Epistasis TES2

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How Genes interact By the end you should be able to: Define epistasis Describe the way in which genes interact Determine the phenotype of offspring from parental genotypes Explain what X inactivation is

description

FOR THOSE AIMING FOR A and A* in biology.This is an excelleent resource for those doing OCR A2 Biology - it contains ocr past paper questions and answers for epistasis.

Transcript of Epistasis TES2

Page 1: Epistasis TES2

How Genes interact

By the end you should be able to:

Define epistasis

Describe the way in which genes interact

Determine the phenotype of offspring from parental genotypes

Explain what X inactivation is

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Recap

So far we have looked at dominant and recessive alleles. However, it is very rare for a characteristic to be controlled by a single gene.

Today we will look at how genes interact with one another.

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Epistasis

In order to see some genes it is sometimes necessary for other genes not to be expressed.

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Look at the two boxes

They both have six sections but because the background of the box on the right is black you cannot see the lines.

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Tabby Cat

This cat has black stripes. We can see these stripes because the rest of its fur is a light colour.

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Black Cat

This cat could also have stripes but because the rest of its fur is black we cannot tell.

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So.....

For a cat to be a tabby cat it needs both the alleles for stripes and also the alleles for a light undercoat so that the stripes can be seen.

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How is this controlled?

In tabby cats there are two different genes involved.

The first gene control whether the cat has is the Agouti gene- this determines grey bands or solid black. There is the dominant A and the recessive a. A means stripes and a means solid coat colour.

AA or Aa = Grey bands

Aa = Solid black coat

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The 2nd allele involved is the allele for coat pattern. There are three possible alleles:

T= Vertical stripes

TB= Freckled

tb= Blotched

TT, or Ttb = Vertical stripes

TTB, TBTB or TBtb = Freckled

tbtb = Blotched

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Work out the phenotypes for the following:

aatbtb

AaTT

AATTB

AaTtb

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Work out the phenotypes for the following:

aatbtb = Black solid

AaTT = Vertical stripes

AATTB = Freckled

AaTtb = Vertical stripes

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Draw a Punnett for the following cross

AAtbtb + aaTT

First work out what the gametes will be- then decide on the genotypes and phenotype of the offspring.

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X inactivation As females have

two copies of the x chromosome early in the development of the of the embryo one x chromosome in each cell is supercoiled to prevent transcription. This supercoiled chromosome forms a visible lump know as the Barr body.

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The process seems to be random so groups of cells in females will have different different X chromosomes inactivated.

This process can lead to interesting coat colouration. If the X chromosome from the father has the gene for a orange coat and the X chromosome from the mother has a gene for a black coat a cat can have a blotched appearance.

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Male cats are black or orange

Female cats are blotched

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Have we learned?

By the end you should be able to:

Define epistasis

Describe the way in which genes interact

Determine the phenotype of offspring from parental genotypes

Explain what X inactivation is