Geophysics of overburden moving geophysics gtom exploration to application
Environmental and Exploration Geophysics Ipages.geo.wvu.edu/~wilson/geol454/lect13/mag2.pdf ·...
Transcript of Environmental and Exploration Geophysics Ipages.geo.wvu.edu/~wilson/geol454/lect13/mag2.pdf ·...
Tom Wilson, Department of Geology and Geography
Environmental and Exploration Geophysics I
tom.h.wilson
Department of Geology and Geography
West Virginia University
Morgantown, WV
Magnetic Methods (II)
Tom Wilson, Department of Geology and Geography
Reminders
• Gravity lab due today
• Writing section – Essay II final draft due Friday, 18th by noon
• Keep reading Chapter 7 on Magnetics.
• Problems 7.1, 2 and 3 due this Thursday
• We’ll get started on the magnetics lab today - due date Dec 1st.
• Additional problems 4 and 5 will be distributed this Thursday.
They will be due Dec. 1st.
Wrap up magnetic methods Dec 1st. We may have time for some exam review on the 1st. Dec. 6th class will be devoted to review.
The final is scheduled Wednesday, December 14th from 11am-1pm in rm 325 Brooks.
Problem 6.9
Tom Wilson, Department of Geology and Geography
What is gmax on the
red curve?
gmax= 0.45mGals
What is X1/2?
Ideas to familiarize yourself with in reading Chapter 7
Tom Wilson, Department of Geology and Geography
• Magnetic materials
• Corrections
• Sign conventions and units
• The potential field
• The dipole field
• Vertical and horizontal gradients of the
dipole field
• Problems to do from Chapter 7
• Intro to magnetics lab
Magnetic materials & magnetic domains
Tom Wilson, Department of Geology and Geography
Ferromagnetic materials (iron,
nickel and cobalt) have very
high susceptibility.
Anti-ferromagnetic materials
have very low susceptibilities
(ex. hematite).
Ferrimagnetic minerals such
as magnetite, ilmenite and
pyrrhotite are the common and
produce a lot of the naturally
occurring magnetic anomalies.
Corrections
Tom Wilson, Department of Geology and Geography
Magnetic fields like gravitational fields are not constant.
However, magnetic field variations are much more erratic and unpredictable
http://www.earthsci.unimelb.edu.au/ES304
/MODULES/ MAG/NOTES/tempcorrect.html
Diurnal variations
Short term fluctuations
Tom Wilson, Department of Geology and Geography
http://en.wikipedia.org/wiki/File:Animati3.gif
Short term micropulsations
Tom Wilson, Department of Geology and Geography
Today’s Space Weather
http://www.swpc.noaa.gov/today.html
Real Time Magnetic field data
http://www.swpc.noaa.gov/ace/ace_rtsw_data.html
Tom Wilson, Department of Geology and Geography
In general there are few corrections to apply to magnetic data. The
largest non-geological variations in the earth’s magnetic field are those
associated with diurnal variations, micropulsations and magnetic
storms.
The vertical gradient of the vertical component of the earth’s magnetic
field at this latitude is approximately 0.025nT/m. This translates into
1nT per 40 meters. The magnetometer we have been using in the field
reads to a sensitivity of 1nT and anomalies of interest to us may be on
the order of 200 nT or more. Hence, elevation corrections are generally
not needed.
Variations of total field intensity as a function of latitude are also
relatively small (0.00578nT/m). The effect over 80 m NS distance
would about 1/2 nT, and over a kilometer, about 5.8 nT (increase to the
north. International geomagnetic reference formula
http://www.ngdc.noaa.gov/IAGA/vmod/igrf.html
Another correction important in the regional
survey removal of the regional field
Tom Wilson, Department of Geology and Geography
The regional field can be removed by
surface fitting and line fitting
procedures identical to those used in
the analysis of gravity data.
The efforts that Stewart undertook to eliminate the regional field from his data
may be very appropriate to magnetic field data analysis and modeling
Some basic relationships
Tom Wilson, Department of Geology and Geography
The Earth’s main fieldS
N
The induced magnetic
field of a metallic drum
The induced field
opposes the main field
The dipole field and sign conventions
upward pointing field lines are negative
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SN
Tom Wilson, Department of Geology and Geography
objectpV
r
From above, we obtain a
basic definition of the
potential (at right) for a unit
positive test pole (pt).
1 2
2
p pV Fdr dr
r
The potential is the integral of the
force (F) over a displacement path.
Note that we consider
the 1/4 term =1
Tom Wilson, Department of Geology and Geography
2
dV pH
dr r
Thus - H (i.e. F/ptest, the field
intensity) can be easily derived from
the potential simply by taking the
negative derivative of the potential
The reciprocal relationship between
potential and field intensity
Tom Wilson, Department of Geology and Geography
Consider the case where the distance to the center of the dipole is much
greater than the length of the dipole. This allows us to treat the problem
of computing the potential of the dipole at an arbitrary point as one of
scalar summation since the directions to each pole fall nearly along
parallel lines.
Tom Wilson, Department of Geology and Geography
cos cos2 2
dipole
p pV
l lr r
Converting to common denominator yields
2
cosdipole
plV
r
From the previous discussion , the field intensity H is just
dr
dV
dr
dVFFdrV , since
where pl = M – the
magnetic moment
Vertical derivative
Tom Wilson, Department of Geology and Geography
2
cosddV d pl
dr dr r
ZE - dipole =
3
2 cospl
r
This yields the field intensity in the radial direction - i.e. in the direction
toward the center of the dipole (along r). This is just the vertical
component of the total field. We can also do this to obtain the horizontal
component of the Earth’s magnetic field intensity.
