Entry Task What is the polynomial function in standard form with the zeros of 0,2,-3 and -1?
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Transcript of Entry Task What is the polynomial function in standard form with the zeros of 0,2,-3 and -1?
Entry Task
• What is the polynomial function in standard form with the zeros of 0,2,-3 and -1?
5.3 Solving Polynomial Equations
Learning Target: Students will be able to understand how to solve
polynomial equations by factoring
Factoring out the GCFFactoring a polynomial with a common monomial factor (using GCF)
Always look for a GCF before using any other factoring method.
Steps:
1. Find the greatest common factor (GCF).
2. Divide the polynomial by the GCF. The quotient is the other factor.
3. Express the polynomial as the product of the quotient and the GCF.
12x5 – 18x3 – 3x2
To factor, express each term as a square of a monomial then apply the rule... a2 b2 (a b)(a b)
Ex: x2 16 x2 42
(x 4)(x 4)
Difference of Squares
4 Steps for factoringDifference of Squares
1. Are there only 2 terms?2. Is the first term a perfect square?3. Is the last term a perfect square?4. Is there subtraction (difference) in the
problem?If all of these are true, you can factor
using this method!!!
1. Factor x2 - 25When factoring, use your factoring table.
Do you have a GCF? Are the Difference of Squares steps true?
Two terms?1st term a perfect square?2nd term a perfect square?Subtraction?Write your answer!
No
Yes x2 – 25
Yes
YesYes
( )( )5 xx + 5-
2. Factor 16x2 - 9When factoring, use your factoring table.
Do you have a GCF? Are the Difference of Squares steps true?
Two terms?1st term a perfect square?2nd term a perfect square?Subtraction?Write your answer!
No
Yes 16x2 – 9
Yes
YesYes
(4x )(4x )3+ 3-
When factoring, use your factoring table.Do you have a GCF? Are the Difference of Squares steps true?
Two terms?1st term a perfect square?2nd term a perfect square?Subtraction?Write your answer! (9a )(9a )7b+ 7b-
3. Factor 81a2 – 49b2
No
Yes 81a2 – 49b2
Yes
YesYes
Try these on your own:
1. x 2 121
2. 9y2 169x2
3. x4 16 Be careful!
11 11x x
3 13 3 13y x y x
22 2 4x x x
Perfect Square Trinomials
• can be factored just like other trinomials but if you recognize the perfect squares pattern, follow the formula!
a2 2ab b2 (a b)2
a2 2ab b2 (a b)2
Ex: x2 8x 16
x2 8x 16 x 4 2
2
x 2 4 2
Does the middle term fit the pattern, 2ab?
Yes, the factors are (a + b)2 :
b
4
a
x 8x
Ex: 4x2 12x 9
4x 2 12x 9 2x 3 2
2
2x 2 3 2
Does the middle term fit the pattern, 2ab?
Yes, the factors are (a - b)2 :
b
3
a
2x 12x
1) Factor x2 + 6x + 9Does this fit the form of our
perfect square trinomial?1) Is the first term a perfect
square?Yes, a = x
2) Is the last term a perfect square?
Yes, b = 33) Is the middle term twice the
product of the a and b?Yes, 2ab = 2(x)(3) = 6x
Perfect Square Trinomials(a + b)2 = a2 + 2ab + b2
(a - b)2 = a2 – 2ab + b2
Since all three are true, write your answer!
(x + 3)2
You can still factor the other way but this
is quicker!
2) Factor y2 – 16y + 64Does this fit the form of our
perfect square trinomial?1) Is the first term a perfect
square?Yes, a = y
2) Is the last term a perfect square?
Yes, b = 83) Is the middle term twice the
product of the a and b?Yes, 2ab = 2(y)(8) = 16y
Perfect Square Trinomials(a + b)2 = a2 + 2ab + b2
(a - b)2 = a2 – 2ab + b2
Since all three are true, write your answer!
(y – 8)2
Sum and Difference of Cubes:
a3 b3 a b a2 ab b2 a3 b3 a b a2 ab b2
3: 64Example x (x3 43 )Rewrite as cubes
Write each monomial as a cube and apply either of the rules.
Apply the rule for sum of cubes:
a3 b3 a b a2 ab b2
(x 4)(x2 4x 16)
(x 4)(x2 x 4 42 )
Ex: 8y3 125Rewrite as cubes
((2y)3 53)
2y 5 4y2 10y 25
Apply the rule for difference of cubes:
a3 b3 a b a2 ab b2 2y 5 2y 2 2y5 5 2
CUBIC FACTORINGEX- factor and solve
8x³ - 27 = 0
8x³ - 27 = (2x - 3)((2x)² + (2x)3 + 3²)
(2x - 3)(4x² + 6x + 9)=0
Quadratic Formula
3i33x X= 3/2
a³ - b³ = (a - b)(a² + ab + b²) b
axx
327
283
3 3
Factoring By Grouping(use with 4 or more terms)
1. Group the first set of terms and last set of terms with parentheses.
2. Factor out the GCF from each group so that both sets of parentheses contain the same factors.
3. Factor out the GCF again (the GCF is the factor from step 2).
Step 1: Group
Example :
b3 3b2 4b 12 Step 2: Factor out GCF from each group
b2 b 3 4 b 3 Step 3: Factor out GCF again
b 3 b2 4
b3 – 3b2 + 4b - 12
3 22 16 8 64x x x 2 x3 8x2 4x 32 2 x3 8x2 4x 32 2 x 2 x 8 4 x 8 2 x 8 x2 4 2 x 8 x 2 x 2
Example :
Try these on your own:
1. x 2 5x 6
2. 3x2 11x 20
3. x3 2164. 8x3 8
5. 3x3 6x2 24x
Answers:
1. (x 6)(x 1)2. (3x 4)(x 5)
3. (x 6)(x2 6x 36)4. 8(x 1)(x2 x 1)5. 3x(x 4)(x 2)
Remember…These are the methods from this section
Homework
p. 301 #5-35 oddsChallenge - #53