reader036.fdocuments.net/reader036/viewer/2022082319/56649da15503460f94a8c8bb/html5/thumbnails/4.jpg)
EXAMPLE 7 Find a general solution
x2
Find the general solution of 2 sin = 1.
Write original equation.2 sin x2 = 1
Divide each side by 2.2 sin x2
12=
x2
General solution forx2 = + 2nπ orπ
6
5π6 + 2nπ
General solution for xx = + 4nπ orπ3
5π3 + 4nπ
![Page 5: EXAMPLE 5 Verify a trigonometric identity Verify the identity cos 3x = 4 cos 3 x – 3 cos x. Rewrite cos 3x as cos (2x + x). cos 3x = cos (2x + x) Use a.](https://reader036.fdocuments.net/reader036/viewer/2022082319/56649da15503460f94a8c8bb/html5/thumbnails/5.jpg)
GUIDED PRACTICE for Examples 5, 6, and 7
Verify the identity.11. sin 3x = 3 sin x – 4 sin3 x
SOLUTION
Sin 3x = sin (2x + x)
= sin 2x cos x + cos 2x sin x
= 2sin xcos xcos x + (1 – 2 sin2 x) sin x
= 2 sin xcos2 x + sin x – 2 sin3 x
= 2 sin x(1 – sin2 x) + sin x – 2sin3 x
= 2 sin x – sin3 x + sin x – 2sin3 x
= 3 sin x – 4 sin3 x
![Page 6: EXAMPLE 5 Verify a trigonometric identity Verify the identity cos 3x = 4 cos 3 x – 3 cos x. Rewrite cos 3x as cos (2x + x). cos 3x = cos (2x + x) Use a.](https://reader036.fdocuments.net/reader036/viewer/2022082319/56649da15503460f94a8c8bb/html5/thumbnails/6.jpg)
GUIDED PRACTICE for Examples 5, 6, and 7
Verify the identity.12. 1 + cos 10x = 2 cos2 5x
SOLUTION
1 + cos 10x = 1 + 2 cos2(5x) – 1 = 2 cos2 5x
![Page 7: EXAMPLE 5 Verify a trigonometric identity Verify the identity cos 3x = 4 cos 3 x – 3 cos x. Rewrite cos 3x as cos (2x + x). cos 3x = cos (2x + x) Use a.](https://reader036.fdocuments.net/reader036/viewer/2022082319/56649da15503460f94a8c8bb/html5/thumbnails/7.jpg)
GUIDED PRACTICE for Examples 5, 6, and 7
Solve the equation.13. tan 2x + tan x = 0 for 0 ≤ x <2π.
ANSWER
0, , , , , π3
2π3 π 4π
35π3
x2
14. 2 cos + 1 = 0
ANSWER
+ 4n π or + 4n π4π3
8π3