Horizontal field intensity
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1d ddV dV
dS r d
Think about where this operator comes from
r
d dS
Main field components vary with colatitude
Tom Wilson, Department of Geology and Geography
2
cosdE
dV d plZ
dr dr r
Vd represents the
potential of the dipole.
FE or H
Toward dipole
center (i.e. center of
Earth’s dipole field
Tom Wilson, Department of Geology and Geography
Tom Wilson, Department of Geology and Geography
2
cosd pl
rd r
Tom Wilson, Department of Geology and Geography
3
sin
r
MH
ds
dVE
Where M = pl
and
3
cos2
r
M
dr
dVZE
Let’s tie these results back into some
observations made earlier in the semester
with regard to terrain conductivity data.
Tom Wilson, Department of Geology and Geography
3
sin
r
MHE
Given
What is HE at the equator? … first what’s ?
is the angle formed by the line connecting the
observation point with the dipole axis. So , in
this case, is a colatitude or 90o minus the
latitude. Latitude at the equator is 0 so is 90o
and sin (90) is 1.
3r
MHE
Tom Wilson, Department of Geology and Geography
0EH
At the poles, is 0, so that
What is ZE at the equator?
3
cos2
r
MZE
is 90
0EZ
Tom Wilson, Department of Geology and Geography
ZE at the poles ….
3
cos2
r
MZE
3
2
r
MZE
The variation of the field intensity at the poles and
along the equator of the dipole may remind you of
the different penetration depths obtained by the
terrain conductivity meters when operated in the
vertical and horizontal dipole modes.
Problem 7.1
Tom Wilson, Department of Geology and Geography
What is the horizontal gradient of the Earth’s magnetic
field (ZE) …
The horizontal gradient is just the horizontal
derivative, used to calculate the horizontal field,
accept, there is no negative sign
Horizontal gradient is E EdZ dZ
dS rd
Horizontal component of the Earth’s magnetic field HE is
dV dV
dS rd
Problem 7.1
Tom Wilson, Department of Geology and Geography
3
sin Thus
r
MHE
3
cos2
r
M
dr
dVZE
2
cosE
dV dV d plH
ds rd rd r
1 d
r d
The relationship between the potential and
field intensity requires use of the minus sign.
However, no minus sign is required when computing
the derivative or gradient
Again – just take the simple derivative to get
the gradient (no negative sign)
Tom Wilson, Department of Geology and Geography
To answer this problem we must evaluate the
horizontal gradient of the vertical component -
1E
dZ
r dor
3
1 2 cosd M
r d r
Take a minute and give it a try.
Problem 7.2
Tom Wilson, Department of Geology and Geography
dipole
p pV
r r
Recognizing that pole strength of the
negative pole is the negative of the positive
pole and that both have the same absolute
value, we rewrite the above as
dipole
p pV
r r
Return to the simpler formulation of
the potential as the sum of potentials
from two poles
surface
r-
r+
A simple geometrical approximation for “back of the
envelope” computations … Can you detect the wall?
Tom Wilson, Department of Geology and Geography
7.3 A buried stone wall constructed from volcanic rocks has
a susceptibility contrast of 0.001cgs emu with its enclosing
sediments. The main field intensity at the site is 55,000nT.
Determine the wall's detectability with a typical proton
precession magnetometer. Assume the magnetic field
produced by the wall can be approximated by a vertically
polarized horizontal cylinder. Refer to figure below, and see
following formula for Zmax.
Background noise at
the site is roughly 5nT.
Magnetic effects of simple geometric shapes
Tom Wilson, Department of Geology and Geography
In-depth discussions of simple geometrical objects are
presented on pages 456 to 482.
For our purposes, however, we will avoid the heavy math
and consider the general usage of half-max relationships in
a manner similar to that developed for the analysis of
gravitational fields produced by simple geometrical
objects using diagnostic positions and depth index
multipliers.
The following problems illustrate some uses of these
ideas.
Archaeological application
Tom Wilson, Department of Geology and Geography
Vertically Polarized Horizontal Cylinder
2
max 2
2 R IZ
z
Maximum field strength
2
2
2
2
2
2
2
1
12
zx
zx
z
IRZ
2
2
2
2
2
max 1
1)(
zx
zx
Z
xZ
General form Normalized shape term
Remember this kind of formulization used in gravity
The wall in problem 7.3 is better approximated
by the horizontal cylinder
Tom Wilson, Department of Geology and Geography
2
max 2
2 R IZ
z
Maximum field strength
EI kF
k = 0.001, FE= 55,000 nT
Approximate cross sectional area of rectangular
wall in circular form and solve for R: i.e. wallAR
Cross sectional area of wall = 1m x 0.5m
Lastly – what is z?
What is R?k=0.001 0.5m
1.0m
1.5mk=0
recall
Problem 7.3 in-class group problem/discussion
Tom Wilson, Department of Geology and Geography
Bring up GM-SYS – Magnetics lab part 1
Tom Wilson, Department of Geology and Geography
Anomaly associated
with buried metallic
materials
Bedrock configuration
determined from gravity
survey
Results obtained
from inverse
modeling
Computed magnetic
field produced by
bedrock
Tom Wilson, Department of Geology and Geography
Reminders
• Gravity lab due today
• Writing section – Essay II final draft due Friday, 18th by noon
• Keep reading Chapter 7 on Magnetics.
• Problems 7.1, 2 and 3 due this Thursday
• We’ll get started on the magnetics lab today - due date Dec 1st.
• Additional problems 4 and 5 will be distributed this Thursday.
They will be due Dec. 1st.
Wrap up magnetic methods Dec 1st. We may have time for some exam review on the 1st. Dec. 6th class will be devoted to review.
The final is scheduled Wednesday, December 14th from 11am-1pm in rm 325 Brooks.