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Euler’s Method
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Euler’s Method
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Euler’s Method. Leonhard Euler. Pronounced like Leon- ard Oiler Swiss mathematician and physicist Introduced the idea of a function f(x) Wrote the work Optics which became the preeminent theory on light until quantum light theory Nine point circle. What is Euler’s Method?. - PowerPoint PPT Presentation
Transcript of Euler’s Method
Euler’s Method
Leonhard Euler
• Pronounced like Leon-ard Oiler• Swiss mathematician and physicist• Introduced the idea of a function f(x)• Wrote the work Optics which became
the preeminent theory on light until quantum light theory• Nine point circle
What is Euler’s Method?
Equation using slopes and values at various points of an equation to approximate the next value of said equation.
Used when the given slope or can not be integrated dx
dy
How It Works• ynew = yold + f’(x)*Δx
• A new y value can be approximated by taking the old value and adding the slope multiplied by the step size, which is the difference between two x values.
First Example!
Given a point (1,2) and = x+y, approximate f(2) with two equal step sizes of .5
1. Write down equation: ynew = yold + f’(x)*Δxf(1.5) = f(1) + f’(1)(0.5)
dxdy
First Example, Cont’d.
2. Plug in relative values: f(1.5) = 2 + (1+2)(.5)
3. Solve: f(1.5) = 3.5 or 7/24. Plug in for new values:
f(2) = 3.5 + f’(1.5)(.5)f(2) = 3.5 + 5(0.5) = 6
Second Example
• Using two equal step sizes of .1, approximate f(.8) given =
and f(1)=2dxdy
22yy
How to Do it
1. Write down the equation ynew=yold+(m)Δx2. Plug in values for f(.9)
1. ynew=2-(.1)(.5)(3)1. f(.9)= 1.85
3. Plug in values for f(.8) 1. ynew=1.85-(.1)(.925)(3.85)
1. f(.8)=1.493875
Be Careful!
• Using Euler’s method gives an approximation, not an actual solution.
• Depending on whether or not the equation is concave up or down, the Euler’s solution could be higher or lower than the actual one.
Oh no! So what about that last example?
Concavity
• In the last example, f’(x) = x + y. f”(x), therefore, is equal to 1.• The concavity is always going to
be positive, which means that the approximate value given by Euler’s method will be lower than the real value.
Now it’s Your Turn!
• f’(x) =
• Find f(3) given point (1,3)• Two equal step sizes
yxx22
Did You Get it Right?
• f(2) = f(1) + f’(1) * (1)– f’(1) = 1 + 2 = 0.5 2(1)(3)
• f(2) = 3 + 0.5 = 3.5• f(3) = f(2) + f’(2) * (1)– f’(2) = 3.5 + 2 = 11
2(2)(3.5) 28
• f(3) = 3.5 + 11/28 = 109/28
YAYYYYYY!!
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